correctly declaring buffer for tcp server c++ - c++

Question

I am using a tcp server that I wrote for handling inputs into a database. I have a tcp client sitting on a server that sends the filename to a tcp server sitting on a different linux server. once the filename is received the linux server goes into a shared folder and pulls the file then inserts it into the database.
my problem is with correctly declaring the buffer and clearing it to make sure I get the correct filename without any gibberish added or anything removed from it.
right now it is working like this:
char data[1024];
which is fine but it does not automatically delete the buffer completely, so i tried to implicitly allocate memory to "data" such as:
char *data = (char*) malloc(1024 * sizeof(char));
...
free(data);
OR
char *data = new char[1024];
...
delete[] data;
For some reason the above two declaration are declaring a buffer of size =8 I got this using
sizeof(data);
also what I am receiving is only 8 characters long. I am not sure why it is doing this, any help??
EDIT
char *data = (char*)malloc(1048 * sizeof(char));
if(data==NULL) exit(1);
cout << "DATA Size: " << sizeof(data) << "\n";
int msglen = read(conn, data, sizeof(data));
cout << "Server got " << msglen << " byte message: " << data << "\n";
if(write(conn, &msglen, sizeof(msglen))<0){
cout << "Failed to write back to the client " << strerror(errno);
}
free(data);
close(conn);

Answer 1

There are several things wrong with your code.
1) dont use malloc - you flagged your question as c++ - use malloc only when necessary replace it with:
const int dataSize = 1024;
char *data = new char[dataSize];
2) sizeof(data) when data is char* returns 8 because it returns size of a pointer not an array when you declare data as array sizeof will return bytes occupied by whole array. you should replace you read with:
int msglen = read(conn,data,dataSize)
3) I assume that u want to write data u've just received back to sender.. Then:
in write function you put sizeof(msglen) as third argument which will (mostly) always return 4. remove sizeof( ).
write(conn, data, msglen);
after you are done with the data dont forget to clear the memory using:
delete[] data;
use delete[] always when you assigned memory with new[].

Answer 2

API write(int socket, char *buf, int len);
Code becomes this:
write(con, data, msglen);

Answer 3

Assuming you can't use the stack (e.g. char buf[1024]), using naked pointers is discouraged as bad style and bug prone. Instead, use RAII and some variant of amanged memory, such as shared_ptr or unique_ptr.
#include <memory> and use a std::shared_ptr<>, or std::unique_ptr<> plus std::move() to return the buffer:
std::size_t bufSize = 1024;
std::unique_ptr<char[]> myUniqueBuf(new char[bufSize]);
ssize_t msglen = ::read(conn, *myUniqueBuf, bufSize); // return type is ssize_t, not int
return std::move(myUniqueBuf); // If you need to return the buffer
// I think you will probably prefer a shared_ptr<> because it has a copy
// constructor which makes it easier to pass around and return from functions
std::shared_ptr<char[]> mySharedBuf(new char[1024]);
ssize_t msglen = ::read(conn, *mySharedBuf, bufSize); // return type is ssize_t, not int
ssize_t bytesOut = ::write(conn, *mySharedBuf, msglen);
return mySharedBuf;
The advantage to std::shared_ptr or std::unique_ptr is that you don't have to worry about cleaning up a naked pointer (i.e. calling delete[] data;) because with managed memory it will happen automatically for you when the buffer handle goes out of scope or the reference count goes to zero (e.g. myUniqueBuf or mySharedBuf).