Can we inherit from Qt containers? - c++

Are we supposed to be able to inherit from Qt containers such as QList, QVector or QMap in order to specialize them and add functionality? If so, what do we need to do in order to be sure that the container works correctly (virtual methods, virtual destructor etc..?). If not, why not and what other options do I have?

Both, STL and Qt Containers opt for non virtual destructors.
There is an interesting discussion why this is, and why its not fixed with Qt5.
QList has no virtual destructor, but is inherited from http://qt-project.org/forums/viewthread/16416
Also, note further differences between STL style and Qt containers. Quoting Jens Weller in his Blog post An introduction into Qt:
Still, there is an important difference between Qt containers and STL containers: Qt containers have value semantics, and will only perform copy on write, while a std container will copy its full contents when copied. This behavoir accounts for most of Qt base classes, that they will only create a new instance for data, when needed. This implicit sharing of resources is a very important concept to understand when dealing with Qt and its containers.
Your options are as always:
composition
E.g.
struct MyFancyList
{
QList<MyType> _data;
bool frobnicate() { return true; }
};
free functions
E.g. extend QList with non-member operations:
template <typename> bool frobnicate(QList<T>& list)
{
// your algorithm
return true;
}
If you really wanted to do funcky stuff, like create an implicit conversion or overload a member operator, you could resort to expression templates.
Update: the latter is also the approach taken by QStringBuilder in new versions. See
Lecture: Expression Templates (video, slides) by Volker Krause
Bonus
For fun, here's a (bad!) illustration of how you could use expression templates to extend the interface of std::stack<T>. See it Live on Coliru or ideone
As we all know, std::stack doesn't model a sequential container, and therefore doesn't have begin(), end(), or operator[] defined. With a bit of hackery, we can define a eDSL to provide these features, without composition or inheritance.
To really drive the point home that you can 'overload' behaviour of the wrapped class in essential ways, we'll make it so that you can implicitly convert the result of extend(stack)[n] to a std::string, even if the stack contains e.g. int.
#include <string>
#include <stack>
#include <stdexcept>
namespace exprtemplates
{
template <typename T> struct stack_indexer_expr
{
typedef std::stack<T> S;
S& s;
std::size_t n;
stack_indexer_expr(S& s, std::size_t n) : s(s), n(n) {}
operator T() const {
auto i = s.size()-n; // reverse index
for (auto clone = s; !clone.empty(); clone.pop())
if (0 == --i) return clone.top();
throw std::range_error("index out of bounds in stack_indexer_expr");
}
operator std::string() const {
// TODO use `boost::lexical_cast` to allow wider range of T
return std::to_string(this->operator T());
}
};
template <typename T> struct stack_expr
{
typedef std::stack<T> S;
S& s;
stack_expr(S& s) : s(s) {}
stack_indexer_expr<T> operator[](std::size_t n) const {
return { s, n };
}
};
}
Now all we have to do is seed our expression templates. We'll use a helper function that wraps any std::stack:
template <typename T>
exprtemplates::stack_expr<T> extend(std::stack<T>& s) { return { s }; }
Ideally, our users never realize the exact types inside exprtemplates namespace:
#include <iostream>
int main()
{
std::stack<double> s;
s.push(0.5);
s.push(0.6);
s.push(0.7);
s.push(0.8);
std::string demo = extend(s)[3];
std::cout << demo << "\n";
}
Voila. More craziness:
auto magic = extend(s);
std::cout << magic[0] << "\n";
std::cout << magic[1] << "\n";
std::cout << magic[2] << "\n";
std::cout << magic[3] << "\n";
double as_double = magic[0];
std::string as_string = magic[0];
Prints
0.5
0.6
0.7
0.8
DISCLAIMERS
I know std::stack has a restrictive interface for a reason.
I know that my indexing implementation has horrific efficiency.
I know that implicit conversions are evil. This is just a contrived example.
In real life, use Boost::Proto to get a DSL going. There are many pitfalls and gotchas in doing all the mechanics by hand.
Look at QStringBuilder for a more real life sample.

Related

Can static polymorphism (templates) be used despite type erasure?

