I have a log file in which I have DEBUG, NORMAL and CRITICAL entries as well as some info that does not start with a regular (for this type of logs) data e.g. [20130313:123412]
[210313:100114] NORMAL: this is normal log
[210313:100114] DEBUG: ../../common/
Additional info:
number of ....
I would like to remove both DEBUG entries as well as those that do not start with [
I know I can do that with:
:g/DEBUG/d
and
:g!/^\[/d
how can I combine this into one ? Or properly use a regex ?
Convert them both to positive or negative rules (as appropriate), and then you can use \| ("or") to match one or the other.
:g/^[^\[]\|DEBUG/d
That would do it. ^[^\[] for lines starting with other than [, or lines containing DEBUG.
Related
I have a log file that I need to search for. The text outside of the brackets is always the same, so to be as precise as I can, I would like to ignore the text inside both square and curved brackets.
So the log is;
[09/May/2022:11:04:05 +0000] NSMMReplicationPlugin - process_postop: Failed to apply update (6278e86f000627440000) error (-1). Aborting replication session(conn=5361 op=6)
Where I do not need the date at the start inside the [ ] or the numbers & text inside both sets of ( ) either side of the (-1) as the (-1) part is key to the search.
I just need to search on;
NSMMReplicationPlugin - process_postop: Failed to apply update error (-1). Aborting replication session
I cannot figure this out! I tried a lazy qualifier but as there's ( ) that I need it didn't work;
(?<=NSMMReplicationPlugin - process_postop: Failed to apply update)(.*)(?=error (-1). Aborting replication session)
I somehow need to escape the ( ) to get the -1 part?
We can use the following pattern which divides the text into 4 groups and only uses group 2 and 4.
(\[.*\])(.*)(\(\w*\))(.*)
to get group 2 and 4 we use \2\4 or $2$4 depending on the flavour of regex.
See https://regex101.com/r/v6izps/1 for an example.
Depending on the language and the tools there may not be any need to put brackets around the 1st and 3rd groups.
We have an old, grown project with thousands of php files and need to clean it up.
Throughout the whole project we do have a lot of function calls similar to:
trans('somestring1');
trans("SomeString2");
trans('more_string',$somevar);
trans("anotherstring4",$somevar);
trans($tx_key);
trans($anotherKey,$somevar);
All of those are embedded into the code and represent translation keys. I would like to find a way to extract all "translation keys" in all occurrences.
The PHP project is in VS Code, so a RegEx Search would be helpful to list the results.
Or I could search through the project with any other tool you would recommend
However I would also need to "export" just the strings to a textfile or similar.
The ideal result would be:
somestring1
SomeString2
more_string
anotherstring4
$tx_key
$anotherKey
As a bonus - if someone knows, how I could get the above list including filename where the result has been found - that would be really fantastic!
Any help would be greatly appreciated!
Update:
The RegEx I came up with:
/(trans)+\([^\)]*\)(\.[^\)]*\))?/gim
list the full occurrence - How can I just get the first part of the result (between Single Quotes OR between Double Quotes OR beginning with $)
See here: regexr.com/548d4
Here are some steps to get exactly what you want. Using this you can do a find and replace on your search results!
So you could do sequential regex find/replaces in the right circumstances.
The replace can be just within the search results editor and not affect the underlying files at all - which is what you want.
You can also have the replace action actually edit the underlying files if you wish.
[Hint: This technique can also make doing a find item a / replace with b in files that contain term c much easier to do.]
(1) Open a new search editor: Ctrl+Shift+P
(That command is currently unbound to a keybinding.)
(2) Paste this regex into the Search input box (with the regex option .* selected):
`(.*?)(\btrans\(['"]?)([^,'")]+)(.*)` - a relatively simple regex
regex101 demo
See my other answer for a regex to work with up to 6 entries per line:
(\s*\d+:\s)?((.*?)(\btrans\(['"]?)([^,'")]*)((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?)(.*)
(3) You will get a list of files with the search results. Now open a Find widget Shift+F in this Search editor.
