Trace Words in Shell Script - regex

Question

I am trying to find malloc-free series. Consider that we have 1000s of test cases. People may forget to free ptr. Please help me in optimizing the script.
Sample File Under test
Test(func_class,func1)
{
int i,j;
char* ptr = (char*) malloc(sizeof(char));
free(ptr);
}
Test(func_class,func1)
{
int i,j;
char* ptr = (char*) malloc(sizeof(char));
/ Memory Leak /
}
Script under development :
export MY_ROOT=`pwd`
_COUNT=0
pwd
_COUNT_WORD=0
filename=test.c
cat $filename | while read line
do
echo "Reading Line = $LINE"
for word in $line
do
_COUNT_WORD=$(($_COUNT_WORD+1))
echo $_COUNT_WORD $word
if [ "$word" == "malloc\(sizeof\(char\)\);" ]; then
_MALLOC_FLAG=1 #this part of the code is not reached
echo "Malloc Flag Hi"
echo $word[2]
fi
done
_COUNT_WORD=0
done
I have some issue in matching the malloc regex. I know the script needs a lot of modifications as we have to find the pattern of individual person writing malloc.

Answer 1

There are other ways to check:
Using awk:
awk '/malloc/ || /free/{count++;}END{printf "%d",count}' fileundertest
This will search for "malloc" and "free" words in file and will print out the count. if count is even you can say for every malloc there is free.
Using grep:
grep -c "malloc" fileundertest
This will count the malloc word in file
Similarly,
grep -c "free" fileundertest
To list out the line number
grep -n "malloc" fileundertest