Outputting Date and Time in C++ using std::chrono - c++

I have been upgrading some old code and have been trying to update to c++11 where possible. The following code is how I used to display the time and date in my program
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
const std::string return_current_time_and_date() const
{
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%Y-%m-%d %X", &tstruct);
return buf;
}
I would like to output the current time and date in a similar format using std::chrono(or similar) but am unsure how to go about doing so. Any help would be greatly appreciated. Thanks

The <chrono> library only deals with time and not dates, except for the system_clock which has the ability to convert its timepoints to time_t. So using <chrono> for dates will not improve things much. Hopefully we get something like chrono::date in the not too distant future.
That said, you can use <chrono> in the following way:
#include <chrono> // chrono::system_clock
#include <ctime> // localtime
#include <sstream> // stringstream
#include <iomanip> // put_time
#include <string> // string
std::string return_current_time_and_date()
{
auto now = std::chrono::system_clock::now();
auto in_time_t = std::chrono::system_clock::to_time_t(now);
std::stringstream ss;
ss << std::put_time(std::localtime(&in_time_t), "%Y-%m-%d %X");
return ss.str();
}
Note that std::localtime may cause data races. localtime_r or similar functions may be available on your platforms.
Update:
Using a new version of Howard Hinnant's date library you can write:
#include "date.h"
#include <chrono>
#include <string>
#include <sstream>
std::string return_current_time_and_date() {
auto now = std::chrono::system_clock::now();
auto today = date::floor<days>(now);
std::stringstream ss;
ss << today << ' ' << date::make_time(now - today) << " UTC";
return ss.str();
}
This will print out something like "2015-07-24 05:15:34.043473124 UTC".
On an unrelated note, returning const objects has become undesirable with C++11; const return values cannot be moved from. I also removed the trailing const because trailing const is only valid for member functions and this function has no need to be a member.

Here's a C++20 solution:
#include <chrono>
#include <format>
std::string get_current_time_and_date()
{
auto const time = std::chrono::current_zone()
->to_local(std::chrono::system_clock::now());
return std::format("{:%Y-%m-%d %X}", time);
}
std::chrono::time_zone::to_local converts a system clock time point (std::chrono::time_point<std::chrono::system_clock, TDuration>) to a local time point (std::chrono::local_time<TDuration>). This local time point can then be formatted using std::format with formatting options similar to strftime.
Currently, only MSVC has implemented std::format. The calendar and timezone additions to chrono
are currently "partially" implemented by Clang and GCC, but check here for the updated status: https://en.cppreference.com/w/cpp/compiler_support. For more information about the chrono library, read here: https://en.cppreference.com/w/cpp/chrono.

An example:
#include <iostream>
#include <chrono>
#include <ctime>
std::string getTimeStr(){
std::time_t now = std::chrono::system_clock::to_time_t(std::chrono::system_clock::now());
std::string s(30, '\0');
std::strftime(&s[0], s.size(), "%Y-%m-%d %H:%M:%S", std::localtime(&now));
return s;
}
int main(){
std::cout<<getTimeStr()<<std::endl;
return 0;
}
Output as below:

For getting also milliseconds, I use chrono and C function localtime_r which is thread-safe (in opposition to std::localtime).
#include <iostream>
#include <chrono>
#include <ctime>
#include <time.h>
#include <iomanip>
int main() {
std::chrono::system_clock::time_point now = std::chrono::system_clock::now();
std::time_t currentTime = std::chrono::system_clock::to_time_t(now);
std::chrono::milliseconds now2 = std::chrono::duration_cast<std::chrono::milliseconds>(now.time_since_epoch());
struct tm currentLocalTime;
localtime_r(&currentTime, &currentLocalTime);
char timeBuffer[80];
std::size_t charCount { std::strftime( timeBuffer, 80,
"%D %T",
&currentLocalTime)
};
if (charCount == 0) return -1;
std::cout << timeBuffer << "." << std::setfill('0') << std::setw(3) << now2.count() % 1000 << std::endl;
return 0;
}
For format: http://www.cplusplus.com/reference/ctime/strftime/

