How can I let users to input values into the sudoku board? - c++

I'm having trouble generating and inserting numbers inside the Board. Here is what I have so far:
enter code here
#include <iostream>
#include <string>
#include <cstring>
#include <vector>
using namespace std;
bool Valid_Set(int line[])
{
bool found = true;
for (int t = 1; (t <= 9 && found); ++t)
{
found = false;
for (int i = 0; i < 9; ++i)
if (line[i] == t) found = true;
}
return found; // returns true if all value 1-9 are in array.
}
bool Valid_Matrix(int sud[9][9])
{
int i, j, check[9];
bool valid = true;
// check each row
for (j = 0; (j < 9) && valid; ++j)
{
for (i = 0; i < 9; ++i)
check[i] = sud[i][j];
valid = Valid_Set(check);
}
// check each column
for (j = 0; (j < 9) && valid; ++j)
{
for (i = 0; i < 9; ++i)
check[i] = sud[j][i];
valid = Valid_Set(check);
}
// check 3x3 area
for (i = 0; (i < 9) && valid; i += 3)
{
for (j = 0; (j < 9) && valid; j += 3)
{
int t = 0;
for (int x = 0; x < 3; ++x)
for (int y = 0; y < 3; ++y)
check[t++] = sud[x + i][y + j];
valid = Valid_Set(check);
}
}
return valid;
}
void numGenerator(int A[]){
for (int i=0; i<9; i++){
A[i]=(1+rand()%9);
}
}
bool check_for_validity(int A[]){
int counter=0;
while (counter!=9){
numGenerator(A);
counter++;
}
for (int i=0; i<9; i++)
for (int j=0; j<9; j++){
if(A[j]==A[i])
numGenerator(A);
}
return true;
}
void main (){
//Descriptions and genral ideas
cout << "WELCOME TO SUDOKU " << endl;
cout << endl;
cout << "RULES: "<< endl;
cout << endl;
cout << "->You'll be given a 9x9 board with some numbers depending on which level of difficulty you choose to play."<< endl;
cout << endl;
cout << "->You have to arrange numbers from 1 to 9 so that a number shows up once in one row, one column and in a 3x3 box." << endl;
cout << endl;
cout << "So, let's get started" << endl;
cout << endl;
cout <<endl;
char dash[9][9];
for (int array=0; array<9; array++) {
for (int array2=0; array2<9; array2++) {
dash[array][array2]='_';
}
}
char row[9];
char column[9];
int num[81];
int num2[9][9];
int length;
length=strlen(row);
//Replaces the _'s in the specified rows/columns and replaces them with the integer the user specified.
for (int i=0; i<length; i++) {
dash[row[i]][column[i]]=num[i]+'0';
}
//Builds the Sudoko board and outputs the full 9x9 array.
cout << " 0 1 2 3 4 5 6 7 8 " << endl;
cout << "-----------------------------------------" << endl;
int i=0;
for (int count=0; count<3; count++) {
for (int count2=0; count2<3; count2++) {
cout << "||_" << dash[count][count2*3] << "_|_" << dash[count][count2*3+1] << "_|_" << dash[count][count2*3+2] << "_";
}
cout << "||" << i << endl;
i++;
}
cout << "-----------------------------------------" << endl;
int j=3;
for (int count=3; count<6; count++) {
for (int count2=0; count2<3; count2++) {
cout << "||_" << dash[count][count2*3] << "_|_" << dash[count][count2*3+1] << "_|_" << dash[count][count2*3+2] << "_";
}
cout << "||" << j << endl;
j++;
}
cout <<"-----------------------------------------" << endl;
int z=6;
for (int count=6; count<9; count++) {
for (int count2=0; count2<3; count2++) {
cout << "||_" << dash[count][count2*3] << "_|_" << dash[count][count2*3+1] << "_|_" << dash[count][count2*3+2] << "_";
}
cout << "||" << z << endl;
z++;
}
cout << "-----------------------------------------" << endl;
for (int row = 0; row < 9; row++) {
cout << "Enter values for row " << row + 1 << " : ";
for (int col = 0; col < 9; col++)
cin >> dash[row][col];
cout << endl << endl;
}
system("pause");
}

This whole section is wrong
char row[9];
char column[9];
int num[81];
int num2[9][9];
int length;
length=strlen(row);
//Replaces the _'s in the specified rows/columns and replaces them with the integer the user specified.
for (int i=0; i<length; i++) {
dash[row[i]][column[i]]=num[i]+'0';
}
You are using row and column even though they haven't got any values. Most likely this will crash your program.
Hard to know what you expected this to do. Perhaps you could explain?
Here's a suggestion for inputing values. Maybe you'll find it useful
// get the user's values
int row, column, value;
cout << "Enter a row number, column number, and value. All numbers should be between 1 and 9\n";
cin >> row >> column >> value;
// put the value in the board, add '0' to convert the integer to a digit
dash[row][column] = value + '0';

