Perform an XSLT Logic - xslt

Question

input:
<Move-Afile>
<Afile>
<Item>
<suppliercode>1</suppliercode>
<PackNumber>1234</PackNumber>
<Item85>
<Quantity>12</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>2</suppliercode>
<PackNumber>567</PackNumber>
<Item85>
<Quantity>3</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>1</suppliercode>
<PackNumber>567</PackNumber>
<Item85>
<Quantity>8</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>3</suppliercode>
<PackNumber>126</PackNumber>
<Item85>
<Quantity>11</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>4</suppliercode>
<PackNumber>876</PackNumber>
<Item85>
<Quantity>32</Quantity>
</Item85>
</Item>
</Afile>
</Move-Afile>
xslt:
i need the solution like the xsl should contain for-each structure like below.
If supplier codes are equal then we have to sum the quantity values of those nodes,otherwise directly map the quantity value.
<xsl:for-each select="/Move-Afile/Afile/Item">
<xsl:choose>
<xsl:when test="suppliercode=suppliercode>
<xsl:value-of select=sum(Quantity)"/><!-- sum of quantity where nodes have equal supplier code-->
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="Quantity"/><!-- map directly the quantity value-->
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
output:
<A>
<target>
<Item>
<Quantity>20</Quantity>
</Item>
<Item>
<Quantity>3</Quantity>
</Item>
<Item>
<Quantity>20</Quantity>
</Item>
<Item>
<Quantity>11</Quantity>
</Item>
<Item>
<Quantity>32</Quantity>
</Item>
</target>
</A>

Answer 1

You don't really need an xsl:choose here, just a single sum statement to sum all Quantity elements for Item elements with the same suppliercode (which include the current node you are on).
<xsl:value-of select="sum(//Item[suppliercode = current()/suppliercode]/Item85/Quantity)"/>
However, it would be more efficient to make use of a key to look for matching Item elements:
<xsl:key name="Item" match="Item" use="suppliercode" />
Then the sum statement is simplified to this
<xsl:value-of select="sum(key('Item', suppliercode)/Item85/Quantity)"/>
You might also like to consider using the XSLT identity transform in building your output XML, as this would be more flexible. You would probably only need a template matching the Quantity element in this case
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="Item" match="Item" use="suppliercode" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Quantity">
<xsl:copy>
<xsl:value-of select="sum(key('Item', ../../suppliercode)/Item85/Quantity)"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When applied to your XML, the following is output
<Move-Afile>
<Afile>
<Item>
<suppliercode>1</suppliercode>
<PackNumber>1234</PackNumber>
<Item85>
<Quantity>20</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>2</suppliercode>
<PackNumber>567</PackNumber>
<Item85>
<Quantity>3</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>1</suppliercode>
<PackNumber>567</PackNumber>
<Item85>
<Quantity>20</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>3</suppliercode>
<PackNumber>126</PackNumber>
<Item85>
<Quantity>11</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>4</suppliercode>
<PackNumber>876</PackNumber>
<Item85>
<Quantity>32</Quantity>
</Item85>
</Item>
</Afile>
</Move-Afile>
If you do want to change or remove other elements, just add separate templates for each case accordingly.