I'm trying to match the first 5 lines, and the last line, in this sample:
-- 2012-09-20 rep +6 = 184
1 12532070 (2)
2 12531806 (5)
2 12531806 (5)
-- 2012-09-21 rep +12 = 196
3 125xxxxx (-1)
3 125xxxxx (-1)
16 12557052 (2)
Leaving the following unmatched:
3 125xxxxx (-1)
3 125xxxxx (-1)
I've tried the following regular expressions:
^.*[^(-1)\r\n].*
^.*[^(-1)].*\r\n
^.*[^\(-1\)\r\n].*
^.*[^\(\-1\)\r\n].*
^.*[?!\(-1)\r\n].*
^(!?.*-1.*\r\n)
But none of them do what I want (mostly matching all lines).
My RegEx skills are not brilliant - can anybody point me in the right direction?
You can use negative lookahead
^(?!.*\(-1\)$).*$\r\n
Rather than trying to create a regular expression for this, I would just use the surrounding language to negate the sense of the match, and use a regex that only matches lines that end in '(-1)\r\n'. For instance:
Shell: grep -v '(-1)^M$'
Perl: !/\(-1\)\r\n/
Ed/Vi: v/(-1)^M$
etc.
Related
We've a "street_number" field which has been freely filed over the years that we want to format. Using regular expressions, we'd like to to extract the real "street_number", and the "street_number_suffix".
Ex: 17 b, "street_number" would be 17, and "street_number_suffix" would be b.
As there's a dozen of different patterns, I'm having troubles to tune the regular expression correctly. I consider using 2 different regexes, one to extract the "street_number", and another to extract the "street_number_suffix"
Here's an exhaustive set of patterns we'd like to format and the expected output:
# Extract street_number using PCRE
input street_number street_number_suffix
19-21 19 null
2 G 2 G
A null A
1 bis 1 bis
3 C 3 C
N°10 10 null
17 b 17 b
76 B 76 B
7 ter 7 ter
9/11 9 null
21.3 21 3
42 42 null
I know I could invoke an expressions that matches any digits until a hyphen using \d+(?=\-).
It could be extended to match until a hyphen OR a slash using \d+(?=\-|\/), thought, once I include \s to this pattern, 21 from 19-21 will match. Adding conditions may no be that simple, which is why I ask your help.
Could anyone give me a helping hand on this ? If it can help, here's a draft: https://regex101.com/r/jGK5Sa/4
Edit: at the time I'm editing, here's the closest regex I could find:
(?:(N°|(?<!\-|\/|\.|[a-z]|.{1})))\d+
Thought the full match of N°10 isn't 10 but N°10 (and our ETL doesn't support capturing groups, so I can't use /......(\d+)/)
To get the street numbers, you could update the pattern to:
(?<![-/.a-z\d])\d+
Explanation
(?<! Negative lookbehind
[-/.a-z\d] Match any of the listed using a charater class
) Close the negative lookbehind
\d+ Match 1+ digits
Regex demo
I have nearly 8000 lines of the following text:
DIL 2 M 006 SC SCHÜTZ 083 1 Stck
25215-1 BIN-SORT 2152310251724-1 BIN-SORT getestet 048 133 Stck
RBBE60-T3dsg 21S003 SEALING 6X8.9X2.4 MM 082 3 Stck
I am only interested in the 3 digit block at the end and the number behind.
So this should be the output:
083 1
048 133
082 3
It could be, that the same number e.g. 048 appears at the beginning of the line. this shouldn't be a hit.
Unfortunatelly i have no idea how to extract this strings with the help of notpad++.
This expression,
.*(\d{3}\s+\d+).*
with a replacement of $1 is likely to work here.
The expression is explained on the top right panel of this demo if you wish to explore/simplify/modify it.
You may try the following find and replace, in regex mode:
Find: ^.*?(\d+ \d+) \S*$
Replace: $1
The logic here is to use .* to consume everything up until the last two consecutive digits in the line. Then, we replace with only the captured two digits.
Demo
I'm trying to validate that a form field contains a valid score for a volleyball match. Here's what I have, and I think it works, but I'm not an expert on regular expressions, by any means:
r'^ *([0-9]{1,2} *- *[0-9]{1,2})((( *[,;] *)|([,;] *)|( *[,;])|[,;]| +)[0-9]{1,2} *- *[0-9]{1,2})* *$'
I'm using python/django, not that it really matters for the regex match. I'm also trying to learn regular expressions, so a more optimal regex would be useful/helpful.
Here are rules for the score:
1. There can be one or more valid set (set=game) results included
2. Each result must be of the form dd-dd, where 0 <= dd <= 99
3. Each additional result must be separated by any of [ ,;]
4. Allow any number of sets >=1 to be included
5. Spaces should be allowed anywhere except in the middle of a number
So, the following are all valid:
25-10 or 25 -0 or 25- 9 or 23 - 25 (could be one or more spaces)
25-10,25-15 or 25-10 ; 25-15 or 25-10 25-15 (again, spaces allowed)
25-1 2 -25, 25- 3 ;4 - 25 15-10
Also, I need each result as a separate unit for parsing. So in the last example above, I need to be able to separately work on:
25-1
2 -25
25- 3
4 - 25
15-10
It'd be great if I could strip the spaces from within each result. I can't just strip all spaces, because a space is a valid separator between result sets.
