I have a text file with the following content:
Static Text MachineA MachineB MachineC
Just Another Line
The first line has two static words (Static Text) with a space between. After those two words there are 0 or more computer names, also seperated with a space.
I need to find a way to add text to the first line (second line does not change) if there are 0 computers but also if there is 1 or more computers. I need to replace all computer names with a new computer name. So the script should edit the file to get something like this:
Static Text MachineX MachineY
Just Another Line
I've looked at the -replace function with Regex but can't figure out why it is not working. This is the script I have:
$OptionsFile = "C:\scripts\OptionsFile.txt"
$NewComputers = "MachineX MachineY"
$content = Get-Content $OptionsFile
$content |
ForEach-Object {
if ($_.ReadCount -eq 1) {
$_ -replace '\w+', $NewComputers
} else {
$_
}
} |
Set-Content $OptionsFile
I hope someone can help me out with this.
If Static Text doesn't appear elsewhere in the file, you could simply do this:
$OptionsFile = "C:\scripts\OptionsFile.txt"
$NewComputers = "MachineX MachineY"
(Get-Content $OptionsFile) -replace '^(Static Text) .*', "`$1 $NewComputers" |
Set-Content $OptionsFile
If Static Text can appear elsewhere, and you only want to replace the first line, you could do something like this:
$OptionsFile = "C:\scripts\OptionsFile.txt"
$NewComputers = "MachineX MachineY"
(Get-Content $OptionsFile) | % {
if ($_.ReadCount -eq 1) {
"Static Text $NewComputers"
} else {
$_
}
} | Set-Content $OptionsFile
If you only know that Static Text consists of two words in the first line, but don't know which words exactly they'll be, something like this should work:
$OptionsFile = "C:\scripts\OptionsFile.txt"
$NewComputers = "MachineX MachineY"
(Get-Content $OptionsFile) | % {
if ($_.ReadCount -eq 1) {
$_ -replace '^(\w+ \w+) .*', "`$1 $NewComputers"
} else {
$_
}
} | Set-Content $OptionsFile
Check if a line is starting with a 'Static Text ' followed by a sequence of word characters and return your string in case there a match:
Get-Content $OptionsFile | foreach {
if($_ -match '^Static Text\s+(\w+\s)+')
{
'Static Text MachineX MachineY'
}
else
{
$_
}
}
Related
I have following beggining of a Powershell script in which I would like to replace the values of variables for different enviroment.
$SomeVar1 = "C:\path\to\file\a"
$SomeVar1 = "C:\path\to\file\a" # Copy for test - Should not be rewriten
$SomeVar2 = "C:\path\to\file\b"
# Note $SomeVar1 = "C:\path\to\file\a" - Should not be rewriten
When I run the rewrite script, the result should look like this:
$SomeVar1 = "F:\different\path\to\file\a"
$SomeVar1 = "C:\path\to\file\a" # Copy for test - Should not be rewrite
$SomeVar2 = "F:\different\path\to\file\b"
# Note $SomeVar1 = "C:\path\to\file\a" - Should not be rewriten
Current script that does(n't) rewrite:
$arr = #(
[PSCustomObject]#{Regex = '$SomeVar1 = "'; Replace = '$SomeVar1 = "F:\different\path\to\file\a"'}
[PSCustomObject]#{Regex = '$SomeVar2 = "'; Replace = '$SomeVar1 = "F:\different\path\to\file\b"'}
)
for ($i = 0; $i -lt $arr.Length; $i++) {
$ArrRegex = [Regex]::Escape($arr[$i].Regex)
$ArrReplace = $arr[$i].Replace
# Get full line for replacement
$Line = Get-Content $Workfile | Select-String $ArrRegex | Select-Object -First 1 -ExpandProperty Line
# Rewrite part
$Line = [Regex]::Escape($Line)
$Content = Get-Content $Workfile
$Content -replace "^$Line",$ArrReplace | Set-Content $Workfile
}
This replaces all the occurences in file on the start of the line (and I need only the 1st one) and doest not replace the one in Note which is okay.
Then I found this Powershell: Replace last occurence of a line in a file which does the exact oposite of what I need, only rewrites the last occurence of the string and it does it in the Note aswell and I would somehow like to change it to do the opposite - 1st occurence, line begining (Wont target the Note)
Code in my case looks like this:
# Rewrite part
$Line = [Regex]::Escape($Line)
$Content = Get-Content $Workfile -Raw
$Line = "(?s)(.*)$Line"
$ArrReplace = "`$1$ArrReplace"
$Content -replace $Line,$ArrReplace | Set-Content $Workfile
Do you have any recommendations on how to archive my goal, or is there a more sothisticated way to replace variables for powershell scripts like this?
