I am trying to read the following XML using XSLT, but can not get the expected results.
If i remove the "xmlns:a="http://schemas.datacontract.org/2004/07/CoreModels" namespace from the txnDetail node, then the xslt below works fine ???
What am i doing wrong ?
The input XML:
<TransactionRsp xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<avlBal>848.35</avlBal>
<blkAmt>0</blkAmt>
<txnDetail xmlns:a="http://schemas.datacontract.org/2004/07/CoreModels">
<a:txnDetail>
<a:billAmount>400</a:billAmount>
<a:txnDateTime>2012-02-23T14:35:45</a:txnDateTime>
</a:txnDetail>
<a:txnDetail>
<a:billAmount>10</a:billAmount>
<a:txnDateTime>2012-07-30T12:22:14</a:txnDateTime>
</a:txnDetail>
</txnDetail>
</TransactionRsp>
The XSLT stylesheet:
<xsl:stylesheet version = '1.0' xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<root>
<xsl:for-each select="TransactionRsp/txnDetail/txnDetail">
<row>
<col name="billAmount"><xsl:value-of select="billAmount"/></col>
<col name="itemID"><xsl:value-of select="itemID"/></col>
</row>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
You need to qualify your XPath expressions with namespace prefix:
<xsl:for-each select="TransactionRsp/txnDetail/a:txnDetail">
<row>
<col name="billAmount"><xsl:value-of select="a:billAmount"/></col>
<col name="itemID"><xsl:value-of select="a:itemID"/></col>
</row>
</xsl:for-each>
EDIT: The namespace must be declared for your XSLT file too. Thanks to #hcayless's comments below.
<xsl:stylesheet version = '1.0'
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
xmlns:a="http://schemas.datacontract.org/2004/07/CoreModels" >
Related
I am trying to learn the basics of XSLT, but am stuck on a particular use case. What I want to achieve is to transform one xml file into another xml (I am using XSLT 2.0), but a condition is that the grouping of elements in the output xml is decided by the value of one particular element in the input xml.
I will try to exemplify my question through a made-up example.
Lets say this is an input xml:
<products>
<shoes>
<shoe>
<name>Ecco City</name>
<category>Urban</category>
</shoe>
<shoe>
<name>Timberland Forest</name>
<category>Wildlife</category>
</shoe>
<shoe>
<name>Asics Gel-Kayano</name>
<category>Running</category>
</shoe>
</shoes>
<clothes>
<shorts>
<name>North Face</name>
<category>Wildlife</category>
</shorts>
<shorts>
<name>Adidas Running Shorts</name>
<category>Running</category>
</shorts>
</clothes>
Based on the value of the category element I want to, for each product, list similar products, that is, other products having the same category in the input xml, like this:
<output>
<forSale>
<item>Asics Gel-Kayano</item>
<similarItem>Adidas Running Shorts</similarItem>
</forSale>
</output>
This doesn't seem to be a grouping problem as such. If I understand correctly, you want to do something like:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="product-by-category" match="*" use="category" />
<xsl:template match="/products">
<output>
<xsl:for-each select="*/*">
<forSale>
<item>
<xsl:value-of select="name" />
</item>
<xsl:for-each select="key('product-by-category', category) except .">
<similarItem>
<xsl:value-of select="name" />
</similarItem>
</xsl:for-each>
</forSale>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>
Applied to your input example, the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<output>
<forSale>
<item>Ecco City</item>
</forSale>
<forSale>
<item>Timberland Forest</item>
<similarItem>North Face</similarItem>
</forSale>
<forSale>
<item>Asics Gel-Kayano</item>
<similarItem>Adidas Running Shorts</similarItem>
</forSale>
<forSale>
<item>North Face</item>
<similarItem>Timberland Forest</similarItem>
</forSale>
<forSale>
<item>Adidas Running Shorts</item>
<similarItem>Asics Gel-Kayano</similarItem>
</forSale>
</output>
Using xslt 1.0, I need to transform below input xml to output xml
--input xml
<Row>
<Column name="NUMBER" sqltype="int">123</Column>
<Column name="DEPT1" sqltype="int">A</Column>
<Column name="CUST_EMPTYPE" sqltype="int">1</Column>
<Column name="CUST_TIJD" sqltype="int">31</Column>
</Row>
--output xml
<EMPLOYEE xmlns="http://xmlns.oracle.com/Employee">
<NUMBER>123</NUMBER>
<DEPT1>IHC</DEPT1>
<CUST_EMPTYPE>1</LASTNAME>
<CUST_TIJD>31</FIRSTNAME>
</EMPLOYEE>
the Column names from input xml are not known at design time, the Column can grow..
Can anyone let me know how to achieve this?
