Displaying a minimum value in an array - c++

Question

Ok, I also need to calculate and display each height after a 5% increase using a separate 10-element array. Any ideas? Sorry about all this. This is my first time using arrays.
#include <iostream>
using namespace std;
int main()
{
int MINheight = 0;
double height[10];
for (int x = 0; x < 10; x = x + 1)
{
height[x] = 0.0;
}
cout << "You are asked to enter heights of 10 students. "<< endl;
for (int x = 0; x < 10; x = x + 1)
{
cout << "Enter height of a student: ";
cin >> height[x];
}
system("pause");
return 0;
}

Answer 1

Simply loop like this:
MINheight = height[0];
for (int x = 1; x < 10; x++)
{
if (height[x] < MINheight)
{
MINheight = height[x];
}
}
std::cout << "minimum height " << MINheight <<std::endl;
Side Note: you should not name a local variable starting with Capital letter, using x as array index is also kind of strange, though they both work fine, but not good style.
You may also use std::min_element as follows:
std::cout << *std::min_element(height,height+10) << std::endl;
//^^using default comparison
To put elements in separate array with increased heights and display them, do the following:
float increasedHeights[10] = {0.0};
for (int i = 0; i < 10; ++i)
{
increasedHeights[i] = height[i] * 1.05;
}
//output increased heights
for (int i = 0; i < 10; ++i)
{
std::cout << increasedHeights[i] << std::endl;
}

Answer 2

Essentially, you can keep track of the minimum value as it is being entered, so:
cout << "You are asked to enter heights of 10 students. "<< endl;
MINheight = numerical_limits<int>::max
for (int x = 0; x < 10; x = x + 1)
{
cout << "Enter height of a student: ";
cin >> height[x];
if(height[x] < MINheight)MINheight = height[x];
}
cout << "Minimum value was: " << MINheight << "\n";
What this does is create a variable with its value the maximum possible value, then when ever a new value is entered by the user, check if it less than current minimum, if so store it. Then print out the current minimum at the end.