Related

How to reverse this loop cpp

I am trying to get the height of these slashes to be a certain length based on input. So far, I have:
#include <iostream>
using namespace std;
int main() {
int n = 0;
cout << "Enter value: ";
cin >> n;
cout << "You entered: " << n << "\n";
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++)
cout << '/' << '/';
cout << "\n";
}
}
I need it to then reverse and go back.
It prints:
//
////
//////
If the user entered 3.
It should print:
//
////
//////
////
//
Can anyone lead me in the right direction? I am new to cpp.
You can use a different kind of loop and add a bool variable to track when the program have reached "n". Then, after the program reaches "n", it sets the bool variable to true and starts to substract until i equals 0
Code below, read comments and ask if you have any further questions:
#include <iostream>
using namespace std;
int main()
{
int n = 0;
cout << "Enter value: ";
cin >> n;
cout << "You have entered: " << n << "\n";
int i = 1;
bool reachedN = false; // tells if [i] has reached [n]
while (i != 0)
{
// Print required slashes
for (int j = 1; j <= i; j++)
{
cout << "//";
}
cout << '\n'; // new line
// Add until i == n, then substract
if (i == n)
{
reachedN = true;
}
if (reachedN)
{
--i;
}
else
{
++i;
}
}
}
If you enter 3, the output is the following:
This is one way to achieve that:
#include <iostream>
using namespace std;
int main() {
int n = 0;
cout << "Enter value: ";
cin >> n;
cout << "You entered: " << n << "\n";
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++)
cout << '/' << '/';
cout << "\n";
}
for (int i = n - 1; i > 0; i--) {
for (int j = 1; j <= i; j++)
cout << '/' << '/';
cout << "\n";
}
}
This is a shorter solution with only two for-loops.
#include <iostream>
using namespace std;
int main()
{
int n = 0;
cout << "Enter value: ";
cin >> n;
cout << "You entered: " << n << "\n";
n = n * 2 - 1;
int r = 0;
for (int j = 0; j < n; j++)
{
if (j > n / 2) r--;
else r++;
for (int i = 0; i < r; i++)
{
cout << '/' << '/';
}
cout << "\n";
}
return 0;
}

Why does incrementing one array, increment another?

I am having a problem with incrementing a single item in an array. It ends up incrementing another array.. How does it do this? this is what I have:
string simulateFIFO(darray<int> requests, int frameSize) {
string results;
int currentPages[frameSize];
int timer[frameSize];
int hits = 0;
int faults = 0;
cout << "STARTING FIFO" << endl;
for (int i = 0; i < requests.size(); i++) {
cout << requests[i] << " ";
}
cout << endl;
cout << endl;
for (int i = 0; i < frameSize; i++) {
currentPages[i] = -1;
timer[i] = 0;
}
// Start Calculations
for (int i = 0; i < requests.size(); i++) {
bool requestSet = false;
for (int j = 0; j < frameSize; j++) {
if (currentPages[j] < 0) {
// Current frame does not have a page
cout << "FRAME IS EMPTY" << endl;
currentPages[j] = requests[i];
requestSet = true;
faults++;
j = frameSize;
}
else if (currentPages[j] == requests[i]) {
cout << "FRAME IS SAME AS REQUEST" << endl;
// Current Frame is set the the page being requested
timer[j] = 0;
requestSet = true;
hits++;
j = frameSize;
}
cout << currentPages[j] << endl;
timer[j]++;
cout << currentPages[j] << endl;
}
// Check to see if a request was set or not
if (requestSet == false) {
cout << "FRAME NEEDS REPLACED" << endl;
// The request wasnt set. Determine which frame to replace with the new request
int lastUsed = 0;
int lastUsedIndex = 0;
for (int j = 0; j < frameSize; j++) {
if (timer[j] > lastUsed) {
lastUsed = timer[j];
lastUsedIndex = j;
}
}
currentPages[lastUsedIndex] = requests[i];
//timer[lastUsedIndex] = 0;
faults++;
}
cout << "HEY 3: " << currentPages[0] << endl;
cout << "NEW FRAME: ";
for (int j = 0; j < frameSize; j++) {
cout << currentPages[j] << " ";
}
cout << endl;
cout << endl;
}
cout << "FIFO" << endl;
cout << faults << endl;
cout << hits << endl;
cout << endl;
return results;
}
My Output ends up being
0
1
Why does increasing one array actually increase the other as well?
Your code includes a possible path of execution:
j = frameSize;
followed by
timer[j]++;
This accesses out of bounds: for an array of dimension frameSize, the valid indices are 0 through frameSize-1.
I guess you actually want to exit the loop; if so then replace j = frameSize; with break; .
NB. int timer[frameSize]; is not permitted in ISO C++; array bounds must be known at compile-time. Your code is relying on a compiler extension.