Having returned relatively recently to C++ after decades of Java, I am currently struggling with a template-based approach to data conversion for instances where type erasure has been applied. Please bear with me, my nomenclature may still be off for C++-natives.
This is what I am trying to achieve:
Implement dynamic variables which are able to hold essentially any value type
Access the content of those variables using various other representations (string, ints, binary, ...)
Be able to hold variable instances in containers, independent of their value type
Convert between variable value and representation using conversion functions
Be able to introduce new representations just by providing new conversion functions
Constraints: use only C++-11 features if possible, no use of libraries like boost::any etc.
A rough sketch of this might look like this:
#include <iostream>
#include <vector>
void convert(const std::string &f, std::string &t) { t = f; }
void convert(const int &f, std::string &t) { t = std::to_string(f); }
void convert(const std::string &f, int &t) { t = std::stoi(f); }
void convert(const int &f, int &t) { t = f; }
struct Variable {
virtual void get(int &i) = 0;
virtual void get(std::string &s) = 0;
};
template <typename T> struct VariableImpl : Variable {
T value;
VariableImpl(const T &v) : value{v} {};
void get(int &i) { convert(value, i); };
void get(std::string &s) { convert(value, s); };
};
int main() {
VariableImpl<int> v1{42};
VariableImpl<std::string> v2{"1234"};
std::vector<Variable *> vars{&v1, &v2};
for (auto &v : vars) {
int i;
v->get(i);
std::string s;
v->get(s);
std::cout << "int representation: " << i <<
", string representation: " << s << std::endl;
}
return 0;
}
The code does what it is supposed to do, but obvoiusly I would like to get rid of Variable::get(int/std::string/...) and instead template them, because otherwise every new representation requires a definition and an implementation with the latter being exactly the same as all the others.
I've played with various approaches so far, like virtual templated, methods, applying the CRDT with intermediate type, various forms of wrappers, yet in all of them I get bitten by the erased value type of VariableImpl. On one hand, I think there might not be a solution, because after type erasure, the compiler cannot possibly know what templated getters and converter calls it must generate. On the other hand I think i might be missing something really essential here and there should be a solution despite the constraints mentioned above.
This is a classical double dispatch problem. The usual solution to this problem is to have some kind of dispatcher class with multiple implementations of the function you want to dispatch (get in your case). This is called the visitor pattern. The well-known drawback of it is the dependency cycle it creates (each class in the hierarchy depends on all other classes in the hierarchy). Thus there's a need to revisit it each time a new type is added. No amount of template wizardry eliminates it.
You don't have a specialised Visitor class, your Variable serves as a Visitor of itself, but this is a minor detail.
Since you don't like this solution, there is another one. It uses a registry of functions populated at run time and keyed on type identification of their arguments. This is sometimes called "Acyclic Visitor".
Here's a half-baked C++11-friendly implementation for your case.
#include <map>
#include <vector>
#include <typeinfo>
#include <typeindex>
#include <utility>
#include <functional>
#include <string>
#include <stdexcept>
struct Variable
{
virtual void convertValue(Variable& to) const = 0;
virtual ~Variable() {};
virtual std::type_index getTypeIdx() const = 0;
template <typename K> K get() const;
static std::map<std::pair<std::type_index, std::type_index>,
std::function<void(const Variable&, Variable&)>>
conversionMap;
template <typename T, typename K>
static void registerConversion(K (*fn)(const T&));
};
template <typename T>
struct VariableImpl : Variable
{
T value;
VariableImpl(const T &v) : value{v} {};
VariableImpl() : value{} {}; // this is needed for a declaration of
// `VariableImpl<K> below
// It can be avoided but it is
// a story for another day
void convertValue(Variable& to) const override
{
auto typeIdxFrom = getTypeIdx();
auto typeIdxTo = to.getTypeIdx();
if (typeIdxFrom == typeIdxTo) // no conversion needed
{
dynamic_cast<VariableImpl<T>&>(to).value = value;
}
else
{
auto fcnIter = conversionMap.find({getTypeIdx(), to.getTypeIdx()});
if (fcnIter != conversionMap.end())
{
fcnIter->second(*this, to);
}
else
throw std::logic_error("no conversion");
}
}
std::type_index getTypeIdx() const override
{
return std::type_index(typeid(T));
}
};
template <typename K> K Variable::get() const
{
VariableImpl<K> vk;
convertValue(vk);
return vk.value;
}
template <typename T, typename K>
void Variable::registerConversion(K (*fn)(const T&))
{
// add a mutex if you ever spread this over multiple threads
conversionMap[{std::type_index(typeid(T)), std::type_index(typeid(K))}] =
[fn](const Variable& from, Variable& to) {
dynamic_cast<VariableImpl<K>&>(to).value =
fn(dynamic_cast<const VariableImpl<T>&>(from).value);
};
}
Now of course you need to call registerConversion e.g. at the beginning of main and pass it each conversion function.
