Returning an integer array - c++

Question

This is one the methods that I have to make for my assignment
int*mode(int &) – returns an integer array containing the modal value(s) of the
population, the reference parameter should be set to the size of the result
But from searching, you cannot return array's from a function? I can calculate modal value from a given array, put it in an array, but return an integer array? maybe the professor meant something else? I know how to do all other methods except that one. I don't even know what that method means (Coming from java)
Header File
#include <string>
using namespace std;
class population
{
public:
//Default Constructor
population(void);
//Constructor that accepts an integer array object, and the size for that array object
population(int[], int);
//Constructor for creating a deep copy
population (const population &);
//For overloading purposes
population & operator = (const population &);
//Destructor that frees dynamic memory associated with the underlying array
~population(void);
//Method for loading new content into an array
void load(string);
//Method for adding new content into existing array
void add(string);
//Accessors
//Returns the size of the population (The number of values stored in the array)
int size();
//Returns the sum of the popluation (The sum of the contents in the array)
int sum();
//Returns the mean of the population
float mean();
//Returns the median of the population
float median();
//Returns the standard deviation of the population
float stddev();
//Returns an integer array containing the modal values of the popluation
int*mode(int &);
private:
int arraySize;
bool sorted;
int * popArray;
};
CPP
#include "population.h"
//Default Constructor
population::population(void)
{
}
//Constructor to intialize the population object
population::population(int arr[], int s)
{
//Store s into a variable
arraySize = s;
//Declare popArray as a Dynamic array
popArray = new int[arraySize];
//Copy the passed array into the popArray
for ( int i=0; i < s; i++)
{
popArray[i] = arr[i];
};
}
//Constructor for deep copying purposes
population::population (const population & p)
{
}
population::~population(void)
{
}
int population::size(void)
{
//Return size of the array, which is the amount of population in the array.
return arraySize;
}
int population::sum(void)
{
//Variable to hold sum of the array
int sumArray = 0;
//Add all the contents of the array into one variable
for ( int i = 0; i < arraySize; i++)
{
sumArray += popArray[i];
}
//Return the sum of the array
return sumArray;
}
float population::mean(void)
{
//Variable to hold sum and the mean of the array
int sumArray = 0;
float meanArray;
//Add all the contents of the array into one variable
for ( int i=0; i < arraySize; i++)
{
sumArray += popArray[i];
}
//Sum of the array divided by number of contents in the array (Average)
meanArray = (sumArray / arraySize);
//Returns mean value in type float
return meanArray;
}
float population::median ()
{
return 1;
}
float population::stddev()
{
return 1;
}
int population::*mode(int & i)
{
return
}

Answer 1

With a prototype like that, I'm guessing that he wants you to new an array to be returned:
int *population::mode(int & i)
{
// compute the number of modal values you need to return
i = /* whatever the size of the return array will be */;
int * ret = new int[i];
// fill in ret
return ret;
}

Answer 2

Try:
int foo(int arrayBar[])
or
int foo(int* arrayBar)
or
int* foo(int arrayBar[])
If those don't work, make sure your pointer is at the beginning of the array.
Source: Return array in a function