How to clip only intersection (not union) of clipping planes? - opengl

Question

In OpenGL/JOGL, when using more than one clipping plane, the union of all clipping planes appears to be applied. What I want is instead the intersection of all clipping planes to be applied. Is this possible? See the below simplified 2-D example.
Edit: An example of clipping by vertex shader (see comments below).

Answer 1

Multi-pass:
#include <GL/glut.h>
void scene()
{
glColor3ub( 255, 0, 0 );
glBegin( GL_QUADS );
glVertex2i( -1, -1 );
glVertex2i( 1, -1 );
glVertex2i( 1, 1 );
glVertex2i( -1, 1 );
glEnd();
}
void display()
{
glClear( GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT );
glMatrixMode( GL_PROJECTION );
glLoadIdentity();
double w = glutGet( GLUT_WINDOW_WIDTH );
double h = glutGet( GLUT_WINDOW_HEIGHT );
double ar = w / h;
glOrtho( -2 * ar, 2 * ar, -2, 2, -1, 1);
glMatrixMode( GL_MODELVIEW );
glLoadIdentity();
glEnable( GL_CLIP_PLANE0 );
// -y plane
GLdouble plane0[] = { -1, 0, 0, 0 };
glClipPlane( GL_CLIP_PLANE0, plane0 );
scene();
// -x plane
GLdouble plane1[] = { 0, -1, 0, 0 };
glClipPlane( GL_CLIP_PLANE0, plane1 );
scene();
glutSwapBuffers();
}
int main( int argc, char **argv )
{
glutInit( &argc, argv );
glutInitDisplayMode( GLUT_RGBA | GLUT_DEPTH | GLUT_DOUBLE );
glutInitWindowSize( 640, 480 );
glutCreateWindow( "Clipping" );
glutDisplayFunc( display );
glutMainLoop();
return 0;
}

Answer 2

Using glClipPlane, no. Vertices are clipped if they are outside the positive halfspace of at least one plane. Once that happens, it doesn't matter what any other plane may be.
However, you can get this effect (or almost any other effect) by writing appropriate values to gl_ClipDistance in a vertex shader.
Any portion where the interpolated value that you write out is less than 0.0 ("negative halfspace") will be clipped, and you can write any value you like, e.g. the squared distance to a point, or the sum of distances to two planes, or anything else you calculate.