Variable::registerConversion(int_to_string);
Variable::registerConversion(string_to_int);
This is not ideal, but hardly anything is ever ideal.
Having said all that, I would recommend you revisit your design. Do you really need all these conversions? Why not pick one representation and stick with it?
Implement dynamic variables which are able to hold essentially any value type
Be able to hold variable instances in containers, independent of their value type
These two requirements are quite challenging on its own. The class templates don't really encourage inheritance, and you already did the right thing to hold what you asked for: introduced a common base class for the class template, which you can later refer to in order to store pointers of the said type in a collection.
Access the content of those variables using various other representations (string, ints, binary, ...)
Be able to introduce new representations just by providing new conversion functions
This is where it breaks. Function templates assume common implementation for different types, while inheritance assumes different implementation for the same types.
You goal is to introduce different implementation for different types, and in order to make your requirements viable you have to switch to one of those two options instead (or put up with a number of functions for each case which you have already introduced yourself)
Edit:
One of the strategies you may employ to enforce inheritance approach is generalisation of the arguments to the extent where they can be used interchangeably by the abstract interface. E.g. you may wrap the converting arguments inside of a union like this:
struct Variable {
struct converter_type {
enum { INT, STRING } type;
union {
int* m_int;
std::string* m_string;
};
};
virtual void get(converter_type& var) = 0;
virtual ~Variable() = default;
};
And then take whatever part of it inside of the implementation:
void get(converter_type& var) override {
switch (var.type) {
case converter_type::INT:
convert(value, var.m_int);
break;
case converter_type::STRING:
convert(value, var.m_string);
break;
}
}
To be honest I don't think this is a less verbose approach compared to just having a number of functions for each type combination, but i think you got the idea that you can just wrap your arguments somehow to cement the abstract class interface.
Implement std::any. It is similar to boost::any.
Create a conversion dispatcher based off typeids. Store your any alongside the conversion dispatcher.
"new conversion functions" have to be passed to the dispatcher.
When asked to convert to a type, pass that typeid to the dispatcher.
So we start with these 3 types:
using any = std::any; // implement this
using converter = std::function<any(any const&)>;
using convert_table = std::map<std::type_index, converter>;
using convert_lookup = convert_table(*)();
template<class T>
convert_table& lookup_convert_table() {
static convert_table t;
return t;
}
struct converter_any: any {
template<class T,
typename std::enable_if<
!std::is_same<typename std::decay<T>::type, converter_any>::value, bool
>::type = true
>
converter_any( T&& t ):
any(std::forward<T>(t)),
table(&lookup_convert_table<typename std::decay<T>::type>())
{}
converter_any(converter_any const&)=default;
converter_any(converter_any &&)=default;
converter_any& operator=(converter_any const&)=default;
converter_any& operator=(converter_any&&)=default;
~converter_any()=default;
converter_any()=default;
convert_table const* table = nullptr;
template<class U>
U convert_to() const {
if (!table)
throw 1; // make a better exception than int
auto it = table->find(typeid(U));
if (it == table->end())
throw 2; // make a better exception than int
any const& self = *this;
return any_cast<U>((it->second)(self));
}
};
template<class Dest, class Src>
bool add_converter_to_table( Dest(*f)(Src const&) ) {
lookup_convert_table<Src>()[typeid(Dest)] = [f](any const& s)->any {
Src src = std::any_cast<Src>(s);
auto r = f(src);
return r;
};
return true;
}
now your code looks like:
const bool bStringRegistered =
add_converter_to_table(+[](std::string const& f)->std::string{ return f; })
&& add_converter_to_table(+[](std::string const& f)->int{ return std::stoi(f); });
const bool bIntRegistered =
add_converter_to_table(+[](int const& i)->int{ return i; })
&& add_converter_to_table(+[](int const& i)->std::string{ return std::to_string(i); });
int main() {
converter_any v1{42};
converter_any v2{std::string("1234")};
std::vector<converter_any> vars{v1, v2}; // copies!
