I have two entities: Category and Icon they have a many to many relationship so i end up with three tables: category icon and icon_category
My goal is to find Icons that are in multiple categories.
For example I have the following
categories: a b c and icons 1 2 3
Here are the categories for the icons:
1 - a b
2 - a
3 - c
I would like to search for an icon that is in category a and b and get 1 as the result.
My first approach was to load in each category (a and b) into separate results and then compare using array_intersect():
$cats = array();
foreach($terms as $term){
$cat = $em->getRepository('SixStringPearBundle:Category')->findOneBy(array("name" => $term));
if($cat){
$cats[$term] = $cat->getIcons();
}
}
This returned $cats[a] = array(icon(1), icon(2) and $cats[b] = array(icon(1))
I then tried the following:
$res = array_shift($cats);
foreach($cats as $cat){
$res = array_intersect($res, $cat);
}
but got the following error: Argument #1 is not an array
I checked the type of $cat[a] and $cat[b] and they are a Doctrine Persistence Collection
I also tried calling $res = $res->toArray() and $cat = $cat->toArray() before calling array_intersect This resolved the error but did not return the expected results: Icon(1)
Does anyone have any thoughts or maybe even a better approach to all of this?
I ended up using the doctrine query builder. It was agonizing but I finally figure it out. Here is the end result:
$qb->select('i')
->from('SixStringPearBundle:Icon', 'i')
->leftJoin('i.categories', 'c')
->where('c.name IN (?1)')
->groupBy('i.id')
->having('count(i.id) = ?2')
->setParameters(array(1 => $terms, 2 => count($terms)));
Related
I'm trying to complete something which should be quite simple but for the life of me, I can't work it out.
I'm trying to calculate the difference between 2 rows that share the same 'Scan type'.
I have attached a photo showing sample data from production. We run a scan and depending on the results of the scan, it's assigned a color.
I want to find the difference in Scan IDs between each Red scan.
Using the attached Photo of Sample data, I would expect a difference of 0 for id 3. A difference of 1 for id 4 and a difference of 10 for id 14.
I have (poorly) written something that works based on the maximum value from the scan id.
I have also tried following a few posts to see if I can get it to work..
var _curid= MAX(table1[scanid])
var _curclueid = MAX(table1[scanid])
var _calc =CALCULATE(SUM(TABLE1[scanid],FILTER(ALLSELECTED(table1[scanid]),table1[scanid]))
return if(_curid-_calc=curid,0,_curid-_calc)
Edit;
Forgot to mention I have checked threads;
57699052
61464745
56703516
57710425
Try the following DAX and if it helps then accept it as the answer.
Create a calculated column that returns the ID where the colour is Red as follows:
Column = IF('Table'[Colour] = "Red", 'Table'[ID])
Create another column as following:
Column 2 =
VAR Colr = 'Table'[Colour]
VAR SCAN = 'Table'[Scan ID]
VAR Prev_ID =
CALCULATE(MAX('Table'[Column 2]),
FILTER('Table', 'Table'[Colour] = Colr && 'Table'[Scan ID] < SCAN))
RETURN
'Table'[Column] - Prev_ID
Output:
EDIT:-
If you want your first value(ID3) to be 0 then relace the RETURN line with the following line:
IF(ISBLANK(Prev_ID) && 'Table'[Colour] = "Red", 0, 'Table'[Column] - Prev_ID )
This will give you the following result:
I am new to Apache Pig. I want to split and flatten the following input into my required output like who are all viewed that product.
My Input :(UserId, ProductId)
12345 123456,23456,987653
23456 23456,123456,234567
34567 234567,765678,987653
My Required Output:(ProductId, UserId)
123456 12345
123456 23456
23456 12345
23456 23456
987653 12345
987653 34567
234567 23456
234567 34567
765678 34567
My Pig Scripts:
a = load '/home/hadoopuser/ips' using PigStorage('\t') as (key:chararray, val:chararray);
b = foreach a generate key as ky1, FLATTEN(TOKENIZE(val)) as vl1;
c = group b by vl1;
d = foreach c generate group as vl2, $1 as ky2;
e = foreach d generate vl2, BagToString(ky2) as kyy;
f = foreach e generate vl2 as vl3,FLATTEN(STRSPLIT(kyy,'_')) as ky3;
g = foreach f generate vl3, FLATTEN(TOKENIZE(ky3)) as kk1;
dump g;
I got the following output which eliminates the repeated (duplicate)values,
(23456,12345)
(123456,12345)
(234567,23456)
(765678,34567)
(987653,12345)
I don't know how to solve this problem. Can anyone help me to solve this problem? and how to do this in a simple way?
Well, the second line of your code does exactly what you want, it simply displays the customer first and the product second. Put first the FLATTEN and then the key part:
a = load '/home/hadoopuser/ips' using PigStorage('\t') as (key:chararray, val:chararray);
b = foreach a generate FLATTEN(TOKENIZE(val)) as ProductId, key as UserId;
dump b;
(123456,12345)
(23456,12345)
(987653,12345)
(23456,23456)
(123456,23456)
(234567,23456)
(234567,34567)
(765678,34567)
(987653,34567)
As to why you are getting only one result per ProductId with your current code, you are grouping by ProductId, which gives you one row per different ProductId with a bag that contains all of the customers who viewed that product. Then, you convert that bag to a huge string separated by _, to convert it again to the same bag as before:
d = foreach c generate group as vl2, $1 as ky2;
e = foreach d generate vl2, BagToString(ky2) as kyy;
f = foreach e generate vl2 as vl3,FLATTEN(STRSPLIT(kyy,'_')) as ky3;
The BagToString UDF converts a bag to a string, joining the different values in the bag separated by a custom delimiter, which defaults to _. In the next line, however, you split it by _ resulting in the same bag as before. However, you FLATTEN that bag, so now instead of having a row with the ProductId and a bag, you have a row with several fields, being the first the ProductId, and the following fields all the customers that viewed the product:
Before FLATTEN:
(23456,{(23456,23456),(12345,23456)})
(123456,{(23456,123456),(12345,123456)})
(234567,{(34567,234567),(23456,234567)})
(765678,{(34567,765678)})
(987653,{(34567,987653),(12345,987653)})
After FLATTEN:
(23456,23456,23456,12345,23456)
(123456,23456,123456,12345,123456)
(234567,34567,234567,23456,234567)
(765678,34567,765678)
(987653,34567,987653,12345,987653)
And here lies the error. You have one only row for each of the products, and several fields in each row for each customer. When applying the last foreach, you select the first field (the product) and the second (the first of all the customers), discarding the rest of the customers on each row.
I have searched for hours but could not find an answer to this, or a module to help.
We are building a store and our client needs the ability to navigate the store by manufacturer. Is there any way that the manufacturer page can list the categories and subcategories.
There seems two ways to do it.
Add brands while adding categories in admin section.
Get all categories inside the brands by join operation while viewing the manufacturer.
Are there any modules available to link up categories with manufacturers so that I can display categories inside the manufacturer page.
Or the only way is to query all the products inside the manufacturer and get the categories out of it... I guess it is not a good solution.
So any suggestions would be a great help.
Thanks.
I figured a way to find the categories that belongs to a manufacturer. The second options seems better.
Here is the function that I added to catalog/model/catalog/manufacturer.php
public function getManufacturerCategories($manufacturer_id) {
$query = $this->db->query("
SELECT
DISTINCT c.category_id,cd.name
FROM
". DB_PREFIX . "manufacturer m
LEFT JOIN ". DB_PREFIX. "product p ON (m.manufacturer_id = p.manufacturer_id)
LEFT JOIN ". DB_PREFIX. "product_to_category p2c ON (p2c.product_id = p.product_id)
LEFT JOIN ". DB_PREFIX. "category c ON (c.category_id = p2c.category_id)
LEFT JOIN ". DB_PREFIX. "category_description cd ON (cd.category_id = p2c.category_id)
WHERE
p.status = 1
AND m.manufacturer_id = '".(int)$manufacturer_id."'
AND c.status= 1
");
return $query->rows;
}
Here is the output array
stdClass Object (
[row] => Array
(
[category_id] => 20
[name] => Desktops
)
[rows] => Array
(
[0] => Array
(
[category_id] => 20
[name] => Desktops
)
[1] => Array
(
[category_id] => 24
[name] => Phones & PDAs
)
)
[num_rows] => 2 )
I need to find the Facebook place for the city for many lat/long points. The actual points refer to personal addresses, so there are no exact place ID's to look for as in the case of a business.
For testing, I was looking for the town of Red Feather Lakes, CO.
The graph search function will return a lot of places, but does not return cities Example
Raw FQL does not let you search by lat/long, and has no concept of "nearby" anyway. Example
An FQL query by ID reveals that there is an least a "Display Subtext" field which indicates that object is a city. Example
Thanks for any help. I have over 80 years of dated and geotagged photos of my dad that he would love to see on his timeline!
EDIT
Cities are not in the place table, they are only in the page table.
There is an undocumented distance() FQL function, but it only works in the place table. (Via this SO answer.)
This works:
SELECT name,description,geometry,latitude,longitude, display_subtext
FROM place
WHERE distance(latitude, longitude, "40.801985", "-105.593719") < 50000
But this gives an error "distance is not valid in table page":
SELECT page_id,name,description,type,location
FROM page
WHERE distance(
location.latitude,location.longitude,
"40.801985", "-105.593719") < 50000
It's a glorious hack, but this code works. The trick is to make two queries. First we look for places near our point. This returns a lot of business places. We then take the city of one of these places, and use this to look in the page table for that city's page. There seems to be a standard naming conventions for cities, but different for US and non-US cities.
Some small cities have various spellings in the place table, so the code loops through the returned places until it finds a match in the page table.
