C++ Program Functions - c++

I am having trouble with my functions. When I use a function to manipulate an array, and print it and move on to the next manipulation function, it uses the array that was previously manipulated instead of the original array. For example, when my function converts every negative number to a positive, I call the next function which zeros out all even numbers, and my array prints out all zeros, instead of using the array from the original.
#include <iostream>
#include <fstream>
#include <cstdlib>
using namespace std;
#define NUMS_PER_LINE 10 // maximum numbers to be printed on each line.
int numbers[100]; // array to hold upto 100 integer numbers.
int numcnt; // actual count (<=100) of numbers in above array.
// reads file content into array
void read_array_from_file (const char filename[])
{
ifstream inpfile(filename);
if (!inpfile.is_open())
{
cout << "Can't open file : " << filename << endl;
exit(1);
}
numcnt=0; // Initialise count of read numbers
// Read numbers from the file into array.
inpfile >> numbers[numcnt];
while (!inpfile.eof()) // Read until EOF is reached.
{
numcnt++; // Got one more number from input file.
inpfile >> numbers[numcnt];
}
inpfile.close();
return;
}
// Print out all the values in the array
void print_array_content (int numsinaline)
{
int i;
for (i=0; i<numcnt+1; i++)
{
if ((i % numsinaline) == 0)
cout << endl;
cout << numbers[i] << " ";
}
cout << endl << endl;
return;
}
// calculate average
double calculate_average ()
{
int i;
float sum=0;
for (i=0; i<(numcnt-1); i++)
{
sum += numbers[i];
}
return (sum/(numcnt-1));
}
// Find numbers larger and smaller than the average.
void find_numbers_smaller_and_larger_than_average (int &larger, int &smaller, int average)
{
int i;
for (i=0; i<(numcnt-1); i++)
{
if (numbers[i] < average)
smaller++;
else if (numbers[i] > average)
larger++;
}
return;
}
// Convert negative numbers to positive in the array 'numbers'.
void convert_negative_to_positive ()
{
int i;
for (i=0; i<(numcnt-1); i++)
{
if (numbers[i] < 0)
numbers[i] *= -1;
}
return;
}
// Convert all even numbers into zero.
void zero ()
{
int i;
for (i=0; i<numcnt; i++)
{
if (numbers[i] > 0)
numbers[i] *= 0;
}
return;
}

First of all, you are using a global variable for your array, so you are never passing it to your function. When you change a global variable in the function, it changes the data in the array. You should be passing that data into the function and NOT using global variables.
Second, while(!inpFile.eof()) is bad! Don't do it.
For file streams:
std::vector<int> numbers;
std::ifstream fin("myfile");
std::copy(std::istream_iterator<int>(fin), std::istream_iterator(), std::back_inserter<vector<int> >(numbers));
Those 3 lines will read the entire file into the vector "numbers".
Third, when declaring your functions, pass the array:
void myFunction(const std::vector<int>& vec); // if you aren't going to change the vector
or
void myFunction(std::vector& vec); // if you are going to change it
and you would call it by simply:
myFunction(numbers);

" it uses the array that was previously manipulated instead of the original array."
Obviously because you have your array declared globally
int numbers[100];
Outside all functions.
When you perform one operation on this array, the element get modified and the new values will be used for next functions.
Instead of this, save of copy of your original array and then use this copy whenever you wish to work on original array

All your operations act on a single global variable, numbers. If you modify it in any of your functions its values will also change in every other occurrence.
Instead, provide a way to tell your functions which array you want to use, how many elements it contains and use several arrays. This also enables you to get rid of the global variable.
Example:
#include <iostream>
using namespace std;
typedef unsigned int array_size_t;
void print_array(int array[], array_size_t size){
for(array_size_t i = 0; i < size; ++i){
cout << array[i] << endl;
}
}
int main(){
int a1[] = {1,2,3,4};
int a2[] = {1,3,3,7,0,0,0,0};
print_array(a1,4);
print_array(a2,8);
}
Remark
If you're allowed use standard containers such as std::vector instead. The solution above is more C than C++-like.

