I have a template which will display all the likes and the person liked for a particular forum. In the template it can display numbers of likes and all the person's username that liked that forum. But I want the full name and not the username (here it is the email). How do I get the full name in the template or if possible from the view itself. Thank you.
forums.html:
{% extends "base.html" %}
{% load forum_tags %}
{% block content %}
<h2>Logged in as -- {{request.user}}</h2>
<h1>Forums:</h1>
{% if forums.count > 0 %}
{% for forum in forums %}
<h2>{{forum.question}}</h2>
<p>{{forum.body | truncatewords:"30"}}</p>
{% if user in forum.likes.all and forum.likes.count > 1 %}
<p>Unlike You and {{forum.likes.count | substract:1}} others liked</p>
{% elif user in forum.likes.all %}
<p>You liked it</p>
{% else %}
<p>Like</p>
{% endif %}
{% for likes in forum.likes.all %}
<li>{{likes}}</li>
{% endfor %}
{% endfor %}
{% else %}
<p>Sorry! No forum to display.</p>
{% endif %}
{% endblock %}
snippet of views.py:
def forums(request):
forums = Forum.objects.all()
c = {'forums': forums}
return render(request, 'forums.html', c)
If you're using the default User model from django.contrib.auth.models, it has a get_full_name method that you can use in your template:
{{ user.get_full_name }}
Otherwise, you can implement that method in your own User model too. Any method that accepts no arguments can be called from templates (unless they have a alters_data attribute set to True).
Related
I'm working on a Django web app and have the following query:
I have a model called 'AppQoSList' which lists the applications available to all users.
I have then another model called 'BasicAppSDWANProfiles' which has a ManyToMany relationship with 'AppQoSList' .
In short, it means a user can have multiple 'BasicAppSDWANProfiles' associated to his account and multiple AppQoS can be within a particular BasicAppSDWANProfiles:
class AppQoSList(models.Model):
app_qos_name = models.CharField(max_length=50, blank=None, null=True)
app_qos_description = models.CharField(max_length=500)
def __str__(self):
return u'%s' % self.app_qos_name
class BasicAppSDWANProfiles(models.Model):
profile_name = models.CharField(max_length=30)
profile_basic_app_qos = models.ManyToManyField(AppQoSList)
tenant_id = models.ForeignKey(Tenant, default=3)
I'm facing issue in my template when I try to display the list of apps available and the associated BasicAppSDWANProfile:
{% for app in apps %}
{% for profile_app in sdwan_prof %}
{% for specific_app in profile_app.profile_basic_app_qos.all %}
{% ifchanged specific_app.pk %}
{% if app.pk == specific_app.pk %}
<td><h4><span class="label label-primary">{{ profile_app.profile_name }}</span></h4></td>
{% else %}
<td><h4><span class="label label-warning">Not Assigned</span></h4></td>
{% endif %}
{% endifchanged %}
{% endfor %}
{% endfor %}
{% endfor %}
Issue with this code is that 'Not Assigned' is displayed 6 times on each row (which corresponds to the number of Apps found in BasicAppSDWANProfiles associated with this user) whereas I would like to display it only once:
Would you have any solution for this ?
Thanks in advance.
I was able to address this issue.
First I did clean up my view code to remove duplicate 'Not Assigned' values.
I pass to my template context a dictionary with only apps that have a profile assigned such as below:
{'citrix-static': 'DPS-BLACKLIST',
'exchange': 'DPS-BLACKLIST',
'ms-lync-audio': 'DPS-WHITELIST',
'ms-update': 'DPS-GREYLIST',
'rtp': 'DPS-WHITELIST',
'share-point': 'DPS-WHITELIST'}
In my template, I only loop through this dictionary:
{% for k,v in app_prof_assign.items %}
{% if app.app_qos_name == k %}
<td><h4><span class="label label-primary">{{ v }}</span></h4></td>
{% endif %}
{% endfor %}
I then simply check if the app is not in the profile dictionary, outside the loop:
{% if app.app_qos_name not in app_prof_assign %}
<td><h4><span class="label label-warning">Not Assigned</span></h4></td>
{% endif %}
Finally, I can get the table populated as expected:
I have two django model, User and Follow.
In the Follow table, I have two attribute a and b which means a following b.
User table is just the django.contrib.auth.User
Let say I am in user A homepage, and A is following B, C and not following D.
I want to list all the username in A's homepage and highlighting those A is following.
In this case B, C should be highlighted and D should not be highlighted.
I was thinking about (pseudocode)
for user in users :
for follow in Following:
if user.username == follow.username:
flag=true
break
if flag:
#print color <p>user.username</p>
else
#print normal..
But I dun think django template allow me to do this.
Is there any other ways to do this?
Here is my code in django template
{% for user in all_user %}
{% for follower in followers %}
{% ifequal user.username follower.follow.username %}
<p class="following">{{user.username}}</p>
{% endifequal %}
{% endfor %}
<p>{{ user.username }}</p>
{% endfor %}
This will duplicate the user that 'A' is following.
Thank you so much
Hm, I would approach this by doing what you have done here, and by passing the variable "flag" to your template, as well as the rest of the objects.
{% if flag == True %}
<do whatever>
{% endif %}
You can also add an attribute to the user in your for loop, then retrieve that in the template.
for user in users :
for follow in Following:
if user.username == follow.username:
user.followed = True
break
Then in your template
{% for user in users %}
{% if user.followed %}
....
{% else %}
....
{% endif %}
{% endfor %}
I would like to display a list of publications on my website; however, I would also like to diaplay a header stating the year for each set of publications published on that particular year.
