I am using the following code to find the difference between two dates basically one is current system date and another server date. I am getting different values at different times, hence I changed the format to only include dates and not datetimes. But still the difference of values remains the same issue. Issue as mentioned in the src line comments.
//dtHigher retrieved from a file from Server
COleDateTime datetimetmp = COleDateTime::GetCurrentTime();
CString strhigherDt = dtHigher.Format(_T("%d/%m/%Y")); //12/07/2022
CString strcurrentDt = datetimetmp.Format(_T("%d/%m/%Y")); //07/07/2022
COleDateTime dateHigher, dateCurrent;
dateHigher.ParseDateTime(strhigherDt);
dateHigher.ParseDateTime(strcurrentDt);
COleDateTimeSpan spanDays = dateHigher - dateCurrent;
CString strdatespan = spanDays.Format(_T("%D.%H.%M.%S")); //this gives some times 4.23.59.59, some times 5.00.00.00
int daysRem = (int) ::ceil(spanDays.GetTotalDays()); //based on above return value, its either 4 or 5
Hello I was able to solve it by getting the date, month and year separately from COleDateTime class and getting the difference manually. Thanks for all the help.
i have been trying to convert a string to date using
${test:toString():toDate('dd-MMM-yy HH.mm.ss.SSSSSSSSS'):format('dd-MMM-yy HH.mm.ss.SSSSSSSSS')}
my value for test attribute is like 13-MAR-20 15.50.41.396000000
when i'm using the above mentioned expression to convert the string to Date, it actually is changing the date as below:
test (input value):
13-MAR-20 15.50.41.396000000
time (output value)
18-Mar-20 05.50.41.000000000
please advise!
I ran into a similar issue with date time encoded in ISO 8601.
The problem is, that the digits after the second are defined as fragment of a second, not milliseconds. If it has 3 digits, it equivalent to milliseconds. If more than 3, the toDate() function parse the fragment of a second as milliseconds. In your case 396000000 milliseconds = 4,58333333 days.
I solved my issue with replaceAll() by cutting digits to first 3.
${test:replaceAll('(\.[0-9]{3})([0-9]+)','$1')}
But my value was formatted as 18-06-20T05:50:41.396000000, so maybe you have to adjust the regex.
I have a google sheet script that fetches youtube's video durations. The problem is the time data is in the ISO 8601 format.
For example:
PT3M23S
The formula I'm using right now does a good job converting this into a more readable format.
=iferror(REGEXREPLACE(getYoutubeTime(B20),"(PT)(\d+)M(\d+)S","$2:$3"))
It converts the above into a more readable format 3:23
Now the issue at hand is if the duration of the video is exactly 3 minutes or if the video is shorter than 1 minute regexreplace doesn't reformat it.
Instead it reads
PT4M OR PT53S
Is there a way to edit the formula to address each variant that potential could occur?
Where it would format PT4M into 4:00 or PT53S into 0:53
Lastly, if the seconds in the duration are between 1-9 the API returns a single digit value for the seconds. Which means the formula above will look wrong. For example, PT1M1S is formatted into 1:1 when it should read 1:01
It would be great if the formula could account for the first 9 seconds and add a 0 to make it more readable.
Thanks for reading this far, if anyone could help me out I'd very much appreciate it.
Just in case its easier to do this within the script itself here's the custom script that retrieves the video duration.
function getYoutubeTime(videoId){
var url = "https://www.googleapis.com/youtube/v3/videos?part=contentDetails&id=" + videoId;
url = url + "&key=";
var videoListResponse = UrlFetchApp.fetch(url);
var json = JSON.parse(videoListResponse.getContentText());
return json["items"][0]["contentDetails"]["duration"];
}
Is very ugly, but seems to work for the examples provided:
=iferror(left(mid(A1,3,len(A1)-2),find("M",mid(A1,3,len(A1)-2))-1)*60,0)+substitute(REGEXreplace(mid(A1,3,len(A1)-2),"(.+M)",""),"S","")
Outputs seconds, eg 203 from PT3M23S. To change to 00:03:23 wap the above formula in ( ... )/86400 and format result as Time.