You are using global variable. All your operation on numbers whatever index will change your certain position's value.
Another potential risk is if your input file contains more than 100 integers, you will do
inpfile >> numbers[100];
or some index number greater than 100.
which will cause a segmentation fault.
You should be very careful when using global variables

You are directly manipulating your array inside of your functions since it is defined globally, instead of passing in a copy as a parameter.
void modify(int[] array) {
//Modify copied array here
}
int main() {
int numbers[100];
int copyNumbers[100];
//Copy numbers
memcpy(copyNumbers, numbers, sizeof(numbers));
modify(copyNumbers);
//Use modified array
memcpy(copyNumbers, numbers, sizeof(numbers)); //Set back to original
modify(copyNumbers); //Modify copy again as original
}

Related

Calculates the position of the max element for array. function returns the max element. pass the array by the pointer and the pos. by the reference

i have a little problem with my college assignment. I don't really understand what's going on with pointers and reference. Could someone point me where I am making a mistake??
using namespace std;
int i, n, maax, *position;
void tablica()
{
int tab[n];
cout<<"enter data:"<<endl;
for (i=0; i<n; i++)
{
cin>>tab[i];
}
maax = tab[0];
for (i=0; i<n; i++)
{
if (maax<tab[i])
{
maax=tab[i];
*position=i+1;
}
}
}
int main()
{
cout<<"array size:"<<endl;
cin>>n;
tablica();
cout<<"max el. position is: "<<&position<<endl;
return 0;
}
Sure we can help you a little bit. But the whole topic of pointers and references cannot be covered in a short answer here on SO. You need to read a book.
The following will be very simplified and there is much more in reality. But let's start with this simple explanantion.
Let me give you a typical example that is often used in C or very early C++ books. Look at the function swap that should exchange the values of 2 variables.
#include <iostream>
void swap(int a, int b) {
int temp = a;
a = b;
b = temp;
}
int main() {
int a = 1, b = 2;
swap(a, b);
std::cout << "a: " << a << "\tb: " << b << '\n';
}
We hope that after the call to the function swap, "a" will contain 2 and "b" will be 1. But it is not. Because in this case (and per default) the variables that are given to the function swap, are passed by value. So, the compiler will generate some code and copies the value of variables "a" and "b" into some local internal storage, also accessible with the name "a" and "b". So, the original "a" and "b" will never be touched or modified. By passing a variable by value, a copy will be mdae. This is often intended, but will not work in this example.
The next development stage was the pointer. The pointer is also a variable that contains a value. But this time it is the address of another variable somehwere in memory. If you have a variable like int a=3; then the 3 is somewhere stored in memory (decided by the compiler of the linker) and you can access the memory region with the name "a".
A pointer can store the memory address of this variable. So not the value 3 of the variable "a", but the address of the variable "a" in memory. The pointer points to that memory region, where the 3 ist stored. If you want to access this value, then you need to dereference the pointer with the * operator. And to get the address of variable 'a', you can write &a. But how does this help?
It helps you indirectly to get modified or result values out of a function. Example:
#include <iostream>
void swap(int *a, int *b) {
int temp = *a;
*a = *b;
*b = temp;
}
int main() {
int a = 1, b = 2;
swap(&a, &b);
std::cout << "a: " << a << "\tb: " << b << '\n';
}
In main we take the address of variable "a" and "b" and give this to the function. The address of the function (the pointer) will be given to the function as value now. A copy of the pointer will be made (not in reality) but this does not harm, because we can now modify the original values of the variable, by derefencing the pointer. Then the function ends and we will find the correct values in the original variables "a" and "b".
But, pointers are notoriously difficult to understand and very error prone. Therefore the "reference" has been invented. It is kind of an alias for a normal variable. And the good point is that if you pass a reference to the function, then you can modify immediately the original value. That makes things very convenient.
The function swap could then be written as
#include <iostream>