for (auto &v : vars) {
int i = v.convert_to<int>();
std::string s = v.convert_to<std::string>();
std::cout << "int representation: " << i <<
", string representation: " << s << std::endl;
}
}
live example.
...
Ok, what did I do?
I used any to be a smart void* that can store anything. Rewriting this is a bad idea, use someone else's implementation.
Then, I augmented it with a manually written virtual function table. Which table I add is determined by the constructor of my converter_any; here, I know the type stored, so I can store the right table.
Typically when using this technique, I'd know what functions are in there. For your implementation we do not; so the table is a map from the type id of the destination, to a conversion function.
The conversion function takes anys and returns anys -- again, don't repeat this work. And now it has a fixed signature.
To add support for a type, you independently register conversion functions. Here, my conversion function registration helper deduces the from type (to determine which table to register it in) and the destination type (to determine which entry in the table), and then automatically writes the any boxing/unboxing code for you.
...
At a higher level, what I'm doing is writing my own type erasure and object model. C++ has enough power that you can write your own object models, and when you want features that the default object model doesn't solve, well, roll a new object model.
Second, I'm using value types. A Java programmer isn't used to value types having polymorphic behavior, but much of C++ works much better if you write your code using value types.
So my converter_any is a polymorphic value type. You can store copies of them in vectors etc, and it just works.

shared_ptr<T> to shared_ptr<T const> and vector<T> to vector<T const>

I'm trying to define a good design for my software which implies being careful about read/write access to some variables. Here I simplified the program for the discussion. Hopefully this will be also helpful to others. :-)
Let's say we have a class X as follow:
class X {
int x;
public:
X(int y) : x(y) { }
void print() const { std::cout << "X::" << x << std::endl; }
void foo() { ++x; }
};
Let's also say that in the future this class will be subclassed with X1, X2, ... which can reimplement print() and foo(). (I omitted the required virtual keywords for simplicity here since it's not the actual issue I'm facing.)
Since we will use polymorphisme, let's use (smart) pointers and define a simple factory:
using XPtr = std::shared_ptr<X>;
using ConstXPtr = std::shared_ptr<X const>;
XPtr createX(int x) { return std::make_shared<X>(x); }
Until now, everything is fine: I can define goo(p) which can read and write p and hoo(p) which can only read p.
void goo(XPtr p) {
p->print();
p->foo();
p->print();
}
void hoo(ConstXPtr p) {
p->print();
// p->foo(); // ERROR :-)
}
And the call site looks like this:
XPtr p = createX(42);
goo(p);
hoo(p);
The shared pointer to X (XPtr) is automatically converted to its const version (ConstXPtr). Nice, it's exactly what I want!
Now come the troubles: I need a heterogeneous collection of X. My choice is a std::vector<XPtr>. (It could also be a list, why not.)
