I have to make an xsl for an xml output exported from a database. The name tags in xml have a prefix bib followed by a colon (as in bib:), and it was defined in xml. But I still got an xsl compiler error saying bib: is not declared. So I added the declaration in xsl. this time the error went away, but the result comes out zero, and I checked the path that is correct. I also tried to exclude "bib:" prefix in xsl after declaration but got the same zero result. I am new to xsl so I don't know what is wrong here. These are my files. Thanks very much.
XML:
<?xml version="1.0" encoding="UTF-8"?>
<embasexmllist>
<cards items="1">
<bib:card items="0" xmlns:bib="http://elsevier.co.uk/namespaces/2001/bibliotek">-
<bib:cardfields>
<bib:Fulltext>
<bib:DOI>10.1371/journal.pone.0068303</bib:DOI>
</bib:Fulltext>
<bib:Title>Mesothelin Virus-Like Particle Immunization Controls Pancreatic Cancer Growth through CD8+ T Cell Induction and Reduction in the Frequency of CD4+foxp3+ICOS- Regulatory T Cells
</bib:Title>
</bib:cardfields>
</bib:card>
</cards>
</embasexmllist>
XSL
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:bib="http://www.bib.com/xml">
<xsl:output indent="yes" omit-xml-declaration="no"
media-type="application/xml" encoding="UTF-8" />
<xsl:template match="/">
<searchresult>
<xsl:apply-templates
select="/embasexmllist/cards/bib:card/bib:cardfields" />
</searchresult>
</xsl:template>
<xsl:template match="bib:cardfields">
<document>
<title><xsl:value-of select="bib:Title" /></title>
<snippet>
<xsl:value-of select="bib:Title" />
</snippet>
<url>
<xsl:variable name="doi" select="bib:Fulltext/bib:DOI"/>
<xsl:value-of
select="concat('http://dx.doi.org/', $doi)" />
</url>
</document>
</xsl:template>
</xsl:stylesheet>
The prefix defines a namespace for the XML elements.
For your stylesheet to work, the namespace declaration needs to match that in your input XML. Replace
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:bib="http://www.bib.com/xml">
with
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:bib="http://elsevier.co.uk/namespaces/2001/bibliotek">
This results in the following output XML:
<?xml version="1.0" encoding="utf-8"?>
<searchresult xmlns:bib="http://elsevier.co.uk/namespaces/2001/bibliotek">
<document>
<title>
Mesothelin Virus-Like Particle Immunization Controls Pancreatic Cancer Growth through CD8+ T Cell Induction and Reduction in the Frequency of CD4+foxp3+ICOS- Regulatory T Cells
</title>
<snippet>
Mesothelin Virus-Like Particle Immunization Controls Pancreatic Cancer Growth through CD8+ T Cell Induction and Reduction in the Frequency of CD4+foxp3+ICOS- Regulatory T Cells
</snippet>
<url>http://dx.doi.org/10.1371/journal.pone.0068303</url>
</document>
</searchresult>
Related
i have the following xml and xslt to render it, but got no results. I checked again and again and see not path problem, and the xsl went through the compiler. so I am not sure if it's namespace problem or something else. many thx!
XML file
<?xml version="1.0" encoding="UTF-8"?>
<bibdataset xsi:schemaLocation="http://www.elsevier.com/xml/ani/ani http://www.elsevier.com/xml/ani/embase_com.xsd"
xmlns="http://www.elsevier.com/xml/ani/ani"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ce="http://www.elsevier.com/xml/ani/common"
xmlns:ait="http://www.elsevier.com/xml/ani/ait">
<item>
<bibrecord>
<item-info>
<itemidlist><ce:doi>10.1258/0268355042555000</ce:doi>
</itemidlist>
</item-info>
<head>
<citation-title>
<titletext xml:lang="en" original="y">Effect of seasonal variations on the emergence of deep venous thrombosis of the lower extremity
</titletext>
</citation-title>
<abstracts>
<abstract xml:lang="en" original="y">
<ce:para>Objective: We aimed to determine the role of seasonal and meteorological variations in the incidence of lower extremity
</ce:para>
</abstract>
</abstracts>
</head>
</bibrecord>
</item>
</bibdataset>
XSLT file
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ce="http://www.elsevier.com/xml/ani/common"
xmlns:ait="http://www.elsevier.com/xml/ani/ait">
<xsl:output indent="yes" omit-xml-declaration="no"
media-type="application/xml" encoding="UTF-8" />
<xsl:template match="/">
<searchresult>
<xsl:apply-templates
select="/bibdataset/item/bibrecord" />
</searchresult>
</xsl:template>
<xsl:template match="bibrecord">
<document>
<title><xsl:value-of select="head/citation-title/titletext" /></title>
<snippet>
<xsl:value-of select="head/abstracts/abstract/ce:para" />
</snippet>
<url>
<xsl:variable name="doilink" select="item-info/itemidlist/ce:doi"/>
<xsl:value-of
select="concat('http://dx.doi.org/', $doilink)" />
</url>
</document>
</xsl:template>
</xsl:stylesheet>
This is indeed an issue with namespaces. In your XML, you have declared a default namespace meaning the root element, and all its descendants, and in this namespace.
