Class 2D array turns to arr [] when called by function C++ - c++

Question

I have a university assignment and I am completely confused on how to pass the array correctly to prevent the array from being passed as a single array and not a 2D array.
We are to create a random maze generator that will allow us to play that maze too. We are using a specialized windows code to display the maze, but that's not were the problem is so Ill leave that out
My lecturer gave us the skeleton code to work from. What must I change to get it to work?
We have not learnt dynamic memory location or vectors. We have to use an array. Please Help!!?
Here is his code:
I have used the same and just added all the function parameters. I have not changed anything with 'maze' though
class MazeSquare
{
public:
bool leftWall, rightWall, bottomWall, topWall;
bool visited;
int steps;
MazeSquare() // constructor
{
Initialise();
}
void Initialise(void) // reinitialise a square for a new maze
{
leftWall = true; // create the maze square with all the walls
rightWall = true;
bottomWall = true;
topWall = true;
visited = false; // the robot has not visited the square yet
steps = 256; // greater than maximum possible number of steps
}
};
// constants
const int MAZE_SIZE = 16;
// function prototypes
void CreateMaze(MazeSquare maze[MAZE_SIZE][MAZE_SIZE]);
void SolveMaze(MazeSquare maze[MAZE_SIZE][MAZE_SIZE]);
void RestartMaze(MazeSquare maze[MAZE_SIZE][MAZE_SIZE]);
void MoveRobot(MazeSquare maze[MAZE_SIZE][MAZE_SIZE], int &x, int &y, Point click);
void DrawWindow(MazeSquare maze[MAZE_SIZE][MAZE_SIZE], int x, int y);
int ccc_win_main() // main function for a graphics program
{
MazeSquare maze[MAZE_SIZE][MAZE_SIZE]; // maze design
int x = 0, y = 0; // robot position
bool exit = false; // flag to control end of program
// initialise the random number generator
srand((unsigned int)(time(NULL)));
/* initialise the window coordinates here */
CreateMaze(maze); // create a new maze
DrawWindow(maze); // draw the image in the GUI window
do
{
// get a mouse click
Point click = cwin.get_mouse("Click a button or move the robot");
// handle the different types of mouse clicks
if (/* new button is clicked */)
{
CreateMaze(maze);
x = 0;
y = 0;
}
if (/* solve button is clicked */)
{
SolveMaze(maze);
}
if (/* restart button is clicked */)
{
RestartMaze(maze);
x = 0;
y = 0;
}
if (/* exit button is clicked */)
{
exit = true;
}
// handle robot moves
if (/* maze is clicked */)
{
MoveRobot(maze, x, y);
}
DrawWindow(maze);
} while (!exit);
return 0;
}

Answer 1

Confusion number one - You cannot pass arrays to functions in C++.
Confusion number two - You cannot declare arrays as function parameters in C++
Confusion number three - 2D arrays are single arrays, a 2D array is an arrays of arrays, therefore it's a 'single array` also. I guess I'm saying the term single array doesn't have much meaning.
Arrays are a confusing topic in C++. You cannot do everything you might expect to be able to do with them. Instead everything is done with pointers. The relationship beween arrays and pointers in C++ is another confusing topic. You really need to read a book. Any specific questions, ask again.
But on the bright side I don't see anything particularly wrong with your code. You're certainly are not passing single arrays to your functions, as you are worried about.
EDIT:
Perhaps I should make this a little clearer. On point two, this code
void CreateMaze(MazeSquare maze[MAZE_SIZE][MAZE_SIZE]);
certainly looks like you are declaring a function with an array parameter. But it doesn't. Instead the compiler takes the code and converts it into the equivalent code that uses pointers.
On point one, this code
CreateMaze(maze); // create a new maze
certainly looks like you are passing an array to a function, but again you are not. Given that code the compiler passes a pointer to the first element of your maze array, it doesn't pass the array itself.