Array of pointers to class instance c++ - c++

This is the code I have so far, it compiles and runs fine but I need help adapting it. It is a banking app that currently works for just one account.
It needs to be adapted to with two new files: bank.h and bank.cpp and, main should contain a pointer to bank and bank should contain an array of pointers to instances of account.
so the new interface would work someting like:
account> 1 12
1 is the account# and 12 is the ammount being depositted.
I really need help adapting me code to do this, I am lost on how to create the array of pointers in bank to instances of account. Any help is much appreciated.
//main.cpp file
using namespace std;
#include <iostream>
#include <stdlib.h>
#include "account.h"
//allocate new space for class pointer
account* c = new account;
//function for handling I/O
int accounting(){
string command;
cout << "account> ";
cin >> command;
//exits prompt
if (command == "quit"){
exit(0);
}
//overwrites account balance
else if (command == "init"){
cin >> c->value;
c->init();
accounting();
}
//prints balance
else if (command == "balance"){
cout << "" << c->account_balance() << endl;
accounting();
}
//deposits value
else if (command == "deposit"){
cin >> c->value;
c->deposit();
accounting();
}
//withdraws value
else if (command == "withdraw"){
cin >> c->value;
c->withdraw();
accounting();
}
//error handling
else{
cout << "Error! Invalid operator." << endl;
accounting();
}
//frees memory
delete c;
}
int main() {
accounting();
return 0;
}
//account.h header file containing class with shared variables and functions
class account{
private:
int balance;
public:
account();
~account();
int value;
int account_balance();
int deposit();
int withdraw();
int init();
};
//account.cpp implementation file
using namespace std;
#include <iostream>
#include "account.h"
account::account(){
}
account::~account(){
}
//balance overwrite function
int account::init(){
balance = value;
}
//balance function
int account::account_balance() {
return balance;
}
//deposit function
int account::deposit(){
balance += value;
}
//withdraw function
int account::withdraw(){
//error handling
if(value>balance){
cout << "Error! insufficient funds." << endl;
return 0;
}
balance -= value;
}

First of all,
//error handling
else{
cout << "Error! Invalid operator." << endl;
accounting();
}
This look ugly, you are recursively calling accounting function after every bad input. Imagine a situation where user type 1 000 000x bad inputs... you will then try to free the memory 1 000 000x times - after one successful input!
//frees memory
delete c;
The whole accounting function is designed wrong. I suppose you don't want to destroy the account after some kind of transaction, right? I think the person who withdraws 10 dollars from their 10 million dollars account which will be then destroyed, will change bank immediately :)
So a while cycle with continue could be solution
//function for handling I/O
int accounting(){
string command;
while(true) {
cout << "account> ";
cin >> command;
//exits prompt
if (command == "quit"){
break;
}
//overwrites account balance
else if (command == "init"){
cin >> c->value;
c->init();
continue;
}
//prints balance
else if (command == "balance"){
cout << "" << c->account_balance() << endl;
continue;
}
//deposits value
else if (command == "deposit"){
cin >> c->value;
c->deposit();
accounting();
}
//withdraws value
else if (command == "withdraw"){
cin >> c->value;
c->withdraw();
continue;
}
//error handling
else{
cout << "Error! Invalid operator." << endl;
continue;
}
}
Then,
int value;
is not a class member, it should be argument of methods withdraw and deposit, like this
//deposit function
void account::deposit(int value){ //int changed to void, you are not returning anything!
balance += value;
}
//withdraw function
bool account::withdraw(int value){
//error handling
if(value>balance){
cout << "Error! insufficient funds." << endl;
return false;
}
if(value<0) {
cout << "Haha, nice try!" << endl;
return false;
}
balance -= value;
return true;
}