void swap(int &a, int &b) {
int temp = a;
a = b;
b = temp;
}
int main() {
int a = 1, b = 2;
swap(a, b);
std::cout << "a: " << a << "\tb: " << b << '\n';
}
And this gives the intented result. And is by far simpler.
Now to your code. First, VLAs (variable length arrays), namely the int tab[n]; where 'n' is no compile time constant, are a not a ppart of the C++ language. You canot use them. You could and should use a std::vector instead, but you did not yet learn about it. So we will use new, to allocate some memory dynamically. Please note: In reality, new, raw pointers for owned memory and C-Style arrays should not be used. But anyway.
Then let us look at your requirements
function returns the max element. pass the array by the pointer and the pos. by the reference
So, we need a function to calculate the max element in an array, then return this value, and additionally copy the position of the max element in a variable, given to the function as reference. We will add an additional parameter for the size of the array, because we will not use VLAs here. The array will be given by pointer.
So the prototype of your function will be:
int getMaxElement(int *array, int sizeOfArray, int& positionOfMaxValue)
To implement such a function, we create an internal variable to hold the max value, which we will later return. Then, we compare all values in a loop against this max value and, if we find a bigger one, then we store this new result. As the initial value, we can simply take the first value of the array.
Example:
#include <iostream>
int getMaxElement(int* array, int sizeOfArray, int& positionOfMaxValue) {
int resultingMaxValue = 0;
if (sizeOfArray > 0) {
resultingMaxValue = array[0];
for (int i = 0; i < sizeOfArray; ++i) {
if (array[i] > resultingMaxValue) {
resultingMaxValue = array[i];
positionOfMaxValue = i;
}
}
}
return resultingMaxValue;
}
int main() {
// Get array size from user
std::cout << "\nPlease enter the array size: ";
int arraySize = 0;
std::cin >> arraySize;
// Create an array
int* array = new int[arraySize];
// Read all values into the array
for (int i = 0; i < arraySize; ++i)
std::cin >> array[i];
// Now calculate the max value and position of the max value
int position = 0;
int maxValue = getMaxElement(array, arraySize, position);
// Show result
std::cout << "\n\nResult:\nThe maximum value '" << maxValue << "' is at position " << position << '\n';
delete[] array;
}
Please remember: This is a very simplified explanation
You shouldn't use global variables (see Are global variables bad?). int tab[n]; is not standard C++, its a variable length array that is only available as extension on some compilers (see Why aren't variable-length arrays part of the C++ standard?). The segfault is because you never allocate memory for the position, it is initialized because its a global, but it doesnt point to an int (see Is dereferencing a pointer that's equal to nullptr undefined behavior by the standard?).
You do not need any array to get the max value and position. And there is no need to use a pointer in your code. Determine the maximum value and position in the same loop that is reading the input and return the result from the function instead of using the global variable:
#include <iostream>
int tablica(int n) {
std::cout<<"enter data:\n";
int max = 0;
int max_pos = 0;
std::cin >> max;
for (int i=1; i<n; i++) {
int number = 0;
std::cin>>number;
if (max<number) {
max=number;
max_pos = i;
}
}
return max_pos;
}
int main()
{
std::cout<<"input size:\n";
int n;
std::cin>>n;
int position = tablica(n);
std::cout<<"max el. position is: "<< position << "\n";
return 0;
}
Look at what the function should do:
"function returns the max element. pass the array by the pointer and the pos. by the reference"
It should not read any array elements.
It should not receive or return values in global variables.
It should not use a pointer to the position.
It should be passed an array (as a pointer) and somewhere to store the maximum position (as a reference), and return the maximum value.
That is, its prototype should look like
int tablica(const int* input, int size, int& max_position)
and main should look something like this:
int main()
{
int n = 0;
cout << "Array size: " << endl;
cin >> n;
int* data = new int[n];
for (int i = 0; i < n; i++)
{
cin >> data[i];
}
int position = -1;
int max_element = tablica(data, n, position);
cout << "The maximum element is " << max_element << ", at index " << position << endl;
delete [] data;
}
Implementing tablica left as an exercise.

