For example, I'm given carModels.cpp, carModels.h, carType.in, manufacturers.h, manufacturers.o, and lastly my own file tester.cpp. How would I go about linking all of these using g++ in a Linux terminal? Would I have to create any additional ".o" files? I'm supposed to assume that the given files already work. Multiple lines in terminal are fine, I just I want a clear understanding of it. (I'm coming from a C++ IDE that I didn't really care for.)
Compile each source file to its own object file:
g++ -I . -c carModels.cpp -o carModels.o
g++ -I . -c tester.cpp -o tester.o
Now link all object files together:
g++ carModels.o tester.o manufacturers.o -o outputname
Consider adding more options like -O3, -std=c++11, -Wall, etc. as needed.
you can do this in two steps, first compile to *.o files,
gcc -c your.cpp other.cpp .....
then link them
gcc -o you_out_put_name the_object_files.o ...
In a single line, that would be just g++ -o tester *.cpp *.o. GCC will sort everything out. In particular, the *.h files are referenced via #include "" statements in the .cpp files.
Related
I'm having a custom C header file that I have created. There are several files in my directory as follows.
lib1/
-lib1.h
-lib1.c
lib2/
-lib2.h
-lib2.c
-lib_main.c
-lib_main.h
-main.c
-main.cpp
-Makefile
Now, for testing the header file with a test file called main.c, I will be giving the following command in the terminal,
gcc lib_main.c lib1/lib1.c lib2/lib2.c main.c -o ./main
Now, how could I test the same header files with main.cpp instead of main.c, how do I change it?
You should (and most probably must) compile separately the c and c++ sources into a object file, and then link together.
As an example
gcc -c -o lib1.o lib1/lib1.c
gcc -c -o lib2.o lib2/lib1.c
gcc -c -o lib_main.o lib_main.c
g++ -c -o main.o main.cpp
g++ -o main lib1.o lib2.o lib_main.o main.o
The first four commands create a series of object files, with extension .o. The last command link together the object files into an executable.
Obviously you need to add the relevant compiler options for each source.
Two important points to notice:
Order of files in the linking is important. See discussion here and here.
To mix c and c++ code with each other, for example if a c++ code calls a c function, you need to follow specific guidelines.
I want to use OpenGL GLEW library. I have the binary downloaded and its folder is in the folder with my .cpp file. My .cpp file uses #include <eglew.h>.
How should I format my command for MinGW to compile my .cpp file? Do I compile with the .lib file like g++ -L./path/to/lib/file.lib test.cpp -o test or do I do something else like link to the header files g++ -I./path/to/headers test.cpp -o test?
To better understand things maybe it's better to split compiling and linking steps.
If you get errors then you will also know in which step the problem occurs.
I'm assuming you have the following folders/files:
/path/to/eglew/include/GL/eglew.h
/path/to/eglew/lib/libglew32.a
Compiling:
g++ -Wall -c -o test.o test.cpp -I/path/to/eglew/include/GL
Linking:
g++ -o test.exe test.o -L/path/to/eglew/lib -lglew32
Though I would expect to see #include <GL/eglew.h> in which case the linker include flag should be -I/path/to/eglew/include.
the program no run. how to fix it ( i use C-Free 4.0)
? g++.exe : cannot specify -o with -c or -S and multiple compilations
Can you include the entire build command that you are using? My guess is that you are trying to compile multiple files into an executable in a single command (such as g++ file1.cc file2.cc file3.cc -o file.exe), but you've also got a -c flag in the commpilation command.
For reference, normally when you compile, two things happen. First, source code gets turned into machine code. Second, machine code gets linked to produce an executable.
In gcc/g++, you can compile one source file into machine code by using the -c flag. You can link one (or many) machine code file(s) into an executable by using the -o flag. There's a shorthand where you can compile and link all in one step using the -o flag (but that's generally not a good idea, because then any change to any file requires you to recompile everything).
