I have the following strings in a text file (big one, more like these and different):
79A18D7F-1517-5981-8446-3A0452727B06
7842A72D-1517-5281-84E4-EAEF09B743F7
6040BEE7-1517-5982-84C1-419B224E647E
615F2747-1517-5981-84AF-787C34967FB2
7468A3E3-1517-5931-84B3-3FC3F701C269
I can find them using grep and regex:
'[0-9A-F]{8}-[0-9]{4}-[0-9]{4}-[0-9A-F]{4}-[0-9A-F]{12}'
what's the sed regex syntax to delete them because:
sed "s/[0-9A-F]{8}-[0-9]{4}-[0-9]{4}-[0-9A-F]{4}-[0-9A-F]{12}//g"
doesn't seem to work.
Thanks!
Use sed -r. You are relying on extended regular expression syntax features without escaping them, but with sed -r you don't have to. If you want to actually delete the lines instead of just clearing them, you can use:
sed -r "/regex/d"
In addition, for regular sed (BRE) you would need to escape the curly braces:
sed 's/[0-9A-F]\{8\}-[0-9]\{4\}-[0-9]\{4\}-[0-9A-F]\{4\}-[0-9A-F]\{12\}//g' file
Related
I want to replace dots with commas for some but not all matches:
hostname_metric (Index: 1) to hostname;metric (avg);22.04.2015 13:40:00;3.0000;22.04.2015 02:05:00;2.0000;22.04.2015 02:00:00;650.7000;2.2594;
The outcome should look like this:
hostname_metric (Index: 1) to hostname;metric (avg);22.04.2015 13:40:00;3,0000;22.04.2015 02:05:00;2,0000;22.04.2015 02:00:00;650,7000;2,2594;
I was able to identify the RegEx which should work to find the correct dots.
;[0-9]{1,}\.[0-9]{4}
But how can I replace them with a comma with awk or sed?
Thanks in advance!
Adding some capture groups to the regex in your question, you can use this sed one-liner:
sed -r 's/(;[0-9]{1,})\.([0-9]{4})/\1,\2/g' file
This matches and captures the part before and after the . and uses them in the replacement string.
On some versions of sed, you may need to use -E instead of -r to enable Extended Regular Expressions. If your version of sed doesn't understand either switch, you can use basic regular expressions and add a few escape characters:
sed 's/\(;[0-9]\{1,\}\)\.\([0-9]\{4\}\)/\1,\2/g' file
sed 's/\(;[0-9]\+\)\.\([0-9]\{4\}\)/\1,\2/g' should do the trick.
I have tested this particular regex in RegExr.com:
/(\*)*((\s)?(\w)*)/g
to match the following:
* Global Links contained...etc
* Change User, contact list...etc
(everything from ... on is just extra words in the sentence, not a literal ...etc)
I tried to use this regex in a sed command as part of a bash script like so:
sed "/(\*)*((\s)?(\w)*)/d" test.txt > stripped.txt
But these two lines still remain in stripped.txt. Is there something I'm not accounting for in the regex or in the file? before these two lines is the start of a block comment (/**) and the block comment end is after them(*/), both of these are on new lines. Am i missing something obscure with new lines or is the sed command/regex wrong?
You aren't accounting for the dialect of regex in use by sed by default. That's not a valid BRE (basic regular expression).
You need to tell sed to use ERE's (extended regular expressions).
For GNU sed that is the -r flag and for BSD sed that is the -E flag (though -r is often available as a compat flag).
sed -r "/(\*)*((\s)?(\w)*)/d" test.txt > stripped.txt
I'm trying to replace two strings in a php file using two sed commands, can't find where I'm wrong.
