XSLT Ignore namespace - xslt

Question

I'm trying to get accustomed to XSLT, and I understand the reason for namespaces, but I'm simply trying to convert local XML files to be consumed by a local application.
I'm trying to convert the file found here: http://uscodebeta.house.gov/download/releasepoints/us/pl/113/31/xml_usc01#113-31.zip
using this code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" name="xml"/>
<xsl:template match="//title">
<xsl:for-each select="section">
<xsl:variable name="href"><xsl:value-of select="ancestor::title/num/#value" />-<xsl:value-of select="ancestor::chapter/num/#value" />-<xsl:value-of select="num/#value" />.xml</xsl:variable>
<xsl:result-document href="$href">
<xsl:element name="structure">
<xsl:element name="unit">
<xsl:attribute name="label">title</xsl:attribute>
<xsl:attribute name="identifier">
<xsl:value-of select="ancestor::title/num/#value" />
</xsl:attribute>
<xsl:attribute name="order_by">
<xsl:value-of select="ancestor::title/num/#value" />
</xsl:attribute>
<xsl:attribute name="level">1</xsl:attribute>
<xsl:value-of select="ancestor::title/num" /> <xsl:value-of select="ancestor::title/heading"/>
</xsl:element>
</xsl:element>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
into the XML example found here:
https://github.com/statedecoded/statedecoded/wiki/XML-Format-for-Parser
This is the conversion for just the first element, but when running with Saxon on the command line, I'm getting the warning:
Warning: SXXP0005: The source document is in namespace http://xml.house.gov/schemas/uslm/1.0, but all the template rules match elements in no namespace
and the output is plain text instead of XML tags.
Any help would be greatly appreciated.
Thanks

Answer 1

Since you're using XSLT 2.0 you can add the xpath-default-namespace attribute on xsl:stylesheet. See http://www.w3.org/TR/xslt20/#standard-attributes for more details.
For example:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xpath-default-namespace="http://xml.house.gov/schemas/uslm/1.0">
You also have the option of using * as the prefix for each element in your paths. That could end up being a lot of work though if your stylesheet grows.
Example:
ancestor::*:title/*:num
Full example:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xpath-default-namespace="http://xml.house.gov/schemas/uslm/1.0">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:apply-templates select="#*|node()"/>
</xsl:template>
<xsl:template match="section">
<xsl:result-document href="{ancestor::title/num/#value}-{ancestor::chapter/num/#value}-{num/#value}.xml">
<structure>
<unit label="title" identifier="{ancestor::title/num/#value}"
order_by="{ancestor::title/num/#value}" level="1">
<xsl:value-of select="concat(ancestor::title/num,' ',ancestor::title/heading)"/>
</unit>
</structure>
</xsl:result-document>
</xsl:template>
</xsl:stylesheet>