I'm trying to match a pattern using RegEx in notepad++, but not having much luck. I'm able to match part but not all of it.
I need to search for this line:
<size value="Large" pax="13074"/>
And replace it with this:
<size value="Very_large" pax="41450" cargo="Largest" cargovolume="3227"/>
Essentially I need to find all patterns matching pax="n"/> and replace them with pax="n" cargo="Largest" cargovolume="0"/> while retaining the initial value of n.
So, ideas anyone?
Press Ctrl + F, move to tab Replace, in Find what do: pax="(\d+)" and in Replace with put this: pax="\1" cargo="Largest" cargovolume="0"
Remember to mark regex. That should retain the number and replace the content.
UPDATE: Hint about saving text for replacement.
Whenever you use regex to do text replacement, wrap the content you want to save in parenthesis and then you can access them using \i where i is the order of appearance of the parenthesis starting at 1.
Hope it helps!
Related
I would like to append _OLD to the end of each strings that starts with SR_ but before the symbol ' or without it
For example my text is the following:
SR_Apple
When the 'SR_APPLE' rotten, we must discard it.
I would like the find and replace to do:
SR_Apple_OLD
When the 'SR_APPLE_OLD' rotten, we must discard it.
I have tried (SR_*)+$.*(?='\s) based on what i Learned but no luck so far. Please help. Thx in Adv
For simple cases you should be able to use
Find: (\bSR_[\w]+)
Replace: $1_OLD
(\bSR_.+?)('|$) and $1_OLD$2 could also work if the text after SR_ is more complex
The lookbehind you're using is only matching the string if it ends with a ' so it won't find the text not in quotes.
regex101 is a useful tool for debugging expressions
I'm extracting case numbers from a wall of text. How do I filter out all the useless text using the replace function in Notepad++ with the help of RegEx? The parts I want to keep are made up of letters, digits, and a hyphen (SPP-1803-2045227).
I would like to turn this...
(SPP-1803-2045227)Useless text goes here. 2019-05-18 *
(SPP-1915-1802667)More useless text. 2019-01-14 *
(SPP-1904-1012523)And some more. 2019-02-03 *
...into this:
SPP-1803-2045227
SPP-1915-1802667
SPP-1904-1012523
I've been playing around with RegEx and also found something in another thread on here before, which wasn't the solution but came very close. Unfortunately I can't find it anymore. It looked something like this:
^(?!S\w+).*\r?\n?
Any help is appreciated.
you could try something like this.
find: .*\((\w{3}-\d{4}-\d{7})\).*
replace with: \1
The above Regular Expression matches the whole line with your letters and digits between an extra pair of parentheses.
When you replace with \1 you keep only the match between parentheses.
Remember to select Regular Expression Search mode.
I don't know anything about Notepad++ Regex.
This is the data I have in my CSV:
6454345|User1-2ds3|62562012032|324|148|9c1fe63ccd3ab234892beaf71f022be2e06b6cd1
3305611|User2-42g563dgsdbf|22023001345|0|0|c36dedfa12634e33ca8bc0ef4703c92b73d9c433
8749412|User3-9|xgs|f|98906504456|1534|51564|411b0fdf54fe29745897288c6ad699f7be30f389
How can I use a Regex to remove the 5th and 6th column? The numbers in the 5th and 6th column are variable in length.
Another problem is the User row can also contain a |, to make it even worse.
I can use a macro to fix this, but the file is a few millions lines long.
This is the final result I want to achieve:
6454345|User1-2ds3|62562012032|9c1fe63ccd3ab234892beaf71f022be2e06b6cd1
3305611|User2-42g563dgsdbf|22023001345|c36dedfa12634e33ca8bc0ef4703c92b73d9c433
8749412|User3-9|xgs|f|98906504456|411b0fdf54fe29745897288c6ad699f7be30f389
I am open for suggestions on how to do this with another program, command line utility, either Linux or Windows.
Match \|[^|]+\|[^|]+(\|[^|]+$)
Repalce $1
Basically, Anchor to the end of the line, and remove columns [-1] and [-2] (I assume columns can't be empty. Replace + with * if they can)
If you need finer detail then that, I'd recommend writing a Java or Python script to manual parse and rewrite the file for you.
I've captured three groups and given them names. If you use a replace utility like sed or vimregex, you can replace remove with nothing. Or you can use a programming language to concatenate keep_before and keep_after for the desired result.
