Where is the model instance for a Django SimplyLazyObject instance? - django

Question

I want to see the model instance corresponding to a SimplyLazyObject that I'm getting so I can print it's __dict__. How can I find the model instance?
e.g.,
ipdb> user
<django.utils.functional.SimpleLazyObject object at 0x10c84d150>

Answer 1

The _wrapped attribute of the SimplyLazyObject instance contains the model instance.
e.g.,
ipdb> user
<django.utils.functional.SimpleLazyObject object at 0x10c84d150>
ipdb> pp(user.__dict__)
{'_setupfunc': <function <lambda> at 0x10c846938>,
'_wrapped': <User: foo#bednark.com>}
ipdb> user._wrapped
<User: foo#bednark.com>
ipdb> type(user._wrapped)
<class 'django.contrib.auth.models.User'>
ipdb> pp(user._wrapped.__dict__)
{'_profile_cache': <UserProfile: foo#bednark.com>,
'_state': <django.db.models.base.ModelState object at 0x10c869290>,
'_username': u'4qInglEqb3HzIFMEuo1H4WkR-HXbWI',
'date_joined': datetime.datetime(2013, 7, 29, 0, 53, 5, 545109),
'email': u'foo#bednark.com',
'first_name': u'Rob',
'id': 24,
'is_active': True,
'is_staff': False,
'is_superuser': False,
'last_login': datetime.datetime(2013, 7, 29, 0, 53, 23, 739774),
'last_name': u'Bednark',
'password': u'pbkdf2_sha256$10000$a1pAQhQuJ2Ng$79CDBtDYWsBxnxShXUSPOTNUVj63cDpaocay6BNzfRs=',
'username': u'foo#bednark.com'}