The design I have in mind is the following. I have two versions of the container: one with read/write access to its elements, one with read-only access to its elements.
using XsPtr = std::vector<XPtr>;
using ConstXsPtr = std::vector<ConstXPtr>;
I've got a class that handles this data:
class E {
XsPtr xs;
public:
E() {
for (auto i : { 2, 3, 5, 7, 11, 13 }) {
xs.emplace_back(createX(std::move(i)));
}
}
void loo() {
std::cout << "\n\nloo()" << std::endl;
ioo(toConst(xs));
joo(xs);
ioo(toConst(xs));
}
void moo() const {
std::cout << "\n\nmoo()" << std::endl;
ioo(toConst(xs));
joo(xs); // Should not be allowed
ioo(toConst(xs));
}
};
The ioo() and joo() functions are as follow:
void ioo(ConstXsPtr xs) {
for (auto p : xs) {
p->print();
// p->foo(); // ERROR :-)
}
}
void joo(XsPtr xs) {
for (auto p: xs) {
p->foo();
}
}
As you can see, in E::loo() and E::moo() I have to do some conversion with toConst():
ConstXsPtr toConst(XsPtr xs) {
ConstXsPtr cxs(xs.size());
std::copy(std::begin(xs), std::end(xs), std::begin(cxs));
return cxs;
}
But that means copying everything over and over.... :-/
Also, in moo(), which is const, I can call joo() which will modify xs's data. Not what I wanted. Here I would prefer a compilation error.
The full code is available at ideone.com.
The question is: is it possible to do the same but without copying the vector to its const version? Or, more generally, is there a good technique/pattern which is both efficient and easy to understand?
Thank you. :-)
I think the usual answer is that for a class template X<T>, any X<const T> could be specialized and therefore the compiler is not allow to simply assume it can convert a pointer or reference of X<T> to X<const T> and that there is not general way to express that those two actually are convertible. But then I though: Wait, there is a way to say X<T> IS A X<const T>. IS A is expressed via inheritance.
While this will not help you for std::shared_ptr or standard containers, it is a technique that you might want to use when you implement your own classes. In fact, I wonder if std::shared_ptr and the containers could/should be improved to support this. Can anyone see any problem with this?
The technique I have in mind would work like this:
template< typename T > struct my_ptr : my_ptr< const T >
{
using my_ptr< const T >::my_ptr;
T& operator*() const { return *this->p_; }
};
template< typename T > struct my_ptr< const T >
{
protected:
T* p_;
public:
explicit my_ptr( T* p )
: p_(p)
{
}
// just to test nothing is copied
my_ptr( const my_ptr& p ) = delete;
~my_ptr()
{
delete p_;
}
const T& operator*() const { return *p_; }
};
Live example
There is a fundamental issue with what you want to do.
A std::vector<T const*> is not a restriction of a std::vector<T*>, and the same is true of vectors containing smart pointers and their const versions.
Concretely, I can store a pointer to const int foo = 7; in the first container, but not the second. std::vector is both a range and a container. It is similar to the T** vs T const** problem.
Now, technically std::vector<T const*> const is a restriction of std::vector<T>, but that is not supported.
A way around this is to start workimg eith range views: non owning views into other containers. A non owning T const* iterator view into a std::vector<T *> is possible, and can give you the interface you want.
boost::range can do the boilerplate for you, but writing your own contiguous_range_view<T> or random_range_view<RandomAccessIterator> is not hard. It gets fancy ehen you want to auto detect the iterator category and enable capabilities based off that, which is why boost::range contains much more code.
Hiura,
I've tried to compile your code from repo and g++4.8 returned some errors.
changes in main.cpp:97 and the remaining lines calling view::create() with lambda function as the second argument.
+add+
auto f_lambda([](view::ConstRef_t<view::ElementType_t<Element>> const& e) { return ((e.getX() % 2) == 0); });
std::function<bool(view::ConstRef_t<view::ElementType_t<Element>>)> f(std::cref(f_lambda));
+mod+
printDocument(view::create(xs, f));
also View.hpp:185 required additional operator, namely:
+add+
bool operator==(IteratorBase const& a, IteratorBase const& b)
{
return a.self == b.self;
}
BR,
Marek Szews
Based on the comments and answers, I ended up creating a views for containers.
Basically I defined new iterators. I create a project on github here: mantognini/ContainerView.
The code can probably be improved but the main idea is to have two template classes, View and ConstView, on an existing container (e.g. std::vector<T>) that has a begin() and end() method for iterating on the underlying container.
With a little bit of inheritance (View is a ConstView) it helps converting read-write with to read-only view when needed without extra code.