For an array you can use the std::vector class.
std::vector<account *>MyAccounts;
MyAccounts.push_back(new account());
Then you can use it like an array accessing it normally.
MyAccounts[i]->accountFunction();
update
I don't know enough about your code, so I give just some general examples here.
In your bank class you have a member like shown above )MyAccounts. Now when ever you add a new account to your bank, you can do it with the push back function.
For example to add a new account and set the initial amount of 100 moneyitems.
MyAccounts.push_back(new account());
size_t i = MyAccounts.size();
MyAccounts[i]->setAmount(100);

You can do something like below
class Bank
{
public:
int AddAccount(Account act){ m_vecAccts.push_back(act);}
....
private:
...
std:vector<account> m_vecAccts;
}
Update:
This is just a Bank class with vector of accounts as private member variable. AddAccount is public function which can add account to vector

Related

if else problem salary formula for loop desire loop user input

asking desire number to become the for loop(how many employee if input is 4 then 4 loop if 3 3 loops), salary formula not working, if else statement for string name to not accept number and vice versa integer to not accept letters. another one of my problem is how can I name the loop for example the question is name hours and rate then the cout should do 1. name hours rate, 2.name hours rate 3.name hours rate... the code is working.. just need some imporvements.
#include <iostream>
#include <cstdlib>
using namespace std;
void displayRules()
{
cout<<"====================="<<endl;
cout<<" EMPLOYEE-SALARY "<<endl;
cout<<"====================="<<endl;
cout<<" "<<endl;
}
int main()
{
char ans;
do
{
system("cls");
displayRules();
struct Employee
{
string name;
double hours;
double rate;
double salary;
Employee *next;
Employee *prev;
};
Employee *head;
head=NULL;
Employee *newEmployee;
Employee *EmpPointer;
Employee *nextEmpPointer;
Employee *prevEmpPointer;
string inpname;
int inpN;
double inphours;
double inprate;
double salary;
salary = (inprate*inphours);
for(int ctr=0; ctr<3; ctr++)
{
cout<<endl;
cout<<"Enter Name: \t\t";
cin>> inpname;
cout<<"Enter # Hours Worked: \t";
cin>> inphours;
if (inphours<0)
{
cout << "Invalid Input! Program Stopped. ";
return 0;
}
cout<<"Enter Rate per Hour: \t";
cin>> inprate;
if (inprate<0)
{
cout << "Invalid Input! Program Stopped. ";
return 0;
}
newEmployee = new Employee;
newEmployee->name=inpname;
newEmployee->hours=inphours;
newEmployee->rate=inprate;
newEmployee->next=NULL;
if (head==NULL)
head=newEmployee;
else
{
EmpPointer=head;
while (EmpPointer->next)
EmpPointer=EmpPointer->next;
EmpPointer->next=newEmployee;
}
}
cout<<endl;
Employee *displayPointer;
displayPointer=head;
system("cls");
cout<<"------------------------------------------------------------"<<endl;
cout<<" =Summary of PAYROLL= "<<endl;
cout<<"------------------------------------------------------------"<<endl;\
cout<<"Employee Name\t"<<"# Hours Worked\t"<<"Rate/Hour\t"<<"Salary\t"<<endl;
while (displayPointer)
{
cout<<displayPointer->name<<"\t\t";
cout<<displayPointer->hours<<"\t\t";
cout<<displayPointer->rate<<"\t\t";
cout<<displayPointer->salary<<endl;
displayPointer=displayPointer->next;
}
cout<<"------------------------------------------------------------"<<endl;
cout<<endl;
cout << "Would you like to run the program again? (Y/N) ";
cin>>ans;
}
while (ans == 'y' or ans == 'Y');
return 0;
}
Note: The salary wasn't being calculated so I fix that.
I broke your code into small functions in which each function only does one thing and one thing only (Single Responsibility Principle).
Also, I introduce function templates that allows you to reuse a function when you provide the type.