Script Solution:
function iso8601HMparse(str) {
return str.replace(/PT(\d+(?=M))?M?(\d+(?=S))?S?/g,function(mm,p1,p2){//regex to get M and S value
return [0,p1,p2].map(function(e){
e = e ? e:0;
return ("00"+e).substr(-2); //fix them to 2 chars
}).join(':');
})
}
Splice it in your script like:
return iso8601HMparse(json["items"][0]["contentDetails"]["duration"].toString());
Spreadsheet Function:
=TEXT(1*REGEXREPLACE(REGEXREPLACE(A1,"PT(\d+M)?(\d+?S)?","00:00$1:00$2"),"[MS]",),"MM:SS")
Late to the party, but here's what I'm using:
=TIMEVALUE(
IFERROR(TEXT(MID(A1,3,FIND("H",A1)-3),"00"),"00")&":"&
IFERROR(TEXT(MID(A1,IFERROR(FIND("H",A1)+1,3),FIND("M",A1)-IFERROR(FIND("H",A1)+1,3)),"00"),"00")&":"&
IFERROR(TEXT(MID(A1,IFERROR(FIND("M",A1)+1,3),FIND("S",A1)-IFERROR(FIND("M",A1)+1,3)),"00"),"00"))
You can also stick ARRAYFORMULA in front of this and change A1 to a a column to get values for a whole list of them.
I have a column of data, diagnosis codes to be exact. the problem is that when the data is imported it turns 111.0 into 111 (or any whole number). I am wondering if there is an update query I can run that will add the ".0" to the end of any value that is 3 characters long. I had a problem of it stripping a value from 008.45 to 8.45 but I figured that part out using:
UPDATE Master SET DIAGNOSIS01 = LEFT("00", 3-LEN(DIAGNOSIS01)) + DIAGNOSIS01
WHERE LEN(DIAGNOSIS01)<3 AND Len(DIAGNOSIS01)>0;
I got that from here on stackoverflow. Is there a variation of this update query I can use to add to the right if it's only 3 digits?
Additional info... formats of the values in this column include xxx.x or xxx.xx with x being a number
When it comes to sql I am very new so please treat me like I'm 3... ;)
UPDATE Master
SET Master.DIAGNOSIS01 = IIf(Len([Master].[DIAGNOSIS01])=3,[Master].[DIAGNOSIS01] & ".0",[Master].[DIAGNOSIS01]);
I am programming in c++,i have a requirement as to get the date only ,rest of the components are not needed,
i have contents in my file in the following way:-
2012-03-26T15:05:24.844Z - DEBUG: Logging_Test:test3 : Testing file logger
2012-03-26T15:05:24.844Z->this part is returned from a function GetDateTime(),which has a stringstream sDateStream and returing to the function GetDateTime() a string
My objective is just to get the date from this part and compare it with the system's date and for the system date i m using:-
void FileLogger::date()
{
SYSTEMTIME time;//variable time to get the system time
GetLocalTime(&time);//reference to the timek
int hour = time.wHour;
if (hour > 12) hour -= 12;
int year = time.wYear;
int month = time.wMonth;
int day = time.wDay;
//not returning anything just storing values of day ,month
//& year
}
now i need to make a comparision b/w two dates and if the date in the .txt is smaller than today's date a new file gets created
please help guys i know it is very simple for the masters but for a starter like me it is creating troubles , please provide help in form of some code so that i can understand it
If you've got the line as a string, and you're sure of the format, the
simplest solution would be:
std::string dateString(
line.begin(), std::find( line.begin(), line.end(), 'T' ) );
(I'd still do some extra checking; e.g. that the dateString is exactly
10 characters long, that it only contains digits or '-', etc.)
This is the ISO date format; it has been especially designed to support
comparison directly as a string, so you might want to consider getting
the system date as a string in ISO format as well. (This is very easy
if you use the standard functions time, localtime and strftime.)