Since I don't like pointers, I used template specialization to hide std::shared_ptr: a view on a container of std::shared_ptr<T> won't required extra dereferencing. (I haven't implemented it yet for raw pointers since I don't use them.)
Here is a basic example of my views in action.

How do I iterate over collections generically in C++?

Simply put, if I have a set and vector how do I create a generic method that can handle both as params.
All I want to do, is iterate over either types of collections. Sounds like it should be trivial but I'm missing something.
void printMeSomeStrings(somebaseclass<string> strings) {
for (auto& str : strings) {
cout << str << endl;
}
}
In C#, I would pass IEnumerable or something like that. Then I could iterate over the collection.
Any general reading explaining the answer would be appreciated.
You could use templates. For instance:
#include <iostream>
template<typename C>
void foo(C const& c)
{
std::cout << "{ ";
for (auto const& x : c)
{
std::cout << x << " ";
}
std::cout << "}";
}
And here is how you would use it:
#include <set>
#include <vector>
int main()
{
std::vector<int> v = {1, 2, 3};
foo(v);
std::cout << std::endl;
std::set<std::string> s = {"Hello,", "Generic", "World!"};
foo(s);
}
Live example.
This is exactly what iterators were designed for.
template <class It>
void print_some_strings(It first, It last) {
while (first != last)
std::cout << *first++ << '\n';
}
The first option is to put the code doing the iterating in a template. This requires exposing the implementation to everyone who uses it, which has disadvantages.
Basically, take a type C as a template parameter, then write your code in terms of that type C.
template<typename C>
void printMeSomeStrings(C&& strings) {
for (auto const& str : strings) {
cout << str << endl;
}
}
If you want to be able to have a strong barrier between interface and implementation, the C++11 approach would be to engage in type erasure on a for-iterable container, and then expose a for-iterable container, like how std::function works.
This is trickier. I personally find writing a for_each function easier than writing a full blown iteration adapter. If you want the full blown container iteration type erasure object, start with boost, or ask me below and I might do it.
The for_each adaptor is easy, however.
#include <functional>
#include <utility>
#include <iterator>
#include <memory>
template<typename T>
struct for_each_helper_interface {
virtual ~for_each_helper_interface() {}
virtual void for_each( std::function< void(T) > const& ) = 0;
};
template<typename C, typename T>
struct for_each_helper:for_each_helper_interface<T> {
C& c;
for_each_helper( C& in ):c(in) {}
virtual void for_each( std::function< void(T) > const& f ) override final {
for( auto&& x:c ) {
f(x);
}
}
};
template<typename T>
struct for_each_adaptor {
std::unique_ptr<for_each_helper_interface<T>> pImpl;
void for_each( std::function< void(T) > const& f ) {
if (pImpl) {
pImpl->for_each(f);
}
}
template<typename C>
for_each_adaptor( C&& c ): pImpl( new for_each_helper<C, T>( std::forward<C>(c) ) ) {}
};
which will type-erase the container of T (or a type convertible to T!) and expose a for_each method that lets you iterate over the contents of the container. Use like this:
#include <set>
#include <iostream>
#include <vector>
void print_stufF( for_each_adaptor<std::string const&> c ) {
c.for_each([&](std::string const&s){
std::cout << s << "\n";
});
}
int main() {
std::set<std::string> s;
s.insert("hello");
s.insert("world");
print_stuff(s);
std::vector<std::string> v;
v.push_back("hola");
v.push_back("bola");
print_stuff(v);
}
What is going on here is that for each type used to construct our adaptor, we build a custom implementation of for each. We then store a pointer to the abstract base class of this custom class, and redirect for each calls to it.
This means anything that specializes std::begin or defines its own begin need not be related: we create ad hoc relationships at point of use instead.
Live example: http://ideone.com/xOqBkI
In C#, I would pass IEnumerable or something like that.
C++ uses the more pythonic approach of duck typing to define interfaces(generally called a concept in C++), rather than using inheritance. To do duck typing in C++, you use a template function like this:
template<typename C>
void printMeSomeStrings(const C& strings)
{
for (const auto& str : strings)
{
cout << str << endl;
}
}
In python, duck typing is done at runtime, but in C++ it is done at compile time, so there is no runtime cost to duck typing, and everything is checked at compile time as well.