<bibdataset .xmlns="http://www.elsevier.com/xml/ani/ani" ...
Now, in your XSLT, you have also declared this namespace, but without a prefix.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
This means it only applies to the elements you are outputting, so your searchresult element gets output in this namespace
<searchresult xmlns="http://www.elsevier.com/xml/ani/ani"
However, it doesn't apply to the xpath expression in your XSLT, and so these are looking for elements in your input XML with no namespace.
In XSLT 2.0 the solution would be to simply declare an "xpath-default-namespace"
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
xpath-default-namespace="http://www.elsevier.com/xml/ani/ani" ...
In XSLT 1.0, you will have to declare the namespace with a prefix, and use this prefix in all the xpath expressions.
Try this XSLT
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.elsevier.com/xml/ani/ani"
xmlns:ani="http://www.elsevier.com/xml/ani/ani"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ce="http://www.elsevier.com/xml/ani/common"
xmlns:ait="http://www.elsevier.com/xml/ani/ait"
exclude-result-prefixes="ani">
<xsl:output indent="yes" omit-xml-declaration="no"
media-type="application/xml" encoding="UTF-8" />
<xsl:template match="/">
<searchresult>
<xsl:apply-templates
select="/ani:bibdataset/ani:item/ani:bibrecord" />
</searchresult>
</xsl:template>
<xsl:template match="ani:bibrecord">
<document>
<title><xsl:value-of select="ani:head/ani:citation-title/ani:titletext" /></title>
<snippet>
<xsl:value-of select="ani:head/ani:abstracts/ani:abstract/ce:para" />
</snippet>
<url>
<xsl:variable name="doilink" select="ani:item-info/ani:itemidlist/ce:doi"/>
<xsl:value-of
select="concat('http://dx.doi.org/', $doilink)" />
</url>
</document>
</xsl:template>
</xsl:stylesheet>
Note that you can remove the line xmlns="http://www.elsevier.com/xml/ani/ani" but that would mean your searchresult (and other) elements would be output with no namespace, so you would need to output it as <ani:searchresult> if you wanted it in the given namespace.
I working with a project in BizTalk where use xslt to convert from and edifact file to an UBL file.
The edifact file contains price values of ###.0 and that do not work. I want to change it to ###.00 using format-number. But I cannot make it work.
This is what I have made so far:
<cbc:Value>
<xsl:variable name="SumOfNodes" select="edi:PRI/edi:C509/C50902"/>
<xsl:value-of select="format-number($SumOfNodes, '0.00')"/>
</cbc:Value>
I am using this stylesheet:
<?xml version="1.0" encoding="utf-16"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:edi="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006/MEDIAMARKT"
xmlns:ubl="urn:oasis:names:specification:ubl:schema:xsd:Order-2"
xmlns:cac="urn:oasis:names:specification:ubl:schema:xsd:CommonAggregateComponents-2"
xmlns:cbc="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2"
exclude-result-prefixes="msxsl edi">
Any ideas on how to solve this??
