Suppose I have the following vlookup command:
=VLOOKUP('Sheet1'!S2,'Sheet2'!$B$138:$C$145,2,FALSE)
When I drag the vlookup to the right I want it to update to
=VLOOKUP('Sheet1'!S2,'Sheet2'!$B$146:$C$153,2,FALSE)
In other words, I want the letters B and C fixed but the numbers to increment by 8. How would I do this?
It looks like your answer is always in column C and your lookup value in column A. If this is the case use INDEX MATCH
=INDEX ( C:C , MATCH ( 'Sheet1'!S2 , 'Sheet2'!$B:$C , 0 ))
I've made a few assumptions. Drop a pic of your tables and I can amend it if you can't work out which bits to change
That may be possible using some long if-then-else logic or macro but it seems an odd thing to do. The numbers represent rows so if you are incrementing them across columns I wonder whether you need to transpose your data and/or use HLOOKUP instead. There is probably a better way to achieve what you want but it is difficult to answer from the question as provided.
Related
I'm finishing my regex project in google sheets and this last question I have for it. Hope you can help.
I have a column, in which one cell may or may not contain multiple strings.
This is an example of it (start position):
Now I want to extract the following values:
Team (A)
Team B
Team (A) Team B
Desired end result image:
I want to check for all 3 possible values, and always sort them with Team (A) as a priority. In case the initial cell (C column) is empty, the result is empty.
I tried this formula:
=ARRAYFORMULA(IFERROR(REGEXEXTRACT(C2,"Team \(A\)|Team B|[Team \(A\) "&" Team B]"),IF(C2="","")))
Problems I have:
Don't know how to give priority :/
Don't know how to give them sorting order :/
All help welcome, thank you.
=ARRAYFORMULA(REGEXREPLACE(IFERROR(
REGEXEXTRACT(C2:C, "(Team \(A\))")&CHAR(10))&
IFERROR(REGEXEXTRACT(C2:C, "(Team B)")), "\n$", ))
Question 1 - Is Tableau able to use multiple results from from a single line in a REGEXP using the global variable to compare against another table during a Join operation? If no, question 2 is null. If yes...
Question 2 - I'm attempting to join two data sources in Tableau using a regexp in a calculated join because the left table has 1 value in each cell (ie. 64826) and the right table has 4 possible matches in each cell (ie. 00000|00000|21678|64826).
The problem is that my regex stops looking after it finds 1 match (the first of 4 values), and the global variable /g has the opposite effect I expected and eliminates all matches.
I've tried calculated joins on the Data Source tab. I've also tried separating those 4 values into their own columns in worksheets using
regexp_extract_nth. In both cases, regex stops looking after the first result. A Left Join seems to work somewhat, while an Outer Join returns nothing.
REGEXP_EXTRACT([Event Number],'(\d{5})')
REGEXP_EXTRACT_NTH([Event Number],'(?!0{5})(\d{5})',1)
With these examples, regex would match a NULL with the left table even though 64826 is in the right table. I expect the calculated join to return all possible matches from the right set, so there'd be a match on 21678 and on 64826, duplicating rows in the right table like so...
21678 - 00000|00000|21678|64826
64826 - 00000|00000|21678|64826
45245 - 45106|45245|00000|00000
45106 - 45106|45245|00000|00000
Your original expression is just fine, we might want to make sure that we are sending a right command in Tableau, which I'm not so sure, maybe let's try an expression similar to:
\b([^0]....)\b
even just for testing, then maybe let's modify our commands to:
REGEXP_EXTRACT([Event Number], '\b([^0]....)\b')
or:
REGEXP_EXTRACT_NTH([Event Number], '\b([^0]....)\b', 1)
to see what happens. I'm assuming that the desired numbers won't be starting with 0.
Please see the demo here
Reference
The documentation for pattern matching for Google Sheets has not been helpful. I've been reading and searching for a while now and can't find this particular issue. Maybe I'm having a hard time finding the correct terms to search for but here is the problem:
I have several numbers (part numbers) that follow this format: ##-####
Categories can be defined by the part numbers, i.e. 50-03## would be one product category, and the remaining 2 digits are specific for a model.
I've been trying to run this:
=countif(E9:E13,"50-03[123][012]*")
(E9:E13 contains the part number formatted as text. If I format it any other way, the values show up screwed up because Google Sheets thinks I'm writing a date or trying to do arithmetic.)
