Invalid Arrary Assignment - c++

Question

im doing a project for my C++ class and I am having problems with this one particular function. I keep getting the error "invalid array assigment and I dont know why. I am just trying to swap positions into a temp variable and swap back to display this information in descending order. the array dateAdded is an array with Chars. I appreciate the help guys
void repAge(){
cout << "You selected Listing by Age" << endl;
int i;
int pos;
string temp;
bool swap;
// Look for empty row
pos = -1;
// look for an empty book row (title[i][0] == '\0')
for (i = 0; i < 20; i++) {
if (bookTitle[i][0] == '\0') {
pos = i;
break;
}
}
// Now pos is last available value.
do
{
swap = false;
for (int count = 0; count < (pos - 1); count++)
{
if (dateAdded[count] < dateAdded[count+1])
{
temp = dateAdded[count];
dateAdded[count] = dateAdded[count+1];
dateAdded[count+1] = temp;
swap = true;
}
}
} while (swap);
for (i = 0; i< pos; i++) {
while (bookTitle[i] != '\0') {
// print it out
cout << "Title: " << bookTitle[i] << endl;
cout << "ISBN: " << isbn[i] << endl;
cout << "Quantity-On-Hand: " << qtyOnHand[i] << endl;
cout << "Wholesale Cost: " << wholesale[i] << endl;
cout << endl;
break;
}
}
The exact error messages that pop up are "invalid array assignment" or "invalid conversion from char* to char".
the array is declared as dateAdded[20][11] and the lines that do not work are the these
temp= dateAdded[count];
dateAdded[count] = dateAdded[count+1];
dateAdded[count+1] = temp;

Answer 1

You say dateAdded is an array of chars - then, at least the following line will fail since temp is declared as string:
dateAdded[count+1] = temp;
Use something like
dateAdded[count+1] = temp[0];
Probably it is even better to declare temp as char - there is no reason to use string to temporarily store an element of a char array.