C++ Grid Issues

I'm printing random numbers enclosed in ascii boxes in a 6x6 grid. Having issues with printing out the grid.
Instead of having 6 columns, all my boxes and numbers are being printed out in 1 column. Been troubleshooting but cant seem to find the issue. Below is the code. Appreciate your assistance.
int main(void)
{
cout << "Magic Grid\n" << endl;
int arrayxy [6][6];
srand((unsigned)time(0));
int lowest=1111, highest=9999;
int range=(highest-lowest)+1;
// Fill array with random values
for (int i = 0; i < 6; ++i)
{
for(int j = 0; j < 6; ++j)
{
arrayxy[i][j] = lowest+int(range*rand()/(RAND_MAX + 1.0));
}
}
// Print array as grid
for (int i = 0; i < 6; ++i)
{
for(int j = 0; j < 6; ++j)
{
cout << char(218);
for (int y=0; y< 4; y++)
{
cout << char(196);
}
cout << char(191) <<endl;
cout << char(179) << arrayxy[i][j] << char(179) << endl;
cout << char(192);
for (int z=0; z< 4; z++)
{
cout << char(196);
}
cout << char(217) <<endl;
}
cout << endl;
}
cout << endl;
}
You should endl after all the columns get printed out, NOT before.
This is how I fixed your code that gives, hopefully, what you wanted to have.
For the record, I specifically changed those ASCII to * and & to make the console result more readable. You can change them back to what you want those characters to be again.
void WriteFrontLine(std::size_t count)
{
for (int i = 0; i < count; i++)
{
cout << '*';
cout << '&' << '&' << '&' << '&';
cout << '*';
}
cout << endl;
}
void WriteEndLine(std::size_t count)
{
for (int i = 0; i < count; i++)
{
cout << '*';
cout << '&' << '&' << '&' << '&';
cout << '*';
}
cout << endl;
}
int main(void)
{
cout << "Magic Grid\n" << endl;
int arrayxy[6][6];
srand((unsigned)time(0));
int lowest = 1111, highest = 9999;
int range = (highest - lowest) + 1;
// Fill array with random values
for (int i = 0; i < 6; ++i)
{
for (int j = 0; j < 6; ++j)
{
arrayxy[i][j] = lowest + int(range*rand() / (RAND_MAX + 1.0));
}
}
// Print array as grid
for (int i = 0; i < 6; ++i)
{
WriteFrontLine(6);
for (int j = 0; j < 6; ++j)
{
cout << '*' << arrayxy[i][j] << '*';
}
cout << endl;
WriteEndLine(6);
cout << endl;
}
cout << endl;
}

c++ forbids comparison between pointer and integer

i have a problem on this code
the errors says ISO c++ forbids comparison between pointer and integer
here is the exercise problem
-the answers to a true false test are as follows TTFFT given a two dimensional answer array in which each row corresponds to the answers provided on one test, write a function that accepts the two dimensional array and the number of tests as parameters and returns a one dimensional array containing the grades for each test.(each question is worth 5 points so that the maxinum possible grade is 25)
any answers will help.
this is the code
#include <iostream>
using namespace std;
int numberofgrades(char [][5], int []);
int main()
{
char testanswers[5][5] = {0};
int testgrades[5] = {0};
int counting1, counting2, counting3;
counting1 = 1;
counting2 = 1;
counting3 = 1;
cout << "this program will record the testgrades you entered: "
<< endl;
for(int i = 0; i < 5; i++)
{
for(int k = 0; k < 5; k++)
{
cout << "enter answers for test no. " << counting1 << ": ";
cin >> testanswers[i][k];
}
counting1++;
}
numberofgrades(testanswers,testgrades);
cout << "testing..." << endl;
cout << endl;
for(int o = 0; o < 5; o++)
{
cout << "test no. " << counting2;
for(int l = 0; l < 5; l++)
{
cout << " " << testanswers[o][l];
}
counting2++;
cout << endl;
}
cout << "testing...." << endl;
cout << endl;
cout << "the total number of scores per test no. is: "
<< endl;
for(int t = 0; t < 5; t++)
{
cout << "test no. " << t << ": " << testgrades[t] << endl;
}
return 0;
}
int numberofgrades(char t1a [][5], int tg1[])
{
for(int j = 0; j < 5; j++)
{
for(int i = 0; i < 5; i++)
{
if(t1a[i] == 't') //this is the problem
{
tg1[j] = tg1[j] + 5;
}
else if(t1a[i] == 'T')
{
tg1[j] = tg1[j] + 5;
}
else if(t1a[i] == 'f')
{
tg1[j] = tg1[j] + 0;
}
else if(t1a[i] == 'F')
{
tg1[j] = tg1[j] + 0;
}
else{
cout << "invalid letter exiting the program"
<< endl;
return 0;
}
}
}
return tg1[5];
}

how to process an array of even numbers from a users input and display them with spaces in C++

