I am trying to search in a string for a certain value and replace it with another value.
The example:
String: "/accounts/{accountId}/cheques/{chequeId}/cancel"
I am trying to replace anything between { and } with the number 1.
So I would end up with:
String: "/accounts/1/cheques/1/cancel"
I am using the following:
prepedURI = System.Text.RegularExpressions.Regex.Replace(prepedURI, "{.*}", "1")
But unfortunately, the Replace function is returning:
String: "/accounts/1/cancel"
It seems to be ignoring the first } and replacing everything up to the 2nd }.
Any advice?
Excuse my dumb. This is my first Regex experience, and I am trying my best to understand all these 'flags' in the pattern.
Example (you can paste into a button click event to see what I mean):
Dim prepedURI As String = "/accounts/{accountId}/cheques/{chequeId}/cancel"
prepedURI = System.Text.RegularExpressions.Regex.Replace(prepedURI, "{.*}", "1")
MsgBox(prepedURI)
Use ? before the closing curly brace
{.*?}
Working example can be found at the following link -
http://rubular.com/r/1LpnGNC3sC
Related
I have a variable rawvalue:
let rawvalue = {abc-def-qwe}
I want to use regex to remove the { and }; I can simply do this by truncating the first and last characters. I built the regex:
^.(.*.).$
I want to know how to apply this regex on my variable to get the desired output?
The syntax you're looking for is like this:
let input = "{abc-def-qwe}";
let re = /^.(.*.).$/;
let fixed = re.exec(input)[1]; // Get the first match group "abc-def-qwe"
Maybe, this RegEx might be a better choice, which creates one group and you can simply call it using $1 and replace your string:
^\{(.+)\}$
For implementation, you might use, maybe these posts: 1, 2, 3.
Let's say I have a line,
$bagel = parser(1);
$potato = parser(3+(other var));
$avocado = parser(3-(var1+var2+var3));
$untouchedtoast = donotremove(4);
I want to print, instead of parser(1), just 1. So I want to strip function calls (matching parser(.) I guess?), but leave the innards untouched. The output would, ideally, be
$bagel = 1;
$potato = 3+(other var);
$avocado = 3-(var1+var2+var3);
$untouchedtoast = donotremove(4);
I tried %s/parser(.)//g, but it only replaced everything to the left of the innards. Tried a few other wildcards, but I think I have to somehow pass a variable from the input regex to the output regex, and I'm not sure if that's possible. If it matters, I'm doing this in vim.
Thoughts?
%s/parser(\(.\+\));/\1;/
Search parser();, extract everything inside () using \(.\+\) group, replace the entire expression with the group (\1), add a semicolon (because it was eaten by the search expression).
Try this:
search: \w\(|\)(?=;)
replace: blank
I have the following tag from an XML file:
<msg><![CDATA[Method=GET URL=http://test.de:80/cn?OP=gtm&Reset=1(Clat=[400441379], Clon=[-1335259914], Decoding_Feat=[], Dlat=[0], Dlon=[0], Accept-Encoding=gzip, Accept=*/*) Result(Content-Encoding=[gzip], Content-Length=[7363], ntCoent-Length=[15783], Content-Type=[text/xml; charset=utf-8]) Status=200 Times=TISP:270/CSI:-/Me:1/Total:271]]>
Now I try to get from this message: Clon, Dlat, Dlon and Clat.
However, I already created the following regex:
(?<=Clat=)[\[\(\d+\)\n\n][^)n]+]
But the problem is here, I would like to get only the numbers without the brackets. I tried some other expressions.
Do you maybe know, how I can expand this expression, in order to get only the values without the brackets?
Thank you very much in advance.
Best regards
The regex
(clon|dlat|dlon|clat)=\[(-?\d+)\]
Gives
As I stated before, if you use this regex to extract the information out of this CDATA element, that's okay. But you really want to get to the contents of that element using an XML parser.
Example usage
Regex r = new Regex(#"(clon|dlat|dlon|clat)=\[(-?\d+)\]");
string s = ".. here's your cdata content .. ";
foreach (Match match in Regex.Matches(input, pattern, RegexOptions.IgnoreCase))
{
var name = match.Groups[1].Value; //will contain "clon", "dlat", "dlon" or "clat"
var inner_value = match.Groups[2].Value; //will contin the value inside the square-brackets, e.g. "400441379"
//Do something with the matches
}
I have a list of label names in a text file I'd like to manipulate using Find and Replace in Notepad++, they are listed as follows:
MyLabel_01
MyLabel_02
MyLabel_03
MyLabel_04
MyLabel_05
MyLabel_06
I want to rename them in Notepad++ to the following:
Label_A_One
Label_A_Two
Label_A_Three
Label_B_One
Label_B_Two
Label_B_Three
The Regex I'm using in the Notepad++'s replace dialog to capture the label name is the following:
((MyLabel_0)((1)|(2)|(3)|(4)|(5)|(6)))
I want to replace each capture group as follows:
\1 = Label_
\2 = A_One
\3 = A_Two
\4 = A_Three
\5 = B_One
\6 = B_Two
\7 = B_Three
My problem is that Notepad++ doesn't register the syntax of the regex above. When I hit Count in the Replace Dialog, it returns with 0 occurrences. Not sure what's misesing in the syntax. And yes I made sure the Regular Expression radio button is selected. Help is appreciated.
UPDATE:
Tried escaping the parenthesis, still didn't work:
\(\(MyLabel_0\)\((1\)|\(2\)|\(3\)|\(4\)|\(5\)|\(6\)\)\)
Ed's response has shown a working pattern since alternation isn't supported in Notepad++, however the rest of your problem can't be handled by regex alone. What you're trying to do isn't possible with a regex find/replace approach. Your desired result involves logical conditions which can't be expressed in regex. All you can do with the replace method is re-arrange items and refer to the captured items, but you can't tell it to use "A" for values 1-3, and "B" for 4-6. Furthermore, you can't assign placeholders like that. They are really capture groups that you are backreferencing.
