let's say I have a class, A
Class A {
int x[100];
vector<int> y;
Fill(x);
Fill(y.begin());
B(x);
B(y.begin());
}
Class Fill (pointer) {
*pointer = 0;
++pointer;
*pointer = 1;
++pointer
}
Class B(container) {
//how do I clear/empty the array and the vector passed by class A given only the pointers to them?
//I must clear an array and a vector in THIS class.
//I DO NOT want to fill them with 0s.
//x and y.begin are POINTERS to the first element of the container, not containers
}
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s
Thank you in advance.
For vector:
some_a_pointer->y.resize(0);
You can't do it with just an iterator (y.begin()).
An array's size can never change, so the best you can do is fill it with 0.
std::vector has a method called clear that will clear all the elements.
So my_vector.clear(); will clear everything. However you can't really do the same for arrays. It's just not possible. At best you can fill them with zeroes or go the wrong way and dynamically allocate the array and then delete it. I would rather not deal with memory issues though so I'd just fill them with zero.
C++11 has a class called std::array<T,N> for static arrays of a compile time size and it has a method called fill that would make filling everything to zero easy (a la looping). You can call it with my_array.fill(0);.
Related
I have a double pointer Array of a structure:
typedef struct Position{
int x;
int y;
} Position;
Position** array = (Position**)malloc(sizeof(Position*)*10); //10 elements
array[0] = (Position*)malloc(sizeof(Position*));
array[0]->x = 10;
array[0]->y = 5;
Can I calculate the length of set array and if so, how?
The normal way for arrays does not work :
int length = sizeof(<array>)/sizeof(<array>[0]);
Once you have dynamically allocated an array, there is no way of finding out the number of elements in it.
I once heard of some hacky way to obtain the size of a memory block, (msize) which would allegedly allow you to infer the size of the data within the block, but I would advice against any such weird tricks, because they are not covered by the standard, they represent compiler-vendor-specific extensions.
So, the only way to know the size of your array is to keep the size of the array around. Declare a struct, put the array and its length in the struct, and use that instead of the naked array.
As you marked the question as C++, I would suggest that you use std::vector, then, after you "allocated some memory" (or requested some memory to allocated by std::vector constructor or by using push_back, or resize), you can simply get the size back using by using std::vector::size.
typedef struct Position{
int x;
int y;
} Position;
std::vector<Position> array(10);
array[0].x = 10;
array[0].y = 5;
size_t size = array.size(); // will be 10
Having only a pointer to some memory block, you cannot defer the size of this memory block. So you cannot defer the number of elements in it.
For arrays of pointers, however, you could infer the number of elements in it under the following conditions:
make sure that every pointer (except the last one) points to a valid object.
for the last pointer in the array, make sure that it is always NULL.
Then you can derive the length by counting until you reach NULL.
Maybe there are some other similar strategies.
Solely from the pointer itself, however, you cannot derive the number of elements in it.
Old question, but in case someone needs it:
#include <stdio.h>
...
int main()
{
char **double_pointer_char;
...
int length_counter = 0;
while(double_pointer_char[length_counter])
length_counter++;
...
return 0;
}
I'm having problem initialising an array of std::vectors.
I'm declaring and initialising it like this:
vector<component_change*>* _changes;
_changes = new vector<component_change*> [numThreads];
in the hope that it's in the same form as this:
int * foo;
foo = new int [5];
but when I hit a breakpoint after the initialisation, _changes' size is 0.
What am I doing wrong and how can I fix it?
I don't want to use a vector of vectors as the number I need remains constant throughout the program but depends on the current hardware. And I'm not just looking for a single vector (Each vector will be used by a different thread then merged when the threads have finished their tasks).
Thanks guys! :)
Your program is correct. But you misinterpreted the debugger. _changes's size is not 0, but the first vector in your array (the one _changes points at) is empty. Thats because the debugger does not know if _changes points at a single element or an array (in that case the compiler would not know how many elements are in that array). Simply use a vector and call std::vector::shrink_to_fit.
If the size can be determined at compile time use a std::array. If the size is a run-time argument then use a vector and don't change the size of the container.
Are you interested in have a vector for each thread, or a vector containing items used by each thread? I assumed the later, but my answer could be adapted.
This is using a statically sized array; (this syntax is close).
const int NUMBER_OF_THREADS = 5;
component_change* _changes[NUMBER_OF_THREADS] =
{
new component_change(1),
new component_change(2),
new component_change(3),
new component_change(4),
new component_change(5)
}
If the number of threads is dynamic, you will have to use a new...
int NUMBER_OF_THREADS = system.getThreadCount();
component_change* _changes = new component_change[NUMBER_OF_THREADS];
for (int i = 0; i < NUMBER_OF_THREADS; i++)
{
_changes[i] = new component_change(i+1);
}
If you want to a std::vector:
int NUMBER_OF_THREADS = system.getThreadCount();
std::vector<component_change*> _changes;
_changes.reserve(NUMBER_OF_THREADS);
for (int i = 0; i < NUMBER_OF_THREADS; i++)
{
_changes.push_back(new component_change(i+1));
}
I think you're kind of mislead, this size that you are reading belongs to the vector in the first element of the array. Its size is equal to 0 since no elements have been inserted in the vector yet.
new vector is usually wrong.
