I'm trying to run a python web server. The server says is running so I assume it is all working, except that I can only see the html text. The jpeg/image and the pdf files won't dispaly. Here is what i have so far.
#import socket module
from socket import *
serverSocket = socket(AF_INET, SOCK_STREAM)
serverSocket.bind(('', 12000))
serverSocket.listen(1)
while True:
print 'Ready to serve...'
connectionSocket, addr = serverSocket.accept()
print 'Required connection', addr
try:
message = connectionSocket.recv(1024)
filename = message.split()[1]
f = open(filename[1:])
outputdata = f.read()
#Fill in start
connectionSocket.send('HTTP/1.0 200 OK\r\n\r\n')
#Fill in end
#Send the content of the requested file to the client
for i in range(0, len(outputdata)):
connectionSocket.send(outputdata[i])
connectionSocket.close()
except IOError:
#Send response message for file not found
#Fill in start
connectionSocket.send('404 Not Found')
#Fill in end
#Close client socket
#Fill in start
connectionSocket.close()
#Fill in end
serverSocket.close()
I'm working on the same thing. I added the line:
connectionSocket.send('Content-Type: image/jpeg')
right after this:
connectionSocket.send('HTTP/1.0 200 OK')
I assume I'm/we're just missing some line in the header.
Related
I captured packets on individual text files with tcpdump, I want to send back the captured packets, first I extracted the IP and Port, but I have not been able to send the packet.
This is my code:
def client():
packet = open("packet3.txt", "r")
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.settimeout(10)
sock.connect(("192.168.128.1", 80))
while True:
try:
sock.send("packet")
sleep(1)
reply = sock.recv(131072)
if not reply:
break
print "recvd: ", reply
except KeyboardInterrupt:
print "bye"
break
sock.close()
return
client()
I get this error:
reply = sock.recv(131072)
error: [Errno 10054] An existing connection was forcibly closed by the remote host
I am trying to send some data from my python client to python server
I have followed this link
My python client code is as follows
#Socket client example in python
import socket #for sockets
import sys #for exit
#create an INET, STREAMing socket
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
except socket.error:
print 'Failed to create socket'
sys.exit()
print 'Socket Created'
host = '10.4.1.25';
port = 80;
try:
remote_ip = socket.gethostbyname( host )
except socket.gaierror:
#could not resolve
print 'Hostname could not be resolved. Exiting'
sys.exit()
#Connect to remote server
s.connect((host , port))
print 'Socket Connected to ' + host + ' on ip ' + remote_ip
message = "16973"
try :
#Set the whole string
s.sendall(message)
except socket.error:
#Send failed
print 'Send failed'
sys.exit()
print 'Message send successfully'
#Now receive data
reply = s.recv(4096)
print reply
the python server code is
import socket
import sys
HOST = '' # Symbolic name meaning all available interfaces
PORT = 80 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'Socket created'
try:
s.bind((HOST, PORT))
except socket.error , msg:
print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
sys.exit()
print 'Socket bind complete'
s.listen(10)
print 'Socket now listening'
#wait to accept a connection - blocking call
conn, addr = s.accept()
print 'Connected with ' + addr[0] + ':' + str(addr[1])
#now keep talking with the client
data = conn.recv(1024)
conn.sendall(data)
conn.close()
s.close()
The Function sendall is used to send data to client , means when I enter the text in terminal on server I should see it on client as well. But this does not happen
The output which I get is
Server Output
$ python server.py
Socket created
Socket bind complete
Socket now listening
Connected with 10.4.1.255:44656
Client Output
$ telnet localhost 8888
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
I am unable to know what's going wrong here?
Also how can I send data (message) from Python Client to Python server??
Any help would be great !
Thanks!
My requirement is to capture logs for a particular http request sent to server from project server log file. So have written two function and trying to execute them parallel using multiprocessing module. But only one is getting executed. not sure what is going wrong.
My two functions - run_remote_command - using paramiko module for executing the tail command on remote server(linux box) and redirecting the output to a file. And send_request - using request module to make POST request from local system (windows laptop) to the server.