How can I print the numbers in main function?

I am new to c++ language. I am trying to solve a problem using function. I have to print the pentagon numbers untill the integer input, but when function returns the values, it only prints one value. I would love some help with it.
#include<iostream>
using namespace std;
int pent(int num){
int p;
for(int i=1;i<=num;i++){
p=(i*(3*i-1)/2);
}
return p;
}
int main(){
int num;
cin>>num;
int sender=pent(num);
cout<<sender<<endl;
return 0;
}
Your function returns int, that is a single integer. To return more, you can use std::vector. As you probably are not familiar with it, I will give you some pointers...
The most simple constructor creates a vector with no entries:
std::vector<int> x;
You can reserve space for elements via reserve:
x.reserve(num);
The vector still has no elements, but it already allocated enough space to hold num elements. This is important, because when we will add elements the vector will grow and that potentially requires to copy all elements to a different place in memory. We can avoid such frequent reallocations by reserving enough space upfront.
To add elements to the vector you can use push_back:
x.push_back(42);
Eventually to print all elements of the vector we can use a range-based for loop:
for (auto element : x) std::cout << element << " ";
So you can rewrite your code like this:
#include <iostream>
#include <vector>
std::vector<int> pent(int num){
std::vector<int> result;
result.reserve(num);
for(int i=1;i<=num;i++){
result.push_back(i*(3*i-1)/2);
}
return result;
}
int main(){
int num;
std::cin >> num;
auto sender = pent(num);
for (auto number : sender) std::cout << number << " ";
}
In your program, from your pent() function you are only returning last calculated value. In you ever time, you are overwriting you variable p.
So there is a way which #asmmo is suggesting, to print in pent() function.
Or you can pass a vector to your pent() function and store values in that and print it in main function.
For your ref:
void pent(int num, vector<int> &arr) {
int p;
for (int i = 1; i <= num; i++) {
arr[i-1] = (i*(3 * i - 1) / 2);
}
}
int main() {
int num;
cin >> num;
vector<int> arr(num);
pent(num, arr);
for (int i = 0; i < num; i++) {
cout << arr[i] << endl;
}
return 0;
}

The three biggest numbers in array

#include<iostream>
using namespace std;
int main()
{
int s;
cin>>s;
int t=3;
int maxValue,imax[t],maxIndex,arr[s];
for(int i=0; i<s; i++){
cin>>arr[i];
}
maxValue=arr[0];
for(int i=0;i<s;i++){
if(arr[i]>maxValue){
maxValue=arr[i];
imax[0] = i;
}
}
maxValue=arr[0];
for(int i=0;i<s;i++){
if (i == imax[0]) { continue; }
if(arr[i]>maxValue){
maxValue=arr[i];
imax[1] = i;
}
}
maxValue=arr[0];
for(int i=0;i<s;i++){
if (i == imax[0]) { continue; }
if (i == imax[1]) { continue; }
if(arr[i]>maxValue){
maxValue=arr[i];
imax[2] = i;
}
}
cout<<"First biggest number:"<<arr[imax[0]]<<"\n";
cout<<"Second biggest number:"<<arr[imax[1]]<<"\n";
cout<<"Third biggest number:"<<arr[imax[2]];
return 0;
}
This program must return tree numbers which is biggest in this arraybut , i do not know why when I introduce as example five numbers (121,34,56,67,545) and the compiler was return 545 and then crash.
Thank you in advance for the answer.
The problem is that before iterating the loop, you first set the maxValue to be the first element in the array. The imax only gets updated whenever there is at least one element greater than the current maxValue. However, if the first element is somehow the maxValue you are looking for, then the imax never gets set, which would be uninitialized causing segmentation fault at the end.
In your code, after finding the largest element 545, the second largest element was never found, since 121 is the first element in the array. Hence after printing out 545, imax[1] is uninitialized and the program crashes.
You use uninitialized array values in lines
cout<<"First biggest number:"<<arr[imax[0]]<<"\n";
cout<<"Second biggest number:"<<arr[imax[1]]<<"\n";
cout<<"Third biggest number:"<<arr[imax[2]];
If there are less than 3 different numbers in input, some imax array elements will not be initialized. Also if input array is empty, imax will not be initialized at all.
Therefore in expression arr[imax[1]] you read element of arr with index, which was not initialized and can be some very big number. It can be fixed if you declare iarr as
int imax[t] = {};
This will zero-initialize all elements of array and will prevent crashing.
Your program also doesn't check number of elements in input array, so if there are less than three input numbers arr[2] will also print uninitialized value.
Here's proper solution using STL algorithms and std::vector. It works with any number of t - you can easily change it to print largest 10 numbers. It is also memory efficient - it does not need to store whole input array so you can process large inputs with it.
#include <algorithm>
#include <iostream>
#include <vector>
int main() {
int s;
std::cin >> s;
unsigned t = 3;
std::vector<int> max_numbers;
max_numbers.reserve(t + 1);
for (int i = 0; i < s; ++i) {
int number;
if (std::cin >> number) { //Check basic input errors
max_numbers.push_back(number); // Add number to top-3 list
// Sort elements in descending order
std::sort(max_numbers.begin(), max_numbers.end(), std::greater<int>());
// Remove duplicates
max_numbers.erase(std::unique(max_numbers.begin(), max_numbers.end()),
max_numbers.end());
// Remove excess elements
if (max_numbers.size() > t) {
max_numbers.resize(t);
}
}
}
std::cout << "Biggest " << t << " numbers are" << std::endl;
for (int i : max_numbers) {
std::cout << i << std::endl;
}
}