This may be due to undeclared namespace in your XSLT. Please check whether namespaces are declared correctly in your XSLT. Unless you show the full XSLT coding with XML coding, we cannot able to provide solution. However please refer the below Sample XML and XSLT with the output
XSLT:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="chapter">
<Value>
<xsl:variable name="num" select="number"/>
<xsl:value-of select="format-number($num,'00.00')"/>
</Value>
</xsl:template>
</xsl:stylesheet>
Sample XML
<?xml version="1.0"?>
<chapter>
<number>45</number>
</chapter>
Output
<?xml version='1.0' ?>
<Value>45.00</Value>
I have a specific problem getting values for width and height out of some XML that has namespace prefixes defined. I can get other values such as SomeText from RelatedMaterial quite easily using normal xpath with namespace "n:" but unable to get values for width and height.
Sample XML:
<Description>
<Information>
<GroupInformation xml:lang="en">
<BasicDescription>
<RelatedMaterial>
<SomeText>Hello</SomeText>
<t:ContentProperties>
<t:ContentAttributes>
<t:Width>555</t:Width>
<t:Height>444</t:Height>
</t:ContentAttributes>
</t:ContentProperties>
</RelatedMaterial>
</BasicDescription>
</GroupInformation>
</Information>
</Description>
Here is an extract from the XSLT:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:n="urn:t:myfoo:2010" xmlns:tva2="urn:t:myfoo:extended:2008"
<xsl:apply-templates select="n:Description/n:Information/n:GroupInformation"/>
<xsl:template match="n:GroupInformation">
<width>
<xsl:value-of select="n:BasicDescription/n:RelatedMaterial/t:ContentProperties/t:ContentAttributes/t:Width"/>
</width>
</xsl:template>
The above XSLT does not work for getting the width. Any ideas?
I'm not sure you have realised that both your input and XSLT is invalid, it's always better to provide working examples.
Anyway, if we look at the XPath expression n:BasicDescription/n:RelatedMaterial/t:ContentProperties/t:ContentAttributes/t:Width you're using a prefix n which is mapped to urn:t:myfoo:2010 but when the data infact is in the default namespace. The same goes for the t prefix which isn't defined at all in neither the input data nor XSLT.
You need to define the namespaces on "both sides", in the XML data and the XSLT transformation and they need to be the same, not the prefixes, but the URI.
Somebody else could probably explain this better than me.
I've corrected your example and added a few things to make this work.
Input:
<?xml version="1.0" encoding="UTF-8"?>
<Description
xmlns="urn:t:myfoo:2010"
xmlns:t="something...">
<Information>
<GroupInformation xml:lang="en">
<BasicDescription>
<RelatedMaterial>
<SomeText>Hello</SomeText>
<t:ContentProperties>
<t:ContentAttributes>
<t:Width>555</t:Width>
<t:Height>444</t:Height>
</t:ContentAttributes>
</t:ContentProperties>
</RelatedMaterial>
</BasicDescription>
</GroupInformation>
</Information>
</Description>
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"
xmlns:n="urn:t:myfoo:2010"
xmlns:t="something...">
<xsl:template match="/">
<xsl:apply-templates select="n:Description/n:Information/n:GroupInformation"/>
</xsl:template>
<xsl:template match="n:GroupInformation">
<xsl:element name="width">
<xsl:value-of select="n:BasicDescription/n:RelatedMaterial/t:ContentProperties/t:ContentAttributes/t:Width"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<width>555</width>
I've got a problem with xsl:include and default namespaces which is causing the final xml document contain nodes with the xmlns=""
In this synario I have 1 source document which is Plain Old XML and doesn't have a namespace:
<?xml version="1.0" encoding="UTF-8"?>
<SourceDoc>
<Description>Hello I'm the source description</Description>
<Description>Hello I'm the source description 2</Description>
<Description/>
<Title>Hello I'm the title</Title>
</SourceDoc>
This document is transformed into 2 different xml documents each with their own default namespace.
First Document:
<?xml version="1.0" encoding="utf-8"?>
<OutputDocType1 xmlns="http://MadeupNS1">
<Description >Hello I'm the source description</Description>
<Description>Hello I'm the source description 2</Description>
<Title>Hello I'm the title</Title>
</OutputDocType1>
Second Document:
<?xml version="1.0" encoding="utf-8"?>
<OutputDocType2 xmlns="http://MadeupNS2">
<Description>Hello I'm the source description</Description>
<Description>Hello I'm the source description 2</Description>
<DocTitle>Hello I'm the title</DocTitle>
</OutputDocType2>
I want to be able to re-use the template for descriptions in both of the transforms. As it's the same logic for both types of document. To do this I created a template file which was xsl:included in the other 2 transformations:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml"/>
<xsl:template match="Description[. != '']">
<Description>
<xsl:value-of select="."/>
</Description>
</xsl:template>
</xsl:stylesheet>
Now the problem here is that this shared transformation can't have a default Namespace as it will be different depending on which of the calling transformations calls it.
