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Closed 9 years ago.
So i got simple code to change all _ to space but...it doesnt work! Any1 knows why? I have no idea
while (fout >> array[x][y]){
if (array[x][y]=='_') array[x][y]==' ';
y++;
if (y==8) {
y=0;
x+=1;
}
}
Take a look at this line:
if (array[x][y]=='_') array[x][y]==' ';
^
You have two equal signs when you are attempting to set the new value.
Related
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Closed 9 years ago.
How can i write this line of code in Coffeescript? Thank's
window.scrollY >= origOffsetY ? navbar.classList.add('navbar-fixed-top') :
navbar.classList.remove('navbar-fixed-top');
I try this, but doesn't work.
if window.scrollY >= origOffsetY then navbar.classList.add('navbar-fixed-top') else navbar.classList.remove('navbar-fixed-top')
Your coffeescript compiles to :
if (window.scrollY >= origOffsetY) {
navbar.classList.add('navbar-fixed-top');
} else {
navbar.classList.remove('navbar-fixed-top');
}
This seems pretty OK for me.
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Closed 10 years ago.
If I have a double: 732734
How can I return 73273 <---- notice the loss of the '4'
Divide by 10 and then floor it to remove the decimals:
number = floor(number / 10.0)
I found this somewhere. It removes the last digits after decimal. Not the actual solution but this might give you some hint:
int main(){
for (int a=0;a<80;a++)
printf(".");
printf("%2.0f\n",1024.48);
printf("%2.0f\n",4.48);
for (int a=0;a<80;a++)
printf(".");
return 0;
}
Output:
................................................................................
1024
4
................................................................................
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Closed 10 years ago.
Can someone help me out here? I need a regex that will match the following pattern:
10-(any 5 digits except 73480)-(any 4 digits)
Examples
valid: 10-12345-1234
invalid: 10-73480-1234
Thanks
You should use negative lookahead to check for any occurance of 10-73480 before matching..
^(?!10-73480)10-\d{5}-\d{4}$
Try it here
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Closed 10 years ago.
Can anyone tell me meaning or possible values of below regular expression?
/(\+\d{2})/
Plus followed by a number on 2 digits.
This matches for instance: +23
A + followed by 2 digits: +23 +01 etc.
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Closed 11 years ago.
[a-zA-Z0-9-_]{3,} this is my currently using regular expression in login page. I would like to allow space in the regexp. How can i do it? I'm lack of knowledge in RegExp.
This is just a character class, so just add space at the end of the class: [a-zA-Z0-9_ -]{3,}
How about:
[a-zA-Z0-9-_\s]{3,}
This will allow all forms of whitespace...