Finally, the code is missing a clean up of pointers to prevent memory leaks. Each time you use the keyword new to obtain a pointer to memory, you need later to check if the pointer contains null and if doesn't then use the keyword delete to free that memory, else you end with memory leaks in your code. Therefore, I leave you with the task to write the function that should iterate your employee list and free the memory to prevent memory leaks.
I hope this is useful.
#include <iostream>
#include <cstdlib>
using namespace std;
struct Employee {
string name;
double hours;
double rate;
double salary;
Employee *next;
Employee *prev;
};
void displayRules() {
cout<<"====================="<<endl;
cout<<" EMPLOYEE-SALARY "<<endl;
cout<<"====================="<<endl;
cout<<" "<<endl;
}
// Here we create a function template to make this code more reusable
template <typename T>
T consoleInput(const std::string& prompt) {
T value;
std::cout << prompt;
std::cin >> value;
return value;
}
// Lets create our own assert to exit the app.
void assertGreaterEqualThanZero(const double value, const std::string& prompt){
if (value < 0) {
cout << prompt;
exit(1);
}
}
// Small functions that do one thing only makes coding easy to debug
Employee* createEmployee(string name, int hours, int rate) {
Employee *newEmployee = new Employee;
newEmployee->name=name;
newEmployee->hours=hours;
newEmployee->rate=rate;
newEmployee->salary = (rate * hours);
newEmployee->next=NULL;
// You need to set and maintain ->prev
// if you are thinking on using a double linked list
// else remove it from the structure since is unused.
return newEmployee;
}
// This is a helper function to add new employees to a list
Employee* addToEmployeeList(Employee* list, Employee* newEmployee){
if (list==NULL) {
list = newEmployee;
} else {
Employee *EmpPointer = list;
while (EmpPointer->next)
EmpPointer=EmpPointer->next;
EmpPointer->next=newEmployee;
}
return list;
}
// The only purpose of this function is to print the list provided
void printEmployeList(Employee* employeeList){
Employee *currentEmployee = employeeList;
system("cls");
cout<<"------------------------------------------------------------"<<endl;
cout<<" =Summary of PAYROLL= "<<endl;
cout<<"------------------------------------------------------------"<<endl;
while (currentEmployee){
cout<<"Employee Name\t"<<"# Hours Worked\t"<<"Rate/Hour\t"<<"Salary\t"<<endl;
cout<<currentEmployee->name<<"\t\t";
cout<<currentEmployee->hours<<"\t\t";
cout<<currentEmployee->rate<<"\t\t";
cout<<currentEmployee->salary<<endl;
cout<<"------------------------------------------------------------"<<endl;
currentEmployee=currentEmployee->next;
}
}
// I leave you with this piece that is missing.
// TODO: create function that delete each employee in the list,
// then deletes the list in order to prevent memory leaks
int main() {
char ans;
do {
system("cls");
displayRules();
Employee *employeeList;
employeeList=NULL;
for(int ctr=0; ctr<3; ++ctr) {
// Lets declare and instantiate when we need it.
string name = consoleInput<string>("Enter Name: \t\t");
// No need to use inp (as inphours) in front of your variables
// It makes it harder to read. Just put hours as a name.
double hours = consoleInput<double>("Enter # Hours Worked: \t");
assertGreaterEqualThanZero(hours, "Invalid Input! Program Stopped.");
double rate = consoleInput<double>("Enter Rate per Hour: \t");
assertGreaterEqualThanZero(rate, "Invalid Input! Program Stopped. ");
Employee *newEmployee = createEmployee(name, hours, rate);
employeeList = addToEmployeeList(employeeList, newEmployee);
}
cout << endl;
printEmployeList(employeeList);
cout << "Would you like to run the program again? (Y/N) ";
cin>>ans;
} while (ans == 'y' or ans == 'Y');
return 0;
}

