Dealing with random files, which has patterns like
Jon Smith-db/his-wife.db/his-keeds.db
Jon Smith-db/his-wife.db/his-siblings/his-k1ds.db
....
....
I need to replace last string his-keeds.db and similar typos to blank, so my attempt is
:1,$s/\/.+\.db$//g
but doesn't work. I was able to do it using awk and perl but failed doing so in vim inbuilt editor. Can anyone help?
this would do the job:
:%s#/[^/]*\.db$#/#
if you don't want the ending slash:
:%s#/[^/]*\.db$##
Try
:g/his-keeds.db$/s///g
instead
Related
I have a very large .CSV document with text I need removing. The data looks like this
774431994&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774431994
774431996&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774431996
774431998&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774431998
774432000&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774432000
774432003&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774432003
774432006&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774432006
774432009&images=774431994,774431996,774431998,774432000,774432003,774432006,774432009&formats=0,0,0,0,0 /1/6/9/5/2/6/8/webimg/774432009
I'm using the following Regex which is working on http://regexr.com/3a6oa
/.{128}(?=webimg).{10}/g
It just doesn't seem to work with Textmate Search. Does anyone know why? I need to select all of this junk and replace it with nothing, the numbers are unique each time.
Thanks very much
Why are you using a lookahead in your pattern? Just use: /.{128}webimg.{10}/g
Why are you using Textmate search at all? I'd need to know more context of the problem to say for sure, but I bet a simple sed command could just be used instead:
sed -i "webimg/d" ./filename.csv
very recently i started to learn PERL so sorry if question appears very novice to anyone. I want to extract the lines started like this
gb|EU883669.1| Nicotiana tabacum phenylalanine ammonia-lyase
but not like this
>gb|EU883669.1| Nicotiana tabacum phenylalanine ammonia-lyase
I am using this code to do this /(?<!\>)[a-z]\|/) but it matches both lines. Any suggestion will be helpful.
Use the ^ anchor to make sure the line starts with alphanumeric: /^[a-z]+\|/
/(?<![a-z>])[a-z]+\|/ might work.
I am trying to make an if-then-else statement using RegEx. I want to match the text if it contains Monty and also contains Python. Also the text should get matched if Monty is not present in the text.
RegEx
(?(?=Monty)(?(?=Python).*|)|^.*).*$
Kindly help!
How about this:
(^(?!.*Monty(?!.*Python.*).*).*$|^.*Python.*Monty.*$)
This passes my tests, but let me know if it works for you.
I am not versed in lookahead regex but just tried to build the regex from what I understood from above description. Check the link to see if this is what you are trying to do.
try this instead
((?=Monty)((?=Python).*|)|^.*).*$
Our standards have changed and I want to do a 'find and replace' in say Dreamweaver(it allows for RegEx or we just got Visual Studio 2010, if it allows for searching by RegEx) for all the underscores and camelCase them.
What would be the RegEx to do that?
RegEx baffles me. I definitely need to do some studying.
Thanks in advance!
Update: A little more info - I'm searching within my html,aspx,cfm or css documents for any string that contains an underscore and replacing it with the following letter capitalized.
I had this problem, but I need to also handle converting fields like gap_in_cover_period_d_last_5_yr into gapInCoverPeriodDLast and found 9 out of 10 other sed expressions, don't like 1 letter words or numbers.
So to answer the question, use sed. sed -s is the equivalent to using the :s command in vim. So the example below is a command (ie sed -s/.../gc
This seemed to work, although I did have to run it twice (word_a_word will become wordA_word on the first pass and wordAWord on the second. sed backward commands, are just too magical for my muggle blood):-
s/\([A-Za-z0-9]\+\)_\([0-9a-z]\)/\1\U\2/gc
I recently had to approach a similar situation you asked about. Here is a regex I've been using in VIM which does the job for me:
%s/_\([a-zA-Z]\)/\u\1/g
As an example:
this_is_a_test becomes thisIsATest
I don't think there is a good way to do this purely with regex. Searching for _ characters is easy, something like ._. should work to find an _ with something on either side, but you need a more powerful scripting system to change the case of the character following the _. I suggest perl :)
I have a solution in PHP
preg_replace("/(_)(.)/e", "strtoupper('\\2')", $str)
There may be a more elegant selector criteria but I wanted to keep it simple.
I am looking to remove a ton of bad spam URL links from my forums using regex in either grep or vim and subsequently using find/replace commands. I am looking for a way to select just the bad URLs to do that.
All of the URLs are different and are preceeded by \n________\n. (Thats 8 underscores)
Here is an example of one of the URLs:
\n________\n[URL=http://boxvaporizers.com]Box Vaporizers[/URL]
So basically I was trying to use the \n... and the [/URL] as boundaries to select that and everything inbetween. What I came up with is this:
[\\]n[_][_][_][_][_][_][_][_][\\]n.*\[\/URL\]]
Using that does not correctly close the search and selects pretty much everything. I very am new at this and appreciate any insight. Thanks.
Assuming GNU ERE, this should work:
\\n_{8}\\n\s\[URL=(.*)].*\[/URL]
RegexBuddy seems to agree with me:
That said,
> grep -E \\n_{8}\\n\s\[URL=(.*)].*\[/URL] test.txt
doesn't work on my system (Cygwin with GNU grep 2.6.3; test.txt's contents are shown in the screenshot above).
If you want to give sed a chance following will do the job:
sed 's/^.*\(\[URL.*\)$/\1/' file.txt
PS: You can do same :s/^.*\(\[URL.*\)$/\1/ in your vi session as well.
OUTPUT
For the file.txt that contains:
\n__\n[URL=http://boxvaporizers.com]Box Vaporizers[/URL]
It produces:
[URL=http://boxvaporizers.com]Box Vaporizers[/URL]
In Vim this should remove all lines that match the pattern:
:g/\\n\%(\\_\)\{8}\\n \[URL=.\{-}\/URL\]/d
That pattern matches the sample text taken literally, all in one line.
I was actually able to do this in Microsoft Word using the following:
[\\]n_{8}[\\]n?*/URL\]
Thank you for all the input, couldn't have done it without the help!