You should use, with most preferred if possible first,
std::vector<component_change> _changes(numThreads);
or
std::vector<std::unique_ptr<component_change>> _changes(numThreads);
or
std::vector<component_change*> _changes(numThreads);
or if each element of the vector should itself contain an array of components (it's not clear in your question)
std::vector<std::vector<**component_change**>> _changes(numThreads);
Declaring the component as one of the above ways, depending on your needs.
Note that the pointers begin not pointing to anything. You'd have to allocate the individual components as a separate step.
The following creates an array of numThreads vectors, not a vector of numThread elements.
new vector<component_change*> [numThreads]
How do I add an element to the end of an array dynamically in C++?
I'm accustomed to using vectors to dynamically add an element. However, vectors does not seem to want to handle an array of objects.
So, my main goal is having an array of objects and then being able to add an element to the end of the array to take another object.
EDIT**
Sorry, its the pushback() that causes me the problems.
class classex
{
private:
int i;
public:
classex() { }
void exmethod()
{
cin >> i;
}
};
void main()
{
vector <classex> vectorarray;
cout << vectorarray.size();
cout << vectorarray.push_back();
}
Now I know push_back must have an argument, but What argument?
Now I know push_back must have an argument, but What argument?
The argument is the thing that you want to append to the vector. What could be simpler or more expected?
BTW, you really, really, really do not want exmethod as an actual method of classex in 99% of cases. That's not how classes work. Gathering the information to create an instance is not part of the class's job. The class just creates the instance from that information.
Arrays are fixed sized containers. So enlarging them is not possible. You work around this and copy one array in a bigger and gain space behind the old end, but that's it.
You can create a array larger than you currently need it and remember which elements are empty. Of course they are never empty (they at least contain 0's), but that's a different story.
Like arrays, there are many containers, some are able to grow, like the stl containers: lists, vectors, deques, sets and so on.
add a Constructor to set i (just to give your example a real world touch) to your example classex, like this:
class classex {
public:
classex(int& v) : i(v) {}
private:
int i;
};
An example for a growing container looks like this:
vector <classex> c; // c for container
// c is empty now. c.size() == 0
c.push_back(classex(1));
c.push_back(classex(2));
c.push_back(classex(3));
// c.size() == 3
EDIT: The question was how to add an element to an array dynamically allocated, but the OP actually mean std::vector. Below the separator is my original answer.
std::vector<int> v;
v.push_back( 5 ); // 5 is added to the back of v.
You could always use C's realloc and free. EDIT: (Assuming your objects are PODs.)
When compared to the requirement of manually allocating, copying, and reallocating using new and delete, it's a wonder Stroustrup didn't add a keyword like renew.
I have the following constructor:
Timing::Timing():
_numMes(INIT_NUMMES),_msgs(new allMSgs*[NUMBER_OF_MSGS])
{
cout<<"build timing OK\n";
}
allMSgs is a struct :
typedef struct AllMSgs
{
double msg;
Agent* dedicatedTo;
}allMSgs;
and the declaration of it is done like this:
allMSgs** _msgs;
but when i try to reach for a field in the array like this:
_msgs[loc]->dedicatedTo=agent->getPointsTo();
i get a segmentation fault.
NUMBER_OF_MSGS is 1000
loc is 0,1,2.... (less then 1000);
help please
You've made an array of pointers, but not set them to point anywhere valid yet. You either need to change it to be simply:
allMSgs* _msgs;
and:
new allMSgs[NUMBER_OF_MSGS]
Or call new for each pointer in the allMSgs array.
Better yet though you could just use a std::vector or other container, with std::vector<allMSgs> _msgs;, which you can use like it was an array in most cases. You can initalise it with a size too.
You have only allocated the array itself. You need to allocate each and every item of the array too. In the constructor, add a for loop that allocates all of the items.
for (int i = 0; i < NUMBER_OF_MSGS; i++)
_msgs[i] = new allMSgs();
You can also just define the array as an array of allMSgs and not pointers to allMSgs.
allMSgs* _msgs;
I have an array in a class that should hold some instances of other objects. The header file looks like this:
class Document {
private:
long arraysize;
long count;
Row* rows;
public:
Document();
~Document();
}
Then in the constructor I initialize the array like this:
this->rows = new Row[arraysize];
But for some reason this just sets rows to an instance of Row rather than an array of rows. How would I initialize an array of Row objects?
Both SharpTooth and Wok's answers are correct.
I would add that if you are already struggling at this level you may be better off using a std::vector instead of a built-in array in this case. The vector will handle growing and shrinking transparently.
This should work. One possible "error" would be an incorrect value for arraySize.
However you should better use a std::vector from the standard library for that purpose.
#include <vector>
class Document {
// ...
std::vector<Row> rows;
// ...
};
and in your constructor:
Document::Document() : rows(arraySize) { // ... }
or
Document::Document() { rows.assign(arraySize, Row()); }
If arraySize contains a reasonable value at that point you actually get an array. I guess you trust your debugger and the debugger only shows the 0th element (that's how debuggers treat pointers), so you think there's only one object behind that pointer.
For i in [0;arraysize[, *(this->rows+i) should be an instance of row.
What precisely makes you think that rows is only one element? Make certain that you arraysize isn't 1. If it is, you'll get an array of 1 element. Mind you, you must still call delete [] with an array of size 1.
Also, why is arraysize different than count? Using that terminology, you should be making an array of count elements and arraysize should be equal to sizeof(Row) * count.
Also, you specifically ask "How would I initialize an array of Row objects?". Do you mean allocate? If so, that's how you would do so. If you mean initialize, the default constructor of Row will be called on each element of the array when the array is allocated.