I need help with getting this users input of an integer and retrieving the even numbers and displaying them with spaces.I already have the input processed into an array and have it reversed (thanks to stackoverflow) now need to extract the even numbers from the array and display them.
#include <iostream>
#include <iomanip>
#include <vector>
using namespace std;
int evenNumbers(char even[], int num[], int indexing[]);
int main()
{
char integers[5];
int numbers[5];
int even[5] = {0,2,4,6,8};
int evens;
cout << "Please enter an integer and press <ENTER>: " << endl;
for (int j = 0; j < 5; j++)
cin >> integers[j];
for (int j = 0; j < 5; j++)
{
numbers[j]= integers[j] - '0';
}
cout << endl;
for (int j = 5; j > 0; j--)
{
cout << integers[j - 1] << " ";
}
cout << endl;
//having problems finding the even numbers and displaying the even numbers
//from the users input of integers, i have only learned how to display the
//subscript by a linear search
evens = evenNumbers(integers, numbers, even);
if (evens == -1)
cout << "There are no even numbers" << endl;
else
{
cout << "The even numbers are: " << (evens + 1) << endl;
}
system("pause");
return 0;
}
int evenNumbers(char even[], int num[], int indexing[])
{
int index = 0;
int position = -1;
bool found = false;
for (int j = 0; j < 5; j++)
{
num[j]= even[j] - '0';
}
while (index < 5)
{
if (num[index] == indexing[index])
{
found = true;
position = index;
}
index++;
}
return position;
}
If you want to display the even numbers from the array integers you can use a simple for loop and if statement:
for(int i = 4; i >= 0; i--)
{
if(integers[i] % 2 == 0)
cout << integers[i] << " ";
}
Your approach is all wrong, you can't detect even numbers by searching a list, you need a mathematical test for evenness. Write a function called is_even which tests one number and returns true if it is even and false if it is not. Then you can use that function, very simply, like this
for (int j = 0; j < 5; j++)
{
if (is_even(integers[j]))
cout << integers[j] << " ";
}
cout << endl;
Now you just need to write the is_even function.
void evennumbers(int num[])
{
for(int i=0;i<5;i++)
{
if(num[i]%2==0)
cout<<num[i]<<" ";
}
}
And avoid taking input to char what if user enters a number with more than one digit
#include <iostream>
#include <iomanip>
#include <vector>
using namespace std;
void validNum(char valid[]);
void reverseNum(char rev[], int num2[]);
void evenNumbers(char even[], int num3[]);
void oddNumbers(char odd[], int num4[]);
int main()
{
char integer[5];
int number[5];
cout << "Your number is: ";
validNum(integer);
cout << "Your number in reverse is: ";
reverseNum(integer, number);
cout << "Even numbers: ";
evenNumbers(integer, number);
cout << endl;
cout << "Odd numbers: ";
oddNumbers(integer, number);
cout << endl;
system("pause");
return 0;
}
void validNum(char valid[])
{
char ch;
cout << "Please enter an integer and press <ENTER>: " << endl;
ch = cin.get;
while (ch < 0 || ch >= 'A' && ch <= 'Z' || ch >= 'a' && ch <= 'z')
{
cout << "ERROR: Please enter a positive integer and press <ENTER>: ";
for (int i = 0; i < 5; i++)
cin >> valid[i];
}
for (int j = 0; j < 5; j++)
{
cout << valid[j] - '0';
}
}
void reverseNum(char rev[], int num2[])
{
for (int j = 0; j < 5; j++)
{
num2[j]= rev[j] - '0';
}
cout << endl;
for (int j = 5; j > 0; j--)
{
cout << rev[j - 1]<< " ";
}
cout << endl;
}
void evenNumbers(char even[], int num3[])
{
for (int i = 0; i < 5; i++)
{
if (even[i] % 2 == 0)
{
cout << num3[i] << " ";
}
}
}
void oddNumbers(char odd[], int num4[])
{
for (int i = 0; i < 5; i++)
{
if (odd[i] % 2 == 1)
{
cout << num4[i] << " ";
}
}
}