E.g. for First Document Transformation:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml"/>
<xsl:template match="SourceDoc">
<OutputDocType1 xmlns="http://MadeupNS1">
<xsl:apply-templates select="Description"/>
<xsl:if test="Title">
<Title>
<xsl:value-of select="Title"/>
</Title>
</xsl:if>
</OutputDocType1>
</xsl:template>
<xsl:include href="Template.xsl"/>
</xsl:stylesheet>
This actually outputs it as follows:
<?xml version="1.0" encoding="utf-8"?>
<OutputDocType1 xmlns="http://MadeupNS1">
<Description xmlns="">Hello I'm the source description</Description>
<Description xmlns="">Hello I'm the source description 2</Description>
<Title>Hello I'm the title</Title>
</OutputDocType1>
Here is the problem. On the description Lines I get an xmlns=""
Does anyone know how to solve this issue?
Thanks
Dave
Your first xslt, which contains the literal result element Description has no default namespace. This element is therefore in no namespace, and is being explicitly rendered as such via xmlns="".
Section 6.2 of Namespaces in XML 1.0 says that:
The attribute value in a default
namespace declaration MAY be empty.
This has the same effect, within the
scope of the declaration, of there
being no default namespace.
In order to control the namespace generated in the included stylesheet you will need to pass the namespace-uri through to its templates, using a variable or param.
<!-- in the included stylesheet -->
<xsl:template match="Description[. != '']">
<xsl:element name="Description" namespace="{$output-namespace}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:template>
<!--
and add this to your First Document Transformation stylesheet
as a top level element under xsl:stylesheet
-->
<xsl:variable name="output-namespace" select="'http://MadeupNS1'"/>
Here is a snip-it of the XML:
<?xml version="1.0" encoding="iso-8859-1" ?>
<NetworkAppliance id="S123456">
<Group id="9">
<Probe id="1">
<Value>74.7</Value>
</Probe>
</NetworkAppliance>
I want to get the single point value of 74.7. There are many groups with unique ID's and many Probes under that group with unique ID's each with values.
I am looking for example XSLT code that can get me this one value. Here is what i have that does not work:
<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" version="3.2" />
<xsl:template match="NetworkAppliance">
<xsl:apply-templates select="Group[#id='9']"/>
</xsl:template>
<xsl:template match="Group">
Temp: <xsl:value-of select="Probe[#id='1']/Value"/>
<br/>
</xsl:template>
</xsl:stylesheet>
Here is what worked for me in the end:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!-- Edited by XMLSpy® -->
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="NetworkAppliance/Group[#id=9]/Probe[#id=1]">
Value: <xsl:value-of select="Value" />
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Don't forget that you can do select several levels at once. Fixing your XML to:
<?xml version="1.0" encoding="iso-8859-1" ?>
<NetworkAppliance id="S123456">
<Group id="9">
<Probe id="1">
<Value>74.7</Value>
</Probe>
</Group>
</NetworkAppliance>
and using this stylesheet:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" version="3.2" />
<xsl:template match="/">
Temp: <xsl:value-of select="//Group[#id='9']/Probe[#id='1']/Value"/>
<br/>
</xsl:template>
</xsl:stylesheet>
we can pick out that one item you're interested in.
Points to note:
The // part of the expression means that the search for Group nodes takes place throughout the whole tree, finding Group nodes at whatever depth they're at.
The [#id='9'] part selects those Group nodes with id of 9
The Probe[#id='1'] part immediately after that selects those children of the Group nodes it found where the id is 1, and so on.
<xsl:value-of select="/NetworkAppliance/Group[#id=9]/Probe[#id=1]/Value"/>
XSLT is just one of the tools in the box, and nothing without XPath.
the xpath for value of a node is /node/text()
So
<xsl:value-of select="Probe[#id='1']/text()"/>