I have a bug with my code (the code at the end of the question). The purpose of my C++ executable is to read a file that contains numbers, copy it in a std::vector and
then just print the contents in the stdout? Where is the problem? (atoi?)
I have a simple text file that contains the following numbers (each line has one number)
mini01:algorithms ios$ cat numbers.txt
1
2
3
4
5
When I execute the program I receive one more line:
mini01:algorithms ios$ ./a.out
1
2
3
4
5
0
Why I get the 6th line in the stdout?
#include <iostream>
#include <string>
#include <fstream>
#include <vector>
using namespace std;
void algorithm(std::vector<int>& v) {
for(int i=0; i < v.size(); i++) {
cout << v[i] << endl;
}
}
int main(int argc, char **argv) {
string line;
std::vector<int> vector1;
ifstream myfile("numbers.txt");
if ( myfile.is_open()) {
while( myfile.good() )
{
getline(myfile, line);
vector1.push_back(atoi(line.c_str()));
}
myfile.close();
}
else {
cout << "Unable to open file" << endl;
}
algorithm(vector1);
return 0;
}
You should not use while (myfile.good()), as it will loop once to many.
Instead use
while (getline(...))
The reason you can't use the flags to check for looping, is that they don't get set until after an input/output operation notices the problem (error or end-of-file).
Don't use good() as the condition of your extraction loop. It does not accurately indicate whether the next read will succeed or not. Move your call to getline into the condition:
while(getline(myfile, line))
{
vector1.push_back(atoi(line.c_str()));
}
The reason it is failing in this particular case is because text files typically have an \n at the end of the file (that is not shown by text editors). When the last line is read, this \n is extracted from the stream. Yes, that may be the very last character in the file, but getline doesn't care to look any further than the \n it has extracted. It's done. It does not set the EOF flag or do anything else to cause good() to return false.
So at the next iteration, good() is still true, the loop continues and getline attempts to extract from the file. However, now there's nothing left to extract and you just get line set to an empty string. This then gets converted to an int and pushed into the vector1, giving you the extra value.
In fact, the only robust way to check if there is a problem with extraction is to check the stream's status bits after extracting. The easiest way to do this is to make the extraction itself the condition.
You read one too many lines, since the condition while is false AFTER you had a "bad read".
Welcome to the wonderful world of C++. Before we go to the bug first, I would advise you to drop the std:: namespace resolution before defining or declaring a vector as you already have
using namespace::std;
A second advise would be to use the pre increment operator ++i instead of i++ wherever feasible. You can see more details on that here.
Coming to your problem in itself, the issue is an empty new line being read at the end of file. A simple way to avoid this would be to check the length of line before using it.
getline(myfile, line);
if (line.size()) {
vector1.push_back(atoi(line.c_str()));
}
This would enable your program now to read a file interspersed with empty lines. To be further foolproof you can check the line read for presence of any non numeric characters before using atoi on it. However the best solution as mentioned would be use to read the line read to the loop evaluation.
Related
I wrote the following C++ program to read a text file line by line and print out the content of the file line by line. I entered the name of the text file as the only command line argument into the command line.
#include <iostream>
#include <fstream>
using namespace std;
int main(int argc, char* argv[])
{
char buf[255] = {};
if (argc != 2)
{
cout << "Invalid number of files." << endl;
return 1;
}
ifstream f(argv[1], ios::in | ios::binary);
if (!f)
{
cout << "Error: Cannot open file." << endl;
return 1;
}
while (!f.eof())
{
f.get(buf,255);
cout << buf << endl;
}
f.close();
return 0;
}
However, when I ran this code in Visual Studio, the Debug Console was completely blank. What's wrong with my code?
Apart from the errors mentioned in the comments, the program has a logical error because istream& istream::get(char* s, streamsize n) does not do what you (or I, until I debugged it) thought it does. Yes, it reads to the next newline; but it leaves the newline in the input!
The next time you call get(), it will see the newline immediately and return with an empty line in the buffer, for ever and ever.
The best way to fix this is to use the appropriate function, namely istream::getline() which extracts, but does not store the newline.
The EOF issue
is worth mentioning. The canonical way to read lines (if you want to write to a character buffer) is
while (f.getline(buf, bufSz))
{
cout << buf << "\n";
}
getline() returns a reference to the stream which in turn has a conversion function to bool, which makes it usable in a boolean expression like this. The conversion is true if input could be obtained. Interestingly, it may have encountered the end of file, and f.eof() would be true; but that alone does not make the stream convert to false. As long as it could extract at least one character it will convert to true, indicating that the last input operation made input available, and the loop will work as expected.
The next read after encountering EOF would then fail because no data could be extracted: After all, the read position is still at EOF. That is considered a read failure. The condition is wrong and the loop is exited, which was exactly the intent.
The buffer size issue
is worth mentioning, as well. The standard draft says in 30.7.4.3:
Characters are extracted and stored until one of the following occurs:
end-of-file occurs on the input sequence (in which case the function calls setstate(eofbit));
traits::eq(c, delim) for the next available input character c
(in which case the input character
is extracted but not stored);
n is less than one or n - 1 characters are stored
(in which case the function calls setstate(
failbit)).
The conditions are tested in that order, which means that if n-1 characters have been stored and the next character is a newline (the default delimiter), the input was successful (and the newline is extracted as well).
This means that if your file contains a single line 123 you can read that successfully with f.getline(buf, 4), but not a line 1234 (both may or may not be followed by a newline).
The line ending issue
Another complication here is that on Windows a file created with a typical editor will have a hidden carriage return before the newline, i.e. a line actually looks like "123\r\n" ("\r" and "\n" each being a single character with the values 13 and 10, respectively). Because you opened the file with the binary flag the program will see the carriage return; all lines will contain that "invisible" character, and the number of visible characters fitting in the buffer will be one shorter than one would assume.
The console issue ;-)
Oh, and your Console was not entirely empty; it's just that modern computers are too fast and the first line which was probably printed (it was in my case) scrolled away faster than anybody could switch windows. When I looked closely there was a cursor in the bottom left corner where the program was busy printing line after line of nothing ;-).
The conclusion
Debug your programs. It's very easy with VS.
Use getline(istream, string).
Use the return value of input functions (typically the stream)
as a boolean in a while loop: "As long as you can extract any input, use that input."
Beware of line ending issues.
Consider C I/O (printf, scanf) for anything non-trivial (I didn't discuss this in my answer but I think that's what many people do).
#include <iostream>
#include <fstream>
#include <sstream>
#include <string>
#include <iomanip>
void add1(std::fstream& files)
{
char c;
int i=0;
int j=0;
int k=0;
int con=0;
string word;
while(files.get(c)&&!files.eof())
{
i++;
j++;
if(c=='\n'||(con>=1&&isspace(c)))
{
con++;
if(con>=2)
{
break;
}
else
{
cout<<j<<"\/"<<i<<endl;
files.seekp(i-j,files.beg);
files.write("h",1);
files.seekg(i);
*seekg ends the loops I tried fstream::clear. I think it would work perfect if seekg worked.
+ without seekg it works but only for 3 lines then its off.
j=0;
word="";
}
}
else
{
con=0;
word=word+c;
}
}
}
*The goal is to be able stream the file, and replace the first letter of every line in the file while streaming.*
You seam to have a logical error and make thinks overcomplicated.
I do not knwow, what you want to do with your variable "word". It is consumed nowhere. So, I will ignore it.
Then you are playing with read and write pointers. That is not necessary. You only need to manipulate the write pointer.
Then, you want to "stream" something. This I do not fully understand. Maybe it means, that you want to write always something to the stream, even, if you do not replace anything. This would in my understanding only make sense, if you would have 2 streams. But in that case it would be brutally simple and no further thinking necessary.