(4) Put the same regex into that Find input. Regex option selected. Put $3 into the Replace field. This only replaces in this Search editor - not the original files (although that can be done if you want it in some case). Replace All.
If using the 1-6 version regex, replace with:
$1$5 $9 $13 $17 $21 $25
(5) Voila. You can now save this Search Editor as a file.
The first answer works for one desired capture per line as in the original question. But that relatively simple regex won't work if there are two or more per line.
The regex below works for up to 6 entries per line, like
trans('somestring1');
stuff trans("SomeString2"); some content trans("SomeString2a");more stuff [repeat, repeat]
But it doesn't for 7+ - you'll need a regex guru for that.
Here is the process again with a twist of using a snippet in the Search Editor instead of a Find/Replace. Using a snippet allows more control over the formatting of the final result.
(1) Open a new search editor: Ctrl+Shift+P (That command is currently unbound to a keybinding.)
(2) Paste this regex into the Search input box (with the regex option .* selected):
`((.*?)(\btrans\(['"]?)([^,'")]*)((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?((.*?)(\btrans\(['"]?)([^,'")]*))?)(.*)`
regex101 demo
(3) You will get a list of files with the search results. Now select all your results individually with Ctrl+Shift+L.
(4) Trigger this keybinding:
{
"key": "alt+i", // whatever keybinding you like
"command": "editor.action.insertSnippet",
"when": "editorTextFocus",
"args": {
"snippet": "${TM_SELECTED_TEXT/((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*)((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?((.*?)(\\btrans\\([\\'\\\"]?)([^,\\'\\\")]*))?)(.*)/$4${8:+\n }$8${12:+\n }$12${16:+\n }$16${20:+\n }$20${24:+\n }$24/g}"
}
},
That snippet will be applied to each selection in your search result. This part ${8:+\n } is a conditional which adds a newline and some spaces if there is a capture group 8 - which would be a second trans(...) on a line.
Demo: (unfortunately, it doesn't properly show the Ctrl+Shift+L selecting all lines individually or the Alt+i snippet trigger)
I have a text file in Notepad++ that contains about 66,000 words all in 1 line, and it is a set of 200 "lines" of output that are all unique and placed in 1 line in the basic JSON form {output:[{output1},{output2},...}]}.
There is a set of characters matching the RegEx expression "id":.........,"kind":"track" that occurs about 285 times in total, and I am trying to either single them out, or copy all of them at once.
Basically, without some super complicated RegEx terms, I am stuck because I can't figure out how to highlight all of them at once, and also the Remove Unbookmarked Lines feature does not apply because this is all in one line. I have only managed to be able to Mark every single occurrence.
So does this require a large number of steps to get the file into multiple lines and work from there, or is there something else I am missing?
Edit: I have come up with a set of Macro schemes that make the process of doing this manually work much faster. It's another alternative but still takes a few steps and quite some time.
Edit 2: I intended there to be an answer for actually just highlighting the different sections all at once, but I guess that it not possible. The answer here turns out to be more useful in my case, allowing me to have a list of IDs without everything else.
You seem to already have a regex which matches single instances of your pattern, so assuming it works and that we must use Notepad++ for this:
Replace .*?("id":.........,"kind":"track").*?(?="id".........,"kind":"track"|$) with \1.
If this textfile is valid JSON, this opens you up to other, non-notepad++ options, like using Python with the json module.
Edited to remove unnecessary steps
I am using the maven replacer plugin and I've run into a situation where I have a regular expression that matches across lines which I need to run on the input file until all matches have been replaced. The configuration for this expression looks like this:
<regexFlags>
<regexFlag>DOTALL</regexFlag>
</regexFlags>
<replacements>
<replacement>
<token>\#([^\n\r=\#]+)\#=([^\n\r]*)(.*)(\#default\.\1\#=[^\n\r]*)(.*)</token>
<value>#$1#=$2$3$5</value>
<replacement>
<replacements>
The input could look like this:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#default.a.b.c#=QQQ
#asdfasd.fasdfs.asdfa#=23423
#default.h.i.j#=234
#default.RR.TT#=393993
and I want the output to look like this:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#asdfasd.fasdfs.asdfa#=23423
#default.RR.TT#=393993
The intention is to re-write the file, but without the tokens with a #default prefix, where another token without the prefix has already been defined.
