XSL - counting nodes depending on parents' position - xslt

Question

I am trying to count nodes depending on the position of their parents.
This is an example :
<tbody>
<row>
<entry>L1C1</entry>
<entry>L1C2</entry>
<entry>L1C3</entry>
</row>
<row>
<entry>L2C1</entry>
<entry morerows="1">L2C2</entry>
<entry>L2C3</entry>
</row>
<row>
<entry>L3C1</entry>
<entry>L3C3</entry>
</row>
</tbody>
For each entry, I want to count the number of entry elements of preceding row elements whose attribute morerows is greater than a number which depends of the position of the row.
I have something like this:
<xsl:variable name="nbRows">
<xsl:value-of select="count(ancestor::tbody/row)">
</xsl:value-of>
</xsl:variable>
<xsl:value-of select="count(parent::row/preceding-sibling::row/entry[#morerows > ($nbRows - count(current()/../preceding-sibling::row))])">
</xsl:variable>"/>
But as you can imagine, this does not work.
Can someone help me with this?

Answer 1

If I understood correctly the question this should do the job:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="row">
<xsl:variable name="nRows" select="count(../row)"/>
<xsl:variable name="precedingEntries" select="preceding-sibling::row/entry"/>
<xsl:variable name="minMoreRows" select="$nRows - position() + 1"/>
<n>
<xsl:value-of select="count($precedingEntries[#morerows>=$minMoreRows])"/>
</n>
</xsl:template>
<xsl:template match="/">
<root>
<xsl:apply-templates/>
</root>
</xsl:template>
</xsl:stylesheet>
The output - when applied to the example in the question - is:
<root>
<n>0</n>
<n>0</n>
<n>1</n>
</root>