Flatten array of structs into several arrays in C++ - c++

Source code to understand the situation:
struct s {
int i;
float f
};
const int cnt = 10;
s *source = new s[cnt];
/*... fill source ...*/
int *dest_i = new int[cnt];
float *dest_f = new float[cnt];
for (int x = 0; x < cnt; x++) {
dest_i[x] = source[x].i;
dest_f[x] = source[x].f;
}
So, here is the question: is there any faster method than iterate through array with loop?

You could unroll your loop. That's all I can think of off the top of my head.
It's a fairly pointless optimization to write yourself, the compiler can try to do it for you if you enable it (in gcc, compile with --funroll-loops)

Related

C++ Allocate Memory 2D array

I get a stack overflow error because of setting a large array. I'm not sure how to allocate memory for this 2D array here, I just can't seem to get the syntax right. I used a vector previously which worked fine but I NEED to use an array for this. This code of nested loops populates the array.
static const int n = 607800;
int vars = 3;
array<int, vars> inputs[n];
//int *inputs = (int*)malloc(n * vars * sizeof(int));
int k = 0;
for (unsigned int a = 0; a < aa.size(); aa++)
{
for (unsigned int b = 0; b < bb.size(); bb++)
{
for (unsigned int c = 0; c < cc.size(); cc++)
{
inputs[k] = { aa[a], bb[b], cc[c] };
k++;
}
}
}
I've tried using new and looping the array for 2D but it didn't work for me. What's the best way to structure this?

Initialization of user-defined array in C++ class?

I'm working on knight's tour problem, and want to define a class, but I am having trouble with initialize an array defined by user. So the user inputs from the command line argvs are the chessboard lengths mX and nY; and a starting position(x,y). So basically, how do I initialize an array that's defined by the user?
First question: In the public part, is it right to declare int ** tour?
Second question: How do I refer to the array tour in the following functions in the same class?
Third question: In main, I called K.knight to initialize an array of dimension specified by the user, but it wasn't initialized. How do I initialize an array in main using the function K.knigt(), and be able to use the array in the following function K.knightfunc()?
class Ktour{
public:
int xSize; //m
int ySize; //n
int ** tour; //array to be initialized
int solutionsCount; //tracking solutions
int position; //position count, from 0 to m * n -1
// initialize tour matrix
void knight(int M, int N) {
position = 1;
solutionsCount = 0;
xSize = M;
ySize = N;
tour = new int * [xSize];
for (int i = 0; i < xSize; i++) {
for (int j = 0; j < ySize; j++) {
tour[i][j] = 0;
std::cout << tour[i][j] << std::endl;
}
}
}
....some other functions defined in between...
....
....
};
...
// main
int main(int argc, char *argv[])
{
Ktour K;
//user inputs chessboard length mX and nY; and a starting position(x,y)
int mX = atoi(argv[1]);
int nY = atoi(argv[2]);
int x = atoi(argv[3]);
int y = atoi(argv[4]);
//initialization
K.knight(mX, nY);
//run the recursive function;
K.knightFunc(x,y);
return 0;
}
Yeah, it seems more logical to initialize in the ctor. My take on this is you are creating an array of int pointers, and have not yet allocated the ints that are being pointed to.
You have a few possibilities:
If we are to think of a common chessboard, then since the array size is known in advance, and it's not especially big, just create it in the class:
class Ktour{
...
int tour[8][8];
...
}
although some purists might say you should only "new" such arrays. If it is a much larger array, you certainly should.
A more straightforward syntax like what you're trying to do, for handling arrays of unknown size would be:
class Ktour{
...
int **tour=0;
KTour(int M, int N) {
tour = new int * [M];
for (int i=0; i<M; ++i)
tour[i] = new int [N];
};
~KTour() {
for (int i=0; i<M; ++i)
delete [] tour[i];
delete [] tour;
};
...
}
You access it quite simply, with:
std::cout << tour[i][j];
The above kind of coding is error-prone. To reduce your future strife with memory access errors, you really should use STL container classes (or Boost ones, or Qt ones when using Qt, if their size isn't too limited - but you can use STL in Qt also), since they produce an error in debug when you access out-of-bounds subscripts for your arrays, instead of, e.g. overwriting important pointers, etc. Thus, you could use something like:
class Ktour{
...
std::vector < std::vector<int> > Tour;
KTour(int M, int N) {
// tour.resize(M); // not needed.
tour.assign(M, std::vector <int> (N, 0));
};
~KTour() {
// No need to delete
};
...
}
and you access it with
std::cout << tour[i][j];
(Note: The extra lines in the code are some artifact of the <pre> and <code> tags; necessitated by not all of my indented lines being recognized as code.)