Here is more info about C++, to help with looking for information. First, the equivalent of the IEnumerator<T> is the iterator in C++. Here is a page about the different iterator categories, and what needs to be implemented for iterators. For legacy reasons, iterators are modeled after pointers in C, which lets you use C arrays with the standard C++ algorithms.
However, unlike IEnumerator<T>, iterators must come in pairs. An iterator to the begining and the end(which is one past the last element). So, the equivalent of IEnumerable<T> in C++ is called a range. In C++11, a range is defined by two free functions, begin(T) and end(T)(it can also be implemented as member function .begin() and .end()).
By defining the concept(aka interface) as two free function, as opposed to using inheritance, ranges can be implemented non-intrusively. So for example, if you have work with some legacy api that uses C style linked lists. They can now be adapted as a C++11 range and used inside a C++ for loop.

inheritance and deque of objects in C++

I have multiple controls organized like this:
deque<wxTextCtrl*> dequeEdit;
deque<wxStaticText*> dequeText;
deque<wxComboBox*> dequeCombo;
All these controls inherit from wxWindow which has mathod Show. I'd like to show (or hide) whole deque at once, without the need of multiple methods for each deque. How could it be done?
I was thinking about making deque of wxWindow for each control, so I could write method
ShowDeque(deque<wxWindow*> deque)
so showing would be easy, but on the other hand, if I'd like to work with e.g. combobox, I'd have to type it back to wxComboBox.
Are there any other possibilites? Thanks.
Use:
for_each(dequeEdit.begin(), dequeEdit.end(), mem_fun(&wxWindow::Show));
Same for any other deques.
Or encapsulate in one function:
template <class Deque>
void showAll(const Deque& dequeObj)
{
using namespace std;
for_each(dequeObj.begin(), dequeObj.end(), mem_fun(&wxWindow::Show));
}
showAll(dequeEdit);
std::for_each: http://en.cppreference.com/w/cpp/algorithm/for_each
std::mem_fun: http://en.cppreference.com/w/cpp/utility/functional/mem_fn
If it's a simple method make it a template:
template <typename WxT>
void ShowDeque(std::deque<WxT*> &d) { ... }
or better, use iterators to abstract out the container type:
template <typename WxIter>
void ShowDeque(WxIter begin, WxIter end) { ... }
or better yet use the standard facilities (Piotr beat me to that one while I was typing!)
You can use a function template.
template <typename T>
void show_all(const std::deque<T*>& d) {
for (typename std::deque<T*>::iterator it=d.begin(); it!=d.end(); ++it)
(*it)->Show();
}
You can then call it like a normal function.
deque<wxTextCtrl*> dequeEdit;
deque<wxStaticText*> dequeText;
deque<wxComboBox*> dequeCombo;
show_all(dequeEdit);
show_all(dequeText);
show_all(dequeCombo);
With a function template you can even make show_all independent of the container you use by adding an additional template argument.
template <typename C, typename T>
void show_all(const C<T*>& d) {
for (typename C<T*>::iterator it=d.begin(); it!=d.end(); ++it)
(*it)->Show();
}
C can then be any STL container, or even any container which supports the same iterator interface.
I came across this question when looking for how to use inheritance of iterators and deque.
The answer's does not give a complete answer related to inheritance, so I will add following:
Let say you have a class and you want this class to have the ability to have a deque inside, in other words to inherit the ability to control a deque container.
Example :
template<typename ElementType>
class myQueOfElements : public deque<ElementType>
{
ElementType placeholder;
myQueOfElements& operator=(unsigned char* rvalue)
{
unsigned char* ptrToNextElement = (unsigned char*)rvalue;
placeholder = ptrToNextElement; // make sure ElementType has its own assignment operator=
push_back(placeholder); // First element
//TODO: Iterate thru the binary and push_back the fetched elements
return *this;
}
};
// How to use:
myQueOfElements<myElementTypeClass> testQue;
testQue = (unsigned char*)&blob[0]; // address to binary data, will be parsed in the assignment operator=
// make sure it has same structure as the ElementType (myElementTypeClass)
// fetch all myElementTypeClass object(s) from the myQueOfElements
for (auto e : testQue) {
std::string strName = e.Name;
std::out << "Element : " << strName.c_str() << endl;
}

Policy-based template design: How to access certain policies of the class?