bames53 solutions are good, but do not compile on my VS2017. The solution with ctime does not compile because localtime is very deprecated. The one with date.h does not compile with the current date.h I just took off github even though the documentation says they should, because today cannot be streamed as is. I omitted the includes but here is code that works:
void TimeTest()
{
auto n = std::chrono::system_clock::now();
auto in_time_t = std::chrono::system_clock::to_time_t(n);
std::tm buf;
localtime_s(&buf, &in_time_t);
std::cout << std::put_time(&buf, "%Y-%m-%d %X") << std::endl;
}
// I just added date.h from this link's guthub to the project.
// https://howardhinnant.github.io/date/date.html
void TimeTest1() {
auto now = std::chrono::system_clock::now();
auto today = floor<date::days>(std::chrono::system_clock::now());
std::cout << date::year_month_day{ today } << ' ' << date::make_time(now - today) << std::endl;
}
// output is
// 2018-04-08 21:19:49
// 2018-04-08 18:19:49.8408289
Feel free to fix bames53 solution and delete mine. My text just won't fit in a comment. I'm sure it can save many people from grief.

The fmt library has the ability to format tm structures: it has the same spec as strftime.
#include <ctime>
#include <fmt/chrono.h>
std::string current_datetime(void)
{
std::time_t tt = std::time(nullptr);
std::tm *tm = std::localtime(&tt);
return fmt::format("{:%Y%m%d}", *tm);
}

Although correct answers were already given, I decided to implement one more solution that outputs also fractional part of second.
You may notice in my code that sometimes I subtract one second from time_t value, - std::chrono::seconds(1), it is because according to documentation to_time_t() may round value instead of truncating (according to doc "If std::time_t has lower precision, it is implementation-defined whether the value is rounded or truncated"), hence I have to subtract 1 second to make it truncated time.
Try it online!
#include <chrono>
#include <string>
#include <sstream>
#include <iomanip>
std::string FormatTime(std::chrono::system_clock::time_point tp) {
std::stringstream ss;
auto t = std::chrono::system_clock::to_time_t(tp);
auto tp2 = std::chrono::system_clock::from_time_t(t);
if (tp2 > tp)
t = std::chrono::system_clock::to_time_t(tp - std::chrono::seconds(1));
ss << std::put_time(std::localtime(&t), "%Y-%m-%d %T")
<< "." << std::setfill('0') << std::setw(3)
<< (std::chrono::duration_cast<std::chrono::milliseconds>(
tp.time_since_epoch()).count() % 1000);
return ss.str();
}
std::string CurrentTimeStr() {
return FormatTime(std::chrono::system_clock::now());
}
#include <iostream>
int main() {
std::cout << CurrentTimeStr() << std::endl;
}
Example Output:
2021-12-02 04:10:51.876
As suggested by #AndyK, starting from C++20 you can use std::chrono::current_zone() and its method to_local(), they return std::chrono::local_time which is directly convertible to your desired string format by outputting to std::ostringstream or through std::format(). Whole function becomes very short:
#include <chrono>
#include <string>
#include <sstream>
#include <iostream>
std::string CurrentTimeStr() {
return (std::ostringstream{} << std::chrono::current_zone()->to_local(
std::chrono::system_clock::now())).str().substr(0, 23);
}
int main() {
std::cout << CurrentTimeStr() << std::endl;
}
But right now not all compilers support this current_zone() function, online GodBolt servers failed to compile it on trunk CLang and GCC, but MSVC compiles it well. Although my local laptop installation of CLang compiled it too.

You can improve the answer from #bames53 by using Boost lexical_cast instead of string stream manipulations.
Here is what I do:
#include <boost/lexical_cast.hpp>
#include <ctime>
std::string return_current_time_and_date() {
auto current_time = std::time(0);
return boost::lexical_cast<std::string>(std::put_time(std::gmtime(& current_time), "%Y-%m-%d %X"));
}

Related

How do I convert a string back into a time_point?