Thank you very much,
Yes. It is quite simple. One minor difference is the deviation between your DEPT1 source and destination value (I really don't know where 'IHC' may have been coming from). I harmonized it in the following XSLT code which just sets the Column/#name nodes to new EMPLOYEE elements with the content of the old text() content:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" />
<xsl:template match="/Row">
<EMPLOYEE xmlns="http:xmlns.oracle.com/Employee">
<xsl:for-each select="Column">
<xsl:element name="{#name}">
<xsl:value-of select="text()" />
</xsl:element>
</xsl:for-each>
</EMPLOYEE>
</xsl:template>
</xsl:stylesheet>
The result of this is:
<EMPLOYEE xmlns="http:xmlns.oracle.com/Employee">
<NUMBER>123</NUMBER>
<DEPT1>A</DEPT1>
<CUST_EMPTYPE>1</CUST_EMPTYPE>
<CUST_TIJD>31</CUST_TIJD>
</EMPLOYEE>
<root>
<dql1>
<row>
<abcd> Prod 1 </abcd>
<td_formulation_name> 123 </td_formulation_name>
</row>
<row>
<abcd> Prod 2 </abcd>
<td_formulation_name> 123 </td_formulation_name>
</row>
</dql1>
</root>
I want to show the output as :-
Prod 1
Prod 2
123
How is it possible through XSLT ? Can any one please help ?
You can just access them using below xslt. Though not very sure if you need this.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:value-of select="root/dql1/row/abcd"/>
<xsl:value-of select="root/dql1/row[2]/abcd"/>
<xsl:value-of select="root/dql1/row/td_formulation_name"/>
</xsl:template>
</xsl:stylesheet>
If you do not know the index or if it is dynamic you can do
<xsl:for-each select="root/dql1/row">
<xsl:value-of select="abcd" />
<xsl:value-of select="td_formulation_name" />
</xsl:for-each>
I have the following xml:
<RootNode xmlns="http://someurl/path/path/path">
<Child1>
<GrandChild1>Value</GrandChild1>
<!-- Lots more elements in here-->
</Child1>
</RootNode>
I have the following xslt:
<xsl:stylesheet version="1.0" xmlns="http://someurl/path/path/path" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<xsl:for-each select="RootNode/Child1">
<NewNodeNameHere>
<xsl:value-of select="GrandChild1"/>
</NewNodeNameHere>
<!-- lots of value-of tags in here -->
</xsl:for-each>
</NewChild1>
</NewRootNode >
</xsl:template>
</xsl:stylesheet>
The problem: this is the my result:
<?xml version="1.0" encoding="utf-8"?>
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1 />
</NewRootNode>
I am expecting to see:
<?xml version="1.0" encoding="utf-8"?>
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<NewNodeNameHere>Value</NewNodeNameHere>
<!-- Other new elements with values from the xml file -->
</NewChild1>
</NewRootNode>
I am missing of the information inside of NewChild1 that should be there.
I think my for-each select is correct, so the only thing I can think of is that there is a problem with the namespace in the Xml and the namespace in the xslt. Can anybody see what I'm doing wrong?
The problem is caused by the namespaces.
Since the xml defines xmlns="http://someurl/path/path/path", it is not in the default namespace anymore.
You can define that namespace with an name like xmlns:ns="http://someurl/path/path/path" in the xsl, and then use that name in the XPath expression.
The following works for me:
<xsl:stylesheet version="1.0" xmlns:ns="http://someurl/path/path/path" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<xsl:for-each select="ns:RootNode/ns:Child1">
<NewNodeNameHere>
<xsl:value-of select="ns:GrandChild1"/>
</NewNodeNameHere>
<!-- lots of value-of tags in here -->
</xsl:for-each>
</NewChild1>
</NewRootNode >
</xsl:template>
</xsl:stylesheet>
The stylesheet namespace should be http://www.w3.org/1999/XSL/Transform instead of http://someurl/path/path/path.
