Suppose I have the following directory structure for the project:
myproj/dir1/file1.d
myproj/dir2/file2.d
myproj/main.d
How can I import main and file2 modules within the source file file1.d?
file1.d will have module dir1.file1; line , file2.d will have module dir2.file2; line and main.d will start with module main;.
Module declarations above will tell D what to do when it encounters line like: import main, dir2.file2;;
As suggested by #sigod , read the http://dlang.org/module.html for more information.
Related
I wanted to test the relative import model of Python 2.X
Directory tree:
exercises/
dir1/
dir2/
mod.py
dir3/
mod2.py
mod3.py
mod.py
import sys
print 'in dir1/dir2/mod.py'
path = [name for name in sys.path if 'Frameworks' not in name].
print 'Module search path of mod is:\n' + str(path)
import dir3.mod2
mod2.py
print 'in dir1/dir2/dir3/mod2.py'
import mod3
mod3.py
print 'in dir1/dir2/dir3/mod3.py by relative import'
'mod' would import 'mod2' from 'dir3', which would then import 'mod3'. In Python 3.X, this would fail because the path to 'mod3' is not provided; in Python 2.X, the interpreter searches the same directory containing 'mod2' before searching the rest of the path starting from the top level directory of 'mod'.
This is the error message I get:
MacBook-Pro-9 exercises % python dir1/dir2/mod.py
in dir1/dir2/mod.py
Module search path of mod is:
['Users/arthur/Desktop/learning_python/exercises/dir1/dir2', '/Library/Python/2.7/site-packages']
Traceback (most recent call last):
File "Desktop/learning_python/exercises/dir1/dir2/mod.py", line 8, in <module>
import dir3.mod2
ImportError: No module named dir3.mod2
I know 'dir2' contains 'dir3/mod2', but for some reason, Python can't find it. I'm pretty sure that the syntax for the import statement is correct.
I modified the print statements and changed 'mod2.py' code to read from . import mod3. I edited nothing else, and it ran just fine in Python 3.8 There was no problem finding 'dir3.mod2'
You have to add an empty file inside dir3 named init.py for python to be able to recognize the directory as a Python package directory. If you have these files
dir3/__init__.py
dir3/mod2.py
dir3/mod3.py
You can now import the code in mod2.py and mod3.py as
import dir3.mod2
import dir3.mod3
or
from dir3 import mod2
from dir3 import mod3
If you remove the init.py file, Python will no longer look for submodules inside that directory, so attempts to import the module will fail.
Here is the a link.
I want to access to my modules.module function A in my main , but when I do this I have an error that I cannot import that.. how can I fix it? I Have seen multiples articles but i hadnt a chance, how can I fix this error of importing modules from subfolders?
**/tool
main.py
/google
/modules
__init__.py
module.py**
ImportError: cannot import name google
main.py
#!/usr/bin/python
import sys
import core.settings
from google.modules import google
if __name__ == '__main__':
try:
core.settings.settings()
google()
except KeyboardInterrupt:
print "interrupted by user.."
except:
sys.exit()
module.py
def google():
print 'A'
the easiest way to work this out is have your main.py in your highest directory (it makes sense anyway for main to be there) and if you really want the real main to be in a sub directory have a dummy main at the top level you can call that just calls the actual main, that way python can see your entire directory tree and will know how to import any sub directory.
alternatively
you could add your parent directory to the sys.path:
parent_dir = os.path.realpath(os.path.join(os.getcwd(),'..')))
sys.path.append(parent_dir)
which will add that directory to the places python searches for when you try to import stuff.
but then you will need to keep track of how deep your main is in the directory tree and its a pretty unelegant solution in my opinion
I created a module and it contains the file's name. But when I use the module instead of the file's name, the 'from' code doesn't work.
svn = raw_input("What file are you looking for?")
from svn import *
I have found the answer, it should be like this:
svn = raw_input("What file are you looking for?")
__import__(svn)
I am trying to understand how to import code from one file to another. I have two files file1.py and file2.py. I am running code in the first file, and have many variables and functions defined in the second file. I am using from file2 import * to import the code into file1.py. I have no problem using variables defined in file2.py in file1.py, but with functions I am getting NameError: name 'myfunc' is not defined when I try to use the function in file1.py. I can fix this problem by writing from file2 import myfunc, but I thought writing * would import everything from that file. What is the difference for functions versus variables?
I have tried to recreate the setup you have described and it is working OK for me. Hopefully this will give you an idea of how to get it to work.
# file1.py #####################################
import sys
sys.path.append("/home/neko/test/")
import file2
if __name__ == "__main__":
file2.testfunc()
# file2.py ######################################
testvar = 'hello'
def testfunc(): print testvar
For this test I was using python version 2.6.6
Both file1.py and file2.py is in /home/neko/test/
I would like to import a module from one location, unload it, and then import a module of the same name from another location in python. Something like:
sys.path.append(module_location_1)
import module
unload module
....
sys.path.append(module_location_2)
import module
I tried the following approach below but have had no luck:
sys.path.insert(0, /path1)
import my_module
print my_module # <module 'my_module' from '/path1/__init__.pyc'>
sys.path.insert(0, /path2)
import my_module
print my_module # still gives: <module 'my_module' from '/path1/__init__.pyc'
Unfortunately after the second input I see the the module is still be loaded from the original location I added to my path. I have tried:
1
removing the first location from sys.path all together between imports
imp.reload(my_module).
both appending and prepending to the path
Thanks!