XSLT - Wrapping up of string after delimiter count 5 (e.g. 5 "|") - xslt

Question

I am newbie in XSLT. I need to wrap up a long string after certain number of delimiter occurs.
Example of such a string is : -
Jason|Michael|John|James|Rick|Paul|JenYee|Ray|Eliza|Shilpa|Abhishek|Patrick|Brent|Kevin|Jim
I don't want to use template for this due to some constraints.
However if its not possible - i am ok with the template.
The output should be like this:
Line 1: Jason|Michael|John|James|Rick| Line 2: Paul|JenYee|Ray|Eliza|Shilpa| Line 3: Abhishek|Patrick|Brent|Kevin|Jim

Answer 1

Use this recursive templates:
<xsl:template name="beforeSeparators">
<xsl:param name="start"/>
<xsl:param name="rest"/>
<xsl:param name="separator"/>
<xsl:param name="count"/>
<xsl:choose>
<xsl:when test="$count <= 0">
<xsl:value-of select="$start"/>
</xsl:when>
<xsl:when test="contains($rest,$separator)">
<xsl:call-template name="beforeSeparators">
<xsl:with-param name="start" select="concat($start,substring-before($rest,$separator),$separator)"/>
<xsl:with-param name="rest" select="substring-after($rest,$separator)"/>
<xsl:with-param name="separator" select="$separator"/>
<xsl:with-param name="count" select="$count - 1"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="concat($start,$rest)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="wrap">
<xsl:param name="str"/>
<xsl:param name="separator"/>
<xsl:param name="separatorsPerLine"/>
<xsl:variable name="line">
<xsl:call-template name="beforeSeparators">
<xsl:with-param name="start" select="''"/>
<xsl:with-param name="rest" select="$str"/>
<xsl:with-param name="separator" select="$separator"/>
<xsl:with-param name="count" select="$separatorsPerLine"/>
</xsl:call-template>
</xsl:variable>
<xsl:value-of select="concat($line,'
')"/>
<xsl:if test="string-length($line) < string-length($str)">
<xsl:call-template name="wrap">
<xsl:with-param name="str" select="substring($str,string-length($line))"/>
<xsl:with-param name="separator" select="$separator"/>
<xsl:with-param name="separatorsPerLine" select="$separatorsPerLine"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
called like this:
<xsl:call-template name="wrap">
<xsl:with-param name="str" select="'Jason|Michael|John|James|Rick|Paul|JenYee|Ray|Eliza|Shilpa|Abhishek|Patrick|Brent|Kevin|Jim'"/>
<xsl:with-param name="separator" select="'|'"/>
<xsl:with-param name="separatorsPerLine" select="5"/>
</xsl:call-template>
produces:
Jason|Michael|John|James|Rick|
Paul|JenYee|Ray|Eliza|Shilpa|
Abhishek|Patrick|Brent|Kevin|
Here is my complete test XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template name="beforeSeparators">
<xsl:param name="start"/>
<xsl:param name="rest"/>
<xsl:param name="separator"/>
<xsl:param name="count"/>
<xsl:choose>
<xsl:when test="$count <= 0">
<xsl:value-of select="$start"/>
</xsl:when>
<xsl:when test="contains($rest,$separator)">
<xsl:call-template name="beforeSeparators">
<xsl:with-param name="start" select="concat($start,substring-before($rest,$separator),$separator)"/>
<xsl:with-param name="rest" select="substring-after($rest,$separator)"/>
<xsl:with-param name="separator" select="$separator"/>
<xsl:with-param name="count" select="$count - 1"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="concat($start,$rest)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="wrap">
<xsl:param name="str"/>
<xsl:param name="separator"/>
<xsl:param name="separatorsPerLine"/>
<xsl:variable name="line">
<xsl:call-template name="beforeSeparators">
<xsl:with-param name="start" select="''"/>
<xsl:with-param name="rest" select="$str"/>
<xsl:with-param name="separator" select="$separator"/>
<xsl:with-param name="count" select="$separatorsPerLine"/>
</xsl:call-template>
</xsl:variable>
<xsl:value-of select="concat($line,'
')"/>
<xsl:if test="string-length($line) < string-length($str)">
<xsl:call-template name="wrap">
<xsl:with-param name="str" select="substring($str,string-length($line)+1)"/>
<xsl:with-param name="separator" select="$separator"/>
<xsl:with-param name="separatorsPerLine" select="$separatorsPerLine"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
<xsl:template match="/">
<xsl:call-template name="wrap">
<xsl:with-param name="str" select="'Jason|Michael|John|James|Rick|Paul|JenYee|Ray|Eliza|Shilpa|Abhishek|Patrick|Brent|Kevin|'"/>
<xsl:with-param name="separator" select="'|'"/>
<xsl:with-param name="separatorsPerLine" select="5"/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
(it just translate a fixed string,, so it can be applied to any XML)

Answer 2

If you can use XSLT 2.0, you could use tokenize().
Example ($input is the string in your question):
<xsl:value-of select="tokenize($input,'\|')[5 >= position()]" separator="|"/>
This will produce: Jason|Michael|John|James|Rick