Code:
import multiprocessing as mp
import paramiko
import datetime
import requests
def run_remote_command():
basename = "sampletrace"
suffixname = datetime.datetime.now().strftime("%y%m%d_%H%M%S")
filename = "_".join([basename, suffixname])
print filename
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
try:
ssh.connect(hostname='x.x.x.x',username='xxxx',password='xxxx')
except Exception as e:
print "SSH Connecting to Host failed"
print e
ssh.close()
print ssh
tail = "tail -1cf /var/opt/logs/myprojectlogFile.txt >"
cmdStr = tail + " " + filename
result = ''
try:
stdin, stdout, stderr = ssh.exec_command(cmdStr)
print "error:" +str( stderr.readlines())
print stdout
#logger.info("return output : response=%s" %(self.resp_result))
except Exception as e:
print 'Run remote command failed cmd'
print e
ssh.close()
def send_request():
request_session = requests.Session()
headers = {"Content-Type": "application/x-www-form-urlencoded"}
data = "some data "
URL = "http://X.X.X.X:xxxx/request"
request_session.headers.update(headers)
resp = request_session.post(URL, data=data)
print resp.status_code
print resp.request.headers
print resp.text
def runInParallel(*fns):
proc = []
for fn in fns:
p = mp.Process(target=fn)
p.start()
proc.append(p)
for p in proc:
p.join()
if __name__ == '__main__':
runInParallel(run_remote_command, send_request)
Output: only the function send_request is getting executed. Even I check the process list of the server there is no tail process is getting created
200
Edited the code per the #Ilja comment
I'm using following function to make telnet connection verification
telnetlib.Telnet("172.28.5.240", "8080")
When the connection refused it shows exception message. Is it possible to hide the message and detect as success or failed through if condition?
You can use try-except-finally blocks
try:
#
#
response = 'Success'
except:
response = 'Failed'
finally:
print response
Based on Suku's answer I develop my code. that is a working answer. And following is my script for reference.
try:
conn = telnetlib.Telnet("172.28.5.240", "80")
response = 'Success'
except:
response = 'Failed'
finally:
print response
None of the options helped me.
Maybe someone will come in handy.
100% working version:
Used to check the availability of the RDP server in ZABBIX:
import telnetlib
response = ''
HOST = '192.168.1.201'
PORT = 3389
tn = telnetlib.Telnet()
try:
tn.open(HOST, PORT, 3)
response = '2'
except Exception:
response = '0'
finally:
tn.close()
print(response)
i'm new in python and english :). i'm trying to send an image file usşng python sockets and i have written this cosdes. it says it work but i get an empty file or missing image file.
this is the codes i've written:
server:
import socket
host = socket.gethostname()
port = 5000
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host, port))
s.listen(1)
sunucu , adres = s.accept()
print "baglanti saglandi"
def recvall(baglanti, buf):
data = ""
while len(data) < buf:
packet = baglanti.recv(buf - len(data))
if not packet:
return None
data += packet
return data
f = open("ggg.png", "w")
while True:
veri = sunucu.recv(512)
if not veri:
break
f.write(veri)
f.close()
print "resim alindi."
sunucu.close()
s.close()
and client:
import socket
host = socket.gethostname()
port = 5000
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host , port))
f = open("ornekresim.png", "r")
while True:
veri = f.readline(512)
if not veri:
break
s.send(veri)
f.close()
print "resim gonderildi"
s.close()
By default the Python function open opens file in text mode, meaning it will handle all input/output as text, while an image is decidedly binary.
A file in text mode will do thing like translating newline sequences (which are different on different systems). That means the data you read will be corrupted.
To open a file in binary mode, then append 'b' to the mode flags, like e.g.
f = open("ornekresim.png", "rb") # <-- Note the 'b' in the mode
However, with your code this leads to another problem, namely that you can't use readline anymore. Not that it made much sense anyway, reading binary data as lines since there are no "lines" in binary data.
You have to use the read function instead.