This returns 0 every time, unless I were to change to:
=countif(E9:E13,"50-03*")
So it seems like wildcards work, but pattern matching does not?
As you identified and Wiktor mentioned COUNTIF only supports wildcards.
There are many ways to do what you want though, to name but 2
=ArrayFormula(SUM(--REGEXMATCH(E9:E13, "50-03[123][012]*")))
=COUNTA(FILTER(E9:E13, REGEXMATCH(E9:E13, "50-03[123][012]*")))
This is a really big hammer for a problem like yours, but you can use QUERY to do something like this:
=QUERY(E9:E13, "select count(E) where E matches '50-03[123][012]' label count(E) ''")
The label bit is to prevent QUERY from adding an automatic header to the count() column.
The nice thing about this approach is that you can pull in other columns, too. Say that over in column H, you have a number of orders for each part. Then, you can take two cells and show both the count of parts and the sum of orders:
=QUERY(E9:H13, "select count(E), sum(H) where E matches '50-03[123][012]' label count(E) '', sum(H) ''")
I routinely find this question on $searchEngine and fail to notice that I linked another question with a similar problem and other relevant answers.
I want to convert an input to desired output. Kindly help.
In the output - the columns value should start from most recent (year)
Please click this to see data
Unfortunately VLOOKUP is not able to fulfill that ask. However the INDEX-function can.
Here is a good read on how to use it:
http://fiveminutelessons.com/learn-microsoft-excel/use-index-lookup-multiple-values-list
This will work for you spreedsheet, if your input table starts at A1 without a header and your output table starts at H3 with the first ID.
You get this by copy&pasting the first column of your input table to column H and then remove duplicates.
{=IF(ISERROR(INDEX($A$1:$C$7,SMALL(IF($A$1:$A$7=$H$3,ROW($A$1:$A$7)),ROW(1:1)),3)),"",
INDEX($A$1:$C$7;SMALL(IF($A$1:$A$7=$H$3,ROW($A$1:$A$7)),ROW(1:1)),3))}
Let's look at the formula step by step:
The curly brackets tell excel that this is an array formula, the interesting part for you is: when you've inserted the formula (without curly brackets) press shift+ctrl+enter, excel will then know that this is an array formula.
'error at formula?, then blank, else formula
=IF(ISERROR(....),"",...)
When you autofill this formula you probably dont know how many instances of your lookup variable are. So when you put this formula in 4 cells, but there are only 3 entries, this bit will keep the cell blank instead of giving an error.
INDEX($A$1:$C$7,SMALL(IF($A$1:$A$7=$H$3,ROW($A$1:$A$7)),ROW(1:1)),3))
$A$1:$C$7 is your data matrix. Your IDs (in your case 125 and 501) are to be found in $A$1:$A$7. ROW(1:1) is the absolute(!) rowID, 3 the absolute(!) column id. So when you move your input table those values have to be changed.
What exactly SMALL and INDEX do are well described in the link above. (Or at least better than I could.)
Hope that clarified some parts,
Tom
I have one table (A) with a phrase, and the other (B) is a phrase that I want to find WITHIN table A's phrase. So I'm joining them as follows:
Create table C as
SELECT A.*
FROM A
JOIN B
where (A.phrase LIKE concat("%",B.phrase,"%"));
It is taking a long time because it's only using one reducer, and I believe this has to do with the nature of the query? Is there a way of speeding this up? I don't think a mapjoin or bucketjoin would help, because I'm not equating two columns, but rather, searching within one table for words from another table...
I found the solution.
The problem was that Hive doesn't do non equi joins well. So I did equi joins to get a subset of table A before I did the non equi join regex. So, 3 steps.
Break A.phrase and B.phrase into individual words.
Equate these words to see which keywords from B.phrase are equal to any keywords from A.phrase - this gives a subset of table A where A.phrase contains at least one keyword from B.phrase.
Use this table A subset to find the whole "%B.phrase%".
I think that EXISTS may be faster simply because your query will return same row from A multiple times for every match:
SELECT
A.*
FROM A as a
WHERE EXISTS (
SELECT
1
FROM B
WHERE a.phrase LIKE concat("%",phrase,"%")
);