I am taking a system_clock time_point, converting it to a string, and then saving it to a configuration file.
Now I want to read that config file and turn the string back into a time point so that I can calculate the difference in time between two time points.
void SaveLastShuffleTime() {
m_lastShuffleTime = std::chrono::system_clock::now();
auto m_lastShuffleTimeTimeT = std::chrono::system_clock::to_time_t(m_lastShuffleTimeTimepoint);
stringstream m_lastShuffeTimeSS;
m_lastShuffeTimeSS << std::put_time(std::localtime(&m_lastShuffleTimeTimeT), "%Y-%m-%d %X");
m_deviceStateSettings.UpdateDeviceStateSettings(LAST_SHUFFLE_TIME, m_lastShuffeTimeSS.str());
}
void CompareLastShuffleTime() {
m _currentShuffleTime = std::chrono::system_clock::now();
/* READ CONFIG FILE AND CONVERT BACK TO TIME POINT */
int timeSinceLastShuffle = (duration_cast<minutes>(m_currentShuffleTime - m_oldShuffleTime)).count();
}
Please let me know if this is viable. The alternative is to save the timepoint as an integer but I would prefer not to do that.
Thanks
I recommend outputting UTC as opposed to local time so that the difference between timestamps isn't altered by UTC offset jumps (e.g. daylight saving).
C++20 makes this very easy, and allows timestamps with subsecond precision:
#include <cassert>
#include <chrono>
#include <iostream>
#include <sstream>
int
main()
{
using namespace std;
using namespace std::chrono;
stringstream s;
auto tp = system_clock::now();
auto tp_save = tp;
s << tp << '\n'; // Write it out
tp = {}; // Zero out the timestamp
s >> parse("%F %T", tp); // Parse it back in
assert(tp == tp_save); // Make sure it is the same
std::cout << s.str(); // This is what was formatted/parsed
}
Example output:
2021-06-17 16:10:10.562738
Vendors are still working on getting this out. But you can use this syntax today with C++11/14/17 and a free, open-source, header-only preview of this part of C++20.1
Just add:
#include "date/date.h"
using namespace date;
and the above works with the preview library.
1 Full disclosure: I am the lead author of this library. I am not pursuing any financial gain from this effort. But sometimes people get grumpy if I don't fully disclose this information.
You could use cctz library. It provides convenient functions for formatting timepoint cctz::format to a string and parsing cctz::parse from a string. And also for working with timezones. Example:
#include <chrono>
#include <iostream>
#include <string>
#include "cctz/time_zone.h"
int main() {
const std::chrono::system_clock::time_point now =
std::chrono::system_clock::now();
std::string now_str =
cctz::format("%Y-%m-%d %H:%M:%S%z", now, cctz::utc_time_zone());
std::cout << now_str << std::endl;
std::chrono::system_clock::time_point tp;
const bool ok =
cctz::parse("%Y-%m-%d %H:%M:%S%z", now_str, cctz::utc_time_zone(), &tp);
if (!ok)
return -1;
}
std::istringstream ss(str);
tm t;
ss >> std::get_time(&t, "%Y-%m-%dT%H:%M:%S");
std::time_t tt = std::mktime(&t);
/// If you don't need UTC time, just comment out the line below.
tt = std::mktime(std::gmtime(&tt));
return std::chrono::system_clock::from_time_t(tt);

C++ get UTC time with milliseconds

I need to get UTC time with milliseconds, I tried use it:
std::string getCurrentUTC()
{
namespace bg = boost::gregorian;
static char const* const fmt = "%Y-%b-%d %H:%M:%S";
std::ostringstream ss;
ss.imbue(std::locale(std::cout.getloc(), new bg::date_facet(fmt)));
ss << bg::day_clock::universal_day();
return ss.str();
}
But it prints the following:
2020-Jun-29 00:00:00
I need the following format:
2020-Jun-29 00:00:00.000
How can I solve this problem?
You could get the UTC time with millisecond as follow:
struct timeb timebStruct;
ftime(&timebStruct);
struct tm *tmStruct = new tm();
gmtime_r(&timebStruct.time, tmStruct);
std::cout << tmStruct->tm_hour
<< tmStruct->tm_min << tmStruct->tm_sec <<
timebStruct.millitm << std::endl
Using this free, open-source, header-only preview of C++20 <chrono> you can write:
#include "date/date.h"
#include <chrono>
#include <string>
#include <sstream>
std::string
getCurrentUTC()
{
namespace ch = std::chrono;
using date::operator<<;
static char const* const fmt = "%Y-%b-%d %T";
std::ostringstream ss;
auto tp = ch::time_point_cast<ch::milliseconds>(ch::system_clock::now());
ss << date::format(fmt, tp);
return ss.str();
}
This works in C++11/14/17. For me it just output:
2020-Jun-29 13:42:21.946
which is the current time UTC to millisecond precision.
When C++20 <chrono> ships, this will port to it by:
Remove #include "date/date.h".
Remove using date::operator<<;
Add #include <format>
Change date::format to std::format
Change "%Y-%b-%d %T" to "{:%Y-%b-%d %T}".

