Pick last item from list in Powershell - list

Question

I'm trying to map a drive letter using this line of code which will give me a list of drives available from d to z.
ls function:[d-z]: -n | ? { !(test-path $_) }
I'd like to then pick the last letter, not random, from the list. How would I go about doing that? New to Powershell, thanks for the help.

Answer 1

You can use Select-Object -Last 1 at the end of that pipeline.

Answer 2

you can just start at the back of the list and go up.
last item: $array[-1]
Second to last: $array[-2]
and so on.

Answer 3

If you look for a much more verbose, but (in my opinion) readable-improved version:
# Get all drives which are used (unavailable)
# Filter for the "Name" property ==> Drive letter
$Drives = (Get-PSDrive -PSProvider FileSystem).Name
# Create an array of D to Z
# Haven't found a more elegant version...
$Letters = [char[]]([char]'D'..[char]'Z')
# Filter out, which $Letters are not in $Drives (<=)
# Again, filter for their letter
$Available = (Compare-Object -ReferenceObject $Letters -DifferenceObject $Drives | Where {$_.SideIndicator -eq "<="}).InputObject
# Get the last letter
$LastLetter = $Available[-1]

Answer 4

Try this:
ls function:[d-z]: -n|?{!(test-path $_)} | Select-Object -Last 1

Answer 5

Another option that doesn't require trying all paths from D-Z is to parse Get-Psdrive. Here's an example:
$lettersInUse = Get-Psdrive | ? { $_.Name.Length -eq 1 } | % { $_.Name }
$lastDriveLetter = [Char]'Z'
while ($lettersInUse -contains $lastDriveLetter) {
$lastDriveLetter = [Char]($lastDriveLetter - 1)
}
$lastDriveLetter

Answer 6

In case you have an array
$newArray = #(git tag --list)
$lastmember = $newArray[$newArray.Count – 1]
In case you have a list
$newArray | Select-Object -Last 1