I think this is solution for your problem.
str.replace(r"(\d{1,2})\s*-\s*(\d{1,2})", "$1-$2")
How it works:
(\d{1,2}) capture group of 1 or 2 numbers.
\s* find 0 or more whitespace.
- find -.
$1 replace content with content of capture group 1
$2 replace content with content of capture group 2
you can also look at this.
I am having hard time trying to convert the following regular expression into an erlang syntax.
What I have is a test string like this:
1,2 ==> 3 #SUP: 1 #CONF: 1.0
And the regex that I created with regex101 is this (see below):
([\d,]+).*==>\s*(\d+)\s*#SUP:\s*(\d)\s*#CONF:\s*(\d+.\d+)
:
But I am getting weird match results if I convert it to erlang - here is my attempt:
{ok, M} = re:compile("([\\d,]+).*==>\\s*(\\d+)\\s*#SUP:\\s*(\\d)\\s*#CONF:\\s*(\\d+.\\d+)").
re:run("1,2 ==> 3 #SUP: 1 #CONF: 1.0", M).
Also, I get more than four matches. What am I doing wrong?
Here is the regex101 version:
https://regex101.com/r/xJ9fP2/1
I don't know much about erlang, but I will try to explain. With your regex
>{ok, M} = re:compile("([\\d,]+).*==>\\s*(\\d+)\\s*#SUP:\\s*(\\d)\\s*#CONF:\\s*(\\d+.\\d+)").
>re:run("1,2 ==> 3 #SUP: 1 #CONF: 1.0", M).
{match,[{0, 28},{0,3},{8,1},{16,1},{25,3}]}
^^ ^^
|| ||
|| Total number of matched characters from starting index
Starting index of match
Reason for more than four groups
First match always indicates the entire string that is matched by the complete regex and rest here are the four captured groups you want. So there are total 5 groups.
([\\d,]+).*==>\\s*(\\d+)\\s*#SUP:\\s*(\\d)\\s*#CONF:\\s*(\\d+.\\d+)
<-------> <----> <---> <--------->
First group Second group Third group Fourth group
<----------------------------------------------------------------->
This regex matches entire string and is first match you are getting
(Zero'th group)
How to find desired answer
Here we want anything except the first group (which is entire match by regex). So we can use all_but_first to avoid the first group
> re:run("1,2 ==> 3 #SUP: 1 #CONF: 1.0", M, [{capture, all_but_first, list}]).
{match,["1,2","3","1","1.0"]}
More info can be found here
If you are in doubt what is content of the string, you can print it and check out:
1> RE = "([\\d,]+).*==>\\s*(\\d+)\\s*#SUP:\\s*(\\d)\\s*#CONF:\\s*(\\d+.\\d+)".
"([\\d,]+).*==>\\s*(\\d+)\\s*#SUP:\\s*(\\d)\\s*#CONF:\\s*(\\d+.\\d+)"
2> io:format("RE: /~s/~n", [RE]).
RE: /([\d,]+).*==>\s*(\d+)\s*#SUP:\s*(\d)\s*#CONF:\s*(\d+.\d+)/
For the rest of issue, there is great answer by rock321987.
I have the following line :
3EAM7A 1 3 EI AMANDINE MRV SHP 70 W 0 SH3-A1 1 SHP 70W OVOIDE AI E27 SON PIA PLUS
I'd like to get the string : EI AMANDINE MRV SHP 70 W. So I decided to select the strings between 1 (can also be 2, 3 or 99) and 0 (can also be 1, 2, 3, 4 or 5).
I tried :
(0|1|2|3|99)(.*)(0|1|2|3|4|5)
But I have this result :
EAM7A 1 3 EI AMANDINE MRV SHP 70 W 0 SH3-A1 1 SHP 70W OVOIDE AI E
that is not what I want to obtain.
Do you have an idea in regex to make that selection work ?
Thanks !
You were pretty close! Try this:
\b(?:0|1|2|3|99) ([^0|1|2|3|99].*?) (?:0|1|2|3|4|5)\b
Regex101
I think that you want to match "word" 4 to 9?
Your desired match will be in group 1
^(\S+\s){3}((\S+\s){6})
Enable the multiline option if you have a whole file of subject strings.
You can try with:
\s(?:[0-3]|99)\s([A-Z].*?)\b(?:[0-5])\b
DEMO
and get string by group $1. Or if your language support look around, try:
(?<=\s[0-3]\s|99)[A-Z].+?(?=\s[0-5]\s)
DEMO
to get match directly.
Another solution that is based on matching all initial space + digit sequences:
\b(?:(?:[0-3]|99)\b\s*)+(.*?)\s*\b(?:[0-5])\b
See demo
The result is in Group 1.
With \b(?:(?:[0-3]|99)\b\s*)+ the rightmost number from the allowed leading set is picked.
You can use following regex :
(?:(?:[0-3]|99)\s)+(.*?)\s(?:[0-5])\s
See demo https://regex101.com/r/iX6oE1/6
Also note that for matching a range of number you can use a character class instead of multiple OR.