Want to transform from strings
setlocale(LC_ALL, $_COOKIE['lang']);
and
putenv("LANGUAGE=".$_COOKIE['lang']);
to the strings
setlocale(LC_ALL, $_COOKIE['lang'].'.utf8');
and
putenv("LANGUAGE=".$_COOKIE['lang'].'.utf8');
so far I've come to the following but does not work
sed -i "s/setlocale\(LC_ALL, \$_COOKIE\['lang'\]\);.*$/setlocale\(LC_ALL, \$_COOKIE\['lang'\]\.'\.utf-8'\)\;/" file.php
sed -i "s/putenv\('LANGUAGE='\.\$_COOKIE\['lang'\]\);.*$/putenv\('LANGUAGE='\.\$_COOKIE\['lang'\]\.'\.utf-8'\)\;/" file.php
I'm definitely not an expert in sed and regular expression, so go easy on me ok?
Try these two:
sed 's/setlocale.LC_ALL, ._COOKIE..lang...;/setlocale\(LC_ALL, $_COOKIE\['\''lang'\''\].'\''.utf8'\''\);/g' file.php
sed 's/putenv..LANGUAGE...._COOKIE..lang...;/putenv\("LANGUAGE=".$_COOKIE\['\''lang'\''].'\''.utf8'\'');/g' file.php
You should not escape the parentheses. There is no need to escape matching characters in the replacement part, either:
sed "s/setlocale(LC_ALL, \$_COOKIE\['lang'\]);.*$/setlocale(LC_ALL, \$_COOKIE['lang'].'.utf-8')\;/"
The putenv line contains double quotes, but your expressions searches for single quotes. Therefore, it cannot match.
I need to find out how to delete up to 10 digits that are at the end of the line in my text file using sed.
For example if I have this:
ajsdlfkjasldf1234567890
asdlkjfalskdjf123456
adsf;lkjasldfkjas123
it should become:
ajsdlfkjasldf
asdlkjfalskdjf
adsf;lkjasldfkjas
can anyone help?
I have this, but its not working:
sed 's/[0-9]{10}$//g'
Have you tried this:
sed 's/[0-9]+$//'
Your command would only match and delete exactly 10 digits at the end of line and only, if you enabled extended regular expressions (-E or -r, depending on your version of sed).
You should try
sed -r 's/[0-9]{1,10}$//'
The following should work:
sed 's/[0-9]\{1,10\}$//' file
Regex syntax in sed requires backslashes before the brackets to use them for repetition, unless you use an extended regex option.
A quick look here suggests you should try this:
$ sed 's/[0-9]\{0,10\}$//g'
{ } should be escaped, unless you switch to extended regex syntax:
$ sed -r 's/[0-9]{0,10}$//g'
I'm trying to insert an absolute path before all images in an HTML file, like this:
<img src="/media/some_path/some_image.png"> to <img src="{ABS_PATH}/some_path/some_image.png">
I tried the following regex to identify the lines :
egrep '(src|href)="/media([^"]*)"'
I want to use sed to make these changes, but the above regexp doesn't work, any hints?
sed 's#(src|href)="/media([^"]*)"##g'
sed: -e expression #1, char 32: unknown option to `s'
EDIT:
ok, now i have:
echo 'src="/media/some_image.png"' | "egrep -o '(src|href)="/media([^"]*)"' | sed 's/(src|href)=\"\/media([^"]*)\"//g'
Sed should match the string, but it doesn't
sed doesn't understand ERE (extended regular expressions), only BRE (basic regular expressions). GNU sed has "-r" option which turn on ERE.
You should change delimiters for regular expressions, because you have slash in the regex, like this:
sed -r 's#(src|href)="/media([^"]*)"##g'
You can use almost any punctuation for delimiters.
You must escape / in sed if using it as a delimiter for the pattern.
So:
sed 's/(src|href)="/media([^"]*)"//g'
becomes:
sed 's/(src|href)="\/media([^"]*)"//g'
Perhaps what is confusing is that egrep (which uses extended regular expressions) has different rules to sed, and vanilla grep (which use basic regular expressions) when it comes to what must be escaped.