I have searched many examples and have yet to be able to find where exactly my problem lies. I am trying to implement the merge sort algorithm from the Cormen intro to algorithms book-- here is where I am at so far-- I have tried throwing in print statements to follow how the arrays are getting rebuilt but I am not seeing it... can anyone help?
Code:
#include <iostream>
#include <cmath>
#include <ctime>
#include <cstdlib>
using namespace std;
int p = 0;
int q = 0;
int r = 0;
int getRandom()
{
int randNum = 0;
randNum = 1 + rand() % 100;
return randNum;
}
void populateArray(int * array, int size)
{
for (int i = 0; i < size; i++) {
array[i]=getRandom();
}
}
void merge (int * array, int p, int q, int r) // p = start, q = mid, r = end
{
int i = 0; // left array iterator
int j = 0; // right array iterator
int n1 = q - p + 1;
int n2 = r - q;
// int arrayL[n1 + 1];
//int arrayR[n2 + 1];
int arrayL[n1];
int arrayR[n2];
for (i = 0; i < n1; i++) {
arrayL[i] = array[p + i];
}
cout << "TEST ARRAY MS A: ";
for (int count = 0; count < n1; count++) {
cout << arrayL[count] << " ";
}
cout << endl << endl;
for (j = 0; j < n2; j++) {
arrayR[j] = array[q + j + 1];
}
cout << "TEST ARRAY MS B: ";
for (int count = 0; count < n2; count++) {
cout << arrayR[count] << " ";
}
cout << endl << endl;
//arrayL[n1 + 1] = 1000;
//arrayR[n2 + 1] = 1000;
//i = 0;
//j = 0;
for (int k = p, i = j = 0; k <= r; k++) {
if (j >= n2 || (i <= n1 && arrayL[i] <= arrayR[j])) {
array[k] = arrayL[i];
i++;
cout << "TEST ARRAY in loop A: ";
for (int tempIt = 0; tempIt < r; tempIt++) {
cout << array[tempIt] << " ";
}
cout << endl << endl;
}
else {
array[k] = arrayR[j];
j++;
cout << "TEST ARRAY in loop B: ";
for (int tempIt = 0; tempIt < r; tempIt++) {
cout << array[tempIt] << " ";
}
cout << endl << endl;
}
cout << "TEST ARRAY in loop: ";
for (int tempIt = 0; tempIt < r; tempIt++) {
cout << array[tempIt] << " ";
}
cout << endl << endl;
}
}
void mergeSort (int * array, int p, int r)
{
if (p < r) {
q = floor((p + r) / 2);
mergeSort(array, p, q);
mergeSort(array, q + 1, r);
merge(array, p, q, r);
}
}
int main(int argc, const char * argv[])
{
unsigned seed = time(0);
srand(seed);
int testArray[5];
populateArray(testArray, 5);
cout << "TEST ARRAY: ";
for (int count = 0; count < 5; count++) {
cout << testArray[count] << " ";
}
cout << endl << endl;
mergeSort(testArray, 0, 4);
cout << "TEST ARRAY after mergeSort: ";
for (int count = 0; count < 5; count++) {
cout << testArray[count] << " ";
}
cout << endl << endl;
return 0;
}
Related
I'm a C++ newb. I need to insert numbers to an array and then display first the odd numbers and then the even numbers in a single array. I've managed to create two separate arrays with the odd and even numbers but now I don't know how to sort them and put them back in a single array. I need your help to understand how to do this with basic C++ knowledge, so no advanced functions. Here's my code:
#include <iostream>
using namespace std;
int main()
{
int N{ 0 }, vector[100], even[100], odd[100], unify[100], i{ 0 }, j{ 0 }, k{ 0 };
cout << "Add the dimension: " << endl;
cin >> N;
cout << "Add the elements: " << endl;
for (int i = 0; i < N; i++) {
cout << "v[" << i << "]=" << endl;
cin >> vector[i];
}
for (i = 0; i < N; i++) {
if (vector[i] % 2 == 0) {
even[j] = vector[i];
j++;
}
else if (vector[i] % 2 != 0) {
odd[k] = vector[i];
k++;
}
}
cout << "even elements are :" << endl;
for (i = 0; i < j; i++) {
cout << " " << even[i] << " ";
cout << endl;
}
cout << "Odd elements are :" << endl;
for (i = 0; i < k; i++) {
cout << " " << odd[i] << " ";
cout << endl;
}
return 0;
}
If you don't need to store the values then you can simply run through the elements and print the odd and the even values to different stringstreams, then print the streams at the end:
#include <sstream>
#include <stddef.h>
#include <iostream>
int main () {
std::stringstream oddStr;
std::stringstream evenStr;
static constexpr size_t vecSize{100};
int vec[vecSize] = {10, 5, 7, /*other elements...*/ };
for(size_t vecIndex = 0; vecIndex < vecSize; ++vecIndex) {
if(vec[vecIndex] % 2 == 0) {
evenStr << vec[vecIndex] << " ";
} else {
oddStr << vec[vecIndex] << " ";
}
}
std::cout << "Even elements are:" << evenStr.rdbuf() << std::endl;
std::cout << "Odd elements are:" << oddStr.rdbuf() << std::endl;
}
Storing and sorting the elements are always expensive.
Basically, it would be better to sort them first.
#include <iostream>
using namespace std;
int main()
{
int numbers[5];
int mergedArrays[5];
int evenNumbers[5];
int oddNumbers[5];
for(int i=0;i<5;i++){
cin>>numbers[i];
}
int temp=numbers[0];
//bubble sort
for(int i = 0; i<5; i++)
{
for(int j = i+1; j<5; j++)
{
if(numbers[j] < numbers[i])
{
temp = numbers[i];
numbers[i] = numbers[j];
numbers[j] = temp;
}
}
}
int nEvens=0;
int nOdds=0;
for(int i = 0; i<5; i++)
{
if(numbers[i]%2==0)
{
evenNumbers[nEvens]=numbers[i];
nEvens++;
}
else if(numbers[i]%2!=0)
{
oddNumbers[nOdds]=numbers[i];
nOdds++;
}
}
int lastIndex=0;
//copy evens
for(int i = 0; i<nEvens; i++)
{
mergedArrays[i]=evenNumbers[i];
lastIndex=i;
}
//copy odds
for(int i =lastIndex; i<nOdds; i++)
{
mergedArrays[i]=oddNumbers[i];
}
return 0;
}
If you have to just output the numbers in any order, or the order given in the input then just loop over the array twice and output first the even and then the odd numbers.
If you have to output the numbers in order than there is no way around sorting them. And then you can include the even/odd test in the comparison:
std::ranges::sort(vector, [](const int &lhs, const int &rhs) {
return ((lhs % 2) < (rhs % 2)) || (lhs < rhs); });
or using a projection:
std::ranges::sort(vector, {}, [](const int &x) {
return std::pair<bool, int>{x % 2 == 0, x}; });
If you can't use std::ranges::sort then implementing your own sort is left to the reader.
I managed to find the following solution. Thanks you all for your help.
#include <iostream>
using namespace std;
int main()
{
int N{0}, vector[100], even[100], odd[100], merge[100], i{0}, j{0}, k{0}, l{0};
cout << "Add the dimension: " << endl;
cin >> N;
cout << "Add the elements: " << endl;
for (int i = 0; i < N; i++)
{
cout << "v[" << i << "]=" << endl;
cin >> vector[i];
}
for (i = 0; i < N; i++)
{
if (vector[i] % 2 == 0)
{
even[j] = vector[i];
j++;
}
else if (vector[i] % 2 != 0)
{
odd[k] = vector[i];
k++;
}
}
cout << "even elements are :" << endl;
for (i = 0; i < j; i++)
{
cout << " " << even[i] << " ";
cout << endl;
}
cout << "Odd elements are :" << endl;
for (i = 0; i < k; i++)
{
cout << " " << odd[i] << " ";
cout << endl;
}
for (i = 0; i < k; i++)
{
merge[i] = odd[i];
}
for (int; i < j + k; i++)
{
merge[i] = even[i - k];
}
for (int i = 0; i < N; i++)
{
cout << merge[i] << endl;
}
return 0;
}
You can use Bubble Sort Algorithm to sort whole input. After sorting them using if and put odd or even numbers in start of result array and and others after them. like below:
//Bubble Sort
void bubbleSort(int arr[], int n)
{
int i, j;
for (i = 0; i < n - 1; i++)
// Last i elements are already
// in place
for (j = 0; j < n - i - 1; j++)
if (arr[j] > arr[j + 1])
swap(arr[j], arr[j + 1]);
}
// Insert In array
int result[100];
if(odd[0]<even[0])
{
for (int i = 0; i < k; i++)
{result[i] = odd[i];}
for (int i = 0; i < j; i++)
{result[i+k] = even[i];}
}else
{
for (int i = 0; i < j; i++)
{result[i] = even[i];}
for (int i = 0; i < k; i++)
{result[i+k] = odd[i];}
}
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I have written next code but 3 functions must be replaced by 1 and I don't know how to.
The program creates 3 arrays but only 1 function must calculate negative numbers of each column and find the max element in each column. Here's the code:
#include <iostream>
#include <ctime>
#include <iomanip>
using namespace std;
int n = 0;
const int m = 3, k = 3, b = 4, u = 5;
int i, j;
void calc(float** array, int i, int j );
void calc1(float** array, int i, int j);
void calc2(float** array, int i, int j);
int main()
{
float** array = new float* [m];
for (int l = 0; l < m; l++) {
array[l] = new float[k];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < k; j++) {
array[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < m; i++)
{
for (int j = 0; j < k; j++) {
cout << setprecision(2) << setw(4) << array[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(array, i, j); // FUNCTION !!!
float** arr = new float* [b];
for (int l = 0; l < b; l++) {
arr[l] = new float[b];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < b; i++) {
for (int j = 0; j < b; j++) {
arr[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < b; i++)
{
for (int j = 0; j < b; j++) {
cout << setprecision(2) << setw(4) << arr[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(arr, i, j); // FUNCTION !!!
float** ar = new float* [u];
for (int l = 0; l < u; l++) {
ar[l] = new float[u];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < u; i++) {
for (int j = 0; j < u; j++) {
ar[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < u; i++)
{
for (int j = 0; j < u; j++) {
cout << setprecision(2) << setw(4) << ar[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc2(ar, i, j); // FUNCTION !!!
}
void calc(float** array, int i, int j) {
int max = array[0][0];
for (int j = 0; j < k; j++)
{
max = array[0][0];
for (int i = 0; i < k; i++) {
if (array[i][j] > max)
max = array[i][j];
if (array[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
void calc1(float** arr, int i, int j) {
int max = arr[0][0];
for (int j = 0; j < b; j++)
{
max = arr[0][0];
for (int i = 0; i < b; i++) {
if (arr[i][j] > max)
max = arr[i][j];
if (arr[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
void calc2(float** ar, int i, int j) {
int max = ar[0][0];
for (int j = 0; j < u; j++)
{
max = ar[0][0];
for (int i = 0; i < u; i++) {
if (ar[i][j] > max)
max = ar[i][j];
if (ar[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
The parameters to calc() should be the number of rows and columns in the array. Then it should use these as the limits in the for loops.
Also, since you're calculating total negative and maximum for each column, you must reset these variables each time through the column loop.
#include <iostream>
#include <ctime>
#include <iomanip>
using namespace std;
const int m = 3, k = 3, b = 4, u = 5;
void calc(float** array, int rows, int cols);
int main()
{
float** array = new float* [m];
for (int l = 0; l < m; l++) {
array[l] = new float[k];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < k; j++) {
array[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < m; i++)
{
for (int j = 0; j < k; j++) {
cout << setprecision(2) << setw(4) << array[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(array, m, k); // FUNCTION !!!
float *arr = new float* [b];
for (int l = 0; l < b; l++) {
arr[l] = new float[b];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < b; i++) {
for (int j = 0; j < b; j++) {
arr[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < b; i++)
{
for (int j = 0; j < b; j++) {
cout << setprecision(2) << setw(4) << arr[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(arr, b, b); // FUNCTION !!!
float** ar = new float* [u];
for (int l = 0; l < u; l++) {
ar[l] = new float[u];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < u; i++) {
for (int j = 0; j < u; j++) {
ar[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < u; i++)
{
for (int j = 0; j < u; j++) {
cout << setprecision(2) << setw(4) << ar[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(ar, u, u); // FUNCTION !!!
