Function Call in switch statement. - c++

Question

Hey guys I'm trying to work out how to call a function in my code using a switch statement. I have tried to look for many different references but no matter what nothing seems to work if somebody could please put me on the right path that would be a big help. Here's the code:
#include <iostream>
#include <string>
using namespace std;
int playGame(string word);
int main()
{
int choice;
bool menu = true;
do{
cout <<"Please select one of the following options: \n";
cout << "1: Play\n"
"2: Help\n"
"3: Config\n"
"4: Quit\n";
cout << "Enter your selection (1, 2 and 3): ";
cin >> choice;
//*****************************************************************************
// Switch menu to display the menu.
//*****************************************************************************
switch (choice)
{
case 1:
cout << "You have chosen play\n";
int playGame(string word);
break;
case 2:
cout << "You have chosen help\n";
cout << "Here is a description of the game Hangman and how it is played:\nThe word to guess is represented by a row of dashes, giving the number of letters, numbers and category. If the guessing player suggests a letter or number which occurs in the word, the other player writes it in all its correct positions";
break;
case 3:
cout << "You have chosen Quit, Goodbye.";
break;
default:
cout<< "Your selection must be between 1 and 3!\n";
}
}while(choice!=3);
getchar();
getchar();
cout << "You missed " << playGame("programming");
cout << " times to guess the word programming." << endl;
}
int playGame(string word) //returns # of misses
{
//keep track of misses
//guess is incorrect
//repeated guess of same character
//guess is correct
int misses = 0;
int exposed = 0;
string display = word;
for(int i=0; i< display.length(); i++)
display[i] ='*';
while(exposed < word.length()) {
cout << "Miss:" << misses << ":";
cout << "Enter a letter in word ";
cout << display << " : ";
char response;
cin >> response;
bool goodGuess = false;
bool duplicate = false;
for(int i=0 ; i<word.length() ; i++)
if (response == word[i])
if (display[i] == word[i]) {
cout << response << " is already in the word.\n";
duplicate = true;
break;
} else {
display[i] = word[i];
exposed++;
goodGuess = true;
}
if (duplicate)
continue;
if (!goodGuess){
misses ++;
cout << response << " is not in the word.\n";
}
}
cout << "Yes, word was " << word << "." << endl;
return misses;
}

Answer 1

You are not calling playGame function in switch statement,
switch (choice)
{
case 1:
cout << "You have chosen play\n";
//int playGame(string word); // this does not call playGame,
// it re-declare playGame function again
playGame("word"); // this will call playGame with word parameter
//^^^^^^^^^^^^^^^
break;

Answer 2

int playGame(string word);
In your switch statement might be the problem...try:
int misses = playGame(word);
You are trying to return the number of misses from your playGame method so you have to put the return data inside a variable.