How to pass arrays in the main func. w/ c++

#include <iostream>
using namespace std;
const int MAX = 1000;
int ArrMix[MAX];
int *ptrArrPos[MAX];
int *ptrArrNeg[MAX];
int PosCounter = 0;
int NegCounter = 0;
int r;
void accept(int ArrMix[MAX])
{
cout<<"Enter the number of elements in your array: ";
cin>>r;
for (int i = 0; i < r; i++)
{
cout<<"Enter value:";
cin>>ArrMix[i];
}
}
void process(int &i)
{
if(ArrMix[i] >= 0)
{
ptrArrPos[PosCounter] = &ArrMix[i];
PosCounter++;
}
else
{
ptrArrNeg[NegCounter] = &ArrMix[i];
NegCounter++;
}
}
void display(int &i)
{
cout<<"Your passed array is: " << endl;
cout<<ArrMix[i] << endl;
cout <<"Total number of positive integers is: "<<PosCounter<<endl;
cout<<"Your positive array is: "<<endl;
for (int i = 0; i < PosCounter; i++)
{
cout << *ptrArrPos[i] << endl;
}
cout<<endl;
cout <<"Total number of Negative integers is: "<<NegCounter<<endl;
cout<<"Your negative array is: "<<endl;
for (int i = 0; i < NegCounter; i++)
{
cout << *ptrArrNeg[i] << endl;
}
}
int main ()
{
int *i;
int a = &i;
accept(&ArrMix[MAX]);
process(a);
display(a);
system("pause>0");
}
The code you see above is a program use to create a user-defined array list of numbers. It should accept numbers from the user, display the passed array, positive numbers array and its negative numbers array. it should evaluate items, meaning separating negatives #s from positive numbers then creating an array for each. next is to use a counter to identify how many positive #s and negative #s are in each array.
I am having problems in passing the array from one function to another using pointers and calling it in the main function. so please help me?
The expression &ArrMix[MAX] returns a pointer to the integer at index MAX in the array. This index is one beyond the array, meaning you pass a pointer to beyond the array to the function which will then happily write to that memory.
Passing an array is as simple as passing any other argument:
accept(ArrMix);
You also have a problem here:
int *i;
int a = &i;
You declare i to be a pointer to an int. Then you use &i which returns the address of the variable i, in other words a pointer to a pointer to an int, and try to assign this double-pointer to a normal int variable.
It seems to me that you might want to return the number of entries is in the array from the access function, and then loop over the entries the user entered in the array and call process for each value. And then in display instead of taking the ArrMix index it should take the size and loop over that to display the ArrMix array.