C++ program stuck in an infinite loop

Please note that I am a complete beginner at C++. I'm trying to write a simple program for an ATM and I have to account for all errors. User may use only integers for input so I need to check if input value is indeed an integer, and my program (this one is shortened) works for the most part.
The problem arises when I try to input a string value instead of an integer while choosing an operation. It works with invalid value integers, but with strings it creates an infinite loop until it eventually stops (unless I add system("cls"), then it doesn't even stop), when it should output the same result as it does for invalid integers:
Invalid choice of operation.
Please select an operation:
1 - Balance inquiry
7 - Return card
Enter your choice and press return:
Here is my code:
#include <iostream>
#include <string>
using namespace std;
bool isNumber(string s) //function to determine if input value is int
{
for (int i = 0; i < s.length(); i++)
if (isdigit(s[i]) == false)
return false;
return true;
}
int ReturnCard() //function to determine whether to continue running or end program
{
string rtrn;
cout << "\nDo you wish to continue? \n1 - Yes \n2 - No, return card" << endl;
cin >> rtrn;
if (rtrn == "1" and isNumber(rtrn)) { return false; }
else if (rtrn == "2" and isNumber(rtrn)) { return true; }
else {cout << "Invalid choice." << endl; ReturnCard(); };
return 0;
}
int menu() //function for operation choice and execution
{
int choice;
do
{
cout << "\nPlease select an operation:\n" << endl
<< " 1 - Balance inquiry\n"
<< " 7 - Return card\n"
<< "\nEnter your choice and press return: ";
int balance = 512;
cin >> choice;
if (choice == 1 and isNumber(to_string(choice))) { cout << "Your balance is $" << balance; "\n\n"; }
else if (choice == 7 and isNumber(to_string(choice))) { cout << "Please wait...\nHave a good day." << endl; return 0; }
else { cout << "Invalid choice of operation."; menu(); }
} while (ReturnCard()==false);
cout << "Please wait...\nHave a good day." << endl;
return 0;
}
int main()
{
string choice;
cout << "Insert debit card to get started." << endl;
menu();
return 0;
}
I've tried every possible solution I know, but nothing seems to work.
***There is a different bug, which is that when I get to the "Do you wish to continue?" part and input any invalid value and follow it up with 2 (which is supposed to end the program) after it asks again, it outputs the result for 1 (continue running - menu etc.). I have already emailed my teacher about this and this is not my main question, but I would appreciate any help.
Thank you!
There are a few things mixed up in your code. Always try to compile your code with maximum warnings turned on, e.g., for GCC add at least the -Wall flag.
Then your compiler would warn you of some of the mistakes you made.
First, it seems like you are confusing string choice and int choice. Two different variables in different scopes. The string one is unused and completely redundant. You can delete it and nothing will change.
In menu, you say cin >> choice;, where choice is of type int. The stream operator >> works like this: It will try to read as many characters as it can, such that the characters match the requested type. So this will only read ints.
Then you convert your valid int into a string and call isNumber() - which will alway return true.
So if you wish to read any line of text and handle it, you can use getline():
string inp;
std::getline(std::cin, inp);
