xslt: move all siblings inside the first one - xslt

I've searched through similar questions, but couldn't make any of the suggestions to work. I have the following xml I need to modify it
<XDB>
<ROOT>
<KEY><ID>12345</ID><DATE>5/10/2011</DATE></KEY>
<PERSONAL><ID>1</ID><INFO><LASTNAME>Smith</LASTNAME>...</INFO></PERSONAL>
<CONTACT><ID>1</ID><EMAIL>asmith#yahoo.com</EMAIL>...</CONTACT>
</ROOT>
<ROOT>
<KEY><ID>98765</ID><DATE>5/10/2013</DATE></KEY>
<CONTACT><ID>2</ID><EMAIL>psmithton#yahoo.com</EMAIL>...</CONTACT>
</ROOT>
...
</XDB>
And it needs to look like this:
<XDB>
<ROOT>
<KEY><ID>12345</ID><DATE>5/10/2011</DATE>
<PERSONAL><ID>1</ID><INFO><LASTNAME>Smith</LASTNAME>...</INFO></PERSONAL>
<CONTACT><ID>1</ID><EMAIL>asmith#yahoo.com</EMAIL>...</CONTACT>
</KEY>
</ROOT>
<ROOT>
<KEY><ID>98765</ID><DATE>5/10/2013</DATE>
<CONTACT><ID>2</ID><EMAIL>psmithton#yahoo.com</EMAIL>...</CONTACT>
</KEY>
</ROOT>
...
</XDB>
I need to make 2...n siblings as children of the first 'key' sibling. Essentially, i need to remove the closing < /KEY> and put it before the closing < /ROOT>. I would appreciate your help.
Thanks.

Following xslt based on Identity transform could make this job
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<!-- Copy everything you find... -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<!-- ... but if you find first element inside ROOT ... -->
<xsl:template match="ROOT/node()[1]">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
<!-- ... copy its sibling into it ... -->
<xsl:copy-of select="following-sibling::*" />
</xsl:copy>
</xsl:template>
<!-- ignore other elements inside ROOT element since they are copied in template matching first element -->
<xsl:template match="ROOT/node()[position() > 1]" />
</xsl:stylesheet>

Related

How to check contain only characters + space and `p` using regex

I want to check to contain only characters + space and <p> nodes inside <used>.
Input:
<root>
<used><p>String 1</p></used>
<used>string 2<p>string 3</p></used>
<used>string 4</used>
<used><image>aaa.jpg</image>para</used>
The output should be:
<ans>
<abc>string 1</abc>
<abc>string 4</abc>
</ans>
Tried code:
<ans>
<abc>
<xsl:template match="root">
<xsl:choose>
<xsl: when test="getCode/matches(text(),'^[a-zA-Z0-9]+$')">
<xsl:text>text()</xsl:text>
</xsl:when>
</xsl:choose>
</xsl:template>
</abc>
</ans>
My tried code is not working as I am expecting. How can I fix this? Thank you. I am using XSLT 2.0
You can use the following XSLT-2.0 stylesheet to get the desired result:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl= "http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<!-- Handle the <root> element -->
<xsl:template match="/root">
<ans>
<xsl:apply-templates select="used" />
</ans>
</xsl:template>
<!-- Create <abc> elements for every matching element -->
<xsl:template match="used[not(*) and matches(text(),'^[\sa-zA-Z0-9]+$')] | used[not(text()) and matches(p/text(),'^[\sa-zA-Z0-9]+$')]/p">
<abc><xsl:copy-of select="text()" /></abc>
</xsl:template>
<!-- Remove all spurious text nodes -->
<xsl:template match="text()" />
</xsl:stylesheet>
Its result is
<?xml version="1.0" encoding="UTF-8"?>
<ans>
<abc>String 1</abc>
<abc>string 4</abc>
</ans>