As for -S, that's for when you want to generate assembly code from source code. I'm guessing that's not what you are doing, though.
Here's an example, just to round it all out. Suppose that you have files file1.cc and file2.cc, and there is a main() function in file1.cc. Then you can create machine code like this:
g++ file1.cc -c
g++ file2.cc -c
This will result in there being two new files, file1.o and file2.o.
Next, you can link them like this:
g++ file1.o file2.o -o file.exe
This will produce file.exe, the final executable that you can run.
Ok, so this might not be a great question, but I'm a bit stuck.
I have 3 programs:
pegio.c/pegio.h - Does hardware initialization and functions for my device
PegIOHandler.cpp/PegIOHandler.h - Handles I/O for device
PegRTU.cpp - Main function
My project implements the opendnp3 (which allows one to transmit data using the DNP3 protocol) library.
Now, to compile it I first compile the pegio.c file
gcc -c pegio.c -o pegio.o
Easy, up to here I understand.
Secondly I compile the IOHandler and reference pegio.c as it uses it.
g++ -c PegIOHandler.cpp pegio.c -o PegIOHandler.o -std=c++0x
Now it gives me the following output.
g++: warning: pegio.o: linker input file unused because linking not done
But, it still creates the object file. HOWEVER, PegIOHandler implements opendnp3 header files, which is included in PegIOHandler.cpp and PegIOHandler.h. When I attempt to compile these files without using the '-c', it tells me that there are undefined references to the opendnp3 files. I know I have to link them to my project, but how do I do that?
Then compililing my third and final file:
g++ PegRTU.cpp pegio.o PegIOHandler.o -o pegrtu -std=c++0x
This now tells me that there are undefined references to the opendnp3 files.
So: How do I link the opendnp3 library to my project / code files???
Thanks!
Ouch. So many misunderstandings. You don't need the previously compiled object files to compile further source files to object code. However, you do need to link them together at the end of the compilation process, including any libraries required. All in all:
gcc -c pegio.c -o pegio.o
g++ -c PegIOHandler.cpp -o PegIOHandler.o -std=c++0x
g++ -c PegRTU.cpp -o PegRTU.o -std=c++0x
g++ -o executable_name *.o -lopendnp3 # or whatever linker flag is needed for OpenDNP3
And pretty please, read this.
I am very aware of compiling C++ programs with g++ in linux environment. But, may be I am missing something, I am getting this strange output/behaviour.
I have source file in test.cpp.
To compile this, I did
(1)
g++ -c test.cpp
g++ -o test test.o
./test
Everything works fine.
But when I did compling and linking in same stage, like this
(2)
g++ test.cpp -o test
./test => Works fine
(3)
g++ -c test.cpp -o test => Doesn't work
In my last case, test is generated but is no more executable; but in my guess it should work fine.
So, what is wrong or do I need to change some settings/configuration ??
I am using g++ 4.3.3
Thanks.
When you say:
g++ -c test.cpp -o test
The -c flag inhibits linking, so no executable is produced - you are renaming the .o file.
Basically, don't do that.
You are forcing compiler to produce an object file and name it like an executable.
Essentially your last line tells: compile this to an object file, but name it test, instead of test.obj.
-c flag means Compile Only
Try
g++ -o test test.cpp
Specifying -o in the g++ command line tells the compiler what name to give the output file. When you tried to do it all in one line, you just told the compiler to compile test.cpp as an object file named test, and no linking was done.
Have a look at the fabulous online manual for GCC for more details.
from the gcc manual:
-c Compile or assemble the source files, but do not link. The linking
stage simply is not done. The ultimate output is in the form of an
object file for each source file.
You must link the compiled object files to get the executable file.
More info about compiling and linking and stuff is here.
Read man g++. The switch -c is to compile only but not to link.
g++ -c test.cpp -o test
does what
g++ -c test.cpp
does but the object file will be test istead of the default name test.o. An object file cannot be executed.