^(?<keep_before>(?:[^|]+\|){3})(?<remove>(?:[^|]+\|){2})(?<keep_after>.*)$
You may have to remove the group namings and use \1 etc. instead, depending on what environment you use.
Demo
From Notepad++ hit ctrl + h then enter the following in the dialog:
Find what: \|\d+\|\d+(\|[0-9a-z]+)$
Replace with: $1
Search mode: Regular Expression
Click replace and done.
Regex Explain:
\|\d+ : match 1st string that starts with | followed by number
\|\d+ : match 2nd string that starts with | followed by number
(\|[0-9a-z]+): match and capture the string after the 2nd number.
$ : This is will force regex search to match the end of the string.
Replacement:
$1 : replace the found string with whatever we have between the captured group which is whatever we have between the parentheses (\|[0-9a-z]+)
I have a txt file with <i> and </i> between words that I would like to remove using Editpad
For example, I'd like to keep when it's like this:
<i>Phrases and words.</i>
And I'd like to remove the </i> and <i> tags inside the phrase, when it's like this:
<i>Phrases</i>and<i> words.</i>
<i>Phrases</i>and <i>words.</i>
I was trying to do that using regex, but I couldn't do it.
As the tag is followed by space or a word character I could find when the line has the double tag with
/ <i>|<\/i> /
but this way I can't just press replace for nothing, I have to edit line by line I search.
There's anyway to accomplish that?
* Edited *
Another example of lines found on the subtitle text
<i>- find me on the chamber.</i>
- What? <i>Go. Go, go, go!</i>
Rule number one: you can't parse html with regex.
That being said, if you know each line follows a certain pattern, you can usually hack something together to work. ;)
If I've understood correctly, it looks like you can simply remove all <i> and </i> that aren't either at the beginning or end of the lines. In that case, one method you could try is the following regex:
(?<=.)\<\/?i\>(?=.)
This will match the tags, with a lookahead and behind to make sure that we aren't at the end/start of a line (by checking if another character exists in front/behind. (Note that typically matched characters in a lookahead/behind won't be replaced when you search/replace.)
Disclaimer: this works on regex101, but notepad++ may have some differences to the pcre regex style.
update to work with Editpad
EDIT: since this question is actually wanting to know how to do this in Editpad, below is a modified alternative:
Try searching for the regex: (.)\<\/?i\>(.). This will match (and capture) exactly one character before and after the <i> tags.
When replacing, use backreferences to replace the entire match with the two captured characters - a replacement string of \1\2 should work.
I have a large logfile (+100 000 lines) in XML like so:
<container>
<request:getApples xml="...">
...
</request:getApples>
<request:getOranges xml="...">
...
</request:getOranges>
</container>
...
I want to extract the :getXXXX part to
getApples
getOranges
by doing a regex find & replace in Sublime Text 2.
Something like
Find: [^(request:)]*(.*) xml
Replace: $1\n
Any regex masters that can assist?
Correcting mart1n's answer and actually using ST2 and your sample input, I came up with the following:
First, CtrlA to select all. Then, CtrlH,
Search: .*?(get\w+) .*
Replace: $1
Replace All
Then,
Search: ^[^get].*$
Replace: nothing
Replace All
Finally,
Search: ^\n
Replace: nothing
Replace All
And you're left with:
getApples
getOranges
Not familiar with Sublime Text but you can do in two parts:
Find .*?\(get\w+\) .* and replace with \1. Now those get* strings are on separate lines with nothing else. All that remains is to remove the cruft.
So, many ways to do this. Easy one: find ^[^g][^e][^t].*$ and replace with nothing (an empty string).
Now you have your file that contains just the string you want and some empty lines, which (I hope) Sublime can get rid of with some delete-empty-lines function.
You can quickly throw all of the above in a macro and execute at will for any input following the same format ;-)
If you're willing to take the problem out of sublime text, you can use the dotall flag along with lazy matching to extract only the getXXX parts.
Replacing
.*?(get\w*) .*?
with
$1\n
should get you most of the way, only leaving a bit of easily removeable closing tags at the end of the file that I can't figure out at present.
You can check this solution here.
Maybe someone could take this and figure out a way to remove the extra closing tags.
Try this
Find what: :(\w+)>|.\s?
Replace with: $1
And if didn't work as intended, then let me know?