#default.a.b.c#=QQQ and #default.h.i.j#=234 have been removed from the output because other tokens already contains a.b.c and h.i.j.
The current problem I have is that the replacer plugin only replaces the first match, so my output looks like this:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#asdfasd.fasdfs.asdfa#=23423
#default.h.i.j#=234
#default.RR.TT#=393993
Here, #default.a.b.c=QQQ is gone, which is correct, but #default.h.i.j#=234 is still present.
If I were writing this in code, I think I could probably just loop while attempting to match on the entire output, and break when there are no matches. Is there a way to do this with the replacer plugin?
Edit: I may have over simplified my example. A more realistic one is:
#d.e.f#=y
#a.b.c#=x
#h.i.j#=aaaa
#default.a.b.c#=QQQ
#asdfasd.fasdfs.asdfa#=23423
#default.h.i.j#=234
#default.RR.TT#=393993
#x.y.z#=0
#default.q.r.s#=1
#l.m.n#=8.3
#q.r.s#=78
#blah.blah.blah#=blah
This shows that it's possible for a default.x.x.x=y to precede a x.x.x=y token (as #default.q.r.s#=1 preceedes #q.r.s#=78`), my prior example wasn't clear about this. I do actually have an expression to capture this, it looks a bit like this:
\#default\.([^\n\r=#|]+)#=([^\n\r|]*)(.*)#\1#=([^\n\r|]*)(.*)
I know line separators are missing from this even though they were in the other one - I was experimenting with removing all line separators and treating it as a single line but that hasn't helped. I can resolve this problem simply by running each replacement multiple times by copying and pasting the configurations a few times, but that is not a good solution and will fail eventually.
I don't believe you could solve this problem as is, a work-around is to reverse the order of the file top to bottom, perform lookahead regex and then reverse the result order
pattern = #default\.(.*?)#[^\r\n]+(?=[\s\S]*#\1#) Demo
another way (depending on the capabilities of "Maven") is to run this pattern
#(.*)(#[\s\S]*)#default\.\1.*
and replace with #$1$2 Demo in a loop until there are no matches
then run this pattern
#default\.(.*)#.*(?=[\s\S]*\1)
and replace with nothing Demo in a loop until there are no matches
It doesn't look like the replacer plugin can actually do what I want. I got around this by using regular expressions to build multiple filter files, and then applying them to the resource files.
My original goal had been to use regular expressions to build a single, clean, and tidy filter file. In the end, I discovered that I was able to get away with just using multiple filters (not as clean or tidy) and apply them in the correct order.
i have a text file in a particular format..
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz
asdasda........................................................
asddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
I need a regular expression to reformat this file using Find and Replace - Visual Studio. The Desc field value has overflowed onto next lines. i need to move them back to the actual line. Final string should be like
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyzsdasda.........asdddddd..
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
I need an RE for "desc=" followed by anything until the next ! symbol
find Desc=([^\|\r\n]+)[\r\n](([^!\r\n][^\r\n]+[\r\n])*), replace with Desc=\1\2 and repeat until every line starts with ! (you can test this using ^[^!] as a search expr which should find nothing).
alternatively find [\r\n]+, replace with the empty string. thereafter find !, replace with \r\n!. this suggestion has 2 drawbacks. it temporarily produces very long lines which your editor (notably vs) may or may not have difficulties with and processes descriptions containing ! incorrectly.
addendum:
your input seems to be fixed format up to the Desc section. if it is indeed, you can apply alternative #2, step 1, being followed by a search/replace run using (!.{53}\|Desc=)/[\r\n]\1.
As mentioned in the comments by #X3074861X, you can use Notepad++.
Input:
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz
asdasda........................................................
asddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
For the find and replace, select the mode as Regular expression with the options as follows:
Find what: \r\n[^!]
Leave Replace with blank.
Output:
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyzsdasda........................................................sddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
Screenshot: