regex match anything between {esbmsg:header:xxxxxx} [closed] - regex

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How to match anything between {esbmsg:header: and }
like xxxxxx could be any string {esbmsg:header:xxxxxx}


Try with:
{esbmsg:header:([^}]*)}
Where [^}]* matches everything that is not } character.


Try this regex
{esbmsg:header:(.*)}
It will also allow you to have any character in value.


Well, if you want to capture only the content of your expression (the "xxxxx" part) the best approach is to use positive look ahead:
(?<={esbmsg:header:)[^}]+
Depending on how your content looks you might have to tweak the [^}] part. For further information on regex (or a detailed explanation of the expression above) I recommend the following:
Regex reference
Regex tutorial

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Regex match every occurance and wildcard condition [closed]

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How can I write a regex that will match the following conditions:
Where every instance of the occurance 'eVar7=' contains the following 'unav'
This should be false:
;AA;;;;eVar7=nr_unav,;AA;;;;eVar7=br_unavail,;AA;;;;eVar7=sugg,;AA;;;;eVar7=sugg,;AA;;;;eVar7=sugg
and this should return true:
;AA;;;;eVar7=nr_unav,;AA;;;;eVar7=br_unavail,;AA;;;;eVar7=nr_unav,;AA;;;;eVar7=nr_unav11,;AA;;;;eVar7=nr_unavasdfasdferwgf

This regex does the opposite. If there is a match means that you don't want it:
eVar7=(?![^;]*?unav)
It uses a negative lookahead. Meaning that after the eVar7 match there should not be something with "unav" in the middle. If so, it matches.
This is just to put you on the right track however as there are a lot to consider with your examples. For example where exactly should this "unav" pattern exist. What characters are allowed between eVar7 and "unav" etc. Feel free to change the regex to suit your needs.

How to start a RegEx statement at the 2nd position of a string [closed]

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I have a string
.HACK G.U. VOL. 1 REBIRTH
I'm using a tool that allows me to specify a RegEx statement that can be used in a replace operation.
I want the RegEx to find all the periods "." that start after the 1st position. The replace operation should return the following.
.HACK GU VOL 1 REBIRTH
Thanks

The following will do the trick:
(?<!^)(\.)
per http://rubular.com/r/w1apzTZLPk
Since Javascript doesn't support negative lookbehind, this can't be done in Javascript, but there are alternatives as discussed in http://blog.stevenlevithan.com/archives/mimic-lookbehind-javascript
One approach in this case would be to capture the previous character and replace it with the same content as part of the replacement process, as in:
(.)(\.)
Note: You don't need to use a capture group for the matching of the literal . in either of the above. I just used that technique to highlight the match in Rubular.

find regular expression named group [closed]

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In my previous question how to find Regular expression named groups, I asked the regular expression for pattern
//input var: x(length),y(width),z(height)
If pattern will be changed like
//input var: x(length in cm),y(width in cm),z(height in cm)
Then what will be the regular expression for this?
what will be the change in this line
Dim extractIndividualInputsRegex As New Regex("(?<input>\w+)\((?<meaning>\w+)\)")
I tried
Dim extractIndividualInputsRegex As New Regex("(?<input>\w+)\((?<meaning>.*)\)")

Try the following:
Dim extractIndividualInputsRegex As New Regex("(?<input>\w+)\((?<meaning>[\w\s]+)\)")
The (?<meaning>[\w\s]+)\) will match a combinations of space and word characters inside the ( and ) which should be enough.
Regex Hero Demo

Try this:
(?<input>\w+)\((?<meaning>\w+) in (?<unit>\w+)\)
Shown on regexr: http://regexr.com?36oss
Or, if you want all three words in meaning group, try:
(?<input>\w+)\((?<meaning>\w+ in \w+)\)
Shown on regexr: http://regexr.com?36osv

Extract the email address, and replacing a character using Regex [closed]

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I am trying to come up with Reg ex expression that would match an email address starting with format E- and replacing the "AT" with an actual "#" sign.
Here is an example:
E-CANAD.JACK AT EXAMPLE.COM.
The desired output will need to look like CANAD.JACK#EXAMPLE.COM.

Replace:
[eE]-([a-zA-Z0-9]+(?:[._-][a-zA-Z0-9]+)*) (?:at|AT) ([a-zA-Z0-9]+(?:[._-][a-zA-Z0-9]+)*[.][a-zA-Z]+)
By:
$1#$2
More:
Visualization by
Debuggex
Demo by RegExr

You didn't mention your language, so I'm assuming perl
s/^E-(.*) AT (.*)$/$1\#$2/;

I'm confused by a simple regex: I need to match something like [Test] but not Test [closed]

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How would I go about writing a regex to match the first example, but not the second?
Thank you --

Try
\[Test\]
You need to escape the [ and ] as they indicate range start/end.

[] are special characters for a regex, used for defining a character class, therefore escape them with backslashes.
\[Test\]
If you use [Test], it will match a single character which is either T, e, s or t.