I have a seemingly very simple problem but I just can't seem to figure it out.
I have data that looks like this :
A (B, C, A)
B (X, Y, Z)
C (F, C, D)
I am using Pig latin to check if the text in the first column is present in the second column.
This is my code for now:
Labels = LOAD 'example.txt' USING PigStorage('\t');
Projected = FOREACH Labels GENERATE $0 AS id, $1 AS group;
X = FILTER Projected BY (group matches '.*(chararray)id.*');
STORE X INTO '/test' USING PigStorage(',');
The output I am expecting is:
A (B, C, A)
C (F, C, D)
I also tried concatenating the ".*" to the id but it was of no avail.
I've been stuck with this for quite sometime and any help would be greatly appreciated. Thanks!
There's two problems, one you can't name your variable group because that's a reserved word, two you're matching the string "(chararray)id", not the id.
Also IMO I think it's cleaner never to assign variables by index, and just to define them in your load statement, you can remove the Projected alias if you do this.
Labels = LOAD 'example.txt' USING PigStorage('\t') AS
(id:chararray, stringvalue:chararray);
X = FILTER Labels BY (stringvalue matches CONCAT(CONCAT('.*',id),'.*'));
STORE X INTO '/test' USING PigStorage(',');
Tested this, it worked.
Related
Goal: I have a bunch of keywords I'd like to categorise automatically based on topic parameters I set. Categories that match must be in the same column so the keyword data can be filtered.
e.g. If I have "Puppies" as a first topic, it shouldn't appear as a secondary or third topic otherwise the data cannot be filtered as needed.
Example Data: https://docs.google.com/spreadsheets/d/1TWYepApOtWDlwoTP8zkaflD7AoxD_LZ4PxssSpFlrWQ/edit?usp=sharing
Video: https://drive.google.com/file/d/11T5hhyestKRY4GpuwC7RF6tx-xQudNok/view?usp=sharing
Parameters Tab: I will add words in columns D-F that change based on the keyword data set and there will often be hundreds, if not thousands, of options for larger data sets.
Categories Tab: I'd like to have a formula or script that goes down the columns D-F in Parameters and fills in a corresponding value (in Categories! columns D-F respectively) based on partial match with column B or C (makes no difference to me if there's a delimiter like a space or not. Final data sheet should only have one of these columns though).
Things I've Tried:
I've tried a bunch of things. Nested IF formula with regexmatch works but seems clunky.
e.g. this formula in Categories! column D
=IF(REGEXMATCH($B2,LOWER(Parameters!$D$3)),Parameters!$D$3,IF(REGEXMATCH($B2,LOWER(Parameters!$D$4)),Parameters!$D$4,""))
I nested more statements changing out to the next cell in Parameters!D column (as in , manually adding $D$5, $D$6 etc) but this seems inefficient for a list thousands of words long. e.g. third topic will get very long once all dog breed types are added.
Any tips?
Functionality I haven't worked out:
if a string in Categories B or C contains more than one topic in the parameters I set out, is there a way I can have the first 2 to show instead of just the first one?
e.g. Cell A14 in Categories, how can I get a formula/automation to add both "Akita" & "German Shepherd" into the third topic? Concatenation with a CHAR(10) to add to new line is ideal format here. There will be other keywords that won't have both in there in which case these values will just show up individually.
Since this data set has a bunch of mixed breeds and all breeds are added as a third topic, it would be great to differentiate interest in mixes vs pure breeds without confusion.
Any ideas will be greatly appreciated! Also, I'm open to variations in layout and functionality of the spreadsheet in case you have a more creative solution. I just care about efficiently automating a tedious task!!
Try using custom function:
To create custom function:
1.Create or open a spreadsheet in Google Sheets.
2.Select the menu item Tools > Script editor.
3.Delete any code in the script editor and copy and paste the code below into the script editor.
4.At the top, click Save save.
To use custom function:
1.Click the cell where you want to use the function.
2.Type an equals sign (=) followed by the function name and any input value — for example, =DOUBLE(A1) — and press Enter.
3.The cell will momentarily display Loading..., then return the result.
Code:
function matchTopic(p, str) {
var params = p.flat(); //Convert 2d array into 1d
var buildRegex = params.map(i => '(' + i + ')').join('|'); //convert array into series of capturing groups. Example (Dog)|(Puppies)
var regex = new RegExp(buildRegex,"gi");
var results = str.match(regex);
if(results){
// The for loops below will convert the first character of each word to Uppercase
for(var i = 0 ; i < results.length ; i++){
var words = results[i].split(" ");
for (let j = 0; j < words.length; j++) {
words[j] = words[j][0].toUpperCase() + words[j].substr(1);
}
results[i] = words.join(" ");
}
return results.join(","); //return with comma separator
}else{
return ""; //return blank if result is null
}
}
Example Usage:
Parameters:
First Topic:
Second Topic:
Third Topic:
Reference:
Custom Functions
I've added a new sheet ("Erik Help") with separate formulas (highlighted in green currently) for each of your keyword columns. They are each essentially the same except for specific column references, so I'll include only the "First Topic" formula here:
=ArrayFormula({"First Topic";IF(A2:A="",,IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) & IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))))})
This formula first creates the header (which can be changed within the formula itself as you like).
The opening IF condition leaves any row in the results column blank if the corresponding cell in Column A of that row is also blank.
JOIN is used to form a concatenated string of all keywords separated by the pipe symbol, which REGEXEXTRACT interprets as OR.
IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) will attempt to extract any of the keywords from each concatenated string in Columns B and C. If none is found, IFERROR will return null.
Then a second-round attempt is made:
& IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>"")))))
Only this time, REGEXREPLACE is used to replace the results of the first round with null, thus eliminating them from being found in round two. This will cause any second listing from the JOIN clause to be found, if one exists. Otherwise, IFERROR again returns null for round two.
CHAR(10) is the new-line character.
I've written each of the three formulas to return up to two results for each keyword column. If that is not your intention for "First Topic" and "Second Topic" (i.e., if you only wanted a maximum of one result for each of those columns), just select and delete the entire round-two portion of the formula shown above from the formula in each of those columns.
I'm trying to replace "x" in each column (excepts for the first 2 columns) with the column name in a table with an unknown number of columns but with at least 2 columns.
I found the code to change one column, but I want it to be dynamic:
#"Ersatt värde" = Table.ReplaceValue(Källa,"x", Table.ColumnNames(Källa){2},Replacer.ReplaceText,{Table.ColumnNames(Källa){2}})
Any ideas on how to solve it?
If I understand correctly, I think you can try either approach below:
#"Ersatt värde" =
let
columnsToTransform = List.Skip(Table.ColumnNames(Källa), 2),
accumulated = List.Accumulate(columnsToTransform, Källa, (tableState as table, columnName as text) =>
Table.ReplaceValue(tableState,"x", columnName, Replacer.ReplaceText, {columnName})
)
in accumulated
or:
#"Ersatt värde" =
let
columnsToTransform = List.Skip(Table.ColumnNames(Källa), 2),
transformations = List.Transform(columnsToTransform, (columnName) => {columnName, each
Replacer.ReplaceText(Text.From(_), "x", columnName)}),
transformed = Table.TransformColumns(Källa, transformations)
in transformed,
Both ways follow a similar approach:
Figure out which columns to do replacements in (i.e. all except the first 2 columns)
Loop over columns determined in previous step and actually do the replacement.
I've used Replacer.ReplaceText since that's what you'd used in your question, but I believe this will replace both partial matches and full matches.
If you only want full matches to be replaced, I think you can use Replacer.ReplaceValue instead.
I'm trying to create "Sale Rep" summaries by "Shop", where I can simply filter a column by the rep's name, them populate a total sales for each shop next to the relevant filter result.
I'm using this to filter all the Stores by Scott:
=(filter(D25:D47,A25:A47 = "Scott"))
Next, want to associate the Store/Account in F to populate with the corresponding value of E inside of G. So, G25 should populate the value of E25 ($724), G26 with E26 ($822), and F27 with E38 ($511.50)
I don't know how to write the formula correctly, but something like this is what I'm trying to do: =IF(F25=D25:D38),E25 I know that's not right, and it won't work in a fill down. But I'm basically trying to look for and copy over the correct value match of D and E inside of G. So, Misty Mountain Medicince in F27 will be matched to the value of E38 and populated in G27.
The filter is what's throwing me off, because it's not a simple fill down. And I don't know how to match filtered results from one column to a matched value in another.
Hope the screenshot helps. Screenshot of table:
Change Field Rep: Scott to Scott and you might apply:
=query(A25:E38,"select D,E where A='"&F24&"'")
// Enter the following into G25 and copy down column G
=(filter(E25:E47, D25:D47 = F25))
or
// Enter the following into G25 will expand with content in F upto row 47
=ArrayFormula(IF(F25:F47 <> 0, VLOOKUP(F25:F47, D25:E47, 2, FALSE),))
I have a string as:
[["structure\/","structure\/home_page\/","structure\/home_page\/headline_list\/","structure\/home_page\/latest\/","topic\/","topic\/location\/","topic\/location\/united_states\/","topic\/location\/united_states\/ohio\/","topic\/location\/united_states\/ohio\/franklin\/","topic\/news\/","topic\/news\/politics\/","topic\/news\/politics\/elections\/,topic\/news\/politics\/elections\/primary\/"]]
I want to regex_extract_all to turn it into elements in a tuple and sepereated by ",". Then I need to filter out the ones don't contain structure and location.
However, I got an error that can't filter regex type. Any idea?
By the way, the ending goal is to parse out the longest hierarchy like (topic|news|politics|elections|primary)
update the script:
data = load load '/web/visit_log/20160303'
USING com.twitter.elephantbird.pig.load.JsonLoader('-nestedLoad') as json:map[];
a = foreach data generate json#section as sec_type;
b = foreach act_flt GENERATE ..host, REGEX_EXTRACT_ALL(act_type, 'topic..(?!location)(.*?)"') as extr;
store b into /user/tad/sec_hir
The syntax for filter matches seems incorrect.The data doesn't seem to have () in it.
c = filter b by not extr matches '(structure|location)';
Try changing this to
c = filter b by not (extr matches 'structure|location');
Suppose I have two dataframes a and b,
a has one column called 'detail':
pure water
wood fire
mineral water
water
fire work
and b has one column called 'type':
water
fire
Many R functions require input text to get match, grep('fire',a), but my question is if there is a way to match a using b? I tried loop but failed. Following SQLDF got all false result for match.
ab <- sqldf(select *,case when detail in (select distinct types from b) then 1 else 0 end as match) from a)
Ideally, one can using something like c <- grep(a$detail,b$types). not sure if it is allowed in R though.
Thanks in advance!
Create a type column in a and then merge on it:
merge(transform(a, type = sub(".* ", "", a$detail)), b, all = TRUE)