My code is
#include <iostream>
#include <string>
#include <stdlib.h>
using namespace std;
int main(void)
{
int n0,n1,n2;
int move = 0;
long unsigned int arr[3][3];
string str;
char color[4]={'B','G','C','\0'};
char col[40];
while( getline(cin,str))
{
if(str[0]=='\0')continue;
int temp=0,n=0;
int i=0,j=0,k=0;
do{ if(str[k]!=' ')temp=temp*10+(str[k]-48);
else {
if(temp==0) {k++;continue;
}
arr[i][j]=temp;
temp=0;
j++;
if(j==3){j=0;i++;}}
k++;
if(str[k]=='\0' && str[k-1]!=' ')arr[i][j]=temp;
}while(str[k]!='\0');
str[0]='\0'; move = 0;
for(;n!=3;n++)
{
for(j=0,k=0;j<3;j++)
{
temp=0;
if(j==n)continue;
if((j+1)%3==n)k=(j+2)%3;
else k=(j+1)%3;
temp= arr[1][n]+ arr[2][n]+arr[0][j]+ arr[2][j]+arr[0][k]+ arr[1][k]; //total movement
if(n==0 && move==0){move = temp;
n0=n,n1=j,n2=k;}
else if(move>temp){move = temp;
n0=n,n1=j,n2=k;}
else if(move == temp){ if(color[n0]>color[n]){n0=n,n1=j,n2=k;}
else if (color[n0]==color[n] && color[n1]>color[j]){n0=n,n1=j,n2=k;}
}
}
}
col[0]=color[n0],col[1]=color[n1],col[2]=color[n2],col[3]=' ',col[4]='\0';
cout<<col<<move;
}
return 0;
}
here when I enter a string and press Enter, courser only goes to the new line but code does not go forward. I have to press Enter twice to continue the program running. but it should work with one enter.
what is the problem here?
I just tried running your code. It works fine only need to input one time. This is what I ran on my compiler.
#include <iostream>
#include <string>
using namespace std;
int main(void)
{
int n0,n1,n2;
int move = 0;
long unsigned int arr[3][3];
string str;
char color[4]={'B','G','C','\0'};
char col[40];
while( getline(cin,str) )
{
cout<<"hello";
}
return 0;
}
OUTPUT
OUTPUT 2
OUTPUT 3
Related
This c++ code giving me errors and I dont know how to remove those errors.
code:
#include <iostream>
#include <string>
#include <fstream>
#include <cctype>
#include <iomanip>
using namespace std;
string& RaiseItToUpperCase(string& w)
{
int len = w.length();
for (int index =0; index <len; index++)
w[index]= toupper(w[index]);
return w;
}
void LoadData()
{
string filename;
while(true)
{
cout<<"Enter Data file:";
cin>>filename;
cout<<"Filename entered"<<filename<<endl;
ifstream myfile(filename.c_str());
if(!myfile.good())
{
cout<<"Please Enter a Valid text File"<<endl;
continue;
}
static std::string const targetExtension ("txt");
if (!(filename.size() >= targetExtension.size()
&& std::equal (filename.end() - targetExtension.size(),
filename.end(),
targetExtension.begin() ) ))
{
cout<<"File is not txt"<<endl;
continue;
}
break;
}
string i = filename;
string o;
cout<<"Enter an output file name:"<< endl;
cin>>o;
ofstream output;
ifstream input(filename);
output.open(o.c_str());
int charc =0;
int numw =0;
int longl =0;
int shortl =10000;
while (input>>1)
{
numw++;
charc = charc + i.length() +1;
if (i.length() > longl)
{
longl = i.length();
}
if (i.length() < shortl)
{
i =RaiseItToUpperCase(i);
output << i;
if(input.get() ==32)
{
output<<" ";
}
else
{
output<<"\n";
}
}
charc = charc - 1;
output<<"\nWord Counter Summary\n"<<endl;
output<<"Total Number of Words:"<<numw<<endl;
output<<"Total Number of Characters:"<<charc<<endl;
output<<" Largest Word Size:"<<longl<<endl;
output<<" Smallest Word Size"<<shortl<<endl;
}
}
int main ()
{
LoadData();
return 0;
}
This is c++ file stream program and I am trying to run this code but it giving me errors and i am not able to figure out how remove this errors
so Can anyone tell me how to remove those errors and make this code run
Update
here is the Error:
Error 1 error C2679: binary '>>' : no operator found which takes a
right-hand operand of type 'int' (or there is no acceptable
conversion) c:\users\acer\documents\visual studio
2012\projects\consoleapplication15\consoleapplication15\source.cpp 52 1 ConsoleApplication15
And thanks in advance
What do you want to do in while (input>>1) ?
If you want read out something:
If you want to read to an integer like int8_t (or int16_t / int32_t etc.):
int8_t number = 0;
while (input >> number)
If you want to read to a char:
char ch;
while (input >> ch)
It should convert a string like this: Example: HEloOO, should be converted into : heLOoo . For some reason it doesn't work,it just wont convert the letters from uppercase to lowercase and vice versa any help would be appreciated ?
#include <stdio.h>
#include <string.h>
#include <ctype.h>
void rek(char array[], int d)
{
int counter=0;
if(d==0)
{
printf("%s \n",array);
printf("%d \n",counter);
}
else
{
if((array[d]>='A' && array[d]<='Z')&&(array[d-1]>='A' && array[d-1]<='Z'))
{
array[d]=array[d]+32;
array[d-1]=array[d-1]+32;
counter++;
rek(array,d-2);
}
if((array[d]>='a' && array[d]<='z')&&(array[d-1]>='a' && array[d-1]<='z'))
{
array[d]=array[d]-32;
array[d-1]=array[d-1]-32;
counter++;
rek(array,d-2);
}
}
}
int main()
{
char array[100];
int d;
gets(array);
d=strlen(array);
rek(array,d);
return 0;
}
Your function does not call itself when two adjacent characters have different cases. Also you can get different results when the string is processed from the start or from the end.
I would write the function the following way
#include <stdio.h>
#include <ctype.h>
char * rek(char *s)
{
if (s[0] && s[1])
{
size_t i = 1;
if (islower((unsigned char)s[0]) && islower((unsigned char)s[1]))
{
s[0] = toupper((unsigned char)s[0]);
s[1] = toupper((unsigned char)s[1]);
++i;
}
else if (isupper((unsigned char)s[0]) && isupper((unsigned char)s[1]))
{
s[0] = tolower((unsigned char)s[0]);
s[1] = tolower((unsigned char)s[1]);
++i;
}
rek(s + i);
}
return s;
}
int main( void )
{
char s[] = "HEloOO";
puts(rek(s));
return 0;
}
The program output is
heLOoo
The main problem is that you recur only if your have a pair of upper-case or lower-case letters. Otherwise, you drop off the end of your if, return to the calling program, and quit converting things.
The initial problem is that you've indexed your string with the length. A string with 6 characters has indices 0-5, but you've started with locations 5 and 6 -- the final 'O' and the null character.
The result is that you check 'O' and '\0'; the latter isn't alphabetic at all, so you drop through all of your logic without doing anything, return to the main program, and finish.
For future reference, Here's the debugging instrumentation I used. Also see the canonical SO debug help.
#include<stdio.h>
#include<string.h>
#include<ctype.h>
void rek(char array[], int d)
{
int counter=0;
printf("ENTER rek %s %d\n", array, d);
if(d==0)
{
printf("%s \n",array);
printf("%d \n",counter);
}
else
{
printf("TRACE 1: %d %c%c\n", d, array[d-1], array[d]);
if((array[d]>='A' && array[d]<='Z')&&(array[d-1]>='A' && array[d-1]<='Z'))
{
printf("TRACE 2: upper case");
array[d]=array[d]+32;
array[d-1]=array[d-1]+32;
counter++;
rek(array,d-2);
}
if((array[d]>='a' && array[d]<='z')&&(array[d-1]>='a' && array[d-1]<='z'))
{
printf("TRACE 3: lower case");
array[d]=array[d]-32;
array[d-1]=array[d-1]-32;
counter++;
rek(array,d-2);
}
}
}
int main()
{
char *array;
int d;
array = "HEloOO";
d=strlen(array);
rek(array,d);
printf("%s\n", array);
return 0;
}
I come up with this dirty solution:
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
string solve(const string& str)
{
if (str.empty()) {
return "";
}
if (str.front() >= 'a' && str.front() <= 'z') {
return (char)toupper(str.front()) + solve(str.substr(1));
}
if (str.front() >= 'A' && str.front() <= 'Z') {
return (char)tolower(str.front()) + solve(str.substr(1));
}
}
int main()
{
string str;
cin >> str;
cout << solve(str) << endl;
return 0;
}
I am still a newbie in programming. I am writing a program of 2D Snell's Law. I know the problem may due to wrong localisations in Xcode, but I am writing in C++ only and g++ even gives me segmentation fault error after compiling successfully.
Here are my code for main function:
#include <string>
#include "Snell.hpp"
int main(int argc, const char * argv[]){//thread 1 exc_bad_access (code=2 address=0x7fff5f238304)
string filename;
double time;
Snell S[3600];
for (int i=1; i<=1; i++) {
while (S[i].angle_tr>0) {
filename="VPVSMOD"+to_string(i)+".txt";
S[i].Open(filename);
time=S[i].Locate(i);
cout<<"The "<<i<<"th event takes "<<time<<" seconds to reach the destination"<<endl;
S[i].angle_tr-=0.01;
}
}
return 0;
}
Here is the code for Snell.hpp
#ifndef Snell_hpp
#define Snell_hpp
#include <iostream>
#include <fstream>
#include <sstream>
#include <iomanip>
#include <string>
#include <algorithm>
#include <cmath>
using namespace std;
class Snell{
private:
double GetV(double lat,double dep);
int ny,nz,time;
double la[30],h[20],v[10][30];
double lat,alt,step;
public:
Snell();
void Open(string filename);
double Locate(int i);
double angle_tr;
};
#endif /* Snell_hpp */
and Snell.cpp:
#include "Snell.hpp"
Snell::Snell(){
ny=1,nz=3,time=0;
lat=0,alt=0,step=1;
angle_tr=M_PI/2;
}
void Snell::Open(string filename){
ifstream fin(filename);
stringstream ss;
string str,tok;
for (int i=0; i<nz; i++) {
(getline(fin, str));
ss.str(str);
for (int j=0; j<ny; j++) {
getline(ss, tok, ',');
v[i][j]=stod(tok);
cout<<v[i][j]<<",i="<<i<<",j="<<j<<endl;
}
ss.clear();
}
fin.close();
angle_tr=v[1][0]/v[0][0];
}
double Snell::GetV(double lat, double dep){
int index_la = 0,index_dep = 0;
index_dep=round(dep);
return (v[index_dep][index_la]+v[index_dep+1][index_la])/2;
}
double Snell::Locate(int i){
string filename;
double count_t=0;
double latt=lat,altt=alt,step_altt_all=0,angle=0,angle_p=0;
double vsy,vsz;
double vs,vs_n;
ofstream fout;
angle=M_PI/2-atan(angle_tr);
vs=GetV(lat, alt);
filename="Test"+to_string(i)+"_"+to_string(time)+".txt";
fout.open(filename,ios::out);
fout<<lat<<","<<alt<<endl;
while (altt!=2) {
//cout<<"Compute Velocity in each dimension"<<endl;
angle_p=angle;
vsy=vs*cos(angle);
vsz=vs*sin(angle);
//cout<<"Check Velocity"<<endl;
if (vsy==0||vsz==0) {
break;
}
//cout<<"Compute reflection point"<<endl;
step_altt_all=step/vsz;
count_t=count_t+step/vsz;//time plus one
latt=latt+vsy*(step_altt_all);
step_altt_all=0;
altt=altt+step;
//cout<<"Compute New Velocity"<<endl;
vs_n=GetV(latt,altt);
if ((vs_n*cos(angle)/vs)>1) {
break;
}
else{
angle=M_PI/2-asin(vs_n*cos(angle)/vs);
vs=vs_n;
if (angle!=angle_p)
fout<</*"position:"<<*/latt<<","<<altt<<endl;
}
}
fout.close();
filename="Result"+to_string(i)+"_"+to_string(time)+".txt";
fout.open(filename);
fout<<0<<" "<<latt<<" "<<altt<<" "<<step<<endl;
fout.close();
return count_t;
}
My immediate guess is: You must have blown your stack. Please see why is stack memory size so limited?
....And yes, On my platform, my guess was correct...
Reproducing your program, but modifying your main.cpp ...
int main(int argc, const char * argv[]){//thread 1 exc_bad_access (code=2 address=0x7fff5f238304)
string filename;
double time;
//Snell S[3600];
std::cout << sizeof(Snell) << " bytes" << std::endl;
return 0;
}
It gives an output of
2848 bytes
....And You are trying to allocate 3600 of them... ~10MB!!
The solution to that is to allocate it on the heap using a std::unique_ptr or better still, your good friend, std::vector.
