I require the regex to match the following pattern in vbscript
[any single digit number] and :any four digit number/
That is, a open square bracket followed by a single digit number followed by a close square bracket or a colon followed by four digit number followed by a slash
I've tried the following pattern which select just a single digit also
[\[]*([:]*([0-9]{1,4})[/]*)[]]*
Thanks in advance,
Madhan
Try like this:
(\[\d\]|\:\d{4}\/)
Live Demo
This should work:
(\[\d\]|:\d{4}/)
Related
I am trying to create a basic regular expression to match a phone number which can either use dots [.] or hyphens [-] as the separator.
The format is 123.456.7890 or 123-456-7890.
The expression I am currently using is:
\d\d\d[-.]\d\d\d[-.]\d\d\d\d
The issue here is that it also matches the phone numbers that have both separators in them which I want to be termed as invalid/not a match. For example, with my expression, 123.456-7890 and 123-456.7890 show up as a match, something I do not want happening.
Is there a way to do that?
Use a backreference:
^\d{3}([.-])\d{3}\1\d{4}$
Here is an explanation of the regex:
^ from the start of the number
\d{3} match any 3 digits
([.-]) then match AND capture either a dot or a dash separator
\d{3} match any 3 digits
\1 match the SAME separator seen earlier
\d{4} match any 4 digits
$ end of the number
You can use this regex:
^\d{3}([-.])\d{3}\1\d{4}$
You can see that it works here.
Key point here - is that you capture your desired character using brackets ([-.])
and then reuse it with back reference \1.
I have an Url formatted as follow : https://www.mywebsite.com/subdomain/123456789.htm. I know that the webpage number is built with exactly 9 or 10 digits. I would like to extract this number using a Regex.
The Regex I use to perform this operation is :
^https://www.mywebsite.com/[A-Za-z0-9_.-~/]+([0-9]{9,10}).htm$
The problem is that when the number is 10 digits long, I get a match which is good but only the last 9 digits are captured. For example : https://www.mywebsite.com/subdomain/1234567890.htm captures 234567890 only.
I could easily create two regexes (one with 9 digits and one with 10) and take the longest number if both matches, but is there any elegant way to solve this problem using Regex?
EDIT
Following remarks which have been made below, there is actually a mistake in my original Regex : the first character group matches the first digit of the 10, and leaves only the 9 others for the capturing group. I've added a screenshot below. Adding a forward slash to the Regex before the capturing group solved the issue, thanks!
As per #TheFourthBird, you are missing a match on the forward slash. Maybe a slightly different approach to yours would be a non-capturing group:
^https://www.mywebsite.com/(?:[^/]+/)+(\d{9,10}).htm$
The character class [A-Za-z0-9_.-~/]+ matches all the character that follow until the end of the line.
This part ([0-9]{9,10}). will then backtrack until it can match the resulting digits, which it can starting from 9 digits and that will be in the capturing group.
Note to either escape the hyphen \- or place it at the start or end of the character class or else it could possible match a range.
One option is to use a word bounary \b before matching the digits
^https://www\.mywebsite\.com/[A-Za-z0-9_.~/-]+\b([0-9]{9,10})\.htm$
Regex demo
Another way could be matching the / right before the digits.
^https://www\.mywebsite\.com/[A-Za-z0-9_.~/-]+/([0-9]{9,10})\.htm$
Regex demo
If there can also be chars a-zA-Z or an underscoe before the digits and a lookbehind is supported, you could also assert that there is not a digit before (?<!\d)
^https://www\.mywebsite\.com/[A-Za-z0-9_.~/-]+(?<!\d)([0-9]{9,10})\.htm$
Regex demo
One more approach. This gets all the numbers between / and htm
(\d+)(?=\.htm)
RegexDemo
How to add suffix in a line using regex? This is my regex:
https://regex101.com/r/vV4zX8/1
The result should be like this:
My sample input is:
one
two
three
four
five
six
seven
So far all I've been able to come up with to use is:
\n replace with - digit \n
But I need the output of:
one - digit
two - digit
three - digit
four - digit
five - digit
six - digit
seven - digit
You can try the regex \b$ which ensures there's a match where a 'word' ends, and replace with - digit (or \b(\n|$) with a replacement of - digit$1 if you don't want to use multiline)
regex101 demo
You could also use ([^\r?\n])$
Regex:
(.+)$
or
(.)$
And don't forget to enable mulitine modifier m.