I have a class that uses several policies that are templated. It is called Dish in the following example. I store many of these Dishes in a vector (using a pointer to simple base class), but then I'd like to extract and use them. But I don't know their exact types.
Here is the code; it's a bit long, but really simple:
#include <iostream>
#include <vector>
struct DishBase {
int id;
DishBase(int i) : id(i) {}
};
std::ostream& operator<<(std::ostream& out, const DishBase& d) {
out << d.id;
return out;
}
// Policy-based class:
template<class Appetizer, class Main, class Dessert>
class Dish : public DishBase {
Appetizer appetizer_;
Main main_;
Dessert dessert_;
public:
Dish(int id) : DishBase(id) {}
const Appetizer& get_appetizer() { return appetizer_; }
const Main& get_main() { return main_; }
const Dessert& get_dessert() { return dessert_; }
};
struct Storage {
typedef DishBase* value_type;
typedef std::vector<value_type> Container;
typedef Container::const_iterator const_iterator;
Container container;
Storage() {
container.push_back(new Dish<int,double,float>(0));
container.push_back(new Dish<double,int,double>(1));
container.push_back(new Dish<int,int,int>(2));
}
~Storage() {
// delete objects
}
const_iterator begin() { return container.begin(); }
const_iterator end() { return container.end(); }
};
int main() {
Storage s;
for(Storage::const_iterator it = s.begin(); it != s.end(); ++it){
std::cout << **it << std::endl;
std::cout << "Dessert: " << *it->get_dessert() << std::endl; // ??
}
return 0;
}
The tricky part is here, in the main() function:
std::cout << "Dessert: " << *it->get_dessert() << std::endl; // ??
How can I access the dessert? I don't even know the Dessert type (it is templated), let alone the complete type of the object that I'm getting from the storage.
This is just a toy example, but I think my code reduces to this. I'd just like to pass those Dish classes around, and different parts of the code will access different parts of it (in the example: its appetizer, main dish, or dessert).
What you have is not exactly policy-based design IMO... if it were, your class should've actually implemented (i.e. extended) the policies.
Now, back to your question/example. In your container, you store a "DishBase*". Right? From that point on, you loose any compile-time information wrt the actual type of the objects in the collection. So, I'm afraid what you try to do is provably impossible.
What you could do, is use an actual policy-based design, eg.
template<class Appetizer, class Main, class Dessert>
class Dish : public DishBase, Appetizer, Main, Dessert {
}
Then, you could simply use dynamic_cast to check at runtime that you can convert your object to any concrete Appetizer/Dessert/Main.
But from your description, I get the impression that you actually need abstract base classes (i.e. abstract base classes may be the design that makes sense for you, and not policies).
You will need to have appropriate member functions for querying (in this case an overload for the concrete Dessert type). The policies should expose a way of discovery. Here's a short example:
#include <iostream>
using namespace std;
struct TA { virtual string foo() { return "TA::foo\n"; } };
struct DTA : TA { virtual string foo() { return "DTA::foo\n"; } };
template <class T>
struct C {
T t;
};
template <class T>
ostream& operator <<(ostream& o, C<T> c) {
o << c.t.foo();
return o;
}
int main(int argc, char* argv[])
{
C<DTA> c;
cout << c;
}
My understanding is that policy-based template classes are not very container friendly. I just opt for plain old polymorphism for this kind of things. I'd be interested in a solution though.
EDIT: It's perhaps not by coincidence that I cannot find any usage of stl containers throughout Alexandrescu's "Modern C++ Desing" book.
EDIT2: More details on the friction between polymorphism and genericity can be found here http://www.artima.com/cppsource/type_erasure.html. You container can perhaps be made of boost::any objects?