I need to use sed to look for all lines in a file with pattern "[whatever]|[whatever]" so I'm using the following regex:
sed '/\"[a-zA-Z0-9]+\|[a-zA-Z0-9]+\"/p' test2.txt
But it's not working because in this file is returning something when it shouldn't
RTV0031605951US|3160595|20/03/2013|0|"Laurie Graham"|"401"
Does anybody know with regex should I use? Thanks in advance
I see three problems with your regular expression:
+ is not a metacharacter, so you need to escape it to get its special meaning.
Similar issue happens with the pipe. Neither it is a metacharacter, so don't escape it to match it literally.
Sed by default prints each line that matches, so add -n that avoids that, if you already use /p that prints it. Otherwise you will have those lines twice in the output.
sed will output anything that is a partial match.
To match only whole lines that match your regex, add ^ and $ to the start/end:
sed '/^\"[a-zA-Z0-9]+\|[a-zA-Z0-9]+\"$/p' test2.txt
sed '/\B\"[ [:alnum:]]\+\"|\"[ [:alnum:]]\+\"\B/!d' file
If you use this in a sed script, do not escape double quotes.
Related
I have a text file with the following pattern written to it:
TIME[32.468ms] -(3)-............."TEXT I WANT TO KEEP"
I would like to discard the first part of each line containing
TIME[32.468ms] -(3)-.............
To test the regular expression I've tried the following:
cat myfile.txt | egrep "^TIME\[.*\]\s\s\-\(3\)\-\.+"
This identifies correctly the lines I want. Now, to delete the pattern I've tried:
cat myfile.txt | sed s/"^TIME\[.*\]\s\s\-\(3\)\-\.+"//
but it just seems to be doing the cat, since it shows the content of the complete file and no substitution happens.
What am I doing wrong?
OS: CentOS 7
With your shown samples, please try following grep command. Written and tested with GNU grep.
grep -oP '^TIME\[\d+\.\d+ms\]\s+-\(\d+\)-\.+\K.*' Input_file
Explanation: Adding detailed explanation for above code.
^TIME\[ ##Matching string TIME from starting of value here.
\d+\.\d+ms\] ##Matching digits(1 or more occurrences) followed by dot digits(1 or more occurrences) followed by ms ] here.
\s+-\(\d+\)-\.+ ##Matching spaces91 or more occurrences) followed by - digits(1 or more occurrences) - and 1 or more dots.
\K ##Using \K option of GNU grep to make sure previous match is found in line but don't consider it in printing, print next matched regex part only.
.* ##to match till end of the value.
2nd solution: Adding awk program here.
awk 'match($0,/^TIME\[[0-9]+\.[0-9]+ms\][[:space:]]+-\([0-9]+\)-\.+/){print substr($0,RSTART+RLENGTH)}' Input_file
Explanation: using match function of awk, to match regex ^TIME\[[0-9]+\.[0-9]+ms\][[:space:]]+-\([0-9]+\)-\.+ which will catch text which we actually want to remove from lines. Then printing rest of the text apart from matched one which is actually required by OP.
This awk using its sub() function:
awk 'sub(/^TIME[[][^]]*].*\.+/,"")' file
"TEXT I WANT TO KEEP"
If there is replacement, sub() returns true.
$ cut -d'"' -f2 file
TEXT I WANT TO KEEP
You may use:
s='TIME[32.468ms] -(3)-............."TEXT I WANT TO KEEP"'
sed -E 's/^TIME\[[^]]*].*\.+//'
"TEXT I WANT TO KEEP"
The \s regex extension may not be supported by your sed.
In BRE syntax (which is what sed speaks out of the box) you do not backslash round parentheses - doing that turns them into regex metacharacters which do not match themselves, somewhat unintuitively. Also, + is just a regular character in BRE, not a repetition operator (though you can turn it into one by similarly backslashing it: \+).