Get time according to rfc3339 with offset

I need to get time according to rfc3339 with time zone offset.
Currently I have:
#include <iostream>
#include <ctime>
#include <iomanip>
int main(int argc, char **argv)
{
auto t = std::time(nullptr);
auto tm = *std::localtime(&t);
std::ostringstream oss;
oss << std::put_time(&tm, "%Y-%m-%dT%H-%M-%S%z");
std::cout << oss.str() << std::endl;
return 0;
}
But the results has one minor issue, the time is:
2019-01-10T10-19-31+0100
But it should be:
2019-01-10T10-19-31+01:00
I checked the documentation:
https://en.cppreference.com/w/cpp/io/manip/put_time
and there seems to not be a way to specify the colon in time offset.
Is there a way to do it with c++11 std::put_time or with something else c++ stl provides

convert Date to time in millisecond in c++?

I have a requirement where I have to convert given string in date time format to milliseconds from epoch.
In Javascript there is date to time conversion api but in c++ I couldn't find anything as such.
Input would look like '2016-Mar-15 09:23:58.665068'
output should be in milliseconds say 14520000785.
I have tried looking into boost but still couldn't find(or understand) how to do?
Also, going through google I find the other way round i.e. converting milliseconds to date format but not what I require nor any helpful post for same.
Any help will be much appreciated.
Using only standard library features:
#include <ctime>
#include <chrono>
#include <iostream>
int main()
{
std::tm tm = {};
const char* snext = ::strptime("2016-Mar-15 09:23:58.665068", "%Y-%b-%d %H:%M:%S", &tm);
auto time_point = std::chrono::system_clock::from_time_t(std::mktime(&tm));
long long duration_ms = time_point.time_since_epoch() / std::chrono::milliseconds(1) + std::atof(snext) * 1000.0f;
std::cout << duration_ms << std::endl;
}
Prints: 1458033838665
See std::chrono::system_clock::now and std::chrono::milliseconds.
Most straightforward would be to just spell it out:
auto pt = boost::lexical_cast<ptime>("2016-Mar-15 09:23:58.665068");
std::cout << (pt - ptime { {1970,0,0}, {} }).total_milliseconds();
Live On Coliru
#include <boost/date_time/posix_time/posix_time.hpp>
#include <boost/date_time/posix_time/posix_time_io.hpp>
#include <boost/date_time.hpp>
#include <sstream>
int main() {
using boost::posix_time::ptime;
ptime pt;
{
std::istringstream iss("2016-Mar-15 09:23:58.665068");
auto* f = new boost::posix_time::time_input_facet("%Y-%b-%d %H:%M:%S%f");
std::locale loc(std::locale(""), f);
iss.imbue(loc);
iss >> pt;
}
std::cout << pt << " " << (pt - ptime{{1970,1,1},{}}).total_milliseconds();
}
Prints
2016-Mar-15 09:23:58.665068 1458033838665
Of course, extract the parsing in a helper function. Keep the locale around for reuse etc.

