How to break a for loop and convert integers? - c++

Question

My program needs to calculates the cost for customers
to replace their carpet at $5 per yard for installation, various padding options,
carpet cost and total all rounded up to the nearest yard.
Padding is cost is based on:
Good - $3 per yard - 1-3year warranty
Better - $4 per yard 3-5 year warranty
Best- $5 per yard - 5-10 year warranty
Excellent - $7 per yard 10-20 year warranty
Operation:
Prompt User for number of rooms For each room:
Prompt length than width for each number of room
Calculate square feet a. convert square feet to square yards and round up b. square yards = yards required for room c. Calculate installation cost by square yard *$5
Prompt user to choose padding. a. Multiply padding cost by square yard of room
Prompt user for carpeting cost per sq yard of room: a. Calculate cost by multiplying input by squareyards required
Output total yards required
Output Installation cost
Output padding cost
Output carpet cost
Output total cost = + Installation + PAdding + Carpet
Grand total = cost of each room
******************/
I have 5 problems so far:
How to convert the integer padding choice to the cost of the quality
The floor loop will not break between rooms
When it displays the room number it starts at 0
How do I get the dollars to display to 2 decimal places?
How will I get the total of each rooms to store as doubles to get the grand total?
#include <iostream>
#include <iomanip>
#include <string>
#include <conio.h>
#include <string>
using namespace std;
const float INSTALL_COST = 5;
const float GOOD_PAD = 3;
const float BETR_PAD = 4;
const float BEST_PAD = 5;
const float EXC_PAD = 7;
const double SQU_FT_YD = 9;
int main ()
{
int padding, rooms, numreq, squareYards;
double length, width, squareFeet,priceSquareYard;
double paddingCost, installFee, totalCost, carpetCost;
//step 1:
cout << "Enter number of rooms: ";
cin >> numreq;
cout << endl;
//Step 2
cout << "Enter length of room: ";
cin >> length;
cout << endl;
cout << "Enter width of room: ";
cin >> width;
cout << endl;
//step 3
cout << "Select quality of padding:<1-4> ";
cout << "\n1. Good - $3 per yard - 1-3 year warranty \n2. Better - $4 per yard 3-5 year warranty \n3. Best- $5 per yard - 5-10 year warranty \n4. Excellent - $7 per yard 10-20 year warranty: ";
cin >> padding;
cout << "Enter price of carpeting per square yard of room: ";
cin >> priceSquareYard;
//step3
for(int x = 0; x < numreq; x++)
{
squareFeet = length * width;
squareYards = ((squareFeet / SQU_FT_YD) + 0.5);
if (squareYards > 0)
squareYards++;
installFee = squareYards * INSTALL_COST;
carpetCost = priceSquareYard * squareYards;
paddingCost = squareYards * padding;
totalCost = carpetCost + installFee + paddingCost;
cout << "\n Room " << x << " Yards Required = " << squareYards;
cout << "\n Room " << x << " Installation = $" <<installFee;
cout << "\n Room " << x << " Padding Cost = $" << paddingCost;
cout << "\n Room " << x << " Carpet Cost = $" << carpetCost;
cout << "\n Room " << x << " Total Cost = $" << totalCost;
}
_getch();
return 0;
}

Answer 1

To get totals within loops, simply store a variable outside of the loop, start it at 0, and increment it within the loop whenever necessary.
And you can use break; to break out of the loop completely. Also, if you need this, continue; will let you stop the current iteration and jump straight to the next iteration of your for-loop.
And for number 4, check this out:
NumberFormat/DecimalFormat treats certain floating-point values as longs instead of doubles