Modify your main to this
#include <string>
#include <memory>
//or #include <vector>
#include "Snell.hpp"
int main(int argc, const char * argv[]){//thread 1 exc_bad_access (code=2 address=0x7fff5f238304)
string filename;
double time;
std::unique_ptr<S[]> p(new Snell[3600]);
//or std::vector<Snell> S(3600);
for (int i=1; i<=1; i++) {
while (S[i].angle_tr>0) {
filename="VPVSMOD"+to_string(i)+".txt";
S[i].Open(filename);
time=S[i].Locate(i);
cout<<"The "<<i<<"th event takes "<<time<<" seconds to reach the destination"<<endl;
S[i].angle_tr-=0.01;
}
}
return 0;
}
I'm using C++. So far, my code goes like this:
#include <stdio.h>
#include <conio.h>
#include <string.h>
#include <windows.h>
int main() {
char word[100]; int ctr, count = 0;
printf("Enter string: "); gets(word);
ctr = 1;
while (word[ctr] != '\0') {
if (word[ctr-1] == word[ctr]) count++;
ctr++;
}
printf("%d", count);
return 0;
}
Sample Run
Enter string: mississippi
3
Enter string: mmmmrrnzzz
6
I've got the first sample run correctly (mississippi) with only 3 characters appearing twice consecutively but not on the second sample run (mmmmrrnzzz) with output 6.
My problem is that, it should not be 6 but 4 instead. 1 for the first two consecutive m, another separate 1 for the next two consecutive m, 1 for r, and 1 for z. I want a separate count for the first "mm" and the second "mm" and also for the "zz" but I don't know how.
I'm a freshman and very new to programming. I wish I could explain better. I'm hoping you could help me. Thank you.
In case of multiple couples like mmmm you need to make a double incrementation of your counter:
#include <stdio.h>
#include <string.h>
int main()
{
char word[100];
int ctr;
int count = 0;
printf("Enter string: ");
gets(word);
int len = strlen(word);
ctr = 1;
while (ctr<len) {
if (word[ctr-1] == word[ctr])
{
count++;
ctr++;
}
ctr++;
}
printf("%d", count);
return 0;
}
First of all the program looks like a C program. In fact you are not using C++. You are using C.:) At least for example in C++ you should use header
#include <cstdio>
instead of
#include <stdio.h>
and so on.
And moreover it has a bug because in general the string can be empty. In this case the condition of the loop skips the first zero-terminating character and the program has undefined behaviour.
Here is a correct approach
#include <stdio.h>
int main( void )
{
const char *s = "mmmmrrnzzz";
size_t count = 0;
while ( *s++ )
{
if ( *s == *( s - 1) )
{
++count;
++s;
}
}
printf( "count = %zu\n", count );
}
The output is
count = 4
Take into account that function gets is unsafe and is not supported by the C (or C++) Standard any more.
You should use function fgets instead of gets.
This will work
#include <stdio.h>
#include <string.h>
int main() {
char word[100]; int ctr, count = 0;
printf("Enter string: "); gets(word);
int len=strlen(word);
ctr = 1;
while (ctr<len) {
if (word[ctr-1] == word[ctr])
{
count++;
ctr++;
}
ctr++;
}
printf("%d", count);
return 0;
}
A standard library version:
#include <algorithm>
#include <iostream>
#include <string>
int main()
{
int count{};
std::string s;
std::cin >> s;
for (auto it = s.begin(); (it = std::adjacent_find(it, s.end())) != s.end(); it += 2)
++count;
std::cout << count << '\n';
}
I have written a code to copy from first string's element to second string except space.it simply takes input and if it gets a space then it doesn't insert character of first string into second string. when i am printing second string at the last,the string is partially broken up. But instead of space,if i put any character the second string fully prints out.I am trying but could you fix my bug please?
#include <bits/stdc++.h>
#include <iostream>
using namespace std;
int main()
{
char str1[100];
while(cin>>str1)
{
char str2[100];
int k=0;
for(int i=0; str1[i]!='\0'; i++)
{
if(str1[i]!=' ')
{
str2[k] = str1[i];
k++;
}
}
str2[k] = '\0';
cout<<"result is "<<str2<<endl;
}
return 0;
}
You can use gets() and puts() to read/display a string:
#include <iostream>
#include <string.h>
using namespace std;
int main(void)
{
char s1[100], s2[100];
int k=0;
puts("Insert your string:");
gets(s1);
for (int i=0; i<strlen(s1); i++) {
if (s1[i] != ' ') {
s2[k]=s1[i];
k++;
}
}
puts(s2);
}