You can try adding an -E option to switch from BRE syntax to the perhaps more familiar ERE syntax, but that still won't enable Perl regex extensions, which are not part of ERE syntax, either.
sed 's/^TIME\[[^][]*\][[:space:]][[:space:]]-(3)-\.*//' myfile.txt
should work on any reasonably POSIX sed. (Notice also how the minus character does not need to be backslash-escaped, though doing so is harmless per se. Furthermore, I tightened up the regex for the square brackets, to prevent the "match anything" regex you had .* from "escaping" past the closing square bracket. In some more detail, [^][] is a negated character class which matches any character which isn't (a newline or) ] or [; they have to be specified exactly in this order to avoid ambiguity in the character class definition. Finally, notice also how the entire sed script should normally be quoted in single quotes, unless you have specific reasons to use different quoting.)
If you have sed -E or sed -r you can use + instead of * but then this complicates the overall regex, so I won't suggest that here.
A simpler one for sed:
sed 's/^[^"]*//' myfile.txt
If the "text you want to keep" always surrounded by the quote like this and only them having the quote in the line starting with "TIME...", then:
sed -n '/^TIME/p' file | awk -F'"' '{print $2}'
should get the line starting with "TIME..." and print the text within the quotes.
Thanks all, for your help.
By the end, I've found a way to make it work:
echo 'TIME[32.468ms] -(3)-.............TEXT I WANT TO KEEP' | grep TIME | sed -r 's/^TIME\[[0-9]+\.[0-9]+ms\]\s\s-\(3\)-\.+//'
More generally,
grep TIME myfile.txt | sed -r ‘s/^TIME\[[0-9]+\.[0-9]+ms\]\s\s-\(3\)-\.+//’
Cheers,
Pedro
I have a large file that contains timestamps in the following format:
2018-08-22T13:06:04.442774Z
I would like to add double quotes around all the occurrences that match this specific expression. I am trying to use sed, but I don't seem to be able to find the right command. I am trying something around these lines:
sed -e s/[0-9]\{4\}-[0-9]\{2\}-[0-9]\{2\}T[0-9]\{2\}:[0-9]\{2\}:[0-9]\{2\}.[0-9]\{6\}Z/"$0"/g my_file.json
and I am pretty sure that the problem is around my "replace" expression.
How should I correct the command?
Thank you in advance.
You should wrap the sed replacement command with single quotes and use & instead of $0 in the RHS to replace with the whole match:
sed 's/[0-9]\{4\}-[0-9]\{2\}-[0-9]\{2\}T[0-9]\{2\}:[0-9]\{2\}:[0-9]\{2\}\.[0-9]\{6\}Z/"&"/g' file > outfile
See the online demo
Also, do not forget to escape the . char if you want to match a dot, and not any character.
You may also remove excessive escapes if you use ERE syntax:
sed -E 's/[0-9]{4}-[0-9]{2}-[0-9]{2}T[0-9]{2}:[0-9]{2}:[0-9]{2}\.[0-9]{6}Z/"&"/g'
If you want to change the file inline, use the -i option,
sed -i 's/[0-9]\{4\}-[0-9]\{2\}-[0-9]\{2\}T[0-9]\{2\}:[0-9]\{2\}:[0-9]\{2\}\.[0-9]\{6\}Z/"&"/g' file
The following works:
sed 's/\([0-9]\{4\}-[0-9]\{2\}-[0-9]\{2\}T[0-9]\{2\}:[0-9]\{2\}:[0-9]\{2\}\.[0-9]\{6\}Z\)/"\1"/g' my_file.json
multiple modifications:
wrap command in single quotes
use \( and \) to create a group (referenced by '\1` in the replacement section)
escape the '.' and '{' and '}' characters
Having the following string inside of a text file.
{"_job":"delete","query":{"query":{"bool":{"must":[{"term":{"_id":"28381"}}],"should":[]}}},"script":{"inline":"ctx._source.meta='This
is a ' test string Peedr'"},"timestamp":1518165383,"host":"","port":"9200","index":"","docType":"","customIndexer":""}
I would like to replace all the ' that are inside the ctx._source.meta='' part with \' using sed.