If we use the same stream and do not want to replace a character, then this is already there, existing, and maybe not overwritten by the same character again.
So, if there is nothing to replace, then we will write nothing . . .
Also, and that is very important, we do no replacement operation, if we have an empty line, because then there is nothing to replace. There is now first character in an empty line.
And, most important, we cannot add characters to the same fstream. In that case we would have to shift the rest of the file one to the right. Therefore. 2 streams are always better. Then, this problem would not occur.
So, what's the logic.
Algorithm:
We always look at the previuosly read character. If that was a '\n' and the current character is not, then we are now in a new line and can replace the first character.
That is all.
It will take also into account, if a '\n' is encoded with 2 characters (for example \r\n). It will always work.
And, it is easy to implement. 10 lines of code.
Please see:
#include <iostream>
#include <fstream>
#include <string>
constexpr char ReplacementCharacter{ 'h' };
void replaceFirstCharacterOfLine(std::fstream& fileStream) {
// Here we stor the previously read character. In the beginning, a file always starts
// with a newline. Therefore we pretend that the last read character is a newline
char previouslyReadCharacter{'\n'};
// Here we store the current read character
char currentCharacter{};
// Get characters from file as lon as there are characters, so, until eof
while (fileStream.get(currentCharacter)) {
// No check, if a new line has started. We ignore empty lines!
if ((previouslyReadCharacter == '\n') && (currentCharacter != '\n')) {
// So last charcter was a newline and this is different. So, we are in a new, none empty line
// Set replacement character
currentCharacter = ReplacementCharacter;
// Go one back with the write pointer
fileStream.seekp(-1, std::ios_base::cur);
// Write (an with taht increment file pointer again)
fileStream.put(currentCharacter);
// Write to file
fileStream.flush();
}
else {
// Do not replace the first charcater. So nothing to be done here
}
// Now, set the previouslyReadCharacter to the just read currentCharacter
previouslyReadCharacter = currentCharacter;
}
}
int main() {
const std::string filename{"r:\\replace.txt"};
// Open file
std::fstream fileStream{ filename };
// Check, if file could be opened
if (fileStream)
replaceFirstCharacterOfLine(fileStream);
else
std::cerr << "\n\n*** Error: Could not open file '" << filename << "'\n\n";
return 0;
}
I began learning strings yesterday and wanted to manipulate it around by filling it with a text from a text file. However, upon filling it the cstring array only prints out the last word of the text file. I am a complete beginner, so I hope you can keep this beginner friendly. The lines I want to print from the file are:
"Hello World from UAE" - First line
"I like to program" - Second line
Now I did look around and eventually found a way and that is to use std::skipary or something like that but that did not print it the way I had envisioned, it prints letter by letter and skips each line in doing so.
here is my code:
#include <fstream>
#include <iostream>
#include <cstring>
#include <cctype>
using namespace std;
int main() {
ifstream myfile;
myfile.open("output.txt");
int vowels = 0, spaces = 0, upper = 0, lower = 0;
//check for error
if (myfile.fail()) {
cout << "Error opening file: ";
exit(1);
}
char statement[100];
while (!myfile.eof()) {
myfile >> statement;
}
for (int i = 0; i < 30; ++i) {
cout << statement << " ";
}
I'm not exactly sure what you try to do with output.txt's contents, but a clean way to read through a file's contents using C++ Strings goes like this:
if (std::ifstream in("output.txt"); in.good()) {
for (std::string line; std::getline(in, line); ) {
// do something with line
std::cout << line << '\n';
}
}
You wouldn't want to use char[] for that, in fact raw char arrays are hardly ever useful in modern C++.
Also - As you can see, it's much more concise to check if the stream is good than checking for std::ifstream::fail() and std::ifstream::eof(). Be optimistic! :)
Whenever you encounter output issues - either wrong or no output, the best practise is to add print (cout) statements wherever data change is occurring.