}
void calc(float** array, int rows, int cols) {
for (int j = 0; j < cols; j++)
{
int n = 0;
int max = array[0][j];
for (int i = 1; i < rows; i++) {
if (array[i][j] > max)
max = array[i][j];
if (array[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
I want to make a c++ program that runs two algorithms - insertion and heap sort. But I keep getting an error that array size must have integral or enumeration type, not double. Where are my mistakes? I'm reading data from file.
#include "stdafx.h"
#include <stdio.h>
#include <tchar.h>
#include <random>
#include <fstream>
#include <iostream>
#include <algorithm>
#include <time.h>
void generuoti(int _N, const char *_file);
void nuskaityti(const char *_file);
void sortInsertion(double A[], int N);
void heapSort(double A[], int N);
void heapify(double A[], int N, int i);
using namespace std;
double *Data;
double* A;
double* B;
double* A1;
double* B1;
double N;
unsigned long int palyginimai1 = 0;
unsigned long int priskyrimai1 = 0;
unsigned long int palyginimai2 = 0;
unsigned long int priskyrimai2 = 0;
int main()
{
srand(time(NULL));
cout << "generuojame atsitktinius duomenis ..." << endl;
generuoti(106000, "duom.txt");
cout << "nuskaitome duomenis ..." << endl;
nuskaityti("duom.txt");
A = new double[N];
B = new double[N];
A1 = new double[N];
B1 = new double[N];
for (int i = 0; i < N; i++) {
A[i] = Data[i];
}
//cout << "Heap array:" << endl;
for (int i = 0; i < N; i++)
//cout << A[i] << " ";
//cout << endl;
//cout << "Insertion array: " << endl;
for (int i = 0; i < N; i++)
{
B[i] = A[i];
//cout << B[i] << " ";
}
for (int i = 0; i < N; i++)
{
A1[i] = A[i];
B1[i] = B[i];
}
//cout << endl;
int nUntil = 2000;
while (nUntil <= 106000)
{
sortInsertion(B1, nUntil);
heapSort(A1, nUntil);
cout << priskyrimai1 << endl;
nUntil = nUntil * 2;
for (int i = 0; i < N; i++)
{
A1[i] = A[i];
B1[i] = B[i];
}
//cout << nUntil << palyginimai2 << " " << priskyrimai2 << endl;
}
/*cout << "Surusiuota skaiciu seka Heap:" << endl;
for (int i = 0; i < N; i++)
cout << A1[i] << " ";
cout << endl;
cout << "Surusiuota skaiciu seka Insertion:" << endl;
for (int i = 0; i < N; i++)
cout << B1[i] << " ";
cout << endl;*/
system("pause");
return 0;
}
void generuoti(int _N, const char *_file) {
ofstream os(_file);
os << _N << endl;
for (int i = 0; i < _N; i++)
{
os << " " << (double)(rand() % 1001) / (double)1000;
}
//os << " " << (double)13 << " " << (double)18 << " " << (double)25 << " " << (double)2 << " " << (double)6 << " " << (double)11 << " " << (double)16 << " " << (double)1 << " " << (double)6 << " " << (double)21 << " " << (double)17;
os.close();
}
void nuskaityti(const char *_file) {
ifstream is(_file);
if (is.fail()) {
cout << "failo nera" << endl;
exit(1);
}
is >> N;
Data = new double[N];
for (int i = 0; i < N; i++) {
is >> Data[i];
}
}
void sortInsertion(double A[], int N) {
double temp;
int hole;
for (int i = 1; i < N; i++)
{
palyginimai1++;
temp = A[i];
hole = i;
while (hole > 0 && A[hole - 1] > temp)
{
palyginimai1++;
A[hole] = A[hole - 1];
priskyrimai1++;
hole--;
}
priskyrimai1++;
A[hole] = temp;
}
}
void heapify(double A[], int N, int i)
{
int largest = i;
int l = 2 * i + 1;
int r = 2 * i + 2;
priskyrimai2 = priskyrimai2 + 3;
if (l < N && A[l] > A[largest])
{
largest = l;
priskyrimai2++;
}
if (r < N && A[r] > A[largest])
{
largest = r;
priskyrimai2++;
}
if (largest != i)
{
swap(A[i], A[largest]);
heapify(A, N, largest);
palyginimai2++;
priskyrimai2++;
}
}
void heapSort(double A[], int N)
{
for (int i = N / 2 - 1; i >= 0; i--)
{
heapify(A, N, i);
palyginimai2++;
}
for (int i = N - 1; i >= 0; i--)
{
swap(A[0], A[i]);
priskyrimai2++;
heapify(A, i, 0);
palyginimai2++;
}
}
Also, I'm counting palyginimai - comparisons, priskyrimai-assignments.