Also, since the input XML uses a namespace all your XPath expressions should be namespace-qualified:
<xsl:template match="/" xmlns:ns1="http://someurl/path/path/path">
<NewRootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NewChild1>
<xsl:for-each select="ns1:RootNode/ns1:Child1">
<NewNodeNameHere>
<xsl:value-of select="ns1:GrandChild1"/>
</NewNodeNameHere>
<!-- lots of value-of tags in here -->
</xsl:for-each>
</NewChild1>
</NewRootNode>
</xsl:template>
I have the following XML:
<?xml version="1.0" encoding="utf-8"?>
<string>
<Table>
<Rows>
<Row Id="0">
<Column Name="INS_NAME" XPath="Ins.Name">Jane</Column>
<Column Name="INS_LASTNAME" XPath="Ins.LastName">Smith</Column>
</Row>
<Row Id="1">
<Column Name="INS_NAME" XPath="Ins.Name">Joe</Column>
<Column Name="INS_LASTNAME" XPath="Ins.LastName">Miller</Column>
</Row>
<Row Id="2">
<Column Name="INS_NAME" XPath="Ins.Name">George</Column>
<Column Name="INS_LASTNAME" XPath="Ins.LastName">Ramsey</Column>
</Row>
</Rows>
</Table>
</string>
and I would like to transform it to this XML using a single XSLT:
<?xml version="1.0" encoding="utf-8"?>
<Customers>
<Customer><Name>Jane</Name><LastName>Smith</LastName></Customer>
<Customer><Name>Joe</Name><LastName>Miller</LastName></Customer>
<Customer><Name>George</Name><LastName>Ramsey</LastName></Customer>
</Customers>
I can do it with two different XSLT's:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:value-of select="/" disable-output-escaping="yes" />
</xsl:template>
</xsl:stylesheet>
and then:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<Customers>
<xsl:for-each select="Table/Rows/Row">
<Customer>
<Name><xsl:value-of select="Column[#Name='INS_NAME']" /></Name>
<LastName><xsl:value-of select="Column[#Name='INS_LASTNAME']" /></LastName>
</Customer>
</xsl:for-each>
</Customers>
</xsl:template>
</xsl:stylesheet>
I have been reading about multi phase transformations but I can't seem to get it. I have tried saving the first XSLT in a variable but it seems disable-output-escaping="yes" does not work when saving to a variable.
Can anybody help?
Thank you.
New information (Edit)
I am now translating the string this way:
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:variable name="stringXml">
<?xml version="1.0" encoding="utf-8"?>
<xsl:value-of select="translate(translate(/,'>','>'),'<','<')" />
</xsl:variable>
...
How can I do a transformation on the resulting XML stored in stringXML?
Final Solution (Edit)
<msxml:script implements-prefix="myLib" language="C#">
<msxml:assembly name="System.Web"/>
<msxml:using namespace="System.Web"/>
<![CDATA[
public System.Xml.XPath.XPathNodeIterator convertText(string text)
{
XmlDocument doc = new XmlDocument();
doc.PreserveWhitespace = true;
doc.LoadXml(text);
return doc.CreateNavigator().Select("/");
}
]]>
</msxml:script>
it seems disable-output-escaping="yes" does not work when saving to a
variable.
Your observation is correct.
DOE only affects the serialization of the (final) result of the transformation and isn't applied on intermediary trees.
Here is what the W3C XSLT 1.0 specification explicitly says:
"An XSLT processor will only be able to disable output escaping if it
controls how the result tree is output. This may not always be the
case. For example, the result tree may be used as the source tree for
another XSLT transformation instead of being output."
The same negative answer holds for trying to use a variable, whose value is a string, containing a textual representation of an XML document.
I had a similar situation where I needed to parse an escaped XML inside my actual XML. I will post up my solution to also help someone else. Please also note that I am also using Saxon-PE parser.
In my situation I have the original XML that contains an escaped XML in a child node. I needed to get the inner XML inside the RootNode of the escaped XML.
Source XML:
<?xml version="1.0" encoding="utf-8"?>
<MyTestXml>
<SomeXmlStuff>
<Text1>Hello</Text1>
<Text2>World</Text2>
</SomeXmlStuff>
<SomeEscapedXml><RootNode><FirstNode>Hello</FirstNode><SecondNode>World</SecondNode><ThirdNode>Again</ThirdNode></RootNode></SomeEscapedXml>
</MyTestXml>
When you unescaped the XML, it looks like this:
<RootNode>
<FirstNode>Hello</FirstNode>
<SecondNode>World</SecondNode>
<ThirdNode>Again</ThirdNode>
</RootNode>
With the following XSLT transformation is applied on the source XML:
<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="3.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:saxon="http://saxon.sf.net/"
exclude-result-prefixes="xsl saxon">
<xsl:template match="/">
<MyOutput>
<xsl:call-template name="GetRootNodeInnerXml">
<xsl:with-param name="escapedXml" select="MyTestXml/SomeEscapedXml" />
</xsl:call-template>
</MyOutput>
</xsl:template>
<xsl:template name="GetRootNodeInnerXml">
<xsl:param name="escapedXml" required="yes" />
<xsl:copy-of select="saxon:parse($escapedXml)/RootNode/node()"/>
<!-- You can also use this line below if you're not using saxon parser. Just make sure your parser supports XSL 3.0 -->
<!--
<xsl:copy-of select="fn:parse-xml($escapedXml)/RootNode/node()" xmlns:fn="http://www.w3.org/2005/xpath-functions"/>
-->
</xsl:template>
</xsl:stylesheet>
This gives you the following output:
<?xml version='1.0' ?>
<MyOutput>
<FirstNode>Hello</FirstNode>
<SecondNode>World</SecondNode>
<ThirdNode>Again</ThirdNode>
</MyOutput>