Get distinct values from xml - xslt

Question

My sample xml looks below: I need to get the distinct states from xml. I am using xslt 1.0 in vs 2010 editor.
<?xml version="1.0" encoding="utf-8" ?>
<states>
<node>
<value>2</value>
<state>DE</state>
</node>
<node>
<value>1</value>
<state>DE</state>
</node>
<node>
<value>1</value>
<state>NJ</state>
</node>
<node>
<value>1</value>
<state>NY</state>
</node>
<node>
<value>1</value>
<state>NY</state>
</node>
</states>
My xslt looks like below:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
xmlns:user="urn:my-scripts">
<xsl:output method="text" indent="yes"/>
<xsl:key name="st" match="//states/node/state" use="." />
<xsl:variable name="disst">
<xsl:for-each select="//states/node[contains(value,1)]/state[generate-id()=generate-id(key('st',.)[1])]" >
<xsl:choose>
<xsl:when test="(position() != 1)">
<xsl:value-of select="concat(', ',.)" disable-output-escaping="yes"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="." disable-output-escaping="yes"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:variable>
<xsl:template match="/" >
<xsl:value-of disable-output-escaping="yes" select="$disst"/>
</xsl:template>
</xsl:stylesheet>
Output: DE,NJ,NY
My above xml looks good for the above test xml.
If I change the xml as below:
<?xml version="1.0" encoding="utf-8" ?>
<states>
<node>
<value>2</value>
<state>DE</state>
</node>
<node>
<value>1</value>
<state>DE</state>
</node>
<node>
<value>1</value>
<state>NJ</state>
</node>
<node>
<value>1</value>
<state>NY</state>
</node>
<node>
<value>1</value>
<state>NY</state>
</node>
</states>
It in not picking the state DE. Can any one suggest the suitable solution.Thanks in advance.
I need to find out the distinct states from the xml.

Answer 1

The problem here is your use of a predicate in your Muenchian grouping XPath:
[contains(value,1)]
This will often make Muenchian grouping fail to find all of the available distinct values. Instead, you should add the predicate to the key:
<xsl:key name="st" match="//states/node[contains(value, 1)]/state" use="." />
Alternatively, you can apply the predicate inside the grouping statement:
<xsl:apply-templates
select="//states/node
/state[generate-id() =
generate-id(key('st',.)[contains(../value, 1)][1])]" />
Full XSLT (with some improvements):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:user="urn:my-scripts">
<xsl:output method="text" indent="yes"/>
<xsl:key name="st" match="//states/node/state" use="." />
<xsl:variable name="a" select="1" />
<xsl:variable name="disst">
<xsl:apply-templates
select="//states/node
/state[generate-id() =
generate-id(key('st',.)[contains(../value, $a)][1])]" />
</xsl:variable>
<xsl:template match="state">
<xsl:if test="position() > 1">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select ="." disable-output-escaping="yes" />
</xsl:template>
<xsl:template match="/" >
<xsl:value-of disable-output-escaping="yes" select="$disst"/>
</xsl:template>
</xsl:stylesheet>
Result when run on your sample XML:
DE,NJ,NY