So I would like for my end result to be like this (my reputation is 1 :( I could not upload the image):
https://dl.dropboxusercontent.com/u/10752936/Screen%20Shot%202013-06-21%20at%206.00.15%20PM.png
I have a table with three columns; id (primary key), title (the title of the article), and date (the date of publications)
In my template file; doing the following will print the header before every article:
{% for curr_pub in all_publications %}
<h1>{{ curr_pub.date.year }}</h1>
<li>{{ curr_pub.title }}</li>
{% endfor %}
I am passing all_publications ordered by '-date' which means that I can compare the year of the current row curr_pub with the previous one and check if it differs or not; and print (or not print) the header accordingly. It seems however, that I cannot do that in the template.
Since I am new to Django and Python, I wasn't sure what to do and this is where I need help; my thoughts were the following:
1) Add a function in the model (def is_it_first_publication(self):) that returns true or false - but I really wasn't able to do that :| - ...and I'm not sure if that is what I needed to do or not!
2) Second one is to do in in the view, and pass extra variable(s) to the template; here's an example (which works just fine for this case):
In the view:
def publications(request):
all_publications = Publications.objects.order_by('-date')
after_first_row_flag = False
f_year = 'Null'
list_of_ids_of_first_publications = []
for curr_pub in all_publications:
if after_first_row_flag:
if curr_pub.date.year != f_year:
list_of_ids_of_first_publications.append(curr_pub.id)
f_year = curr_pub.date.year
else:
# The year of first (or earliest) publication has to be added
#
list_of_ids_of_first_publications.append(curr_pub.id)
f_year = curr_pub.date.year
after_first_row_flag = True
template = loader.get_template('counters/publications.html')
context = RequestContext(request, {
'all_publications': all_publications,
'list_of_first_publications': list_of_ids_of_first_publications,
})
return HttpResponse(template.render(context))
In the template:
{% for curr_pub in all_publications %}
{% if curr_pub.id in list_of_first_publications %}
<h1> {{ curr_pub.date.year }} </h1>
{% endif %}
<li> Placeholder for [curr_pub.title] </li>
{% endfor %}
The regroup built in filter can do this for you without annotating your objects in the view. As the documentation says, it's kind of complicated.
https://docs.djangoproject.com/en/dev/ref/templates/builtins/#regroup
{% regroup all_publications by date.year as year_list %}
{% for year in year_list %}
<h1>{{ year.grouper }}</h1>
{% for publication in year.list %}
<li>{{ publication.title }}</li>
{% endfor %}
{% endfor %}
I think you want the regroup template tag;
{% regroup all_publications by date as publication_groups %}
<ul>
{% for publication_group in publication_groups %}
<li>{{ publication_group.grouper }}
<ul>
{% for publication in publication_group.list %}
<li>{{ publication.title }}</li>
{% endfor %}
</ul>
</li>
{% endfor %}
</ul>
Maybe the template tag regroup could help.
Alternatively, you could do this grouping by year in the view function (will try to provide code later).
My coding is:
views
def showThread(request, thread_id)
post_list = Post.objects.filter(id = thread_id)
post_likes = PostLikes.objects.all()
return render_to_response('show.html',locals(),context_instance=RequestContext(request))
models:
class Post(models.Model):
subject = models.CharField(max_length = 250)
body = models.TextField()
thread = models.ForeignKey('self', null = True, editable = False )
Show.html:
{% for post in post_list %}
{{post.id}}{{post.subject}}
{% endfor %}
{% for post_like in post_likes %}
{% if post_like.post_id == post.id and post_like.user_id == user.id %}
U like this post{{post}}
{% else %}
{{post}}
{% endif %}
{% endfor %}
In the show.html, else part, it displays the values again and again. But i need only one time.How can i break the for loop when i enter into else condition.Please help me..
Django's for tag doesn't provide you with any means to break out of the loop. You'll simply have to filter the collection in your own view and slice it after the point your condition fails and supply that to your template.
You can use the django custom template tag found in this django snippets page. If you have doubts on using it, go to this page to learn about custom template tags.
Then load the template tag in your template using {% load loop_break %}. Then you can break the for loop as given below:
{% for post_like in post_likes %}
{% if post_like.post_id == post.id and post_like.user_id == user.id %}
U like this post{{post}}
{% else %}
{{post}}
{{ forloop|break }}
{% endif %}
{% endfor %}
Here the for loop will break when it enters the else part.
you could probably use ifchanged tag:
https://docs.djangoproject.com/en/dev/ref/templates/builtins/?from=olddocs#ifchanged
However, you probably should consider moving this logic to view.
If you can structure your if statement to detect when you want to output nothing, you can simply put nothing inside your else clause:
{% for post_like in post_likes %}
{% if post_like.post_id == post.id and post_like.user_id == user.id %}
U like this post{{post}}
{% else %}
{% if forloop.first %}
{{post}}
{%else%}{%endif%}
{% endif %}
{% endfor %}
The above might not do quite what you want - you will have to tweak it yourself. The only thing you can't do is set a flag that this is the first entry into the else clause.
Given is a model called "comment" with a foreign key relationship to a model called "task".
{% for task in tasks %}
{% for comment in task.comment_set.all %}
{{ comment }}
{% endfor %}
...
What is the best way to limit this to 5 comments like:
Entry.objects.all()[:5]
{% for task in tasks %}
{% for comment in task.comment_set.all|slice:"5" %}
{{ comment }}
{% endfor %}
{% endfor %}
You don't. You should not do "real work" in a template, this breaks the MVC pattern.
Do the real work in the view, and pass the data to the template (using the context dictionary).
def handle_comments(request):
tasks = Task.objects.all()
comments = {}
for task in tasks:
comments[task] = task.comment_set.all()[:5]
return render_to_response('commenting.html', {'comments': comments})
You can then iterate over the comments in your template:
{% for task, task_comments in comments.items %}{{ task }}{% endfor %}