To reach the results you've shown you would need to write a small program that would allow you to check the captured values and perform the appropriate replacements.
EDIT: here's an example of how to achieve this in C#
var numToWordMap = new Dictionary<int, string>();
numToWordMap[1] = "A_One";
numToWordMap[2] = "A_Two";
numToWordMap[3] = "A_Three";
numToWordMap[4] = "B_One";
numToWordMap[5] = "B_Two";
numToWordMap[6] = "B_Three";
string pattern = #"\bMyLabel_(\d+)\b";
string filePath = #"C:\temp.txt";
string[] contents = File.ReadAllLines(filePath);
for (int i = 0; i < contents.Length; i++)
{
contents[i] = Regex.Replace(contents[i], pattern,
m =>
{
int num = int.Parse(m.Groups[1].Value);
if (numToWordMap.ContainsKey(num))
{
return "Label_" + numToWordMap[num];
}
// key not found, use original value
return m.Value;
});
}
File.WriteAllLines(filePath, contents);
You should be able to use this easily. Perhaps you can download LINQPad or Visual C# Express to do so.
If your files are too large this might be an inefficient approach, in which case you could use a StreamReader and StreamWriter to read from the original file and write it to another, respectively.
Also be aware that my sample code writes back to the original file. For testing purposes you can change that path to another file so it isn't overwritten.
Bar bar bar - Notepad++ thinks you're a barbarian.
(obsolete - see update below.) No vertical bars in Notepad++ regex - sorry. I forget every few months, too!
Use [123456] instead.
Update: Sorry, I didn't read carefully enough; on top of the barhopping problem, #Ahmad's spot-on - you can't do a mapping replacement like that.
Update: Version 6 of Notepad++ changed the regular expression engine to a Perl-compatible one, which supports "|". AFAICT, if you have a version 5., auto-update won't update to 6. - you have to explicitly download it.
A regular expression search and replace for
MyLabel_((01)|(02)|(03)|(04)|(05)|(06))
with
Label_(?2A_One)(?3A_Two)(?4A_Three)(?5B_One)(?6B_Two)(?7B_Three)
works on Notepad 6.3.2
The outermost pair of brackets is for grouping, they limit the scope of the first alternation; not sure whether they could be omitted but including them makes the scope clear. The pattern searches for a fixed string followed by one of the two-digit pairs. (The leading zero could be factored out and placed in the fixed string.) Each digit pair is wrapped in round brackets so it is captured.
In the replacement expression, the clause (?4A_Three) says that if capture group 4 matched something then insert the text A_Three, otherwise insert nothing. Similarly for the other clauses. As the 6 alternatives are mutually exclusive only one will match. Thus only one of the (?...) clauses will have matched and so only one will insert text.
The easiest way to do this that I would recommend is to use AWK. If you're on Windows, look for the mingw32 precompiled binaries out there for free download (it'll be called gawk).
BEGIN {
FS = "_0";
a[1]="A_One";
a[2]="A_Two";
a[3]="A_Three";
a[4]="B_One";
a[5]="B_Two";
a[6]="B_Three";
}
{
printf("Label_%s\n", a[$2]);
}
Execute on Windows as follows:
C:\Users\Mydir>gawk -f test.awk awk.in
Label_A_One
Label_A_Two
Label_A_Three
Label_B_One
Label_B_Two
Label_B_Three
Can anyone help me with a regex to turn:
filename_author
to
author_filename
I am using MS Word 2003 and am trying to do this with Word's Find-and-Replace. I've tried the use wildcards feature but haven't had any luck.
Am I only going to be able to do it programmatically?
Here is the regex:
([^_]*)_(.*)
And here is a C# example:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main()
{
String test = "filename_author";
String result = Regex.Replace(test, #"([^_]*)_(.*)", "$2_$1");
}
}
Here is a Python example:
from re import sub
test = "filename_author";
result = sub('([^_]*)_(.*)', r'\2_\1', test)
Edit: In order to do this in Microsoft Word using wildcards use this as a search string:
(<*>)_(<*>)
and replace with this:
\2_\1
Also, please see Add power to Word searches with regular expressions for an explanation of the syntax I have used above:
The asterisk (*) returns all the text in the word.
The less than and greater than symbols (< >) mark the start and end
of each word, respectively. They
ensure that the search returns a
single word.
The parentheses and the space between them divide the words into
distinct groups: (first word) (second
word). The parentheses also indicate
the order in which you want search to
evaluate each expression.
Here you go:
s/^([a-zA-Z]+)_([a-zA-Z]+)$/\2_\1/
Depending on the context, that might be a little greedy.
Search pattern:
([^_]+)_(.+)
Replacement pattern:
$2_$1
In .NET you could use ([^_]+)_([^_]+) as the regex and then $2_$1 as the substitution pattern, for this very specific type of case. If you need more than 2 parts it gets a lot more complicated.
Since you're in MS Word, you might try a non-programming approach. Highlight all of the text, select Table -> Convert -> Text to Table. Set the number of columns at 2. Choose Separate Text At, select the Other radio, and enter an _. That will give you a table. Switch the two columns. Then convert the table back to text using the _ again.
Or you could copy the whole thing to Excel, construct a formula to split and rejoin the text and then copy and paste that back to Word. Either would work.
In C# you could also do something like this.
string[] parts = "filename_author".Split('_');
return parts[1] + "_" + parts[0];
You asked about regex of course, but this might be a good alternative.