String representation of time_t?

time_t seconds;
time(&seconds);
cout << seconds << endl;
This gives me a timestamp. How can I get that epoch date into a string?
std::string s = seconds;
does not work
Try std::stringstream.
#include <string>
#include <sstream>
std::stringstream ss;
ss << seconds;
std::string ts = ss.str();
A nice wrapper around the above technique is Boost's lexical_cast:
#include <boost/lexical_cast.hpp>
#include <string>
std::string ts = boost::lexical_cast<std::string>(seconds);
And for questions like this, I'm fond of linking The String Formatters of Manor Farm by Herb Sutter.
UPDATE:
With C++11, use to_string().
Try this if you want to have the time in a readable string:
#include <ctime>
std::time_t now = std::time(NULL);
std::tm * ptm = std::localtime(&now);
char buffer[32];
// Format: Mo, 15.06.2009 20:20:00
std::strftime(buffer, 32, "%a, %d.%m.%Y %H:%M:%S", ptm);
For further reference of strftime() check out cppreference.com
The top answer here does not work for me.
See the following examples demonstrating both the stringstream and lexical_cast answers as suggested:
#include <iostream>
#include <sstream>
int main(int argc, char** argv){
const char *time_details = "2017-01-27 06:35:12";
struct tm tm;
strptime(time_details, "%Y-%m-%d %H:%M:%S", &tm);
time_t t = mktime(&tm);
std::stringstream stream;
stream << t;
std::cout << t << "/" << stream.str() << std::endl;
}
Output: 1485498912/1485498912
Found here
#include <boost/lexical_cast.hpp>
#include <string>
int main(){
const char *time_details = "2017-01-27 06:35:12";
struct tm tm;
strptime(time_details, "%Y-%m-%d %H:%M:%S", &tm);
time_t t = mktime(&tm);
std::string ts = boost::lexical_cast<std::string>(t);
std::cout << t << "/" << ts << std::endl;
return 0;
}
Output: 1485498912/1485498912
Found: here
The 2nd highest rated solution works locally:
#include <iostream>
#include <string>
#include <ctime>
int main(){
const char *time_details = "2017-01-27 06:35:12";
struct tm tm;
strptime(time_details, "%Y-%m-%d %H:%M:%S", &tm);
time_t t = mktime(&tm);
std::tm * ptm = std::localtime(&t);
char buffer[32];
std::strftime(buffer, 32, "%Y-%m-%d %H:%M:%S", ptm);
std::cout << t << "/" << buffer;
}
Output: 1485498912/2017-01-27 06:35:12
Found: here
Standard C++ does not have any time/date functions of its own - you need to use the C localtime and related functions.
the function "ctime()" will convert a time to a string.
If you want to control the way its printed, use "strftime". However, strftime() takes an argument of "struct tm". Use "localtime()" to convert the time_t 32 bit integer to a struct tm.
The C++ way is to use stringstream.
The C way is to use snprintf() to format the number:
char buf[16];
snprintf(buf, 16, "%lu", time(NULL));
Here's my formatter -- comments welcome. This q seemed like it had the most help getting me to my a so posting for anyone else who may be looking for the same.
#include <iostream>
#include "Parser.h"
#include <string>
#include <memory>
#include <ctime>
#include <chrono>
#include <iomanip>
#include <thread>
using namespace std;
string to_yyyyMMddHHmmssffffff();
string to_yyyyMMddHHmmssffffff() {
using namespace std::chrono;
high_resolution_clock::time_point pointInTime = high_resolution_clock::now();
std::time_t now_c = std::chrono::system_clock::to_time_t(pointInTime);
microseconds micros = duration_cast<microseconds>(pointInTime.time_since_epoch());
std::size_t fractional_microseconds = micros.count() % 1'000'000;
std:stringstream microstream;
microstream << "00000" << fractional_microseconds;
string formatted = microstream.str();
int index = formatted.length() - 6;
formatted = formatted.substr(index);
std::stringstream dateStream;
dateStream << std::put_time(std::localtime(&now_c), "%F %T") << "." << formatted;
formatted = dateStream.str();
return formatted;
}
There are a myriad of ways in which you might want to format time (depending on the time zone, how you want to display it, etc.), so you can't simply implicitly convert a time_t to a string.
The C way is to use ctime or to use strftime plus either localtime or gmtime.
If you want a more C++-like way of performing the conversion, you can investigate the Boost.DateTime library.
localtime did not work for me. I used localtime_s:
struct tm buf;
char dateString[26];
time_t time = time(nullptr);
localtime_s(&buf, &time);
asctime_s(dateString, 26, &buf);