XSLT code to remove xml tag

I have an incoming XML like below: I need to remove the <shoeboxImage> tag from the incoming below XML.
Incoming XML Input:
<attachReceipt>
<baseMessage>
<returnCode>200</returnCode>
</baseMessage>
<payload>
<returnCode>0</returnCode>
<shoeboxItem>
<shoeboxImageCount>2</shoeboxImageCount>
<shoeboxImages>
<shoeboxImage>
<name>receiptImage.jpg</name>
</shoeboxImage>
<shoeboxImage>
<name>receiptImage.jpg</name>
</shoeboxImage>
</shoeboxImages>
</shoeboxItem>
</payload>
</attachReceipt>
Expected Output:
<attachReceipt>
<baseMessage>
<returnCode>200</returnCode>
</baseMessage>
<payload>
<returnCode>0</returnCode>
<shoeboxItem>
<shoeboxImageCount>2</shoeboxImageCount>
<shoeboxImages>
<name>receiptImage.jpg</name>
<name>receiptImage.jpg</name>
</shoeboxImages>
</shoeboxItem>
</payload>
</attachReceipt>
Need some xslt code snippet to do this.
I don't have the necessary software installed to actually test this, but this should work:
<xsl:template match="shoeboxImage">
<xsl:apply-templates select="*|text()"/>
</xsl:template>
The idea is that when a shoeboxImage element is encountered, it generates nothing for the element itself, and just continues with its children.
You need to have an identity template and a template that will remove the element shoeboxImage but will retain its descendants.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<!-- identity template -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- template override for the element shoeboxImage -->
<xsl:template match="shoeboxImage">
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>

How change a Node Position using XSLT

I have a problem with the XML Web response i am getting. The Inner Loop warehouseItems have a node leadTimeCumulative and leadTimeDays coming on the first and Second Position for the FIrst time, for the Rest its coming last. I need to keep these node always in the Last position in side the Loop.
Example
<Envelope>
<Body>
<searchItemResponse>
<status>
<statusCode>Success</statusCode>
</status>
<itemList>
<itemWithWarehouses>
<item>
<originOfData>SME</originOfData>
<itemNumbers>
<shortNumber>115632</shortNumber>
<tssArticleNumber>PT0401450-T46N</tssArticleNumber>
</item>
<warehouseItems>
<leadTimeCumulative>14</leadTimeCumulative>
<leadTimeDays>14</leadTimeDays>
<warehouse>
<code>GA01</code>
</warehouse>-
<stockItem>-
<quantities>
<quantityAvailable>0</quantityAvailable>
<quantityOnHand>0</quantityOnHand>
</quantities>
</stockItem>-
<stockClass>
<group>MTO</group>
</stockClass>
</warehouseItems>-
<warehouseItems>-
<warehouse>
<code>GL01</code>
</warehouse>-
<stockItem>-
<quantities>
<quantityAvailable>0</quantityAvailable>
<quantityOnHand>0</quantityOnHand>
</quantities>
</stockItem>-
<stockClass>
<group>MTO</group>
</stockClass>
<leadTimeCumulative>14</leadTimeCumulative>
<leadTimeDays>14</leadTimeDays>
</warehouseItems>-
<warehouseItems>-
<warehouse>
<code>GS01</code></warehouse>-
<stockItem>-
<quantities>
<quantityAvailable>0</quantityAvailable>
<quantityOnHand>0</quantityOnHand>
</quantities>
</stockItem>-
<stockClass>
<group>MTO</group>
</stockClass>
<leadTimeCumulative>10</leadTimeCumulative>
<leadTimeDays>10</leadTimeDays>
</warehouseItems>-
</itemWithWarehouses>
</itemList>
</searchItemResponse>
</Body>
</Envelope>
I need any XSLT for changing the position of the node leadTimeCumulative and leadTimeDays to the Last like the rest of the Loop Structure. Please help me.
The above part is solved.
I need an improvement along with this.The tssArticleNumber node need to copy to the respective warehouse items with a different node name like "Item No". Please give me another XSLT for this. Thanks
try the following stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- this is called an identity template -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- a template to override warehouseItems -->
<xsl:template match="warehouseItems">
<xsl:copy>
<!-- apply templates except leadTimeCumulative and leadTimeDays -->
<xsl:apply-templates select="node()[not(self::leadTimeCumulative) and not(self::leadTimeDays)]|#*"/>
<Item_No><xsl:value-of select="../item//tssArticleNumber"/></Item_No>
<xsl:apply-templates select="leadTimeCumulative"/>
<xsl:apply-templates select="leadTimeDays"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