In the example above I've This is a ' test string Peedr which I would like to convert to This is a \' test string Peedr, so the desired output would be:
{"_job":"delete","query":{"query":{"bool":{"must":[{"term":{"_id":"28381"}}],"should":[]}}},"script":{"inline":"ctx._source.meta='This
is a \' test string
Peedr'"},"timestamp":1518165383,"host":"","port":"9200","index":"","docType":"","customIndexer":""}
I'm using the following regex to get the ' that is inside the ctx._source.meta string (3rd capture group).
(meta=')(.*?)(')(.*?)(')
I've the regex, but I dont know how to use the sed comand in order to replace the 3rd capture group with \'.
Can someone give me a hand and tell me the sed comand I have to use?
Thanks in advance
sed generally does not support the Perl regex extensions, so the non-greedy .*? will probably not do what you hope. If you want to use Perl regex, use Perl!
perl -pe "s/(meta='.*?)(')(.*?')/\$1\\\\\$2\$3/"
This will still not necessarily work if the input is malformed; a better approach would be to specifically exclude single quotes from the match, and then you don't need the non-greedy matching.
sed "s/\\(meta='[^']*\\)'\\([^']*'\\)/\\1\\\\'\\2/"
In both cases, the number of backslashes required to escape the backslashes inside the shell's double quotes is staggering.
You put back-references to groups except one you want to replace. There is a better way to accomplish same task:
sed -E "s/(ctx\._source\.meta=')([^']*)(')([^']*')/\1\2\\'\4/"
You may use:
sed "s/ ' / \\\' /g" sample.txt
The first part will instruct sed to only look for a single quote between 2 spaces, as such ctx._source.meta='This and string Peedr'"} will not match, hence will not be changed.
Edit:
At the poster's request, I edited my sed command to apply to extra use cases:
sed "s/\(ctx._source.meta='.*\)'\(.*Peedr'\"\)/\1\\\'\2/g"
I want to replace dots with commas for some but not all matches:
hostname_metric (Index: 1) to hostname;metric (avg);22.04.2015 13:40:00;3.0000;22.04.2015 02:05:00;2.0000;22.04.2015 02:00:00;650.7000;2.2594;
The outcome should look like this:
hostname_metric (Index: 1) to hostname;metric (avg);22.04.2015 13:40:00;3,0000;22.04.2015 02:05:00;2,0000;22.04.2015 02:00:00;650,7000;2,2594;
I was able to identify the RegEx which should work to find the correct dots.
;[0-9]{1,}\.[0-9]{4}
But how can I replace them with a comma with awk or sed?
Thanks in advance!
Adding some capture groups to the regex in your question, you can use this sed one-liner:
sed -r 's/(;[0-9]{1,})\.([0-9]{4})/\1,\2/g' file
This matches and captures the part before and after the . and uses them in the replacement string.
On some versions of sed, you may need to use -E instead of -r to enable Extended Regular Expressions. If your version of sed doesn't understand either switch, you can use basic regular expressions and add a few escape characters:
sed 's/\(;[0-9]\{1,\}\)\.\([0-9]\{4\}\)/\1,\2/g' file
sed 's/\(;[0-9]\+\)\.\([0-9]\{4\}\)/\1,\2/g' should do the trick.
I need to find out how to delete up to 10 digits that are at the end of the line in my text file using sed.
For example if I have this:
ajsdlfkjasldf1234567890
asdlkjfalskdjf123456
adsf;lkjasldfkjas123
it should become:
ajsdlfkjasldf
asdlkjfalskdjf
adsf;lkjasldfkjas
can anyone help?
I have this, but its not working:
sed 's/[0-9]{10}$//g'
Have you tried this:
sed 's/[0-9]+$//'
Your command would only match and delete exactly 10 digits at the end of line and only, if you enabled extended regular expressions (-E or -r, depending on your version of sed).
You should try
sed -r 's/[0-9]{1,10}$//'
The following should work:
sed 's/[0-9]\{1,10\}$//' file
Regex syntax in sed requires backslashes before the brackets to use them for repetition, unless you use an extended regex option.
A quick look here suggests you should try this:
$ sed 's/[0-9]\{0,10\}$//g'
{ } should be escaped, unless you switch to extended regex syntax:
$ sed -r 's/[0-9]{0,10}$//g'