Initializing multidimensional dynamical array in c++

I'm having problems declaring a multidimensional dynamical array in c style. I want to declare dynamically an array like permutazioni[variable][2][10], the code i'm using is as following (carte is a class i defined):
#include "carte.h"
//other code that works
int valide;
carte *** permutazioni=new carte**[valide];
for (int i=0; i<valide; i++){
permutazioni[i]=new carte*[2];
for (int j=0; j<2; j++) permutazioni[i][j]=new carte[10];
}
the problem is, whenever i take valide=2 or less than 2, the code just stops inside the last for (int i=0; i<valide; i++) iteration, but if i take valide=3 it runs clear without any problem. There's no problem as well if i declare the array permutazioni[variable][10][2] with the same code and any value of valide. I really have no clue on what the problem could be and why it works differently when using the two different 3d array i mentioned before
You show a 3D array declared as permutazioni[variable][10][2] but when you tried to dynamical allocate that you switched the last two dimensions.
You can do something like this:
#include <iostream>
#define NVAL 3
#define DIM_2 10 // use some more meaningfull name
#define DIM_3 2
// assuming something like
struct Card {
int suit;
int val;
};
int main() {
// You are comparing a 3D array declared like this:
Card permutations[NVAL][DIM_2][DIM_3];
// with a dynamical allocated one
int valid = NVAL;
Card ***perm = new Card**[valid];
// congrats, you are a 3 star programmer and you are about to become a 4...
for ( int i = 0; i < valid; i++ ){
perm[i] = new Card*[DIM_2];
// you inverted this ^^^ dimension with the inner one
for (int j = 0; j < DIM_2; j++)
// same value ^^^^^
perm[i][j] = new Card[DIM_3];
// inner dimension ^^^^^
}
// don't forget to initialize the data and to delete them
return 0;
}
A live example here.
Apart from that it is always a good idea to check the boundaries of the inddecs used to access to the elements of the array.
How about using this syntax? Haven't tested fully with 3 dimensional arrays, but I usually use this style for 2 dimensional arrays.
int variable = 30;
int (*three_dimension_array)[2][10] = new int[variable][2][10];
for(int c = 0; c < variable; c++) {
for(int x = 0; x < 2; x++) {
for(int i = 0; i < 10; i++) {
three_dimension_array[c][x][i] = i * x * c;
}
}
}
delete [] three_dimension_array;
Obviously this could be c++ 11/14 improved. Could be worth a shot.

Array of structs with Array in the struct

I am completely stuck on this problem... The code structure that is given is as follows:
typedef struct _myvar{
uint32_t someInt;
uint32_t *ptr;
} myvar;
...
myvar **var;
..
var = new myvar*[x]; // where x is an int
for(int i = 0; i < y; i++){ // y is usually 2 or 4
var[i] = new myvar[z]; //create dynamic 2d array
for(int j = 0; j < z; j++){
var[i][j].ptr = new int[b]; //where b is another int
}
}
What happens is I want to create a 2d structure that has one part of it being 3d i.e. the ptr is just a pointer to an array of ints.
My code compiles but I get seg faults in trying to allocate memory so ptr can point to it. I tried working on this for about an hour and figure it was time for some help.
Thanks!
EDIT1: Fixed code issue in regards to comment on code not compiling.. Secondly... I cannot use vectors as much as I would like to... The data structure that I have there is what I have to use.
EDIT2: b is dynamic and set at the command line. For testing purposes use 16.
I think you are getting confused with your indices. In your first loop you use var[i], so i must stop at x, not at y. For the columns I have used j and y. Not sure what z is.
Then, as pointed out by others, you shouldn't mix int and uint32_t.
Try this:
#include <iostream>
using namespace std;
typedef struct _myvar{
uint32_t someInt;
uint32_t *ptr;
} myvar;
int main() {
myvar **var;
int x = 3;
int y = 4;
var = new myvar*[x]; // where x is an int
for(int i = 0; i < x; i++) { // i stops at x
var[i] = new myvar[y]; //create dynamic 2d array
for(int j = 0; j < y; j++){
var[i][j].ptr = new uint32_t[16]; // used 16 for testing
}
}
return 0;
}

