How to programmatically iterate in XSLT across multiple files with similar name - xslt

Question

A have following xmls:
data_0.xml
data_1.xml
data_3.xml
and so on...
And in xslt file I want to iterate through all files, so I tried for-each function.
<xsl:for-each select="document('data.xml')/*">
How to iterate on all of them? Add mask somehow? This surely won't work:
<xsl:for-each select="document('data_*.xml')/*">

Answer 1

Here is your solution in xslt 1.0:
I have four files in my filesystem:
Doc1.xml:
<p>Doc1</p>
Doc2.xml:
<p>Doc2</p>
Doc3.xml:
<p>Doc3</p>
Doc4.xml:
<p>Doc4</p>
and my xslt to get their output is:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<Root>
<xsl:call-template name="getDocuments"/>
</Root>
</xsl:template>
<xsl:template name="getDocuments">
<xsl:param name="fileStartWith" select="'Doc'"/>
<xsl:param name="endCounter">4</xsl:param>
<xsl:param name="startCounter">1</xsl:param>
<xsl:choose>
<xsl:when test="$endCounter > 0">
<xsl:variable name="fileName"><xsl:value-of select="concat($fileStartWith,$startCounter,'.xml')"/></xsl:variable>
<xsl:for-each select="document($fileName)/*">
<xsl:copy-of select="."/><xsl:text>
</xsl:text>
</xsl:for-each>
<xsl:call-template name="getDocuments">
<xsl:with-param name="startCounter" select="$startCounter + 1"/>
<xsl:with-param name="fileStartWith" select="$fileStartWith"/>
<xsl:with-param name="endCounter" select="$endCounter - 1"/>
</xsl:call-template>
</xsl:when>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
generated output is:
<Root>
<p>Doc1</p>
<p>Doc2</p>
<p>Doc3</p>
<p>Doc4</p>
</Root>
Please make sure that xslt and xml is on the same path otherwise you need to change the content of document function.