$fb_token = 'YOUR_TOKEN';
// Red Feather Lakes, Colorado
$lat = '40.8078';
$long = '-105.579';
// Karlsruhe, Germany
$lat = '49.037868';
$long = '8.350124';
$states_arr = array('AL'=>"Alabama",'AK'=>"Alaska",'AZ'=>"Arizona",'AR'=>"Arkansas",'CA'=>"California",'CO'=>"Colorado",'CT'=>"Connecticut",'DE'=>"Delaware",'FL'=>"Florida",'GA'=>"Georgia",'HI'=>"Hawaii",'ID'=>"Idaho",'IL'=>"Illinois", 'IN'=>"Indiana", 'IA'=>"Iowa", 'KS'=>"Kansas",'KY'=>"Kentucky",'LA'=>"Louisiana",'ME'=>"Maine",'MD'=>"Maryland", 'MA'=>"Massachusetts",'MI'=>"Michigan",'MN'=>"Minnesota",'MS'=>"Mississippi",'MO'=>"Missouri",'MT'=>"Montana",'NE'=>"Nebraska",'NV'=>"Nevada",'NH'=>"New Hampshire",'NJ'=>"New Jersey",'NM'=>"New Mexico",'NY'=>"New York",'NC'=>"North Carolina",'ND'=>"North Dakota",'OH'=>"Ohio",'OK'=>"Oklahoma", 'OR'=>"Oregon",'PA'=>"Pennsylvania",'RI'=>"Rhode Island",'SC'=>"South Carolina",'SD'=>"South Dakota",'TN'=>"Tennessee",'TX'=>"Texas",'UT'=>"Utah",'VT'=>"Vermont",'VA'=>"Virginia",'WA'=>"Washington",'DC'=>"Washington D.C.",'WV'=>"West Virginia",'WI'=>"Wisconsin",'WY'=>"Wyoming");
$place_search = json_decode(file_get_contents('https://graph.facebook.com/search?type=place¢er=' . $lat . ',' . $long . '&distance=10000&access_token=' . $fb_token));
foreach($place_search->data as $result) {
if ($result->location->city) {
$city = $result->location->city;
$state = $result->location->state;
$country = $result->location->country;
if ($country=='United States') {
$city_name = $city . ', ' . $states_arr[$state]; // e.g. 'Chicago, Illinois'
}
else {
$city_name = $city . ', ' . $country; // e.g. 'Rome, Italy'
}
$fql = 'SELECT name,page_id,name,description,type,location FROM page WHERE type="CITY" and name="' .$city_name. '"';
$result = json_decode(file_get_contents('https://graph.facebook.com/fql?q=' . rawurlencode($fql) . '&access_token=' . $fb_token));
if (count($result->data)>0) {
// We found it!
print_r($result);
break;
}
else {
// No luck, try the next place
print ("Couldn't find " . $city_name . "\n");
}
}
}
I found this solution worked for me when looking for a page for the closest city to the specified latitude/longitude. For some reason LIMIT 1 didn't return the closest city so I bumped up the limit and then took the first result.
SELECT page_id
FROM place
WHERE is_city and distance(latitude, longitude, "<latitude>", "<longitude>") < 100000
ORDER BY distance(latitude, longitude, "<latitude>", "<longitude>")
LIMIT 20
please pardon the absolutely newbie question but i'm very new to tableau.
what I'd like to do is create a message based on which filter flags are active. so, in psuedo code, i'd do something like this:
message = ''
if filter1 == 1:
message += 'filter 1 is active'
if filter2 == 1:
message += ' filter 2 is active'
return message
problem is, I'm not even sure how to do multiple if statements - i keep getting a syntax error. Any help will be greatly appreciated.
Here is an example of how I accomplished something similar:
IF [ZAVUFA1_FED_COLL_CHOICE_1] = 'xxxxx' THEN 1
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_2] = 'xxxxx' THEN 2
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_3] = 'xxxxx' THEN 3
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_4] = 'xxxxx' THEN 4
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_5] = 'xxxxxx' THEN 5
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_6] = 'xxxxx' THEN 6
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_7] = 'xxxxxx' THEN 7
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_8] = 'xxxxxx' THEN 8
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_9] = 'xxxxx' THEN 9
ELSEIF [ZAVUFA1_FED_COLL_CHOICE_10] = 'xxxxxx' THEN 10
ELSEIF ISNULL([ZAVUFA1_FED_COLL_CHOICE_1]) THEN 99
END
As much as I love stackoverflow, Tableau also has a great user forum on their site.
You would create a calculated field called message with this code:
IF filter1 = 1 THEN 'filter 1 is active' END
+ IF filter2 = 1 THEN ' filter 2 is active' END
what I ended up doing is creating a calculated field for each if statement. I then created yet another calculated field that concatenates all of the output from each of the first set of calculated fields I created. Seems like a bit of a hack so If anyone knows of a more elegant way of doing this (making a calculated field of a series of calulated fields seems awfully kludgy) I'd be glad to pass on the points for answering.