Best way to represent a 2-D array in C++ with size determined at run time

In C++ I'd like to do something like:
int n = get_int_from_user();
char* matrix = new char[n][n];
matrix[0][0] = 'c';
//...
matrix[n][n] = 'a';
delete [][] matrix;
but of course this doesn't work. What is the best way to do something similar? I've seen some solutions to this but they seem pretty messy.
The manual dynamic way:
Let's say you want an array of width*height, the most efficient way is to just use a single dimensional array:
char *matrix = new char[width*height];
To delete it:
delete[] matrix;
To access it:
char getArrayValue(char *matrix, int row, int col)
{
return matrix[row + col*width];
}
To modify it:
void setArrayValue(char *matrix, int row, int col, char val)
{
matrix[row + col*width] = val;
}
Boost Matrix:
Consider using boost::matrix if you can have the dependency.
You could then tie into the boost linear algebra libraries.
Here is some sample code of boost::matrix:
#include <boost/numeric/ublas/matrix.hpp>
using namespace boost::numeric::ublas;
matrix<char> m (3, 3);
for (unsigned i = 0; i < m.size1 (); ++ i)
for (unsigned j = 0; j < m.size2 (); ++ j)
m (i, j) = 3 * i + j;
On the stack for some compilers:
Some compilers actually allow you to create arrays on the stack with runtime determined sizes. g++ is an example of such a compiler. You cannot do this by default VC++ though.
So in g++ this is valid code:
int width = 10;
int height = 10;
int matrix[width][height];
Drew Hall mentioned that this C99 feature is called Variable Length Arrays (VLAs) and it can probably be turned on in any modern compiler.
I usually do something like this:
char *matrix = new char [width * height];
matrix[i + j * width] = 'c'; // same as matrix[i][j] = 'c';
delete [] matrix;
You seem to be missing the whole point of C++ (C with classes) :-). This is the sort of use that's crying out for a class to implement it.
You could just use STL or other 3rd party class library which I'm sure would have the data structure you're looking for but, if you need to roll your own, just create a class with the following properties.
constructor which, given n, will just create a new n*n array of char (e.g., charray)..
member functions which get and set values based on x.y which simply refer to charray[x*n+y];
destructor which delete[]'s the array.
What about std::vector< std::vector<int> > array2d; ?
For a true two dimensional array:
int n = get_int_from_user();
char** matrix = new char*[n];
for (int i = 0; i < n; i++) {
matrix[i] = new char[n];
}
// Operations on matrix.
for (int i = 0; i < n; i++) {
delete [] matrix[i];
}
delete matrix;
Just off the top of my head. Mistakes, no doubt. However, other people have posted a more elegant approach, I think.
I like the 1-d array approach (the selected answer by Brian R. Bondy) with the extension that you wrap the data members into a class so that you don't need to keep track of the width separately:
class Matrix
{
int width;
int height;
char* data;
public:
Matrix();
Matrix(int width, int height);
~Matrix();
char getArrayValue(int row, int col);
void setArrayValue(int row, int col, char val);
}
The implementation is an exercise for the reader. ;)
I think this would be a good one.
int n = get_int_from_user();
char **matrix=new (char*)[n];
for(int i=0;i<n;i++)
matrix[i]=new char[n];
matrix[0][0] = 'c';
//...
matrix[n][n] = 'a';
for(int i=0;i<n;i++)
delete []matrix;
delete []matrix;
std::vector<int> m;
Then call m.resize() at runtime.
int* matrix = new int[w*h];
if you want to do something like Gaussian elimination your matrix should be
int** matrix = new int*[h];
for(size_t i(0); i < h; ++i)
matrix[i] = new int[w];
(in Gaussian elimination we usually need to exchange one row with another so it's better to swap pointers to rows in constant time rather than swapping by copying in linear time).