So I first modified your code as follows:
while (!myfile.eof()) {
myfile >> statement;
std::cout<<statement;
}
This way, the output I got was - all lines are printed but the last line gets printed twice.
So,
We understood that data is being read correctly and stored in statement.
This raises 2 questions. One is your question, other is why last line is printed twice.
To answer your question exactly, in every loop iteration, you're reading the text completely into statement. You're overwriting existing value. So whatever value you read last is only stored.
Once you fix that, you might come across the second question. It's very common and I myself came across that issue long back. So I'm gonna answer that as well.
Let's say your file has 3 lines:
line1
line2
line3
Initially your file control (pointer) is at the beginning, exactly where line 1 starts. After iterations when it comes to line3, we know it's last line as we input the data. But the loop control doesn't know that. For all it knows, there could be a million more lines. Only after it enters the loop condition THE NEXT TIME will it come to know that the file has ended. So the final value will be printed twice.
I have numerical text data lines ranging between 1mb - 150 mb in size, i need to write lines of numbers related to heights, for example: heights=4 , new text must include lines: 1,5,9,13,17,21.... consequentially.
i have been trying to find a way to do this for a while now, tried using a list instead of vector which ended up with compilation errors.
I have cleaned up the code as advised. It now writes all lines sample2 text, all done here. Thank you all
I am open to method change as long as it delivers what i need, Thank you for you time and help.
following is what i have so far:
#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <vector>
using namespace std;
int h,n,m;
int c=1;
int main () {
cout<< "Enter Number Of Heights: ";
cin>>h;
ifstream myfile_in ("C:\\sample.txt");
ofstream myfile_out ("C:\\sample2.txt");
string line;
std::string str;
vector <string> v;
if (myfile_in.is_open()) {
myfile_in >> noskipws;
int i=0;
int j=0;
while (std::getline(myfile_in, line)) {
v.push_back( line );
++n;
if (n-1==i) {
myfile_out<<v[i]<<endl;
i=i+h;
++j;
}
}
cout<<"Number of lines in text file: "<<n<<endl;
}
else cout << "Unable to open file(s) ";
cout<< "Reaching here, Writing one line"<<endl;
system("PAUSE");
return 0;
}
You need to use seekg to set the position at the beginning of the file, once you have read it (you have read it once, to count the lines (which I don't think you actually need, as this size is never used, at least in this piece of code)
And what is the point if the inner while? On each loop, you have
int i=1;
myfile_out<<v[i]; //Not writing to text
i=i+h;
So on each loop, i gets 1, so you output the element with index 1 all the time. Which is not the first element, as indices start from 0. So, once you put seekg or remove the first while, your program will start to crash.
So, make i start from 0. And get it out of the two while loops, right at the beginning of the if-statement.
Ah, the second while is also unnecessary. Leave just the first one.
EDIT:
Add
myfile_in.clear();
before seekg to clear the flags.
Also, your algorithm is wrong. You'll get seg fault, if h > 1, because you'll get out of range (of the vector). I'd advise to do it like this: read the file in the while, that counts the lines. And store each line in the vector. This way you'll be able to remove the second reading, seekg, clear, etc. Also, as you already store the content of the file into a vector, you'll NOT lose anything. Then just use for loop with step h.
Again edit, regarding your edit: no, it has nothing to do with any flags. The if, where you compare i==j is outside the while. Add it inside. Also, increment j outside the if. Or just remove j and use n-1 instead. Like
if ( n-1 == i )
Several things.
First you read the file completely, just to count the number of lines,
then you read it a second time to process it, building up an in memory
image in v. Why not just read it in the first time, and do everything
else on the in memory image? (v.size() will then give you the number
of lines, so you don't have to count them.)
And you never actually use the count anyway.
Second, once you've reached the end of file the first time, the
failbit is set; all further operations are no-ops, until it is reset.
If you have to read the file twice (say because you do away with v
completely), then you have to do myfile_in.clear() after the first
loop, but before seeking to the beginning.