A quick solution would be to replace anywhere you use the subscript([]) operator do this instead: A = new double[(int)N];
I hope this helps.
#include<iostream>//Pls note:Only header allowed...
As this is the C++ i dont think so any other header is needed for that math function.
using namespace std;
int comparator(int audience[][2], int index1, int index2) {
int b1, e1;
int b2, e2;
b1 = audience[index1][1];
e1 = audience[index1][2];
b2 = audience[index2][1];
e2 = audience[index2][2];
double re1;
re1 = pow(b1, e1);
cout << re1 << endl;
double re2 = pow(b2, e2);
cout << re2 << endl;
if (re1 == re2)
{
return 0;
}
if (re1 > re2)
{
return -1;
}
if (re1 < re2)
{
return 1;
}
}
//Nothing has to be done with the rest of the two functions.
void sorting(int audience[][2], int N, int &i_index, int &j_index)
{
int i, j, temp;
for (i = 0; i<N - 1; i++)
{
if (audience[i][2] < audience[i + 1][2])
continue;
else
i_index = i;
break;
}
for (i = N; i > 1; i++)
{
if (audience[i][2]>audience[i - 1][2])
continue;
else
j_index = i;
break;
}
for (i = i_index + 1; i < j_index - 1; i++)
{
min = audience[i_index + 1][2];
for (i = )
if (audience[i_index][1] > audience[i_index + 1][1])
{
temp = audience[i_index + 1][1];
audience[i_index + 1][1] = audience[i_index][1];
audience[i_index][1] = temp;
}
}
for (i = i_index + 1; i <= j_index - 1; i++)
{
min = audience[i][2];
for (j = i_index + 2; j <= j_index - 1; j++)
{
if (min > audience[j][2])
{
temp = audience[i_index + 2][2];
audience[i_index + 1][2] = audience[i_index][2];
audience[i_index][2] = temp;
}
}
}
}
void merge(int audience[][2], int mergedarray[][2], int N, int i_index, int j_index)
{
}
int main()
{
int audience[100][2], mergedmarks[100][2];
int i, N;
int index1 = 0, index2 = 0;
int comp_result;
cout << "Enter the value of N : ";
cin >> N; // Enter size of the table
cout << "Enter the base and exponent for " << N << "rows " << endl;
for (i = 0; i < N; i++)
cin >> audience[i][0] >> audience[i][1]; //Enter numbers in the table
cout << endl << "Checking Function 1: Compare ecodes for 5 index pairs" << endl;
for (i = 0; i < 5; i++)
{
cout << "\nEnter indices of row1 and row2 that you want to compare: ";
cin >> index1 >> index2;
if (index1 < 0 || index2 < 0 || index1 >= N || index2 >= N)
continue;
comp_result = comparator(audience, index1, index2);
if (comp_result == -1)
cout << "ecode of index 1 is greater than ecode of index2" << endl;
else if (comp_result == 1)
cout << "ecode of index 1 is less than ecode of index2" << endl;
else if (comp_result == 0)
cout << "ecode of index 1 is equal to ecode of index2" << endl;
}
cout << endl;
int index_i = 0, index_j = N;
sorting(audience, N, index_i, index_j);
cout << "Checking Function 2: Printing sorted array " << endl;
for (i = 0; i < N; i++)
cout << audience[i][0] << " " << audience[i][1] << endl;
cout << endl;
cout << "index i: " << index_i << "\nindex j: " << index_j << endl;
cout << endl << "Checking Function 3: Printing Merged Array " << endl;
merge(audience, mergedmarks, N, index_i, index_j);
int merge_array_size = index_i + (N - (index_j + 1));
for (i = 0; i < N; i++)
cout << mergedmarks[i][0] << " " << mergedmarks[i][1] << endl;
cout << endl;
return 0;
}
This is the whole problem. I have to still edit the merge function. That is the whole problem.This is all.