C++ Program Apparently Printing Memory Address instead of Array

#include <iostream>
using namespace std;
int main(){
int findMax(int *);
const int MAX = 100;
int values[MAX];
char ivals[256];
// Get the space-separated values from user input.
cin.getline(ivals, 256, '0');
char *helper;
// Clean input array and transfer it to values.
for(int i = 0; i < (MAX) && ivals[i] != 0; i++){
helper = ivals[i * 2];
values[i] = atoi(helper);
}
int mval = findMax(values);
cout << values << endl << mval;
return 0;
}
//Function to find the maximum value in the array
int findMax(int arr[]){
int localmax = 0;
for(int i = 0; i < (sizeof(arr)/sizeof(int)); i++){
if(arr[i] > localmax){
localmax = arr[i];
}
}
return localmax;
}
The purpose of this program is for the user to input a space-separated series of values ended by a 0. That array is then to be analyzed to find the max. I figured out how to convert what is originally a char[] into an int[] so that I can use the findMax() function on it without error but the sorting loop seems to have a problem of its own and when "cout << values << endl << mval;" is called, it returns only a memory address instead of what should be a non-spaced sequence of ints. Can anybody explain what I am doing wrong? It seems that I may have made some mistake using the pointers but I cannot figure out what.
Printing values won't print the contents of the array as you expect, it will print the memory location of the first element of the array.
Try something like this instead:
#include <iterator>
#include <algorithm>
// ...
copy(&values[0], &values[MAX], ostream_iterator(cout, " "));
Sorry I can't post actual working code, but your original post is a mess with many syntax and syntactic errors.
EDIT: In the interest of being more complete and more approachable & understandable to beginners, I've written a small program that illustrates 4 ways to accomplish this.
Method 1 uses copy with an ostream_iterator as I've done above.
Method 2 below is probably the most basic & easiest to understand.
Method 3 is a C++0x method. I know the question is tagged C++, but I thought it might be educational to add this.
Method 4 is a C++ approach using a vector and for_each. I've implemented a functor that does the dumping.
Share & Enjoy
#include <iostream>
#include <iterator>
#include <algorithm>
#include <functional>
#include <vector>
using namespace std;
struct dump_val : public unary_function<int,void>
{
void operator()(int val)
{
cout << val << " ";
}
};
int main(){
int vals[5] = {1,2,3,4,5};
// version 1, using std::copy and ostream_iterator
copy(&vals[0], &vals[5], ostream_iterator<int>(cout, " "));
cout << endl;
// version 2, using a simple hand-written loop
for( size_t i = 0; i < 5; ++i )
cout << vals[i] << " ";
cout << endl;
// version 3, using C++0x lambdas
for_each(&vals[0], &vals[5], [](int val)
{
cout << val << " ";
}
);
cout << endl;
// version 4, with elements in a vector and calling a functor from for_each
vector<int> vals_vec;
vals_vec.push_back(1);
vals_vec.push_back(2);
vals_vec.push_back(3);
vals_vec.push_back(4);
vals_vec.push_back(5);
for_each( vals_vec.begin(), vals_vec.end(), dump_val() );
cout << endl;
}
When you pass around an array of X it's really a pointer to an array of X that you're passing around. So when you pass values to cout it only has the pointer to print out.
You really should look into using some of the standard algorithms to make your life simpler.
For example to print all the elements in an array you can just write
std::copy(values, values+MAX, std::ostream_iterator<int>(std::cout, "\n"));
To find the max element you could just write
int mval = *std::max_element(values, values+MAX);
So your code becomes
#include <iostream>
using namespace std;
int main(){
const int MAX = 100;
int values[MAX];
char ivals[256];
// Get the space-separated values from user input.
cin.getline(ivals, 256, '0');
char *helper;
// Clean input array and transfer it to values.
for(int i = 0; i < (MAX) && ivals[i] != 0; i++){
helper = ivals[i * 2];
values[i] = atoi(helper);
}
copy(values, values+MAX, ostream_iterator<int>(cout, "\n"));
cout << *std::max_element(values, values+MAX);
return 0;
}
Doing this removes the need for your findMax method altogether.
I'd also re-write your code so that you use a vector instead of an array. This makes your code even shorter. And you can use stringstream to convert strings to numbers.
Something like this should work and is a lot less code than the original.
int main(){
vector<int> values;
char ivals[256];
// Get the space-separated values from user input.
cin.getline(ivals, 256, '0');
int temp = 0;
stringstream ss(ivals);
//read the next int out of the stream and put it in temp
while(ss >> temp) {
//add temp to the vector of ints
values.push_back(temp);
}
copy(values.begin(), values.end(), ostream_iterator<int>(cout, "\n"));
cout << *std::max_element(values.begin(), values.end());
return 0;
}
Array of int is promoted to a pointer to int when passed to a function. There is no operator << taking ordinary array. If you want to use operator << this way, you need to use std::vector instead.
Note: it is possible technically to distinguish array when passed to a function using template, but this is not implemented for standard operator <<.
for(int i = 0; i < (sizeof(arr)/sizeof(int)); i++){
sizeof(arr) here is the size of the pointer to the array. C++ will not pass the actual array, that would be grossly inefficient. You'd typically only get one pass through the loop. Declare your function like this:
int findMax(int* arr, size_t elements) {
//...
}
But, really, use a vector.
Oh, hang on, the question. Loop through the array and print each individual element.