Thanks in advance.
So I finally figured it out, I had to add Select-String "^$ArrRegex" during $Line creation to exclude any string that were on on line beggining and then use this Regex to do the job: ^(?s)(.*?\n)$Line
In my case it does the following: Only selects 1st occurnece on the beggining of the line and replaces it. It ignores everything else and when re-run, does not rewrite others. The copies of vars will not really exist in final version and will be set once like $Var1 = "Value" and never changed during script, but I wanted to be sure that I won't replace something by mistake.
The final replacing part does look like this:
for ($i = 0; $i -lt $arr.Length; $i++) {
$ArrRegex = [Regex]::Escape($arr[$i].Regex)
$ArrReplace = $arr[$i].Replace
$Line = Get-Content $Workfile | Select-String "^$ArrRegex" | Select-Object -First 1 -ExpandProperty Line
$Line = [Regex]::Escape($Line)
$Line = "^(?s)(.*?\n)$Line"
$ArrReplace = "`$1$ArrReplace"
$Content -replace $Line, $ArrReplace | Set-Content $Workfile
}
You could possibly use flag variables like below to only do the first replacement for each of your regex patterns.
$Altered = Get-Content -Path $Workfile |
Foreach-Object {
if(-not $a) { #If replacement hasn't been done, replace
$_ = $_ -replace 'YOUR_REGEX1','YOUR_REPLACEMENT1'
if($_ -match 'YOUR_REPLACEMENT1') { $a = 'replacement done' } #Set Flag
}
if(-not $b) { #If replacement hasn't been done, replace
$_ = $_ -replace 'YOUR_REGEX2','YOUR_REPLACEMENT2'
if($_ -match 'YOUR_REPLACEMENT2') { $b = 'replacement done' } #Set Flag
}
$_ # Pipe back to $Altered
}
$Altered | Set-Content -Path $WorkFile
Just reverse the RegEx, if that is what you are after:
Clear-Host
#'
abc
abc
abc
'# -replace '^(.*?)\babc\b', '$1HelloWorld'
# Results
<#
HelloWorld
abc
abc
#>
I want to write a powershell script which will convert a string which is present between double quotes in a file, and convert it into upper case.
The files are placed in different folders.
I am able to extract the string between the double quotes and convert it to upper case, but not able to replace it in the correct position.
Ex : This is the input string.
"e" //&&'i&&
The output should be
"E" //&&'i&&
This is what i have tried. Also this even i not replacing the content of the file.
$items = Get-ChildItem * -recurse
# enumerate the items array
foreach ($item in $items)
{
# if the item is a directory, then process it.
if ($item.Attributes -ne "Directory")
{
(Get-Content $item.FullName ) |
Foreach-Object {
if (($_ -match '\"'))
{
$str = $_
$ext = [regex]::Matches($str, '".*?"').Value -replace '"'
$ext = $ext.ToUpper()
Write-Host $ext
$_ = $ext
}
else { }
} |
Set-Content $item.FullName
}
}
This can do it. Really I wasn't following your code so I stripped it and modified the regex.
$items = Get-ChildItem "C:\Users\UsernameHere\Desktop\Folder123\*.txt"
# enumerate the items array
foreach ($item in $items){
# if the item is a directory, then process it.
if ($item.Attributes -ne "Directory"){
$content = (gc $item.FullName )
$content = $content.replace('"\w.*"',$matches[0].ToUpper)
$content | sc $item
}
}
If you had powershell 6 or 7:
'"hi"' -replace '".*"', { $_.value.toupper() }
"HI"
'"e" //&&''i&&' -replace '".*"', { $_.value.toupper() }
"E" //&&'i&&
I am able to print the upper case characters with the below code, but the file is not getting updated. It still has the old characters, How to update the fie with new contents.
$items = Get-ChildItem *.txt -recurse
# enumerate the items array
foreach ($item in $items)
{
# if the item is a directory, then process it.
if ($item.Attributes -ne "Directory")
{
(Get-Content $item.FullName ) |
Foreach-Object {
$str = $_
$_ = [regex]::Replace($_, '"[^"]*"', { param($m) $m.Value.ToUpper() })
Write-Host $_
} |
Set-Content $item.FullName
}
}
I've been reading a ton of material and thought I had found my solution but no luck. I need to find apostrophes contained in a name and then replace them with a double. I am loading a file to an array and then looping through that, looking for the apostrophes. The catch is that each row can have several apostrophes so that's why it's not a simple find and replace.
Here is a sample of the file:
create(xxxxxxx)using(xxxxxxx)name('O'Doe, John')
replace(xxxxxxx)instdata('ab 1234 ')
create(xxxxxxx)using(xxxxxxx)name('Doe, O'Jane')
replace(xxxxxxx)instdata('ab 5678 ')
There are other lines inbetween but they don't contain apostrophes.
Here is what I have so far:
$Pattern = "[A-Z]'[A-Z]"
$user = gc C:\Temp\mfnewuser.ins
for ($i = 0; $i -lt $user.count; $i++) {
if ($user[$i] -match $Pattern) {
$user[$i] = [regex]::replace($strText, $Pattern.substring(2,1), "''")
$user | out-file C:\Temp\mfnewuser.ins
}
}
I'm looking for a capital letter, followed by an apostrophe, followed by another capital. Because of the other commas, I can't just do a global replace. I know my pattern matching is working but I can't seem to manipulate it with the substring. The substring looks at $Pattern as a string instead of the result of a regex. If I can save the regex result to a variable, that would be great. I think then the replace would be easy.
Tried this as well but no luck either:
$Pattern = "[A-Z]'[A-Z]"
$NewPattern = "[A-Z]''[A-Z]"
$f = Get-Content C:\Temp\mfnewuser.ins
$f = $f -replace $Pattern, $NewPattern
$f | out-file C:\Temp\mfnewuser.ins
I may be approaching this all wrong and there is an easier way but I haven't seen anything yet.
EDIT:
Based on Bill_Stewarts example below, I've got this to work on the First Name but not yet the Last Name:
$Pattern = "[A-Z]'[A-Z]"
$user = gc C:\Temp\mfnewuser.ins
for ($i = 0; $i -lt $user.count; $i++) {
if ($user[$i] -match $Pattern) {
$user[$i] = $user[$i] -replace "(.*[A-Z])'([A-Z]+.*)", "`$1''`$2"
$user | out-file C:\Temp\mfnewuser.ins
}
}
Perhaps something like this?
get-content "test.txt" | foreach-object {
$_ -replace "([A-Z])'([A-Z])", "`$1''`$2"
}
Regular expressions can be grouped using ( ) and the -replace operator supports substring replacement ($1 and $2).
Replace your line, with the following.
$user[$i] = $user[$i] -replace "([A-Z])'([A-Z])", "`$1`''`$2"
Or try one of the following. This should suffice.
get-content "mfnewuser.ins" | foreach-object {
$_ -replace "([A-Z])'([A-Z])", "`$1`''`$2"
} | set-content "mfnewuser.ins"
...
get-content "mfnewuser.ins" | foreach-object {
$_ -replace "([a-zA-Z', ]+)'([a-zA-Z', ]+)", "`$1`''`$2"
} | set-content "mfnewuser.ins"
quick one:
$logFile="D:\Code\functest\1725.log"
function getTime($pattern) {
Get-Content $logFile | %{ if ($_.Split('\t') -match $pattern) {$_} }
}
getTime("code")
gives me
simple 17-Feb-2011 10:45:27 Updating source code to revision: 49285
simple 17-Feb-2011 10:54:22 Updated source code to revision: 49285
but if I change the print value from
$_
to
$matches
I get nothing. I thought this array should have been created automatically? probably something silly, but this is my first day of using powershell :-)
EDIT: what I want to return is
Get-Date (column 2 of the matching line)
Your call to Split() is using C# conventions to escape the t to specify a tab character. In PowerShell, you use a single backtick e.g. $_.Split("`t"). Also -match is behaving a bit differently on an array like this so have it operate on each individual string like so:
Get-Content $logFile | Foreach {$_.Split("`t")} | Where { $_ -match $pattern }
There's also a sort of hidden trick here with Get-Content where you can get it to split for you:
Get-Content $logFile -del "`t" | Where { $_ -match $pattern }
Update: based on the updated question, try something like this:
gc $logFile | % {$cols = $_.Split("`t"); if ($cols[2] -match $pattern) {$cols[1]}}
Keeping in mind that arrays are 0-based in PowerShell. If the text is already in a DateTime format that PowerShell/.NET understand, you can just cast it to a DateTime like so [DateTime]$cols[1].
The $_.Split('\t') is breaking it.
First, it's breaking on every letter "t", not at tabs.
Second, it return a array that confounds -match.