You need to include the pow header, which is math.h, in order to use it.
add at the beginning of your file:
#include <math.h>
#include <iostream>
using namespace std;
POW is declared in math.h header file so use
#include<math.h>
i wanna print a X with * , i have done the left side of the X but i don't know how to print the other side (flip/mirror) .
if you run this codes it will print just the left side of (X) and now i wanna print the right side of (X) ? so what should i do to complete the (X) using stars(*)? thank you guys.
i was wondering is it possible to do this?(i'm a newbie to programming)
#include <iostream>
// Expected output pattern:
//
// * *
// * *
// * *
// *
// * *
// * *
// * *
using namespace std;
int main() {
cout << "Printing X with star(*)" << endl;
cout << endl;
int i;
int p;
for (i = 1; i <= 10; i++) {
for (int j = 1; j <= 10; j++) {
if (j > i) break;
cout << " ";
cout << "\t";
}
cout << "\t\t\t\t";
for (p = 1; p <= 10; p++) {
cout << "*";
}
cout << endl;
}
for (i = 10; i >= 1; i--) {
for (int j = 1; j <= 10; j++) {
if (j > i) break;
cout << " ";
cout << "\t";
}
cout << "\t\t\t\t";
for (p = 1; p <= 10; p++) {
cout << "*";
}
cout << endl;
}
return 0;
}
You're on the right track, to do the right hand side you have to print more **** on each line in addition to what you already have done. It might help to think of printing each line of the X as printing some **** then some spaces then more **** and reduce the number of spaces each time you get closer to the cross-over point. Does that make sense? This might help get you further (. = space):
*......*
.*....*
..*..*
...**
and so on
This is one of many ways you could get there:
int main()
{
int size = 8;
int spacesBefore;
int spacesBetween = size;
int numStars = 1;
// Top half:
int i, j;
for ( i = 0; i < size/2; i++ ) {
spacesBetween = size - ( 2 * ( i + 1 ) );
spacesBefore = i;
for ( j = 0; j < spacesBefore; j++ ) // before
cout << " ";
for ( j = 0; j < numStars; j++ ) // * left
cout << "*";
for ( j = 0; j < spacesBetween; j++ ) // between
cout << " ";
for ( j = 0; j < numStars; j++ ) // * right
cout << "*";
cout << endl;
}
// bottom half, do the same kind of thing but changing the spacings
// ...
}
ok thank you every one that helped me , i found the answer i wanted after almost 6 hours and here is the answer:
#include <iostream>
using namespace std;
int main() {
cout << "Printing X with stars" << endl;
cout << endl;
int i;
int p;
int k;
int s;
int count = 72;
for (i = 1; i <= 10; i++) {
for (int j = 1; j <= 10; j++) {
if (j > i) break;
cout << " ";
cout << "\t";
}
cout << "\t\t\t\t";
for (p = 1; p <= 10; p++) {
cout << "* ";
}
for (k=1; k<=count; k++){
cout << " ";
}
count-=8;
for (s=1; s<=10; s++){
cout << "* ";
}
cout << endl;
}
count = 0;
for (i = 10; i >= 1; i--) {
for (int j = 1; j <= 10; j++) {
if (j > i) break;
cout << " ";
cout << "\t";
}
cout << "\t\t\t\t";
for (p = 1; p <= 10; p++) {
cout << "* ";
}
for (k=1; k<=count; k++) {
cout << " ";
}
count +=8;
for (s=1; s<=10; s++){
cout << "* ";
}
cout << endl;
if (count == 80) break;
}
return 0;
}