Replacement string:
\1 - digit
DEMO
You can try like this : check below image
For DEMO
I figured out a regular expresion for my country's phone but I've something missing.
The rule here is: (Area Code) Prefix - Sufix
Area Code could be 3 to 5 digits
Prefix could be 2 to 4 digits.
Area Code + Prefix is 7 digits long.
Sufix is always 4 digits long
Total digits are 11.
I figured I could have 3 simple regex chained with an OR "|" like this:
/(\(?\d{3}\)?[- .]?\d{4}[- .]?\d\d\d\d)|(\(?\d{4}\)?[- .]?\d{3}[- .]?\d\d\d\d)|(\(?\d{5}\)?[- .]?\d{2}[- .]?\d\d\d\d)/
The thing I'm doing wrong is that \d\d\d\d doesn't match only 4 digits for the sufix, for example: (011) 4740-5000 which is a valid phone number, works ok but if put extra digits it will also return as a valid phone number, ie: (011) 4740-5000000000
You should use ^ and $ to match whole string
For example ^\d{4}$ will match exactly 4 digits not more not less.
Here is the complete regex pattern
^((\(?\d{3}\)? \d{4})|(\(?\d{4}\)? \d{3})|(\(?\d{5}\)? \d{2}))-\d{4}$
Online demo
As per your regex pattern delimiter can be -,. or single space then try
^((\(?\d{3}\)?[-. ]?\d{4})|(\(?\d{4}\)?[-. ]?\d{3})|(\(?\d{5}\)?[-. ]?\d{2}))[-. ]?\d{4}$
This pattern works fine for me:
/^\\(?(\d{3,5})?\\)?\s?(15)?[\s|-]?(4)\d{2,3}[\s|-]?\d{4}$/
I've tested this in regex101:
/^((?:\(?\d{3}\)?[- .]?\d{4}|\(?\d{4}\)?[- .]?\d{3}|\(?\d{5}\)?[- .]?\d{2})[- .]?\d{4})$/
RegEx Demo
^ Matches the beginning of a string
( Beginning of capture group
(?: Beginning of non-capturing group
Your different options for area code & prefix
) End non-capturing group
[- .]?\d{4} The last four digits of the phone number
) End capture group
$ Matches the end of a string
If you're trying to validate such a phone number, then the following one should suit your needs:
^(?=.{15}$)[(]\d{3,5}[)] \d{2,4}-\d{4}$
Debuggex Demo
You need to match the complete expression by indicating the start and end with anchors. You also don't need alternation for the different lengths.
/^(?=(\D*\d){11}$)\(?\d{3,5}\)?[- .]?\d{2,4}[- .]?\d{4}$/
Here's the breakdown:
(?=(\D*\d){11}$) is a non-capturing group ensuring that there are 11 digits total,
with any number of non-digits amongst them
\(?\d{3,5}\)?[- .]? matches 3-5 digits in parens (area code), followed by a separator
\d{2,4}[- .]? matches 2-4 digits (prefix), followed by a separator
\d{4} matches the suffix
I'm trying to come up with some regex to match against 1 hyphen per any number of digit groups. No characters ([a-z][A-Z]).
123-356-129811231235123-1235612346123451235
/[^\d-]/g
The one above will match the string below, but it will let the following go through:
1223--1235---123123-------
I was looking at the following post How to match hyphens with Regular Expression? for an answer, but I didn't find anything close.
#Konrad Rudolph gave a good example.
Regular expression to match 7-12 digits; may contain space or hyphen
This tool is useful for me http://www.gskinner.com/RegExr/
Assuming it can't ever start with a hyphen:
^\d(-\d|\d)*$
broken down:
^ # match beginning of line
\d # match single digit
(-\d|\d)+ # match hyphen & digit or just a digit (0 or more times)
$ # match end of line
That makes every hyphen have to have a digit immediately following it. Keep in mind though, that the following are examples of legal patterns:
213-123-12314-234234
1-2-3-4-5-6-7
12234234234
gskinner example
Alternatively:
^(\d+-)+(\d+)$
So it's one or more group(s) of digits followed by hyphen + final group of digits.
Nothing very fancy, but in my tests it matched only when there were hyphen(s) with digits on both sides.