With the following code:
Get-Content $logFile | %{ if ($_ -match $pattern) { $matches } }
getTime("code") would return:
Name Value
---- -----
0 code
0 code
This would allow to search with regular expressions, as in
$answerArray = getTime("(\t)(\d+)")
$digitsOfSecondResult = $answerArray[1][2]
Write-Output $digitsOfSecondResult
If you just want to print the lines that match the pattern, try:
Get-Content $logFile | %{ if ($_ -match $pattern) { $_} }
To get the date:
function getTime($pattern) {
Get-Content $logFile | %{ if ($_ -match $pattern) { Get-Date $matches[1] } }
}
getTime("`t(.+)`t.*code")
Or:
function getTime($pattern) {
Get-Content $logFile | %{ if ($_ -match "`t(.+)`t.*$pattern") { Get-Date $matches[1] } }
}
getTime("code")
I think we have a bunch of commented out code in our source, and rather than delete it immediately, we've just left it. Now I would like to do some cleanup.
So assuming that I have a good enough RegEx to find comments (the RegEx below is simple and I could expand on it based on our coding standards), how do I take the results of the file that I read up and output the following:
Filename
Line Number
The actual line of code
I think I have the basis of an answer here, but I don't know how to take the file that I've read up and parsed with RegEx and spit it out in this format.
I'm not looking for the perfect solution - I just want to find big blocks of commented out code. By looking at the result and seeing a bunch of files with the same name and sequential line numbers, I should be able to do this.
$Location = "c:\codeishere"
[regex]$Regex = "//.*;" #simple example - Will expand on this...
$Files = get-ChildItem $Location -include *cs -recurse
foreach ($File in $Files) {
$contents = get-Content $File
$Regex.Matches($contents) | WHAT GOES HERE?
}
You could do:
dir c:\codeishere -filter *.cs -recurse | select-string -Pattern '//.*;' | select Line,LineNumber,Filename
gci c:\codeishere *.cs -r | select-string "//.*;"
The select-string cmdlet already does exactly what you're asking for, though the filename displayed is a relative path.
I would go personally even further. I would like to compute number of consecutive following lines. Then print the file name, count of lines and the lines itself. You may sort the result by count of lines (candidates for delete?).
Note that my code doesn't count with empty lines between commented lines, so this part is considered as two blocks of commented code:
// int a = 10;
// int b = 20;
// DoSomething()
// SomethingAgain()
Here is my code.
$Location = "c:\codeishere"
$occurences = get-ChildItem $Location *cs -recurse | select-string '//.*;'
$grouped = $occurences | group FileName
function Compute([Microsoft.PowerShell.Commands.MatchInfo[]]$lines) {
$local:lastLineNum = $null
$local:lastLine = $null
$local:blocks = #()
$local:newBlock = $null
$lines |
% {
if (!$lastLineNum) { # first line
$lastLineNum = -2 # some number so that the following if is $true (-2 and lower)
}
if ($_.LineNumber - $lastLineNum -gt 1) { #new block of commented code
if ($newBlock) { $blocks += $newBlock }
$newBlock = $null
}
else { # two consecutive lines of commented code
if (!$newBlock) {
$newBlock = '' | select File,StartLine,CountOfLines,Lines
$newBlock.File, $newBlock.StartLine, $newBlock.CountOfLines, $newBlock.Lines = $_.Filename,($_.LineNumber-1),2, #($lastLine,$_.Line)
}
else {
$newBlock.CountOfLines += 1
$newBlock.Lines += $_.Line
}
}
$lastLineNum=$_.LineNumber
$lastLine = $_.Line
}
if ($newBlock) { $blocks += $newBlock }
$blocks
}
# foreach GroupInfo objects from group cmdlet
# get Group collection and compute
$result = $grouped | % { Compute $_.Group }
#how to print
$result | % {
write-host "`nFile $($_.File), line $($_.StartLine), count of lines: $($_.CountOfLines)" -foreground Green
$_.Lines | % { write-host $_ }
}
# you may sort it by count of lines:
$result2 = $result | sort CountOfLines -desc
$result2 | % {
write-host "`nFile $($_.File), line $($_.StartLine), count of lines: $($_.CountOfLines)" -foreground Green
$_.Lines | % { write-host $_ }
}
If you have any idea how to improve the code, post it! I have a feeling that I could do it using some standard cmdlets and the code could be shorter..
I would look at doing something like:
dir $location -inc *.cs -rec | `
%{ $file = $_; $n = 0; get-content $_ } | `
%{ $_.FileName = $file; $_.Line = ++$n; $_ } | `
?{ $_ -match $regex } | `
%{ "{0}:{1}: {2}" -f ($_.FileName, $_.Line, $_)}
I.e. add extra properties to the string to specify the filename and line number, which can be carried through the pipeline after the regex match.
(Using ForEach-Object's -begin/-end script blocks should be able to simplify this.)