if (!isNumber(inp)) {
std::cout << "ERROR\n";
return 1;
}
int choice = std::stoi(inp); // May throw an exception if invalid range
See stoi
Your isNumber() implementation could look like this:
#include <algorithm>
bool is_number(const string &inp) {
return std::all_of(inp.cbegin(), inp.cend(),
[](unsigned char c){ return std::isdigit(c); });
}
If you are into that functional style, like I am ;)
EDIT:
Btw., another bug which the compiler warns about: cout << "Your balance is $" << balance; "\n\n"; - the newlines are separated by ;, so it's a new statement and this does nothing. You probably wanted the << operator instead.
Recursive call bug:
In { cout << "Invalid choice of operation."; menu(); } and same for ReturnCard(), the function calls itself (recursion).
This is not at all what you want! This will start the function over, but once that call has ended, you continue where that call happened.
What you want in menu() is to start the loop over. You can do that with the continue keyword.
You want the same for ReturnCard(). But you need a loop there.
And now, that I read that code, you don't even need to convert the input to an integer. All you do is compare it. So you can simply do:
string inp;
std::getline(std::cin, inp);
if (inp == "1" || inp == "2") {
// good
} else {
// Invalid
}
Unless that is part of your task.
It is always good to save console input in a string variable instead of another
type, e.g. int or double. This avoids trouble with input errors, e.g. if
characters instead of numbers are given by the program user. Afterwards the
string variable could by analyzed for further actions.
Therefore I changed the type of choice from int to string and adopted the
downstream code to it.
Please try the following program and consider my adaptations which are
written as comments starting with tag //CKE:. Thanks.
#include <iostream>
#include <string>
using namespace std;
bool isNumber(const string& s) //function to determine if input value is int
{
for (size_t i = 0; i < s.length(); i++) //CKE: keep same variable type, e.g. unsigned
if (isdigit(s[i]) == false)
return false;
return true;
}
bool ReturnCard() //function to determine whether to continue running or end program
{
string rtrn;
cout << "\nDo you wish to continue? \n1 - Yes \n2 - No, return card" << endl;
cin >> rtrn;
if (rtrn == "1" and isNumber(rtrn)) { return false; }
if (rtrn == "2" and isNumber(rtrn)) { return true; } //CKE: remove redundant else
cout << "Invalid choice." << endl; ReturnCard(); //CKE: remove redundant else + semicolon
return false;
}
int menu() //function for operation choice and execution
{
string choice; //CKE: change variable type here from int to string
do
{
cout << "\nPlease select an operation:\n" << endl
<< " 1 - Balance inquiry\n"
<< " 7 - Return card\n"
<< "\nEnter your choice and press return: ";
int balance = 512;
cin >> choice;
if (choice == "1" and isNumber(choice)) { cout << "Your balance is $" << balance << "\n\n"; } //CKE: semicolon replaced by output stream operator
else if (choice == "7" and isNumber(choice)) { cout << "Please wait...\nHave a good day." << endl; return 0; }
else { cout << "Invalid choice of operation."; } //CKE: remove recursion here as it isn't required
} while (!ReturnCard()); //CKE: negate result of ReturnCard function
cout << "Please wait...\nHave a good day." << endl;
return 0;
}
int main()
{
string choice;
cout << "Insert debit card to get started." << endl;
menu();
return 0;
}