Need to move PI to inside the root element

I have an xml file that starts with processing instruction at the top. So, I need to replace this PI('?change' not '?xml') to inside the root element. I mean below scenario is the original and look at the PI
<?xml version="1.0" encoding="UTF-8"?>
<?change id="69817" type="addition" mark="start"?>
<part id="PARTIII">
<title><p just="center" fli="0" li="0" ri="0" before="1" after="1">PART 3</p>
<p fli="0" li="0" ri="0" just="center" before="0"><font size="normal" smallcaps="yes">Mergers and Acquisitions</font></p></title>
<div class="annotations">
So, I need to move the first PI(change) that is before root element to inside the root element. How i can achieve this. Any help?
I mean the above code should be(look at the PI 'change')
<?xml version="1.0" encoding="UTF-8"?>
<part id="PARTIII"><?change id="69817" type="addition" mark="start"?>
<title><p just="center" fli="0" li="0" ri="0" before="1" after="1">PART 3</p>
<p fli="0" li="0" ri="0" just="center" before="0"><font size="normal" smallcaps="yes">Mergers and Acquisitions</font></p></title>
<div class="annotations">
try the following stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="processing-instruction()[following-sibling::part]"/>
<xsl:template match="part">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:copy-of select="preceding-sibling::processing-instruction()"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

XSLT 1.0 text nodes printing by default

I have looked at XSL xsl:template match="/" but the match pattern that triggered my question is not mentioned there.
I have a rather complex XML structure:
<?xml version="1.0" encoding="UTF-8"?>
<MATERIAL_DATA>
<LOG>
<USER>Peter</USER>
<DATE>2011-02-18</DATE>
<MATERIALS>
<item>
<MATNR>636207</MATNR>
<TEXTS>
<item>
<TEXT>granola bar 40gx24</TEXT>
</item>
</TEXTS>
<PRICES>
<item>
<MATNR>636207</MATNR>
<COST>125.78</COST>
</item>
</PRICES>
<SALESPRICES>
<item>
<B01>
<MATNR>636207</MATNR>
<CURR>CZK</CURR>
<DATBI>9999-12-31</DATBI>
<DATAB>2010-10-05</DATAB>
</B01>
<B02>
<item>
<PRICE>477.60</PRICE>
<KUNNR>234567</KUNNR>
</item>
</B02>
</item>
</SALESPRICES>
</item>
</MATERIALS>
</LOG>
</MATERIAL_DATA>
Now if I apply the following XSLT, my output looks correct:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" encoding="UTF-8"/>
<xsl:template match="node() | #*">
<xsl:apply-templates select="* | #*" />
</xsl:template>
<xsl:template match="B02">
<xsl:element name="Mi">
<xsl:value-of select="item/KUNNR"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I get the output:
<?xml version="1.0" encoding="UTF-8"?>
<Mi>234567</Mi>
But if I apply the XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" encoding="UTF-8"/>
<xsl:template match="/*">
<xsl:element name="MenuItems">
<xsl:apply-templates select="LOG/MATERIALS/item/SALESPRICES/item"/>
</xsl:element>
</xsl:template>
<xsl:template match="B02">
<xsl:element name="Mi">
<xsl:value-of select="item/KUNNR"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
the output looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<MenuItems>
636207
CZK
9999-12-31
2010-10-05
<Mi>234567</Mi>
</MenuItems>
All values from the element <B01> are in the output! But why - I am not matching <B01>!?
How does
<xsl:template match="node() | #*">
<xsl:apply-templates select="* | #*" />
</xsl:template>
make the output come out correctly? All I am doing with this is match all nodes or attributes and apply-templates to everything or all attributes.
But in my opinion it should not make a difference to when I exactly match <B01>!
Why is this happening?
XSLT includes the following default templates (among others):
<!-- applies to both element nodes and the root node -->
<xsl:template match="*|/">
<xsl:apply-templates/>
</xsl:template>
<!-- copies values of text and attribute nodes through -->
<xsl:template match="text()|#*">
<xsl:value-of select="."/>
</xsl:template>
In your first stylesheet you're implicitly matching all text nodes with node(), thus overriding the default action. Then, in the B2 template, you output your target value and apply no further templates, which stops processing.
In the second stylesheet, you explicitly apply templates to all children of LOG/MATERIALS/item/SALESPRICES/item, causing the default templates to process the nodes you don't explicitly handle. Because you explicitly handle B2 without applying templates to its children, the default templates are never invoked for those nodes. But the default templates are applied to the children of B1.
Adding the following template to your second stylesheet would override the default action for text nodes:
<xsl:template match="text()|#*"></xsl:template>
With the following result:
<?xml version="1.0" encoding="UTF-8"?>
<MenuItems><Mi>234567</Mi></MenuItems>
More:
http://www.w3.org/TR/xslt#built-in-rule
Looks like you are running into the built in template rules.
Specifically the text rule - this will copy text nodes if not overridden.