Disabling Implicit Casting in c++ - c++

Question

Is it possible to disable implicit casting in C/C++.
Suppose I want to write a validity function that makes me enter only integers in range [1,10]
I have written:
#include <iostream>
using namespace std;
int main( )
{
int var=0;
cout << "Enter a number (Integer between 1 to 10) : ";
while( (!(cin >> var )) || (var > 10 ) || (var < 1) )
{
cout << "U nuts .. It can only be [1,10]\n";
cin.clear();
cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
cout << "Enter a number (Integer between 1 to 10) : ";
}
cout << "\nYou entered : " << var;
return 0;
}
But if the user enters 9.5 it accepts it by converting the float 9.5 as 9 and storing it in var. I want any float entry to be treated as invalid entry. How do I achieve this most compactly.
I do not want to do something of this sort:
#include <iostream>
#include <cmath>
using namespace std;
int main( )
{
float var=0;
cout << "Enter a number (Integer between 1 to 10) : ";
while( (!(cin >> var )) ||(var < 1)|| (var > 10 ) || !(ceilf(var) == var) )
{
cout << "U nuts .. It can only be [1,10]\n";
cin.clear();
cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
cout << "Enter a number (Integer between 1 to 10) : ";
}
cout << "\nYou entered : " << var;
return 0;
}
This serves my purpose . But what I want to know, that is there any way where a conversion from float to int - I can suppress or it can show it as false input.
Similar to the way cin >> var where var type is int - if we enter char it returns false condition. Can we achieve the same for float entry ?
Thanks

Answer 1

But if the user enters 9.5 it accepts it by converting the float 9.5 as 9 and storing it in var.
No it doesn't. If the the user enters 9.5, then cin >> var stops reading when it hits the . (and leaves it on the stream). There's no float-to-int conversion because you haven't read a float, just an int.
The fix is to read the rest of the input (after cin >> var), and make sure there's nothing bad left over after the end of the int.

Answer 2

If you want to validate all of the input, you will have to get the whole line first.
Try:
string line;
getline(cin, line); // gets whole line
char *endptr;
long int var = strtol(line.c_str(), &endptr, 10); // converts string to int
// now check that endptr points to end of the string
if (endptr<line.c_str()+line.length()) {
// extra characters found after the integer
}