Function with structure as argument producing error: free(): invalid pointer: 0x00007efd47b

I've made an addDepartment function that takes a structure as an argument. When I enter input to initialize the "dept[counter].departmentHead" at the bottom of the function, it triggers the error message.
I'm copying the logic from another code I wrote using classes instead of structures and that one works fine so I'm really not sure why this one isn't working. Tried messing with the index to make sure I wasn't going over the size of the array but that doesn't seem to fix the issue.
#include <iostream>
#include <fstream>
#include <iomanip>
#include <cstring>
using namespace std;
struct Department{
string departmentName;
string departmentHead;
int departmentID;
double departmentSalary;
};
//...
Department addDepartment(Department dept[3]){
int repeat=0;
int counter=0;
if (counter>2){
cout<<"The array is full, you can not add any more Departments."<<endl;
}
else{
cout << "Please Enter Department Details:"<<endl;
cout << "Department ID : ";
cin >> dept[counter].departmentID;
for(int x=0; x<3; x++){
for (int y=x+1; y<3; y++){
if(dept[x].departmentID==dept[y].departmentID)
repeat++;
}
}
if(repeat!=0)
cout<<"Value must be unique!"<<endl;
else{
cout << "Department Name : ";
cin >> dept[counter].departmentName;
cout << "Head of Department : ";
cin >> dept[counter].departmentHead;
counter++;
}
}
}
//...
int main()
{
Employee emp[5];
Department dept[3];
initialID(emp,dept,0);
initialID(emp,dept,1);
int response;
while(response!=6){
displayMenu();
cout<< "Please make a selection : \n";
cin >> response;
while((response!=1)&&(response!=2)&&(response!=3)&&(response!=4)&&(response!=5)&&(response!=6)){
cout<< "Please enter a valid choice (1 - 6): ";
cin >> response;
}
if(response==1){
addDepartment(dept);
}
else if(response==2){
//addEmployee(emp,dept);
}
else if(response==3){
}
else if(response==4){
}
else if(response==5){
//salaryReport(dept);
}
}
cout << "Thank you, goodbye.";
}
Why it breaks.
The addDepartment function never actually returns a department. When the function exits, the space where the return newly created Department would be is left uninitialized. This causes undefined behavior. The compiler tries to destruct the Department object like it normally would, but because it was never initialized, free gets called on garbage (causing the error).
We can fix this by adding a line to addDepartment returning the actual department:
Department addDepartment(Department dept[3]){
int repeat=0;
int counter=0;
if (counter>2){
cout<<"The array is full, you can not add any more Departments."<<endl;
}
else{
cout << "Please Enter Department Details:"<<endl;
cout << "Department ID : ";
cin >> dept[counter].departmentID;
for(int x=0; x<3; x++){
for (int y=x+1; y<3; y++){
if(dept[x].departmentID==dept[y].departmentID)
repeat++;
}
}
if(repeat!=0)
cout<<"Value must be unique!"<<endl;
else{
cout << "Department Name : ";
cin >> dept[counter].departmentName;
cout << "Head of Department : ";
cin >> dept[counter].departmentHead;
counter++;
}
}
return /* some department */;
}
Alternatively, you could make addDepartment void.
Other considerations. Don't pass raw C arrays to functions. It doesn't do what you intend.
If you want to pass a copy of an array, pass a std::array, which will be copied automatically:
Department addDepartment(std::array<Department, 3> dept);
If want to access the elements of an existing array, pass a pointer:
Department addDepartment(Department* dept, int count);
One problem that I see is that you are creating an array of 3 Department objects in main and assuming that you have 5 elements in initialID.
Change main to create an array of 5 Department objects.
int main()
{
Employee emp[5];
Department dept[5];
...

Why string comparison results an infinite loop

I have a Plane's entity class such as:
class Plane{
private:
string tailNumber;
public:
void setTail(string tail);
string getTail();
}
and a Planes' collection class such as:
class Planes{
public:
void addPlane();
void printDetails();
void printAllPlanes();
private:
vector<Plane> currentPlane;
}
addPlane definition:
void Planes::addPlane(){
Plane a;
string temp;
cout << "Enter tail:";
getline(cin, temp);
a.setTail(temp);
currentPlane.push_back(a);
}
My printDetails definition:
void Planes::printDetails()
{
cout << "Enter Plane's Tail Number: ";
getline(cin, tail);
cin.ignore();
for (unsigned int i = 0; i < currentPlane.size(); i++)
{
if (currentPlane[i].getTailNumber() == tail)
{
//print tail number by calling accessor function}
}
else
{
cout << "Error.";
}
}
and my main class:
int main(){
Plane a;
int userChoice;
do{
cout << "1.Add Plane";
cout << "2.Print All Planes";
cout << "3.Print a plane";
cout << "4.Quit";
cin >> userChoice;
if (userChoice == 1)
a.addPlane();
else if (userChoice == 2)
a.printAllPlanes();
else if (userChoice == 3)
a.printDetails();
}while (userChoice != 4);
return 0;
}
I am successfully adding a new object and print all objects in my vector to display. The problem is if my tail number is: "TGA", then running currentPlane[0].getTail() return "TGA". However, when compare the user-input variable tail = "TGA" with currentPlane[0].getTail() = "TGA" yields an infinite-loop of do-while menu for some reason that I do not understand (because it is a simple string comparison?).
If I only enter integer value such as "12345", then it will jump to the else branch instead of infinite-looping. If I enter any alphanumeric value, then the infinite-looping will appear again.
Can you help me, please?
Nothing to do with string comparisons, the problem with your code is at no point do you set the variable userChoice.
Presumably you meant to have some code somewhere like
cin >> userChoice;
but you don't have anything like that, so the behaviour of your program is undefined.
You really should have had a compiler warning telling you that you are using an uninitialised variable. Pay attention to compiler warnings and fix any that you get.