You only test for is_open after having read the file once. This test
should be immediately after the open.
You also set noskipws, although you don't do any formatted input
which would be affected by it.
The final while is highly suspect. Because you haven't done the
clear, you probably never enter the loop, but if you did, you'd very
quickly start accessing out of bounds: after reading n lines, the size
of v will be n, but you read it with index i, which will be n * h.
Finally, you should explicitly close the output file and check for
errors after the close, just in case.
It's not clear to me what you're trying to do. If all you want to do is
insert h empty lines between each existing line, something like:
std::string separ( h + 1, '\n' );
std::string line;
while ( std::getline( myfile_in, line ) ) {
myfile_out << line << separ;
}
should do the trick. No need to store the complete input in memory.
(For that matter, you don't even have to write a program for this.
Something as simple a sed 's:$:\n\n\n\n:' < infile > outfile would do
the trick.)
EDIT:
Reading other responses, I gather that I may have misunderstood the
problem, and that he only wants to output every h-th line. If this is
the case:
std::string line;
while ( std::getline( myfile_in, line ) ) {
myfile_out << line << '\n';
for ( int count = h - 1; h > 0; -- h ) {
std::getline( myfile_in, line );
// or myfile_in.ignore( INT_MAX, '\n' );
}
}
But again, other tools seem more appropriate. (I'd follow thiton's
suggestion and use AWK.) Why write a program in a language you don't
know well when tools are already available to do the job.
If there is no absolutely compelling reason to do this in C++, you are using the wrong programming language for this. In awk, your whole program is:
{ if ( FNR % 4 == 1 ) print; }
Or, giving the whole command line e.g. in sh to filter lines 1,5,9,13,...:
awk '{ if ( FNR % 4 == 1 ) print; }' a.txt > b.txt
Here is my code:
#include <iostream>
#include <stdlib.h>
#include <fstream>
using namespace std;
int main() {
string line;
ifstream inputFile;
inputFile.open("input.txt");
do {
getline(inputFile, line);
cout << line << endl;
} while (line != "0");
return 0;
}
input.txt content:
5 9 2 9 3
8 2 8 2 1
0
In Enclipse, it goes to infinite-loop. I'm using MinGW 5.1.6 + Eclipse CDT.
I tried many things but I couldn't find the problem.
Since you are on windows try:
} while (line != "0\r");
The last line is stored as "0\r\n". The \n is used as the line delimiter by getline so the actual line read will be "0\r"
or
you can convert the dos format file to UNIX format using command
dos2unix input.txt
Now your original program should work. The command will change the \r\n at the end of the line to \n
Also you should always do error checking after you try to open a file, something like:
inputFile.open("input.txt");
if(! inputFile.is_open()) {
cerr<< "Error opening file";
exit(1);
}
It will create an infinite loop if no line contains exactly 0. For example 0\n is not the same thing as 0. My guess is that that is your problem.
EDIT: To elaborate, getline should be discarding the newline. Perhaps the newline encoding of your file wrong (i.e. windows vs. unix).
Your main problem is working directory.
Because you are specifying a file using a relative path it searches for the file from the current working directory. The working directory can be specified by your dev environment. (Note: The working directory is not necessarily the same directory where the executable lives (this is a common assumption among beginners but only holds in very special circumstances)).
Though you have a special end of input marker "0" you should also check that the getline() is not failing (as it could error out for other reasons (including beady formatted input). As such it is usually best to check the condition of the file as you read it.
int main()
{
string line;
ifstream inputFile;
inputFile.open("input.txt");
while((getline(inputfile, line)) && (line != "0"))
{
// loop only entered if getline() worked and line !="0"
// In the original an infinite loop is entered when bad input results in EOF being hit.
cout << line << endl;
}
if (inputfile)
{
cout << line << endl; // If you really really really want to print the "0"
// Personally I think doing anything with the termination
// sequence is a mistake but added here to satisfy comments.
}
return 0;
}