Processing values in each text file one at a time c++

I'm trying to processes values from two text files.One holds a set of chars and the other holds a set of integers.each in their respective places in the text file will amount to one test case.For example the first value that is read in each text file is 1 test case.The values are then used to be checked for variability then Which will then be used as variables through out my code.then in the end prints out a double. The issue is I do not know how to reach that second iteration of test cases. All my code does is read the first values of each text file and prints out the double i need but for only the first test case. As i was typing this out i thought of maybe deleting the values once they are done being used then rerunning the program by having my main in a for loop? suggestions?
#include <iostream>
#include <fstream>
using namespace std;
//function prototypes
char getPackage();
bool vaildPackage(char);
int getHours();
bool validHours(int);
double calculatePakg_A(int);
double calculatePakg_B(int);
double calculatePakg_C(int);
void showBill(double);
int main()
{
char Package = getPackage();
int Hours = getHours();
double bill;
switch (Package)
{
case 'A':bill = calculatePakg_A(Hours);
cout << bill << endl;
break;
case 'B':bill = calculatePakg_B(Hours);
cout << bill << endl;
break;
case 'C':bill = calculatePakg_C(Hours);
cout << bill << endl;
break;
case 'a':bill = calculatePakg_A(Hours);
cout << bill << endl;
break;
case 'b':bill = calculatePakg_B(Hours);
cout << bill << endl;
break;
case 'c':bill = calculatePakg_C(Hours);
cout << bill << endl;
break;
default: cout << "you did not enter a valid Service Plan. \n";
break;
}
return 0;
}
char getPackage()
{
ifstream inputFile;
char a;
inputFile.open("Packages.txt");
do
{
inputFile >> a;
} while (! vaildPackage(a));
return a;
}
bool vaildPackage(char a)
{
return a == 'a' || a == 'A'|| a == 'B' || a == 'b'|| a == 'C' || a == 'c';
}
int getHours()
{
ifstream inFile;
int n;
inFile.open("Hours.txt");
do
{
inFile >> n;
} while (! validHours(n));
return n;
}
bool validHours(int n)
{
return n>=0 && n<= 720;
}
double calculatePakg_A(int hrs)
{
if(hrs <=50)
{
return 15.00;
}
else
{
return (hrs-50) * 2.00 + 15;
}
}
double calculatePakg_B(int hrs)
{
if(hrs <=100)
{
return 20.00;
}
else
{
return (hrs-100) * 1.50 + 20.00;
}
}
double calculatePakg_C(int hrs)
{
if(hrs <=150)
{
return 25.00;
}
else
{
return (hrs-150) * 1.00 + 25.00;
}
}
Package.txt
A a B b C c e c
Hours.txt
50 51 100 101 149 251 750 722
As I'm sure you know, you can read multiple fields from a stream:
ifstream inputFile;
char a;
inputFile.open("Packages.txt");
inputFile >> a;
cout << a << endl;
inputFile >> a;
cout << a << endl;
The reason your code doesn't work is that when control returns from getPackage(), the variable inputFile is deleted, so every time you call that function, it opens the file anew and starts reading from the beginning.
One solution is to make the input stream a static variable, so that it will not be deleted, but will maintain its state from one call to the next:
char getPackage()
{
static ifstream inputFile("Packages.txt");
char a;
inputFile >> a;
return a;
}
I think the only issue here is this.
In the function getPackage()
inputFile.open("Packages.txt");
This opens the file every time you call this function
Due to this, this function is reading the first entry (only) every time.
The same issue with getHours function.
One way out is you can read all entries from the file once into a data structure, say vector and iterate through the vector in the main function.
Another way is open the file(s) in main function and introduce a loop in main that calls these functions. Every time they are called, they would return the next entry from the file. This requires passing the opened file ifstream & as an argument to functions getHours and getPackage